Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6

Balbharati Maharashtra State Board 11th Commerce Maths Solution Book Pdf Chapter 6 Permutations and Combinations Ex 6.6 Questions and Answers.

Maharashtra State Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6

Question 1.
Find the value of
(i) 15C4
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q1 (i)

(ii) 80C2
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q1 (ii)

(iii) 15C4 + 15C5
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q1 (iii)

(iv) 20C1619C16
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q1 (iv)

Question 2.
Find n if
(i) 6P2 = n 6C2
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q2 (i)

(ii) 2nC3 : nC2 = 52 : 3
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q2 (ii)

(iii) nCn-3 = 84
Solution:
nCn-3 = 84
∴ \(\frac{n !}{(n-3) ![n-(n-3)] !}\) = 84
∴ \(\frac{\mathrm{n}(\mathrm{n}-1)(\mathrm{n}-2)(\mathrm{n}-3) !}{(\mathrm{n}-3) ! \times 3 !}\) = 84
∴ n(n – 1) (n – 2) = 84 × 6
∴ n(n – 1) (n – 2) = 9 × 8 × 7
Comparing on both sides, we get
∴ n = 9

Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6

Question 3.
Find r if 14C2r : 10C2r-4 = 143 : 10
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q3
∴ \(\frac{14 \times 13 \times 12 \times 11}{2 \mathrm{r}(2 \mathrm{r}-1) \times(2 \mathrm{r}-2)(2 \mathrm{r}-3)}=\frac{143}{10}\)
∴ 2r(2r – 1)(2r – 2)(2r – 3) = 14 × 12 × 10
∴ 2r(2r – 1)(2r – 2)(2r – 3) = 8 × 7 × 6 × 5
Comparing on both sides, we get
∴ r = 4

Question 4.
Find n and r if.
(i) nPr = 720 and nCn-r = 120
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q4 (i)

(ii) nCr-1 : nCr : nCr+1 = 20 : 35 : 42
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q4 (ii)
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q4 (ii).1

Question 5.
If nPr = 1814400 and nCr = 45, find r.
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q5
∴ r! = 40320
∴ r! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1
∴ r! = 8!
∴ r = 8

Question 6.
If nCr-1 = 6435, nCr = 5005, nCr+1 = 3003, find rC5.
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q6
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q6.1

Question 7.
Find the number of ways of drawing 9 balls from a bag that has 6 red balls, 5 green balls and 7 blue balls so that 3 balls of every colour are drawn.
Solution:
9 balls are to be selected from 6 red, 5 green, 7 blue balls such that the selection consists of 3 balls of each colour.
∴ 3 red balls can be selected from 6 red balls in 6C3 ways.
3 green balls can be selected from 5 green balls in 5C3 ways.
3 blue balls can be selected from 7 blue balls in 7C3 ways.
∴ Number of ways selection can be done if the selection consists of 3 balls of each colour
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q7

Question 8.
Find the number of ways of selecting a team of 3 boys and 2 girls from 6 boys and 4 girls.
Solution:
There are 6 boys and 4 girls.
A team of 3 boys and 2 girls is to be selected.
∴ 3 boys can be selected from 6 boys in 6C3 ways.
2 girls can be selected from 4 girls in 4C2 ways.
∴ Number of ways the team can be selected = 6C3 × 4C2
= \(\frac{6 !}{3 ! 3 !} \times \frac{4 !}{2 ! 2 !}\)
= \(\frac{6 \times 5 \times 4 \times 3 !}{3 \times 2 \times 1 \times 3 !} \times \frac{4 \times 3 \times 2 !}{2 \times 2 !}\)
= 20 × 6
= 120
∴ The team of 3 boys and 2 girls can be selected in 120 ways.

Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6

Question 9.
After a meeting, every participant shakes hands with every other participants. If the number of handshakes is 66, find the number of participants in the meeting.
Solution:
Let there be n participants present in the meeting.
A handshake occurs between 2 persons.
∴ Number of handshakes = nC2
Given 66 handshakes were exchanged.
∴ 66 = nC2
∴ 66 = \(\frac{n !}{2 !(n-2) !}\)
∴ 66 × 2 = \(\frac{\mathrm{n}(\mathrm{n}-1)(\mathrm{n}-2) !}{(\mathrm{n}-2) !}\)
∴ 132 = n(n – 1)
∴ n(n – 1) = 12 × 11
Comparing on both sides, we get n = 12
∴ 12 participants were present at the meeting.

Question 10.
If 20 points are marked on a circle, how many chords can be drawn?
Solution:
To draw a chord we need to join two points on the circle.
There are 20 points on a circle.
∴ Total number of chords possible from these points = 20C2
= \(\frac{20 !}{2 ! 18 !}\)
= \(\frac{20 \times 19 \times 18 !}{2 \times 1 \times 18 !}\)
= 190

Question 11.
Find the number of diagonals of an n-sided polygon. In particular, find the number of diagonals when
(i) n = 10
(ii) n = 15
(iii) n = 12
Solution:
In n-sided polygon, there are ‘n’ points and ‘n’ sides. .
∴ Through ‘n’ points we can draw nC2 lines including sides.
∴ Number of diagonals in n sided polygon = nC2 – n (∴ n = number of sides)
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6 Q11

Question 12.
There are 20 straight lines in a plane so that no two lines are parallel and no three lines are concurrent. Determine the number of points of intersection.
Solution:
There are 20 lines such that no two of them are parallel and no three of them are concurrent.
Since no two lines are parallel
∴ they intersect at a point
∴ Number of points of intersection if no two lines are parallel and no three lines are concurrent = 20C2
= \(\frac{20 !}{2 ! 18 !}\)
= \(\frac{20 \times 19 \times 18 !}{2 \times 1 \times 18 !}\)
= 190

Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6

Question 13.
Ten points are plotted on a plane. Find the number of straight lines obtained by joining these points if
(i) no three points are collinear
(ii) four points are collinear
Solution:
There are 10 points on a plane.
(i) No three of them are collinear:
Since a line is obtained by joining 2 points,
number of lines passing through these points if no three points are collinear = 10C2
= \(\frac{10 !}{2 ! 8 !}\)
= \(\frac{10 \times 9 \times 8 !}{2 \times 1 \times 8 !}\)
= 5 × 9
= 45

(ii) When 4 of them arc collinear:
∴ Number of lines passing through these points if 4 points are collinear
= 10C24C2 + 1
= 45 – \(\frac{4 !}{2 ! 2 !}\) + 1
= 45 – \(\frac{4 \times 3 \times 2 !}{2 \times 2 !}\) + 1
= 45 – 6 + 1
= 40

Question 14.
Find the number of triangles formed by joining 12 points if
(i) no three points are collinear
(ii) four points are collinear
Solution:
There are 12 points on the plane
(i) When no three of them are collinear:
Since a triangle can be drawn by joining any three non-collinear points.
∴ Number of triangles that can be obtained from these points = 12C3
= \(\frac{12 !}{3 ! 9 !}\)
= \(\frac{12 \times 11 \times 10 \times 9 !}{3 \times 2 \times 1 \times 9 !}\)
= 220

(ii) When 4 of these points are collinear:
∴ Number of triangles that can be obtained from these points = 12C34C3
= 220 – \(\frac{4 !}{3 ! \times 1 !}\)
= 220 – \(\frac{4 \times 3 !}{3 !}\)
= 220 – 4
= 216

Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.6

Question 15.
A word has 8 consonants and 3 vowels. How many distinct words can be formed if 4 consonants and 2 vowels are chosen?
Solution:
Out of 8 consonants, 4 can be selected in 8C4
= \(\frac{8 !}{4 ! 4 !}\)
= \(\frac{8 \times 7 \times 6 \times 5 \times 4 !}{4 \times 3 \times 2 \times 1 \times 4 !}\)
= 70 ways
From 3 vowels, 2 can be selected in 3C2
= \(\frac{3 !}{2 ! 1 !}\)
= \(\frac{3 \times 2 !}{2 !}\)
= 3 ways
Now, to form a word, these 6 letters (i.e., 4 consonants and 2 vowels) can be arranged in 6P6 i.e., 6! ways.
∴ Total number of words that can be formed = 70 × 3 × 6!
= 70 × 3 × 720
= 151200
∴ 151200 words of 4 consonants and 2 vowels can be formed.

Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.5

Balbharati Maharashtra State Board 11th Commerce Maths Solution Book Pdf Chapter 6 Permutations and Combinations Ex 6.5 Questions and Answers.

Maharashtra State Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.5

Question 1.
In how many different ways can 8 friends sit around a table?
Solution:
We know that ‘n’ persons can sit around a table in (n – 1)! ways
∴ 8 friends can sit around a table in 7! ways
= 7 × 6 × 5 × 4 × 3 × 2 × 1
= 5040 ways.
∴ 8 friends can sit around a table in 5040 ways.

Question 2.
A party has 20 participants and a host. Find the number of distinct ways for the host to sit with them around a circular table. How many of these ways have two specified persons on either side of the host?
Solution:
A party has 20 participants.
All of them and the host (i.e., 21 persons) can be seated at a circular table in (21 – 1)! = 20! ways.
When two particular participants be seated on either side of the host.
Host takes chair in 1 way.
These 2 persons can sit on either side of host in 2! ways
Once host occupies his chair, it is not circular permutation any more.
Remaining 18 people occupy their chairs in 18! ways.
∴ Total number of arrangement possible if two particular participants be seated on either side of the host = 2! × 18!

Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.5

Question 3.
Delegates from 24 countries participate in a round table discussion. Find the number of seating arrangements where two specified delegates are
(i) always together.
(ii) never together.
Solution:
(i) Delegates of 24 countries are to participate in a round table discussion such that two specified delegates are always together.
Let us consider these 2 delegates as one unit.
They can be arranged among themselves in 2! ways.
Also, these two delegates are to be seated with 22 other delegates (i.e. total 23) which can be done in (23 – 1)! = 22! ways.
∴ The total number of arrangements if two specified delegates are always together = 22! × 2!

(ii) When 2 specified delegates are never together then, the other 22 delegates can participate in a round table discussion in (22 – 1)! = 21! ways.
∴ There are 22 places of which any 2 places can be filled by those 2 delegates who are never together.
∴ Two specified delegates can be arranged in 22P2 ways.
∴ Total number of arrangements if two specified delegates are never together = 22P2 × 21!
= \(\frac{22 !}{(22-2) !}\) × 21!
= \(\frac{22 !}{20 !}\) × 21!
= 22 × 21 × 21!
= 21 × 22 × 21!
= 21 × 22!

Question 4.
Find the number of ways for 15 people to sit around the table so that no two arrangements have the same neighbours.
Solution:
There are 15 people to sit around a table.
∴ They can be arranged in (15 – 1)! = 14! ways.
But, they should not have the same neighbour in any two arrangements.
Around the table, arrangements (i.e. clockwise and anticlockwise) coincide.
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.5 Q4
∴ Number of arrangements possible for not to have same neighbours = \(\frac{14 !}{2}\)

Question 5.
A committee of 20 members sits around a table. Find the number of arrangements that have the president and the vice president together.
Solution:
A committee of 20 members sits around a table.
But, President and Vice-president sit together.
Let us consider President and Vice-president as one unit.
They can be arranged among themselves in 2! ways.
Now, this unit with the other 18 members of the committee is to be arranged around a table, which can be done in (19 – 1)! = 18! ways.
∴ The total number of arrangements possible if President and Vice-president sit together = 18! × 2!

Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.5

Question 6.
Five men, two women, and a child sit around a table. Find the number of arrangements where the child is seated
(i) between the two women.
(ii) between two men.
Solution:
(i) 5 men, 2 women, and a child sit around a table
When a child is seated between two women
∴ The two women can be seated on either side of the child in 2! ways.
Let us consider these 3 (two women and a child) as one unit.
Also, these 3 are to be seated with 5 men, (i.e. a total of 6 units) which can be done in (6 – 1)! = 5! ways.
∴ The total number of arrangements if the child is seated between two women = 5! × 2!

(ii) Two men out of 5 men can sit on either side of the child in 5P2 ways.
Let us take two men and a child as one unit.
Now these are to be arranged with the remaining 3 men and 2 women
i.e., a total of 6 events (3 + 2 + 1) is to be arranged around a round table which can be done in (6 – 1)! = 5! ways.
∴ The total number of arrangements, if the child is seated between two men = 5P2 × 5!

Question 7.
Eight men and six women sit around a table. How many sitting arrangements will have no two women together?
Solution:
8 men can be seated around a table in (8 – 1)! = 7! ways.
There are 8 gaps created by 8 men’s seats.
∴ 6 Women can be seated in 8 gaps in 8P6 ways
∴ Total number of arrangements so that no two women are together = 7! × 8P6

Question 8.
Find the number of seating arrangements for 3 men and 3 women to sit around a table so that exactly two women are together.
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.5 Q8
Two women sit together and one woman sits separately.
Women sitting separately can be selected in 3 ways.
The other two women occupy two chairs in one way (as it is a circular arrangement).
They can be seated on those two chairs in 2 ways. Suppose two chairs are chairs 1 and 2 shown in the figure.
Then the third woman has only two options viz chairs 4 or 5.
∴ The third woman can be seated in 2 ways. 3 men are seated in 3! ways
∴ Required number = 3 × 2 × 2 × 3!
= 12 × 6
= 72

Question 9.
Four objects in a set of ten objects are alike. Find the number of ways of arranging them in a circular order.
Solution:
Ten things can be arranged in a circular order of which 4 are alike in \(\frac{9 !}{4 !}\) ways.
∴ Required total number of arrangements = \(\frac{9 !}{4 !}\)

Maharashtra Board 11th Commerce Maths Solutions Chapter 6 Permutations and Combinations Ex 6.5

Question 10.
Fifteen persons sit around a table. Find the number of arrangements that have two specified persons not sitting side by side.
Solution:
Since 2 particular persons can’t be sitting side by side.
The other 13 persons can be arranged around the table in (13 – 1)! = 12!
13 people around a table create 13 gaps in which 2 people are to be seated
Number of arrangements of 2 people = 13P2
∴ The total number of arrangements in which two specified persons not sitting side by side = 12! × 13P2
= 12! × 13 × 12
= 13 × 12! × 12
= 12 × 13!

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Balbharti Maharashtra State Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 1.
a. Alloy of sodium with mercury.
Answer:
Silver amalgam.

b.Molecular formula of common ore of aluminium.
Answer:
Al2O3.nH2O

c. The oxide that forms salt and water by reacting with both acid and base.
Answer:
Aluminium oxide (Al2O3).

d. device used for grinding an ore.
Answer:
The device used for grinding an ore is grinding mill.

e. The nonmetal having electrical conductivity.
Answer:
Graphite having electrical conductivity.

f. The reagent that dissolves noble metals.
Answer:
Aqua regia is the reagent that dissolves noble metals like gold and platinum.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 2.
Make pairs of substances and their properties.

Column I Column II
Substance Property
(1) Potassium bromide (a) Combustible
(2) Gold (b) Soluble in water
(3) Sulphur (c) No chemical reaction
(4) Neon (d) High ductility
(e) Magnetic ingredient

Answer:
(1) Potassium bromide – Soluble in water
(2) Gold – High ductility
(3) Sulphur – Combustible
(4) Neon – No chemical reaction

Question 3.
Identify the pairs of metals and their ores from the following.

Column I (ores) Column II (metals)
(1) Bauxite (a) Mercury
(2) Cassiterite (b) Aluminium
(3) Cinnabar (c) Tin
(d) Copper

Answer:
(1) Bauxite – Aluminium
(2) Cassiterite – Tin
(3) Cinnabar – Mercury

Question 4.
Explain the terms.
a. Metallurgy
Answer:
Metallurgy: The process used for extraction of metals in their pure form from their ores, then metals are further purified by different methods of purification. All the process is called metallurgy.

b. Ores.
Answer:
Ores: The minerals from which metals are extracted profitably and conveniently are called ores.
Examples: Bauxite (Al2O3.H2O), Cinnabar (HgS).

c. Minerals.
Answer:
Minerals: The naturally occurring compounds of metals along with other impurities are known as minerals.
Examples: Rocks are composed of mixtures of minerals. Talc and granite are minerals.

d. Gangue.
Answer:
Gangue: Ores contain metal compounds with some of the impurities like soil, sand, rocky material, etc. These impurities are called gangue.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 5.
Write scientific reasons.
a. Lemon or tamarind is used for cleaning copper vessels turned greenish.
Answer:

  • Copper undergoes oxidation in air to form black copper oxide. Copper oxide reacts slowly with carbon dioxide in air and gains a green coat. This green substance is copper carbonate.
  • Lemon and tamarind contain acid. The acid dissolves the green coating of basic copper carbonate present on the surface of a tarnished copper utensil and makes it shiny again.

b. Generally the ionic compounds have high melting points.
Answer:

  • The ionic compounds exist in solid state and are hard due to strong electrostatic force of attraction between oppositely charged ions.
  • The intermolecular force of attraction is high in ionic compounds and large energy is required to overcome it. Therefore, ionic compounds have high melting points.

c. Sodium is always kept in kerosene.
(OR)
Why is sodium stored in kerosene?
Answer:

  • Sodium reacts so vigorously with atmospheric oxygen that it catches fire if kept in the open.
  • It does not react with kerosene and sinks in it. Hence, to protect sodium and to prevent accidental fires it is always kept in kerosene.

d. Pine oil is used in the froth floatation process.
Answer:

  • In the concentration of an ore by froth floatation process, the ore is mixed with water and pine oil. When air is bubbled through the mixture a froth is formed.
  • The mineral particles in the ore are preferentially wetted by the oil and float on the top in the froth.
  • The gangue particles are wetted by water and settle down. Thus the mineral can be separated from the gangue and the ore is concentrated.

e. Anodes need to be replaced from time to time during the electrolysis of alumina.
Answer:

  • During electrolysis of alumina, the oxygen liberated at the carbon anode reacts with graphite rods (carbon anode) and forms carbon dioxide.
  • As the anodes get oxidised during electrolysis of alumina, they are continuously eroded. Hence, it is necessary to replace anodes from time to time.

Question 6.
When a copper coin is dipped in silver nitrate solution, a glitter appears on the coin after some time. Why does this happen? Write the chemical equation.
Answer:
When a copper coin is dipped in a silver nitrate solution, more reactive copper displaces silver from silver nitrate solution. The silver so liberated deposits on the copper coin. As a result, a shiny coat of silver is formed on the coin.
Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) + 2Ag(s)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 7.
The electronic configuration of metal ‘A’ is 2, 8, 1 and that of metal ‘B’ is 2, 8, 2. Which of the two metals is more reactive? Identify these metals. Write their reaction with dilute hydrochloric acid. (Practice Activity Sheet – 1)
Answer:
If the number of electrons in the outermost orbit is less, then the metal is more reactive. Metal A contains one electron in the outermost shell, while metal B contains two electrons. Hence, metal A is more reactive than metal B.

Metal A is sodium and metal B is magnesium. Reactions of Na and Mg with dil. HCl are,
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 1

Question 8.
Draw a neat labelled diagram.
a. Magnetic separation method.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 2

b. Forth floatation.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 3

c. Electrolytic reduction of alumina.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 4

d. Hydraulic separation method.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 5

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 9.
Write chemical equation for the following events.
a. Aluminium came in contact with air.
Answer:
When aluminium is exposed to air, it develops a thin oxide layer of aluminium.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 6

b. Iron filings are dropped in aqueous solution of copper sulphate.
Answer:
When iron filings are dropped in copper sulphate solution, more reactive iron displaces copper from copper sulphate solution. The iron filings get coated with reddish brown copper metal and the blue colour of copper sulphate fades gradually and ferrous sulphate is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 7

c. A reaction was brought about between ferric oxide and aluminium.
Answer:
The reaction between ferric oxide and iron produces aluminium oxide and iron. It is a thermite reaction and is highly exothermic.
It produces a large amount of heat, which is released to melt oxygen and aluminium. This reaction is used in welding of machineries. It is also used in warfare to make grenades.

The chemical reaction for the above is as follows:
3Fe3O2 + 4Al → 2Al2O3 + 6Fe

d. Electrolysis of alumina is done.
Answer:
During electrolysis of alumina, aluminium is deposited at the cathode. Molten aluminium being heavier than the electrolyte, is collected at the bottom of the tank. Oxygen gas is liberated at the anode.
Anode reaction: 2O → O2 + 4e (Oxidation)
Cathode reaction: Al3+ + 3e → Al(l) (Reduction)

e. Zinc oxide is dissolved in dilute hydrochloric acid.
Answer:
Zinc oxide is dissolved in dilute hydrochloric acid, zinc chloride and water are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 8

Question 10.
Complete the following statement using every given options.
During the extraction of aluminium
a. Ingredients and gangue in bauxite.
b. Use of leuching during the concentration of ore.
c. Chemical reaction of transformation of bauxite into alumina by Hall’s process.
d. Heating the aluminium ore with concentrated caustic soda.
Answer:
c. Chemical reaction of transformation of bauxite into alumina by Hall’s process.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 11.
Divide the metals Cu, Zn, Ca, Mg, Fe, Na, Li into three groups, namely, reactive metals, moderately reactive metals and less reactive metals.
Answer:
Reactive metals: Na, Li, Ca
Moderately reactive metals: Zn, Fe, Mg,
Less reactive metals: Cu

Project: (Do it your self)

Collect metal vessels and various metal articles. Write detailed informciton. write the steps in the procedure that can be done in the laboratory for giving glitter to these. Seek guidance from your teacher.

Can you recall? (Text Book Page No. 93)

Question 1.
what are the physical properties of metals and nonmetals?
Answer:
Properties of metals:

  1. Solid state (Exception: Mercury and gallium)
  2. Typical lustre
  3. Malleability and ductility
  4. Hardness (Exception: Lithium, sodium and potassium)
  5. Good conductors of heat and electricity
  6. High melting and boiling points (On the other hand, the melting and boiling points of the metals sodium, potassium, mercury and galium are very low.)
  7. Sonorous and produce sound on striking a hard surface.

Properties or nonmetals:

  1. Gaseous or solid state (Exception: Bromine in liquid state)
  2. Lack of any typical lustre (Exception: Iodine and Diamond)
  3. Brittleness in the solid state (Exception: Diamond is the hardest natural substance)
  4. Bad conductors of heat and electricity (Exception: Graphite) (Diamond is good conductor of heat)
  5. Low melting and boiling points.

Can you recall? (Text Book Page No. 102)

Question 1.
What is the electronic definition of oxidation and reduction?
Answer:
When a metal loses çlectrons the process is called an oxidation while when a nonmetal gains electrons, it is called a reduction,
Na → Na+ + e (oxidation)
Cl + e → Cl (reduction)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Can you recall? (Text Book Page No. 106)

Question 1.
What is meant by corrosion?
Answer:
Corrosion is degradation of a material due toreaction with its environment.

Question 2.
Have you observed the following things?
(1) Old iron bars in the builthngs.
Answer:
When old iron bars in the buildings are exposed to moist air for a long time, they acquire a coating of browm nlaky substance called rust. (Fe2O3.H2O)

(2) Copper vessels not cleaned for a long time.
Answer:
If copper vessels are not cleaned for a long time, they react with moist carbon dioxide in the air, lose their shine and gain a green coat of copper carbonate. (CuCO3)

Question 3.
Silver ornaments or idols exposed to air for a long time.
Answer:
When silver ornaments or idols are kept exposed to air for a long time, silver reacts with sulphur in the air to form a coating of black silver sulphide. (Ag2S)

Question 4.
Old vehicles fit to be thrown away.
Answer:
The metallic parts of the body of old cars are corroded, eaten up and sometimes become perforated. The old cars also lose the original colour due to formation of flakes of rust.

Use your brain power! (Text Book Page No. 98)

Question 1.
In the reaction between chlorine and HBr a transformation or HBr into Br2 takes place. Can this transformation be called oxidation? What Is the oxidant that brings about this oxidation?
Answer:
The conversion of HBr to Br2 is an oxidation process. In the above reaction, Cl2 in the oxidant.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Can you tell? (Text Book Page No. 104)

Question 1.
what are the moderately reactive metals?
Answer:
In the middle of the reactivity series, metals such as iron. zinc, lead, copper are moderately reactive.

Question 2.
In which form to the moderately reactive metals occur in nature?
Answer:
The moderately reactive metals which occur in nature are in the form of their sulphide salts or carbonate salts.

Think about it (Text Book Page No. 106)

Question 1.
Why do silver articles turn blackish while copper vessels turn greenish on keeping in air for long time?
Answer:

  1. Silver articles turn blackish on exposure to air for a long time. This is because of silver sulphide (Ag2S) laver formed on the silver articles by the reaction of silver with hydrogen sulphide.
  2. Carbon dioxide in moist air reacts with copper vessel. Copper loses its lustre due to formation of greenish layer of copper carbonate (CuCO3) on its surface.

Question 2.
Why do pure gold and platinum always glitter?
Answer:
Gold and platinum are noble metals as they do not react with moisture, O2 and CO2 from air also acids and alkalis, therefore, pure gold and platinum always glitter.

Use your brain power! (Text Book Page No. 103)

Question 1.
Write the electrode reaction for electrolysis of molten magnesium chloride and calcium chloride.
Answer:
(1) Magnesium chloride (MgCl2):
MgCl2 → Mg2+ + 2Cl
At the cathode: Mg2+ + 2e → Mg
At the anode: 2Cl → Cl2 + 2e

(2) Calcium chloride (CaCl2):
At the cathode: Ca2+ + 2e → Ca
At the anode: 2Cl → Cl2 + 2e

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Can you tell? (Text Book Page No. 106)

Question 1.
Which measures would you suggest to stop the corrosion of metallic articles or not allow the corrosion to start?
Answer:
Various types of methods are used to protect metals from corrosion. Almost in all the methods, special attention is paid so that iron does not rust. It is possible to lower the rate of the process of rusting of iron. Corrosion of metals can be stopped by detaching the air from metals.

Some methods are as follows :

  1. To fix a layer of some substance on the metal surface so that the contact of the metal with moisture and oxygen in the air is prevented and no reaction would occur between them.
  2. To prevent corrosion of metals by applying a layer of paint, oil, grease or varnish on their surface. For example, corrosion of iron can be prevented by this method.

Question 2.
What is done so to prevent rusting of iron windows and iron doors of your house?
Answer:
To prevent rusting of iron windows and iron doors in the house, they are painted so that they do not rust.

Question 3.
What is done so to prevent rusting or iron windows and iron doors of your house?
Answer:
To prevent rusting of iron windows and iron doors in the house, they are painted so that they do not rust.

Use your brain power! (Text Book Page No. 107)

Question 1.
Can we permanently prevent the rusting of an iron article by applying a layer of paint on its surface?
Answer:
The method of painting is alright for some time. We cannot protect the articles permanently from rusting by painting them.

Question 2.
Why do new iron sheets appear shiny?
Answer:
The new iron sheets appear shiny because a layer of non-corrosionable metal is fixed on the surface of corrosionable metal.

Collect information. (Text Book Page No. 108)

Question 1.
What are the various alloys used in daily life? Where are those used?
Answer:

Various alloys Uses
1. Bronze It is used to prepare: Coins, utensils, medals, statues
2. Brass Pipes, condenser tubes, utensils worshipping God.
3. Stainless steel Utensils, tools, dairy equipment, boilers.
4. Steel Construction of bridges and buildings, cutting tools, blades.
5. Tungsten steel High speed cutting tools
6. Amalgam Silver amalgam used by dentists
7. Duralumin Bodies of aircraft, buses, kitchenwares
8. Aluminium bronze Pigment in ink and paint
9. German silver Electrical heaters, resistors
10. Gun metal Guns, boiler fittings
11. Magnelium Beams of scientific balances, aircraft parts.
12. Gold with copper or nickel or silver or platinum Jewellery

Question 2.
What are the properties that the alloy used for minting coins should have?
Answer:
The alloy used for minting coins should have excellent wear resistance and anti-corrosion properties.

Fill in the blanks:

Question 1.
……………has the highest melting point.
Answer:
Tungsten has the highest melting point.

Question 2.
Mercury and…………are two metals in the liquid state at room temperature.
Answer:
Mercury and galium are two metals in the liquid state at room temperature.

Question 3.
…………is the hardest natural substance.
Answer:
Diamond is the hardest natural substance.

Question 4.
The naturally occurring compounds of metals along with other impurities are known as………….
Answer:
The naturally occurring compounds of metals along with other impurities are known as minerals.

Question 5.
The minerals from which metals are extracted profitably and conveniently are called…………..
Answer:
The minerals from which metals are extracted profitably and conveniently are called ores.

Question 6.
An ore contains some of the impurities like soil, sand, etc. These impurities are called…………
Answer:
An ore contains some of the impurities like soil, sand, etc. These impurities are called gangue.

Question 7.
The process of extraction of a metal from its ore is called……….
Answer:
The process of extraction of a metal from its ore is called metallurgy.

Question 8.
Bauxite is a common ore of………..
Answer:
Bauxite is a common ore of aluminium.

Question 9.
…………. process is used for the purification of bauxite.
Answer:
Bayer’s process is used for the purification of bauxite.

Question 10.
During the electrolysis of alumina, ………..is liberated at the anode.
Answer:
During the electrolysis of alumina, oxygen is liberated at the anode.

Question 11.
The reaction of iron oxide with aluminium is known as…………..reaction.
Answer:
The reaction of iron oxide with aluminium is known as thermit reaction.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 12.
The process of coating a thin layer of zinc on iron is known as…………
Answer:
The process of coating a thin layer of zinc on iron is known as galvanising.

Question 13.
The metal that produces a sound on striking a hard surface is said to be………….
Answer:
The metal that produces a sound on striking a hard surface is said to be sonorous.

Question 14.
The process in which carbonate ores are changed into oxides by heating strongly in limited air is known as …………….
Answer:
The process in which carbonate ores are changed into oxides by heating strongly in limited air is known as calcination.

Question 15.
…………compounds are insoluble in solvents like kerosene and petrol.
Answer:
Ionic compounds are insoluble in solvents like kerosene and petrol.

Question 16.
…………… is used to obtain pure metals from impure metals.
Answer:
Electrolys is method is used to obtain pure metals from impure metals.

Question 17.
Corrosion can be prevented-by putting a layer of…………metal on corrosionable metal.
Answer:
Corrosion can be prevented by putting a layer of non-corrosionable metal on corrosionable metal.

Rewrite the following statements by selecting the correct options:

Question 1.
………… is a metal.
(a) Mg
(b) S
(c) P
(d) Br
Answer:
Mg is a metal.

Question 2.
………. is a nonmetal.
(a) Au
(b) Hg
(c) Br
(d) Cu
Answer:
Br is a nonmetal.

Question 3.
………… is a metalloid.
(a) Aluminium
(b) Antimony
(c) Zinc
(d) Mercury
Answer:
Antimony is a metalloid.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 4.
Metalloids have properties of ………..
(a) metals
(b) nonmetals
(c) both metals and nonmetals
(d) neither metals nor nonmetals
Answer:
Metalloids have properties of both metals and nonmetals.

Question 5.
…………. is a good conductor of electricity.
(a) Bromine
(b) Iodine
(c) Graphite
(d) Sulphur
Answer:
Graphite is a good conductor of electricity.

Question 6.
………. is a metal which is in liquid form at ordinary temperature and pressure.
(a) Magnesium
(b) Sodium
(c) Scandium
(d) Mercury
Answer:
Mercury is a metal which is in liquid form at ordinary temperature and pressure.

Question 7.
………. is an amphoteric oxide.
(a) Na2O
(b) MgO
(c) ZnO
(d) SO2
Answer:
ZnO is an amphoteric oxide.

Question 8.
……….. is an acidic oxide.
(a) Na2O
(b) CO2
(c) FeO3
(d) H2O
Answer:
CO2 is an acidic oxide.

Question 9.
………. is a basic oxide.
(a) CO2
(b) K2O
(C) SO2
(d) Al2O3
Answer:
K2O is a basic oxide.

Question 10.
………… is an ore of aluminium.
(a) Cryolite
(b) Bauxite
(c) Haematite
(d) Aluminium carbonate
Answer:
Bauxite is an ore of aluminium.

Question 11.
Bronze is an alloy of ………..
(a) copper and tin
(b) copper and zinc
(c) copper and iron
(d) iron and nickel
Answer:
Bronze is an alloy of copper and tin.

Question 12.
An alloy prepared from iron, nickel and chromium is known as …………
(a) brass
(b) bronze
(c) stainless steel
(d) amalgam
Answer:
An alloy prepared from iron, nickel and chromium is known as stainless steel.

Question 13.
…………. is an allotropic form of a nonmetal which conducts electricity.
(a) Sulphur
(b) Graphite
(c) Chlorine
(d) Iodine
Answer:
Graphite is an allotropic form of a nonmetal which conducts electricity.

Question 14.
………….. has an oxide which is soluble in sodium hydroxide.
(a) Calcium
(b) Magnesium
(c) Iron
(d) Zinc.
Answer:
Zinc has an oxide which is soluble in sodium hydroxide.

Question 15.
………… prevents the rusting of iron.
(a) Copper
(b) Zinc
(c) Aluminium
(d) Silver
Answer:
Zinc prevents the rusting of iron.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 16.
………….. is obtained by the reduction of its oxide by carbon.
(a) Zinc
(b) Aluminium
(c) Sodium
(d) Potassium
Answer:
Zinc is obtained by the reduction of its oxide by carbon.

Question 17.
………….. is used as an anode during the electrolytic reduction of bauxite.
(a) Sulphur
(b) Graphite
(c) Platinum
(d) Aluminium
Answer:
Graphite is used as an anode during the electrolytic reduction of bauxite.

Question 18.
Silver gets corroded due to ………… in air.
(a) oxygen
(b) hydrogen sulphide
(c) carbon dioxide
(d) nitrogen
Answer:
Silver gets corroded due to hydrogen sulphide in air.

Question 19.
…………. is the hardest substance and has the highest melting and boiling points.
(a) Iodine
(b) Sulphur
(c) Diamond
(d) Phosphorus
Answer:
Diamond is the hardest substance and has the highest melting and boiling points.

Question 20.
Jewellery articles are gold plated ………….
(a) to prevent corrosion
(b) to prevent rusting of the base metal
(c) to make articles attractive
(d) all of these
Answer:
(d) all of these

Question 21.
To show that zinc is more reactive than copper, the correct procedure is to ………..
(a) prepare copper sulphate solution and dip a zinc strip in it
(b) prepare zinc sulphate solution and dip a copper strip in it
(c) heat together zinc and copper strips
(d) add dil. nitric acid to both the strips
Answer:
To show that zinc is more reactive than copper, the correct procedure is to prepare copper sulphate solution and dip a zinc strip in it.

Question 22.
Iron is ………
(a) more reactive than zinc
(b) more reactive than aluminuium
(c) less reactive than copper
(d) less reactive than aluminium
Answer:
Iron is less reactive than aluminium.

Question 23.
A solution of Al2(SO4)3 in water is …………
(a) blue
(b) pink
(c) green
(d) colourless
Answer:
A solution of Al2(SO4)3 in water is colourless.

Question 24.
A solution of ………… in water is blue in colour.
(a) CuSO4
(b) FeSO4
(c) ZnSO4
(d) Al2(SO4)3
Answer:
A solution of CuSO4 in water is blue in colour.

Question 25.
A solution of …………. n water is green in colour.
(a) CuSO4
(b) FeSO4
(c) ZnSO4
(d) Al2(SO4)3
Answer:
A solution of FeSO4 in water is green in colour.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 26.
What would be the correct order if Zn, Fe, Al and Cu are arranged in increasing order of reactivity?
(a) Cu, Fe, Zn, Al
(b) Al, Cu, Fe, Zn
(c) Zn, Al, Cu, Fe
(d) Fe, Zn, Al, Cu (Practice Activity Sheet – 2)
Answer:
(a) Cu, Fe, Zn, Al

Question 27.
During the extraction of aluminium ……….
(a) Ingredients and gangue in bauxite
(b) Use of leaching during the concentration of ore
(c) Chemical reaction of transformation of bauxite into alumina by Hall’s process.
(d) Heating the aluminium ore with concentrated caustic soda.
Answer:
During the extraction of aluminium Chemical reaction of transformation of bauxite into alumina by Hall’s process.

Question 28.
A solution of CuSO4 in water is ………… in colour.
(a) pink
(b) blue
(c) colourless
(d) green
Answer:
A solution of CuSO4 in water is blue in colour.

Question 29.
Which of the following process is to be carried out to avoid the formation of greenish layer on brass vessels due to corrosion?
(a) Plating
(b) Anodization
(c) Tinning
(d) Alloying (Practice Activity Sheet – 3)
Answer:
(c) Tinning

State whether the following statements are True or False (If a statement is false, correct it and rewrite it.):

Question 1.
Metals are known as sonar metals.
Answer:
True.

Question 2.
Diamond is the softest natural substance.
Answer:
False. (Diamond is the hardest natural substance.)

Question 3.
Electrolysis method is used to obtain pure metals from impure metals.
Answer:
True.

Question 4.
Iodine and diamond are lustrous substances.
Answer:
True.

Question 5.
Aqua Regia is a mixture of conc. HCl and conc. HNO3 in the ratio of 1:3.
Answer:
False. (Aqua Regia is a mixture of conc. HCl and conc. HNO3 in the ratio of 3:1.)

Question 6.
Corrosion of metals can be stopped by detaching the air from metals.
Answer:
True.

Question 7.
Due to corrosion a greenish layer forms on the surface of copper or brass vessel.
Answer:
True.

Question 8.
Ionic compounds are soluble in kerosene.
Answer:
False. (Ionic compounds are soluble in water and insoluble in kerosene.)

Question 9.
Ionic compounds in the solid state conduct electricity.
Answer:
False. (Ionic compounds in the solid state do not conduct electricity.)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 10.
Mercury, silver and gold are very reactive metals.
Answer:
False. (Mercury, silver and gold are least reactive metals.)

Question 11.
In electroplating a metal is coated with another metal using electrolysis.
Answer:
True.

Question 12.
In anodising method. the copper or aluminium article is used as anode.
Answer:
True.

Question 13.
Silver plated spoon, gold plated ornaments are the examples of alloying.
Answer:
False. (Silver plated spoon, gold plated ornaments are the examples of electroplating)

Question 14.
silver amalgam is mainly used by dentists.
Answer:
True.

Question 15.
Aluminium oxide is an acidic oxide.
Answer:
False. (Aluminium oxide is an amphoteric oxide.)

Question 16.
copper reacts with moist carbon form copper carbonate.
Answer:
True.

Question 17.
Corrosion is degradation of a reaction with its environment.
Answer:
True.

Find the correlation in the given pair and rewrite the answer:

Question 1.
Brass : Copper and Zinc :: Bronze :………….
Answer:
Brass : Copper and Zinc :: Bronze : Copper and tin

Question 2.
Tinning : Tin :: Galvanizing :…………….
Answer:
Tinning : Tin :: Galvanizing : Zinc

Question 3.
Pressure cooker : Anodizing :: Silver plated spoons :…………..
Answer:
Pressure cooker : Anodizing :: Silver plated spoons : Electro-plating

Question 4.
The sulphides ores are strongly heated in air : Roasting :: The carbonates ores are strongly heated in a limited supply of air :………….
Answer:
The sulphides ores are strongly heated in air : Roasting :: The carbonates ores are strongly heated in a limited supply of air : Calcination.

Question 5.
Sulphide ores : Froth floatation method : Cassiterite ore :………..
Answer:
Sulphide ores : Froth floatation method : Cassiterite ore : Magnetic separation method.

Find the odd one out:

Question 1.
Sodium, Potassium, Silver, Sulphur
Answer:
Sulphur. (All except sulphur, others are metals.)

Question 2.
Boron, Chlorine, Bromine, Fluorine
Answer:
Boron. (All except boron, others are nonmetals.)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 3.
Copper, Iron, Mercury, Brass
Answer:
Brass. (All except brass, others are metals.)

Question 4.
Brass, Bronze, Phosphorus, Stainless steel
Answer:
Phosphorus. (All except phosphorus, others are alloys.)

Question 5.
Magnesium chloride, Sodium chloride, Water, Zinc chloride
Answer:
Water. (All except water, others are ionic compounds.)

Question 6.
Tinning, Anodization, Alloying, Froth floatation (March 2019)
Answer:
Froth floatation. (All except froth floatation, others are processes of coating a thin layer of metal on the surface of other metals.)

Match the following:

Question 1.

Column I Column II
(1) ZnS (a) Cuprous sulphide
(2) HgS (b) Bauxite
(3) Cu2S (c) Zinc blend
(4) Al2O3.H2O (d) Cinnabar
(e) Cryolite

Answer:
(1) ZnS – Zinc blend
(2) HgS – Cinnabar
(3) Cu4S – Cuprous sulphide
(4) Al2O3.H2O – Bauxite.

Question 2.

Column I Column II
(1) Copper and zinc (a) Stainless steel
(2) Copper and tin (b) Zinc amalgam
(3) Iron, nickel and chromium (c) Bronze
(4) Mercury and zinc (d) Brass
(e) Steel

Answer:
(1) Copper and zinc – Brass
(2) Copper and tin – Bronze
(3) Iron, nickel and chromium – Stainless steel
(4) Mercury and zinc – Zinc amalgam.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 3.

Column I Column II
(1) Galvanising (a) Pressure cooker
(2) Tinning (b) Silver plated spoons
(3) Electroplating (c) Coating of tin on copper
(4) Anodizing (d) Coating of Zn on iron

Answer:
(1) Galvanising – Coating of Zn on iron
(2) Tinning – Coating of tin on copper
(3) Electroplating – Silver plated spoons
(4) Anodizing – Pressure cooker.

Translate the following statements into chemical equations and then balance them:

Question 1.
steam is passed over aluminium.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 9

Question 2.
Extraction of copper from its sulphide ore.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 10
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 11

Question 3.
Thermit reaction.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 12

Question 4.
Magnesium reacts with hot water.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 13

Question 5.
what happens when aluminium oxide dissolves in aqueous sodium hydroxide?
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 14

Question 6.
Zinc reacts with sulphuric acid.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 15

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 7.
Iron reacts with sulphuric acid.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 16

Name the following:

Question 1.
A metal which forms an amphoteric oxide.
Answer:
Aluminium forms an amphoteric oxide.

Question 2.
An alloy of copper and zinc.
Answer:
An alloy of copper and zinc is termed as brass.

Question 3.
A compound which is added to lower the fusion temperature.
Answer:
Cryolite (AlF3, 3NaF) and fluorspar (CaF2) are added to lower the fusion temperature.

Question 4.
A metal which does not react with cold water but reacts with steam.
Answer:
Aluminium does not react With cold water but reacts with Steam.

Question 5.
A common ore of aluminium.
Answer:
Bauxite (Al2O3.H2O) is a common ore of aluminium.

Question 6.
A metal which is in liquid state at ordinary temperature.
Answer:
Mercury is in liquid state at ordinary temperature.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 7.
Two metals which are malleable.
Answer:
Iron and aluminium are malleable metals.

Question 8.
Two metals which are ductile.
Answer:
Gold and silver are ductile metals.

Question 9.
Two metals which are good conductors of heat.
Answer:
Silver and copper are good conductors of heat.

Question 10.
Two metals which are good conductors of electricity.
Answer:
Copper and aluminium are good conductors of electricity.

Question 11.
Two metals which are used for making cooking vessels.
Answer:
Copper and aluminium are used in making cooking vessels.

Question 12.
Two metals having low melting points.
Answer:
Sodium and potassium have low melting points.

Question 13.
Two highly reactive metals.
Answer:
Sodium and potassium are highly reactive metals.

Question 14.
A nonmetal which is in liquid state at room temperature.
Answer:
Bromine is in liquid state at room temperature.

Question 15.
Two ionic compounds.
Answer:
Sodium chloride (NaCl) and magnesium chloride (MgCl2) are ionic compounds.

Question 16.
The process of heating the sulphide ore to a high temperature in the excess of air.
Answer:
In roasting, sulphide ore is heated to a high temperature in the excess of air.

Question 17.
The process of heating the carbonate ore to a high temperature in limited air.
Answer:
In calcination, carbonated ore is heated to a high temperature in limited air.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 18.
The compound formed by the reaction between aluminium oxide and sodium hydroxide.
Answer:
Sodium aluminate is formed by the reaction between aluminium oxide and sodium hydroxide.

Question 19.
Two metals which are found in the free state in nature.
Answer:
Gold (Au) and silver (Ag) are found in the free state in nature.

Question 20.
A metal which has the highest melting point.
Answer:
Tungsten has the highest melting point.

Question 21.
Two nonmetals which are lustrous.
Answer:
Iodine and diamond are lustrous in nature.

Answer the following questions in one sentence each:

Question 1.
State the property of the metals due to which they can be drawn into wires.
Answer:
The property of the metal due to which they can be drawn into wires is called ductility.

Question 2.
State the property of the metals due to which they can be beaten into thin sheets.
Answer:
The property of the metals due to which they can be beaten into thin sheets is called malleability.

Question 3.
Which is the hardest substance?
Answer:
Diamond which is a form of carbon is the hardest substance.

Question 4.
What material is used to coat electrical wires?
Answer:
PVC (Polyvinyl chloride) is used to coat electrical wires.

Question 5.
State two metals which can be cut easily with a knife.
Answer:
Sodium and potassium are soft metals and can be cut easily with a knife.

Question 6.
Which of the following metals react with cold water?
Sodium, iron, copper, potassium.
Answer:
Sodium and potassium metals react with cold water.

Question 7.
Which of the following metals do not react with cold water or hot water?
Sodium, potassium, aluminium, iron.
Answer:
Aluminium and iron do not react with cold water or hot water.

Question 8.
State two metals which displace hydrogen from dilute acids and two metals which do not do so.
Answer:
Metals which displace hydrogen from dilute acids are: Magnesium and zinc.
Metals which do not displace hydrogen from dilute acids are: Copper and silver.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 9.
Arrange the following metals in the increasing order of their activity:
Copper, Silver, Aluminium, Iron. (Practice Activity Sheet – 1)
Answer:
The arrangement of metals in the increasing order of their activity:
Silver < Copper < Iron < Aluminium

Question 10.
Write the chemical equation for the reaction of hot iron with steam.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 17

Question 11.
Complete the following reactions:
(1) Zn(s) + H2O(g) → _____________
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 18
Answer:
(1) Zn(s) + H2O(g) → ZnO(s) + H2(g)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 19

Question 12.
Complete the following reactions:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 20
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 21

Question 13.
3MnO2 + 4Al → 3Mn + 2Al2O3 + heat.
Identify the substances undergone oxidation and reduction reactions.
Answer:
MnO2 is reduced to Mn.
Al is oxidised to Al2O3

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 14.
State the impurities present in the bauxite ore.
Answer:
The main impurities present in the bauxite ore are silica (SiO2) and iron oxide (Fe2O3).

Question 15.
Write the formula of (i) bauxite (ii) cryolite.
Answer:
The formula of bauxite is Al2OH2O and that of cryolite is (Na3AlF6).

Question 16.
What is galvanization?
Answer:
The process of coating a thin layer of zinc on iron or steel is called galvanization.

Question 17.
Name the reaction in which aluminium is used as a reducing agent.
Answer:
The thermite reaction in which iron oxide is reduced by aluminium. Aluminium is used as a reducing agent in the thermit reaction.

Question 18.
What are the constituents of bronze?
Answer:
Copper and tin are the constituents of bronze.

Question 19.
State the term used to express the purity of gold.
Answer:
The purity of gold is expressed in carat.

Question 20.
What is meant by amalgam?
Answer:
The amalgam is an alloy in which one of the metals is mercury.

Question 21.
What is meant by electroplating?
Answer:
A process in which a less reactive metal is coated on a more reactive metal by electrolysis is called electroplating.

Question 22.
Why are metals called electropositive elements?
Answer:
Metals are reactive. They lose electrons and become positively charged ions. Therefore, metals are called electropositive elements.

Answer the following questions:

Question 1.
Distinguish between the physical properties of metals and nonmetals with respect to the following points:
(1) Physical state (2) Lustre (3) Ductility and malleability (4) Conduction of heat and electricity (5) Hardness (6) Melting and boiling points.
Answer:
(1) Physical state: Under ordinary conditions, metals are generally solids. Exceptions: mercury and gallium are liquids. Under ordinary conditions, nonmetals may be solids or gases. Exception: bromine is in liquid state.

(2) Lustre: Metals usually have a high lustre (called metallic lustre). They can be polished to give a highly reflective surface. With the exceptions of gold and copper, metals usually have silvery grey colour. Nonmetals lack lustre, exceptions: graphite and iodine. Some nonmetals are colourless and others possess a variety of colours.

(3) Ductility and malleability: Metals are ductile and malleable. Nonmetals are not ductile and mallfeable.

(4) Conduction of heat and electricity: Metals are good conductors of heat and electricity. Nonmetals are bad conductors of heat and electricity. Exception: Graphite is a good conductor of electricity.

(5) Hardness: Metals are usually hard, but not brittle, exceptions: sodium, potassium, lead, zinc. Nonmetals are brittle in the solid state, exception: diamond.

(6) Melting and boiling points: The melting and boiling points of metals are high, exceptions: sodium, potassium, mercury, gallium. The melting and boiling points of nonmetals are low, exceptions: carbon, silicon.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 2.
Write any three physical properties of nonmetals.
Answer:

  1. Nonmetals may be solid or gaseous.
  2. Nonmetals lack lustre. They are not ductile and malleable.
  3. The melting and boiling points of nonmetals are low.
  4. Nonmetals are bad conductors of heat and electricity.

Question 3.
Metals are good conductors of heat. Explain why.
Answer:
(1) The electrons in the outermost shells of atoms of a metal are free to move throughout the metal.
(2) When a metal is heated, these electrons start moving with higher velocity and conduct heat. Hence, metals are good conductors of heat.

Question 4.
Metals are good conductors of electricity. Explain why.
Answer:
(1) The electrons in the outermost shells of atoms of a metal are free to move throughout the metal.
(2) When a potential difference is applied between the ends of a metal wire, the net movement of the electrons in a particular direction, from a point at lower potential to a point at higher potential, constitutes an electric current. Hence, metals are good conductors of electricity.

Question 5.
A metal can be drawn into a wire. Explain why.
Answer:

  1. The property due to which a substance can be drawn into a thin wire without cracking or breaking is called ductility.
  2. Metals are ductile. Thus, a metal can be drawn into a wire.

Question 6.
A metal can be hammered into a thin sheet. Explain why.
Answer:

  1. The property due to which a substance can be hammered (or rolled) into a thin sheet without cracking is called malleability.
  2. Metals are malleable. Thus, a metal can be hammered to form a thin sheet.

Question 7.
How do metals react with oxygen?
Answer:
Metals combine with oxygen on heating in air and metal oxides are formed.
Metal + Oxygen → Metal oxide
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 22

Question 8.
How does a metal react with water?
Answer:
Sodium and potassium react vigorously with water to evolve hydrogen. Calcium reacts with water slowly and less vigorously to evolve hydrogen and the metal floats on water. Magnesium reacts with hot water to evolve hydrogen. Aluminium, iron and zinc do not react with cold or hot water but they react with steam to evolve their oxides and hydrogen.
2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g) + heat energy
2K(s) + 2H2O(l) → 2KOH(aq) + H2(g) + heat energy
2Ca(s) + 2H2O(l) → 2Ca(OH)2(aq) + H2(g)
Mg(s) + 2H2O(hot) → Mg(OH)2(aq) + H2(g)
2Al(s) + 3H2O steam → Al2O3(s) + 3H2(g)
3Fe(s) + 4H2O steam → Fe3O4 + 4H2(g)
Zn(s) + H2O steam → ZnO(s) + H2(g)

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 9.
(9) How does a metal react with an acid?
Answer:
Reaction of metals with acids: Metals react with dilute hydrochloric acid or dilute sulphuric acid to form metal chloride or metal sulphate and hydrogen gas. The rate of evolution of H2 is maximum in case of magnesium. The reactivity decreases in the order
Mg > Al > Zn > Fe.
Mg(s) + 2HCl(aq) → MgCl2(s) + H2(g)
2Al(s) + 6HCl(aq) → 2AlCl3(aq) + 3H2(g)
Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
Fe(s) + 2HCl(aq) → FeCl2(aq) + H2(g)
Fe(s) + H2SO4(aq) → FeSO4 + H2(g)
Zn(s) + H2SO4(aq) → ZnSO4 + H2(g)
Mg(s) + H2SO4(aq) → MgSO4(aq) + H2(g)

Question 10.
How does a metal react with nitric acid?
Answer:
Metals react with nitric acid to form nitrate salts. Depending on the concentration of nitric acid, various oxides of nitrogen (NO, NO2) are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 23

Question 11.
Arrange the following metals in the decreasing order of chemical reactivity:
Cu, Mg, Fe, Ca, Zn, Na.
Answer:
The reactivity of metal decreases in the following order:
Na > Mg > Ca > Zn > Fe > Cu.

Question 12.
What is meant by aqua regia?
Answer:
Aqua regia is a highly corrosive and fuming liquid. It is a freshly prepared mixture of conc. HCl and conc. HNO3 in the ratio of 3:1. Most of the substances dissolve in it. Aqua regia is a reagent which dissolves gold and platinum.

Question 13.
How does a metal react with salts of other metals?
Answer:
The reaction of metals with solutions of salts of other metals is the displacement reaction. If a metal A displaces other metal B from the solution of its salt, it means that the metal A is more reactive than the metal B.
Metal A + Salt solution of metal B → Salt solution of metal A + metal B
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 24
In this reaction Fe has displaced Cu from CuSO4. It means Fe is more reactive than Cu.

Question 14.
Explain the reactivity series of the metals.
Answer:
The arrangement of metals in decreasing order of their reactivity in the form of a series is called the reactivity or activity series of the metals.
The most reactive metal is placed at the top of the list and least reactive metal is placed at the bottom of the list.

On the basis of reactivity, we can classify metals into the following categories:

  1. High reactivity metals
  2. Moderately reactive metals
  3. Less reactive metals.

1. Extraction of High reactivity metals: The metals which are placed at the top of the reactivity series are very reactive. They are never found in nature as free elements, e.g., sodium, potassium, calcium and aluminium. These metals are obtained by electrolytic reduction.

2. Extraction of Moderately reactive metals: The metals in the middle of reactivity series such as iron, zinc, lead, copper are moderately reactive. These elements are present as sulphides or carbonates in nature. Generally metals are obtained from their oxide as compared to their sulphides and carbonates.

3. Extraction of Less reactive metals: The metals which are placed at the bottom of the reactivity series are least reactive. They occur in free state, e.g. gold, silver and copper. Copper and silver are also found in the combined state as sulphide and oxide ores. These metals are obtained from their ores by just heating the ores in air.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 15.
Atomic number of metal “A” is 11, while atomic number of metal “B” is 20. Which of them will be more reactive? Write the chemical reaction of dilute HCl with metal “A”. (Practice Activity Sheet – 2)
Answer:
Metal ‘A’ is more reactive than metal ‘B’.
Atomic number of metal ‘A’ is 11, hence it is Na.
2Na + 2HCl → 2NaCl(aq) + H2(g)

Question 16.
How does a metal react with a nonmetal?
Answer:
By oxidation of a metal, cations are formed, on the other hand by reduction of a nonmetal, anions are formed. The ionic compound is formed due to the metal losing electrons while the nonmetal accepts the electrons. The ionic compound of sodium chloride is formed as sodium loses one electron while chlorine accepts one electron.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 25
Similarly Mg and K form ionic compounds MgCl2 and KCl.

Question 17.
How do nonmetals react with oxygen?
Answer:
Nonmetals combine with oxygen to form acidic oxides. In some cases, neutral oxides are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 26

Question 18.
How do nonmetals react with water?
Answer:
Nonmetals do not react with water, (exception : halogen). Chlorine dissolves in water giving hypochlorous acid.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 27

Question 19.
How do nonmetals react with dilute acids?
Answer:
Nonmetals do not react with dilute acid, (exception: halogen). Chlorine reacts with dil. hydrobromic acid to form bromine and HCl.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 28

Question 20.
How do nonmetals react with hydrogen?
Answer:
Nonmetals react with hydrogen under certain conditions (such as proper temperature, pressure, catalyst, etc.)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 29

Question 21.
What is meant by an ionic compound?
Answer:
The compound formed from two units, namely cation and anion is called an ionic compound.

Question 22.
What is meant by an ionic bond?
Answer:
The cation and anion being oppositely charged, there is an electrostatic force of attraction between them, this force of attraction between cation and anion is called the ionic bond.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 23.
State the general properties of ionic compounds.
Answer:

  1. Ionic compounds are solids and hard due to strong electrostatic force of attraction between oppositely charged ions.
  2. They are generally brittle. When pressure is applied they break into pieces.
  3. They have high melting and boiling points, due to intermolecular force of attraction is high in ionic compounds.
  4. They are soluble in water and insoluble in solvents such as kerosene and petrol.
  5. Ionic compounds cannot conduct electricity when in solid state, they are electrically neutral. They conduct electricity in the molten state and also in an aqueous solution.

Question 24.
Explain the following terms:
1. Concentration of ores
2. Roasting
3. Calcination
4. Refining
Answer:
1. Concentration of ores: The process of separating gangue from the other ores is called concentration of ores.
2. Roasting: The process of heating an ore to a high temperature in excess of air and converting it into its oxide is called roasting.
Examples: ZnS (zinc blend), PbS (Galena)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 30
3. Calcination: The process of heating an ore in a limited supply of air and converting it into its oxide is called calcination.
Example: Zinc carbonate (ZnCO3)
ZnCO3 → ZnO + CO2
4. Refining: The metal obtained by chemical reduction contains impurities. The process of electrolysis method is used to obtain pure metals from impure metals is known as refining.

Question 25.
State two methods of concentration of ores in which the heavy particles of ores can be separated from the light gangue particles by the gravitational method.
Answer:

  1. Wilfley table method
  2. Hydraulic separation method are two methods of concentration of ores in which the heavy particles of ores can be separated from the light, gangue particles by the gravitational method.

Question 26.
What are the different methods used for removing gangue from ores?
(OR)
Write the five methods of concentration of ores.
Answer:

  1. Wilfley table method
  2. Hydraulic separation method
  3. Magnetic separation method
  4. Froth floatation method
  5. Leaching method.

Question 27.
Write short notes on: (1) Wilfley table method (2) Hydraulic separation method (3) Magnetic separation method (4) Froth floatation method (5) Leaching method.
Answer:
(1) Wilfley table method : (Separation based on gravitation) This method of separation uses the Wilfley table, it is made by fixing narrow and thin wooden wedges/blocks on inclined surface with low slope. The table is kept continuously vibrating.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 31
Lumps of the ore is made powdered ore by using ball mill. This powdered ore is poured on the table and a stream of water is simultaneously released from the upper side. This result in the lighter gangue particles getting carried away along with the flowing water, while the heavier particles in which proportion of minerals is more and proportion of gangue particles is less, are blocked by the wooden wedges and is collected through the slits between them.

(2) Hydraulic separation method: The hydraulic separation method is based on the working of a mill. This is a tapering vessel similar to that used in a grinding mill. It opens in a tank like a container that is tapering on the lower side. The tank has an outlet for water on the upper side and a water inlet on the lower side.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 32
Finely ground ore is added to the tank. A fast stream of water is released in the tank from the lower side. The lighter gangue particles flow out along with the water stream from the outlet on the upper side of the tank and are collected separately, simultaneously the heavy particles of the ore are collected at the bottom from the lower side of the tank. This method is based on the law of gravitation, wherein particles of the same size are separated by their weight with the help of water.

(3) Magnetic separation method: Electro-magnetic machine is used in this method. The main parts of this machine are two types of iron rollers and the conveyor belt continuously moving around them. One of the rollers is nonmagnetic while the other is electromagnetic. The conveyor belt moving around the rollers is made up of leather or brass (nonmagnetic). The powdered ore is poured at that end of the conveyor belt which is on the side of the nonmagnetic roller. Two collector vessels are placed below the magnetic roller.

The particles of the nonmagnetic part in the ore are not attracted towards the magnetic roller. Therefore, they are carried out further along the belt and fall in the collector vessel which is away from the magnetic roller. Simultaneously the particles of the magnetic ingredients of the ore stick to the magnetic roller and therefore fall in the collector vessel near the belt.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 33
In this way the magnetic and nonmagnetic particles in the ore are separated because of their magnetic nature. For example, cassiterite is a tin ore. It contains mainly the nonmagnetic ingredient stannic oxide (SnO2) and the magnetic ingredient ferrous tungstate (FeWO4). These are separated by the electromagnetic method.

(4) Froth floatation method: The froth floatation method is based on the two opposite properties, hydrophilic and hydrophobic, of the particles. The metal sulphides particles get wet mainly with oil due to their hydrophobic property. The gangue particles get wet with water due to the hydrophilic property.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 34
In this method the finely ground mineral is put into a big tank containing a lot of water. The finely powdered ore and vegetable oil such as pine oil, eucalyptus oil are mixed with water for formation of froth. The pressurised air is blown through the mixture. There is an agitator rotating around its axis in the centre of the floatation tank. The agitator is used as per the requirement. Bubbles are formed due to the blown air.

A foam is formed from oil, water and air bubbles together, due to the agitating. This foam rises to the surface of the water and floats. Hence this method is called froth floatation. Sulphide minerals float with the foam on water as they get and can be removed. The gangue particles are wetted by water, settles down at the bottom. This method is used for concentration of zinc blend (ZnS) and copper pyrite (CuFeS2).

(5) Leaching: Leaching is the first step in the extraction of the metals like aluminium, gold and silver from their ores. In this method the ore is soaked in a particular solution for long time. The ore dissolves in that solution due to specific chemical reaction. The gangue, however, does not react and therefore does not dissolve in that solution. It can be separated easily.

For example, concentration of bauxite, the aluminium ore, is done by leaching method. Bauxite is soaked in aqueous NaOH or aqueous Na2CO3 which dissolves the main ingredient alumina in it. This means that bauxite is leached by sodium hydroxide.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 28.
Draw a neat labelled diagram of the arrangement of the equipment used in (1) Wilfley table method (2) Hydraulic separation method.
Answer:
1. Wilfley table method:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 35

2. Hydraulic separation method:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 36

Question 29.
Complete the following flow chart and answer the questions below:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 37
(i) In which method pine oil is used?
(ii) Explain that method of concentration in brief. (Practice Activity Sheet – 2)
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 38
(i) Pine oil is used in froth floatation method.

(ii) The finely powdered ore and vegetable oil such as pine oil, eucalyptus oil are mixed with water for formation of froth. The pressurised air is blown through the mixture. The agitator is used as per the requirement. Bubbles are formed due to the blown air. A foam is formed from oil, water and air bubbles together, due to the agitating. This foam rises to the surface of the water and floats. Hence this method is called froth floatation. Sulphide minerals float with the foam on water as they get and can be removed. The gangue particles are wetted by water, settles down at the bottom. This method is used for concentration of zinc blend (ZnS) and copper pyrite (CuFeS2).

Question 30.
A tapping vessel opens in a tank like container that is tapering on the lower side. The tank has an outlet for water on the upper side and a water inlet on the lower side. Finely ground ore is released in the tank. A forceful jet of water is introduced in the tank from lower side and gangue particles and pure ore are separated by this method.
(i) The above description is of which gravitation separation method?
(ii) Draw labelled diagram of this method. (March 2019)
Answer:
(i) Hydraulic separation method.
(ii)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 39

Question 31.
How are sodium, magnesium and potassium obtained from their molten chloride salts?
Answer:
The metals sodium, calcium and magnesium are obtained by electrolysis of their molten chloride salts. In this process metal is deposited on the cathode while chlorine gas is liberated at the anode.

Question 32.
Name the main ore of aluminium.
Answer:
Bauxite (Al2O3·H2O) is the main ore of aluminium.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 33.
What is bauxite? What are the main impurities found in this ore?
Answer:
Bauxite (Al2O3·H2O) is hydrated aluminium oxide. It contains 30% to 70% Al2O3. The main impurities present in it are iron oxide (Fe2O3) and sand (SiO2).

Question 34.
From which ore is aluminium extracted? What are the stages in its extraction (give only names)?
Answer:
Aluminium is extracted from bauxite (Al2O3·nH2O). Stages id the extraction: (i) Concentration of ore, i.e., conversion of bauxite into alumina, (ii) Electrolytic reduction of alumina.

Question 35.
Describe Bayer’s process for concentration of bauxite.
Answer:
(1) Bayer’s process is used to obtain pure aluminium oxide from bauxite.
(2) Bauxite is then concentrated by chemical separation. Bauxite contains impurities like iron oxide (Fe2O3) and silica (SiO2).
(3) Bauxite ore is powdered and heated with sodium hydroxide under high pressure for 2 to 8 hours at 140 °C in the digester. The aluminium oxide being amphoteric in nature present in bauxite reacts with sodium hydroxide to form water soluble sodium aluminate. This means that bauxite leached by sodium hydroxide. Silica reacts with sodium hydroxide to form soluble sodium silicate. The basic iron oxide (Fe2O3) in the gangue remains unaffected. It is separated by filtration.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 40
(4) The filtrate containing sodium aluminate and sodium silicate is stirred with water and then cooling to 50° C. It is hydrolysed to give precipitate of aluminium hydroxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 41
(5) Aluminium hydroxide is then filtered, washed with water, dried and then calcinated by heating at 1000 °C to get pure aluminium oxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 42

Question 36.
Describe Hall’s process for concentration of bauxite.
Answer:
In Hall’s process the ore is powdered and then it is leached by heating with aqueous sodium carbonate in the digester to form water soluble sodium aluminate. Then the insoluble impurities are filtered opt. The filtrate is warmed and neutralised by passing carbon dioxide gas through it. This result in precipitation of aluminium hydroxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 43
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 44
The precipitate of Al(OH)3 obtained in this processes is filtered, washed, dried and then calcinated by heating at 1000 °C to obtain alumina.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 45

Question 37.
Describe the process of preparation of aluminium by the electrolysis of alumina.
(OR)
Draw and label the diagram of electrolysis of alumina and explain the electrolytic reduction of alumina.
Answer:
Electrolytic reduction of alumina:
(1) The electrolytic cell consists of a rectangular steel tank lined from inside with graphite.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 46
(2) The carbon lining (graphite) acts as a cathode. The anode consists of graphite rods suspended in the molten electrolyte.
(3) Alumina has very high melting point ( > 2000 °C). The electrolysis of alumina is carried out at a low temperature by dissolving it in molten cryolite (Na3AlF6). The solution of alumina in cryolite and small amount of fluorspar (CaF2) is added in the mixture to lower its melting point up to 1000 °C.
(4) On passing an electric current, alumina is electrolysed.
(5) Molten aluminium is collected at the cathode, while oxygen gas is evolved at the anode.
The electrode reactions are shown below:
Al2O3 → 2Al3+ + 3O2-
Anode reaction: 2O2- → O2(g) + 4e
Cathode reaction: Al3+ + 3e → Al
The molten aluminium is heavier than the electrolyte. Therefore, it sinks to the bottom of the electrolyte and is removed from time to time. About 99% pure aluminium is obtained by this process. The oxygen gas liberated reacts with carbon anode and forms carbon dioxide. As the anode gets oxidised during the electrolysis of alumina, it has to be replaced from time to time.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 38.
In the extraction of aluminium:
(i) Name the process of concentration of bauxite.
Answer:
The process of concentration of bauxite is known as Bayer’s process.

(ii) Write the cathode reaction in electrolytic reduction of alumina.
Answer:
At the cathode: Al3+ + 3e → Al.

(iii) Write the function and formula of cryolite in the extraction of aluminium.
Answer:
Cryolite is added to the molten mixture of alumina to reduce the melting point to about 1000 °C.
The formula of cryolite is (Na3AlF6) or AlF3, 3NaF.

(iv) write an equation for the action of heat on aluminium hydroxide.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 47

(v) Draw the diagram of extraction of aluminium.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 48

(vi) Write the anode reaction in electrolytic reduction of alumina.
Answer:
Al2O3 → 2Al3+ + 3O2-
At Anode: 2O2- → O2(g) + 4e

(vii) Write the cathode reaction in electrolytic reduction of alumina.
Answer:
Al2O3 → 2Al3+ + 3O2-
Cathode: Al3+ + 3e → Al(l)

Question 39.
What happens when aluminium ore is heated with caustic soda? Write the balanced chemical equation for the same.
Answer:
When aluminium ore is heated with caustic soda solution under high pressure for 2 to 8 hours and at 140 °C to 150 °C, aluminium oxide from aluminium ore, being amphoteric in nature, dissolves in caustic soda solution to form sodium aluminate.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 49

Question 40.
How is zinc extracted from its ore zinc sulphide or zinc carbonate?
Answer:
The crude zinc sulphide ore is heated strongly in excess of air. Zinc sulphide is converted into zinc oxide. This process is known as roasting.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 50
(OR)
The crude zinc carbonate ore is heated strongly in limited supply of air. Zinc carbonate is converted into zinc oxide. This process is known as calcination.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 51
The zinc oxide is reduced to zinc by using a reducing agent such as carbon.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 52

Question 41.
How is copper extracted from its sulphide ore?
Answer:
Copper is found as cuprous sulphide (Cu2S) in nature. When Cu2S is heated in air, copper is obtained.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 53

Question 42.
How is mercury extracted from cinnabar?
(OR)
Extraction of mercury from its ore cinnabar and write the corresponding chemical reaction.
Answer:
Cinnabar is an ore of mercury. When cinnabar is heated (roasted), it is converted into mercuric oxide (HgO). Mercuric oxide is then reduced to mercury on further heating.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 54

Question 43.
Show the steps involved in the extraction of moderately reactive metals from their sulphide ores.
Answer:
Moderately reactive elements are present as sulphides or carbonates in nature.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 55

Question 44.
In the reactivity series of metals, some metals are misplaced. Rearrange these metals in the decreasing order of their reactivity.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 56
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 57

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 45.
Complete the table, if a metal reacts with the reagent then mark ✓ and if not then ✗.

Metal Ferrous
sulphate
Silver
nitrate
Copper
sulphate
Zinc
sulphate
Cu
Al

Answer:

Metal Ferrous
sulphate
Silver
nitrate
Copper
sulphate
Zinc
sulphate
Cu
Al

Question 46.
Explain the term corrosion with a suitable example.
(OR)
What is corrosion ?
Answer:
The process in which a metal is destroyed gradually by the action of air, moisture or a chemical (like an acid) on its surface is called corrosion.
(OR)
Corrosion is degradation of a material due to reaction with its environment.
The major problem of corrosion occurs with iron, as it is used as a structural material in construction, bridges, shipbuilding.
Iron gets covered by reddish brown flakes when exposed to atmosphere. This is an example of corrosion.

Question 47.
Explain the different methods to prevent corrosion of metals.
Answer:
(1) Corrosion of a metal can be prevented if the contact between metal and air is cut off.
(2) Corrosion of a metal is prevented by coating with something which does not allow moisture and oxygen to react with it.
(3) A layer of oil or paint or grease is applied on the surface of a metal to prevent corrosion. The rusting or corrosion of iron can be prevented by this method.
(4) Corrosion is also prevented by coating a corrosive metal with a noncorrosive metal. Galvanising, tinning, electroplating, anodising and alloying are the different methods in which a metal is coated with a noncorrosive metal to prevent corrosion.

Question 48.
Write three methods of preventing rusting of iron.
Answer:

  1. The rusting of iron can be prevented by painting, oiling, greasing or varnishing its surface.
  2. Galvanisation is another method of protecting iron from rusting by coating iron with a thin layer of zinc.
  3. Corrosion of iron is prevented by coating iron with noncorrosive substance like carbon. This process is termed as alloying.

Question 49.
What is meant by an alloy? Give two examples with chemical composition.
Answer:
The homogeneous mixture formed by mixing a metal with other metals or nonmetals in certain proportion is called an alloy.
Examples:
1. Bronze: Bronze is an alloy formed from 90% copper and 10% tin. Bronze statues stay well in sun and rain.
2. Stainless steel: Stainless steel alloy is made from 74% iron, 18% chromium and 8% carbon. This alloy does not get stained with air or water and does not rust.

Write short notes on the following:

Question 1.
Galvanizing.
Answer:
(1) The process of coating a thin layer of zinc on iron or steel is called galvanization.
(2) In this method corrosion of zinc occurs first because zinc is more electropositive than iron. After a few years zinc layer goes away and the iron layer gets exposed and starts rusting.
(3) In galvanization an iron object is dipped into molten zinc. A thin layer of zinc is formed all over the iron object. Examples: Shiny iron nails, pin, iron pipes.

Question 2.
Tinning.
Answer:
The process of coating a thin layer of tin (molten tin) on copper or brass is called tinning. Cooking vessels made of copper and brass get a greenish coating due to corrosion. The greenish substance is copper carbonate and it is poisonous. If buttermilk or curry is placed in such a vessel it gets spoiled. Therefore, these vessels are coated with tin to prevent corrosion.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 3.
Electroplating.
Answer:
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 58
The process in which a less reactive metal is coated on a more reactive metal by electrolysis is called electroplating.
Examples: Silver-plated spoon, gold-plated jewellery.
(1) Which process will you study with the help of above material and solutions.
Answer:
With the help of above material and solutions, electroplating process is studied.

(2) Define the process.
Answer:
The process in which less reactive metal is coated on a more reactive metals by electrolysis is called electroplating.

(3) Write the anode and cathode reactions.
Answer:
At anode: Ag → Ag+ + e
At cathode: Ag+ + e → Ag

Question 4.
Anodizing.
(OR)
Identify the process shown in the above diagram and explain it in brief. (Practice Activity Sheet – 3)
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 59
Answer:
The anodizing technique is an application of electrolysis. In this method copper or aluminium article is used as anode and it is coated with a strong film of their oxides by means of electrolysis. This oxide layer is strong and uniform all over the surface. This thin film protects the metals from corrosion. The protection can be further increased by making the oxide layer thicker during the anodization.
Examples: Kitchen articles such as ; anodized pressure cooker and anodized pan.

Question 5.
Alloying.
Answer:
A homogenous mixture of two or more metals or a metal and a nonmetal in a definite proportion is called an alloy. The physical properties of an alloy are different from those of its constituents. Alloys are corrosion resistant. Alloy decreases the intensity of corrosion of metals.

Examples: Brass is made from copper and zinc, 90 % Copper and 10 % tin are used to make an alloy called bronze, Stainless steel is made from 74% iron, 8 % carbon and 18 % chromium.

Distinguish between: (Two points of distinction)

Question 1.
Metals and Nonmetals.
Answer:
Metals:

  1. Metals have a lustre.
  2. They are generally good conductors of heat and electricity.
  3. They are generally solids at room temperature.
    Exception: Mercury and gallium are liquids.
  4. Metals form basic oxides.

Nonmetals:

  1. Nonmetals have no lustre.
    Exception: Iodine and Diamond.
  2. They are bad conductors of heat and electricity.
    Exception: Graphite.
  3. They are generally gases and solids at room temperature.
    Exception: Bromine is a liquid.
  4. Nonmetals form acidic or neutral oxides.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 2.
Roasting and Calcination.
Answer:
Roasting:

  1. In this process, the ore is heated strongly in the presence of air.
  2. In this process, sulphide ore is converted into metal oxide.
  3. During this process SO2 is given out.

Calcination:

  1. In this process, the ore is heated strongly in the limited supply of air.
  2. In this process, carbonate ore is converted into metal oxide.
  3. During this process CO2 is given out.

Give scientific reasons for the following:

Question 1.
Calcium floats on water during the reaction with water.
Answer:

  1. Calcium reacts with water less vigorously hence the heat evolved is not sufficient for hydrogen to catch fire.
  2. Instead, calcium floats on water because the bubbles of hydrogen gas formed stick to the surface of the metal.

Question 2.
Common salt has high melting and boiling points.
Answer:

  • Common salt is an ionic compound. Common salt is solid and hard due to strong electrostatic attraction between oppositely charged Na+ and Cl- ions.
  • A large amount of energy is required to break the strong intermolecular attraction (strong ionic bond). Hence, common salt has high melting and boiling points.

Question 3.
Metals are good conductors, while non-metals are poor conductors of electricity.
Answer:

  • The electrons in the outermost orbit of atoms of a metal are free to move throughout the metal.
  • When a potential difference is applied between the ends of a metal wire, the movement of the electrons constitutes an electric current. Hence, metals are good conductors of electricity.
  • Nonmetals involve covalent bonding and do not have free electrons like metals. Hence, nonmetals are poor conductors of electricity.

Question 4.
Sodium is more reactive than aluminium.
Answer:

  • If the number of electrons in the outermost orbit of an atom of a metal is less, the metal is more reactive.
  • Sodium has electronic configuration (2, 8, 1) and aluminium has electronic configuration (2, 8, 3). The number of electrons in the outermost orbit of sodium and aluminium atoms are 1 and 3, respectively. Hence, sodium is more reactive than aluminium.

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 5.
When zinc granules are added to copper sulphate solution, the blue coloured solution turns colourless.
Answer:

  • Zinc is more reactive than copper.
  • When zinc granules are added to copper sulphate solution, they displace copper from the copper sulphate solution to form zinc sulphate solution. As zinc sulphate is colourless, the blue coloured solution of copper sulphate disappears.

Question 6.
When an iron nail is dipped into a copper solution, a shiny coat of copper is formed on the nail.
Answer:

  • Iron is more reactive than copper.
  • When an iron nail is dipped into copper sulphate solution, iron displaces copper from the copper sulphate solution. The copper so liberated deposits on the iron nail. As a result, a shiny coat of copper is formed on the nail.

Question 7.
Cryolite (Na3AlF6) and fluorspar (CaF2) are added to the electrolytic mixture containing pure alumina.
Answer:
(1) Alumina has very high melting point ( > 2000 °C). Cryolite (Na3AlF6) and fluorspar (CaF2) lower the fusion temperature of the mixture containing alumina from 2000 ° C to 1000 ° C, thereby saving electrical energy.
(2) They increase the conductivity and the mobility of the fused mixture. Hence, cryolite and fluorspar are added to the electrolytic mixture containing pure alumina.

Question 8.
Air is bubbled through the mixture in Froth floatation process.
Answer:
(1) In the froth floatation process, in a tank water, ore and an oil are mixed. When air is bubbled through the mixture the oil forms froth.
(2) The mineral particles are wetted by the oil and float on the surface.
(3) The gangue particles are wetted by water and settle down. Hence, the ore can be concentrated. Hence, air is bubbled through the mixture in froth floatation process.

Question 9.
Silver amalgam is used for filling dental cavities.
Answer:
(1) Silver is a soft metal and wears off on constant usage particularly due to abrasion. Silver amalgam is an alloy of silver with mercury.
(2) It is a hard substance. It is nontoxic. Besides these properties it is a lustrous shining substance. It melts at a comparatively low temperature and can therefore conveniently fill in the cavities. Hence, silver amalgam is used for filling dental cavities.

Explain the following reactions with the help of balanced equations:

Question 1.
Out of sodium and sulphur which is a metal? Explain its reaction with oxygen. (March 2019)
Answer:
Sodium is a metal. Sodium reacts with oxygen in air at room temperature to form sodium oxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 60

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 2.
Magnesium burns in air.
Answer:
When magnesium bums in air, it combines with oxygen, emitting intense light and heat to form magnesium oxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 61

Question 3.
Copper reacts with air.
Answer:
Copper tarnishes in moist air and forms black coloured oxide when strongly heated.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 62

Question 4.
Sodium reacts with water.
Answer:
When sodium reacts with water, it evolves hydrogen which immediately catches fire producing a lot of heat.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 63

Question 5.
Calcium reacts with water.
Answer:
Calcium reacts with water less vigorously to form hydrogen gas and calcium hydroxide. In this reaction, the heat evolved is not sufficient for hydrogen to catch fire.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 64

Question 6.
Steam is passed over aluminium.
Answer:
When steam is passed over aluminium, hydrogen gas and aluminium oxide are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 65

Question 7.
Steam is passed over iron.
Answer:
When steam is passed over iron, iron (III) oxide and hydrogen gas are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 66

Question 8.
Magnesium reacts with dil. hydrochloric acid.
Answer:
When magnesium reacts with dil. hydrochloric acid, magnesium chloride is formed and hydrogen gas is evolved.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 67

Question 9.
Aluminium is treated with dil. hydrochloric acid.
Answer:
When aluminium is treated with dil. hydrochloric acid, aluminium chloride and hydrogen gas are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 68

Question 10.
Zinc reacts with dil. hydrochloric acid.
Answer:
When zinc reacts with dil. hydrochloric acid, zinc chloride and hydrogen gas are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 69

Question 11.
Iron is treated with dil. hydrochloric acid.
Answer:
When iron reacts with dil. hydrochloric acid, ferrous chloride and hydrogen gas is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 70

Question 12.
Copper is reacted with cone, nitric acid.
Answer:
When copper is reacted with cone, nitric acid, copper nitrate and reddish brown nitrogen dioxide are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 71

Question 13.
Copper is reacted with dil. nitric acid.
Answer:
When copper is reacted with dil. nitric acid, copper nitrate and nitric oxide are formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 72

Question 14.
Sodium metal is reacted chlorine gas.
Answer:
When sodium metal is reacted with chlorine, sodium chloride an ionic compound is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 73

Question 15.
Sulphur burns in air.
Answer:
When sulphur burns in air, it combines with oxygen to form acidic sulphur dioxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 74

Question 16.
Chlorine dissolves in water.
Answer:
When chlorine dissolves in water, hypochlorous acid is formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 75

Question 17.
Chlorine is treated with hydrobromic acid.
Answer:
When chlorine is treated with hydrobromic acid, chlorine displaces bromine from hydrobromic acid.
Cl2(g) + 2HBr(aq) → 2HCl(aq) + Br2(aq)

Question 18.
Hydrogen gas is passed over boiling sulphur.
Answer:
When hydrogen gas is passed over boiling sulphur, sulphur combines with hydrogen to form hydrogen sulphide which has rotten egg smell.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 76

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Question 19.
Sodium aluminate is treated with water.
Answer:
When sodium aluminate is treated with water, it is hydrolysed to give a precipitate of aluminium hydroxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 77

Question 20.
Dry aluminium hydroxide is ignited at 1000 °C.
Answer:
When dry aluminium hydroxide is ignited at 1000 °C, alumina (Al2O3) formed.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 78

Question 21.
Zinc sulphide is heated strongly in excess of air.
Answer:
When zinc sulphide is heated strongly in excess of air, it forms zinc oxide and sulphur dioxide gas.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 79

Question 22.
Zinc carbonate is heated strongly in a limited supply of air.
Answer:
When zinc carbonate is heated strongly in a limited supply of air, it gives zinc oxide and carbon dioxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 80

Question 23.
Zinc oxide is treated with carbon.
Answer:
When zinc oxide is treated with carbon, it is reduced to zinc. In this reaction, carbon acts as reducing agent.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 81

Question 24.
Manganese dioxide is heated with aluminium.
Answer:
When manganese dioxide is heated with aluminium, manganese dioxide is reduced to manganese and large amount of heat is evolved.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 82

Question 25.
Cinnabar is heated in air.
Answer:
When cinnabar is heated in air, it forms mercuric oxide and sulphur dioxide.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 83

Question 26.
Cuprous sulphide is heated in air.
Answer:
When cuprous sulphide is heated in air, cuprous oxide is formed. Cuprous oxide is reduced to copper in the presence of ore.
Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy 84

Maharashtra Board Class 10 Science Solutions Part 1 Chapter 8 Metallurgy

Project: (Do it your self)

Project 1.
Which metals are used in day to day life? What are its uses?

Project 2.
Which nonmetals are used in day to day life? What are its uses?

Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2

Balbharati Maharashtra State Board 11th Commerce Maths Solution Book Pdf Chapter 2 Measures of Dispersion Ex 2.2 Questions and Answers.

Maharashtra State Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2

Question 1.
Find the variance and S.D. for the following set of numbers.
7, 11, 2, 4, 9, 6, 3, 7, 11, 2, 5, 8, 3, 6, 8, 8, 2, 6
Solution:
Given data: 7, 11, 2, 4, 9, 6, 3, 7, 11, 2, 5, 8, 3, 6, 8, 8, 2, 6
The tabulated form of the above data is as given below:
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q1
We prepare the following table for the calculation of variance and S. D.
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q1.1
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q1.2

Question 2.
Find the variance and S.D. for the following set of numbers.
65, 77, 81, 98, 100, 80, 129
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q2
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q2.1

Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2

Question 3.
Compute the variance and standard deviation for the following data:
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q3
Solution:
We prepare the following table for the calculation of variance and S.D.:
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q3.1

Question 4.
Compute the variance and S.D.
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q4
Solution:
We prepare the following table for the calculation of variance and S.D.:
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q4.1

Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2

Question 5.
The following data gives the age of 100 students in a school. Calculate variance and S.D.
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q5
Solution:
We prepare the following table for the calculation of variance and S.D:
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q5.1

Question 6.
The mean and variance of 5 observations are 3 and 2 respectively. If three of the five observations are 1, 3, and 5, find the values of the other two observations.
Solution:
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q6
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q6.1
∴ (x4 – 4)(x4 – 2) = 0
∴ x4 = 4 or x4 = 2
From (i), we get
x5 = 2 or x5 = 4
∴ The two numbers are 2 and 4.

Question 7.
Obtain standard deviation for the following data:
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q7
Solution:
We prepare the following table for the calculation of standard deviation.
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q7.1

Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2

Question 8.
The following distribution was obtained by change of origin and scale of variable X.
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q8
If it is given that mean and variance are 59.5 and 413 respectively, determine actual class intervals.
Solution:
Here, Mean = \(\bar{x}\) = 59.5, and
Var(X) = σ2 = 413
Let xi be a mid value of class and
d = \(\frac{x-a}{h}\), where a is assumed mean and h is class width.
We prepare the following table for calculation of mean and variance of di.
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q8.1
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q8.2
Now, Var(X) = h2. Var(D)
∴ 413 = h2 × 4.13
∴ h2 = 100
∴ h = 10
Substituting h = 10 in (i), we get
-0.1 × 10 + a = 59.5
∴ -1 + a = 59.5
∴ a = 59.5 + 1
∴ a = 60.5
We prepare the following table to determine actual class intervals for corresponding values of di.
Maharashtra Board 11th Commerce Maths Solutions Chapter 2 Measures of Dispersion Ex 2.2 Q8.3
∴ The actual class intervals are 15.5 – 25.5, 25.5 – 35.5, …….., 95.5 – 105.5

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Balbharti Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 1.
Remake the table taking into account relation between entries in three columns.

I II III
Coal Potential energy Wind electricity plant
Uranium Kinetic energy Hydroelectric plant
Water reservoir Nuclear energy Thermal plant
Wind Thermal energy Nuclear power plant

Answer:

I II III
Coal Thermal energy Thermal plant
Uranium Nuclear energy Nuclear power plant
Water reservoir Potential energy Hydroelectric plant
Wind Kinetic energy Wind electricity plant

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 2.
Which fuel is used in thermal power plant? what are the problems associated with this type of power generation?
Answer:
(1) The fuel used in the thermal power plant is coal. Coal contains chemical energy. Upon burning it releases heat energy. This heat is used for generation of electricity in the thermal power plants.

(2) Problems associated with power 8enerations by thermal power plant:
(a) Air pollution: Due to burning of coal, there is emission of carbon dioxide, carbon monoxide, sulphur dioxide and nitrogen dioxide gases. These are harmful and toxic to health.
(b) Soot particles emitted during combustion can cause severe respiratory problems such as asthma.

Question 3.
Other than thermnl power plant. which power plants use thermal energy for power generation? In what different ways is the thermal energy obtained?
Answer:
(1) The power plant based on natural gas and the nuclear power plants also used thermal energy for the power generation. Apart from these, solar energy is also used to produce heat and thereby create the power.
(2) In nuclear power plant, the energy is released by carrying out fission of nuclei of atoms like Uranium or Plutonium. This energy is used to generate the steam of high temperature and high pressure. The steam rotates the turbine. The kinetic energy in steam drives the turbine and turbine in turn drives the generator.
(3) The combustion of natural gas produces gas, which is used to run the turbine. This gas is under high pressure and high temperature. This is used to produce thermal energy.
(4) In solar thermal power plant, thermal energy is generated with the help of solar radiation. For this reflectors and absorbers are used for concentrating solar radiation and converting it into thermal energy.

Question 4.
Which type/types of power generation involve maximum number of steps of energy conversion? In which power generation is the number minimum?
Answer:
The steps of energy conversion are maximum in the thermal power generation. They are minimum in wind energy generation.

Question 5.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 1
a. Maximum energy generation in India is done using …………… energy.
Answer:
Maximum energy generation in India is done using thermal energy.

b. ………. energy is a renewable source of energy.
Answer:
wind energy is a renewable source of energy.

c.Solar energy can be called ……. energy.
Answer:
Solar energy can be called clean energy.

d. ……. energy of wind is used in wind mills.
Answer:
kinetic energy of wind is used in wind mills.

e. ………. energy of water in darns is used for generation of electricity.
Answer:
Potential energy of water in darns is used for generation of electricity.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 6.
Explain the difference.
a. Conventional and Non-conventional Sources of energy.
Answer:
Conventional Sources of energy:

  1. Conventional sources of energy are largely polluting, they release lot of carbon through its emissions.
  2. Conventional sources of energy are not eco¬friendly.
  3. The fuels produced from the conventional sources of energy are comparatively costlier.
  4. Conventional energy power plants require less area and its management cost is also less.
  5. Conventional source of energy are non-renewable.
  6. Conventional sources of energy are in the form of limited reserves. After few years they will be completely over. e.g. Fossil fuels, coal, crude oil, diesel, petrol, natural gas, etc.

Non-conventional Sources of energy:

  1. Non-conventional sources of energy are not polluting, They do not release carbon or other toxic gases.
  2. Non-conventional sources of energy are eco-friendly.
  3. The energy obtained from the non-conventional sources of energy are comparatively cheaper.
  4. Non-conventional energy power plants require more area and its management cost is also more.
  5. Non-conventional source of energy are renewable.
  6. Non-conventional energy sources qre in abundance on the earth. They are persistent and sustainable. Thus they will not get over. e.g. Solar energy, wind energy, etc.

b. Thermal electricity generation and Solar thermal electricity generation.
Answer:
Thermal electricity generation:

  1. After burning the coal, the heat that is produced is used in the generation of thermal electricity.
  2. For producing heat, the coal is burnt in the boilers.
  3. The combustion of coal produces heat. This heat converts water into steam, which is under very high temperature and pressure. By its force the turbines move. The turbines in turn are connected to generator which rotates and produces energy.
  4. Thermal energy is polluting and not eco-friendly.
  5. The fuel here is coal, its reserves are limited.

Solar thermal electricity generation:

  1. Solar radiations are used in solar thermal electricity production.
  2. For production of heat, many reflectors are used which reflect the radiations of the sun into the absorbent.
  3. Sun’s heat convert the water into steam that rotates the turbine. The turbines then rotate the generators. This generates the electricity.
  4. Solar energy is not polluting, it is eco-friendly.
  5. The solar radiations are in abundance and are sustainable and persistent.

Question 7.
What is meant by green energy? Which energy sources can be called green energy sources and why? Give examples.
Answer:
(1) Green energy means eco-friendly form of energy which does not cause environmental problems and are non-exhaustible, perpetual and sustainable.
(2) These sources of energy do not produce toxic gases or other pollutants, therefore they are safe.
(3) Examples of green energy: (i) Hydroelectric energy (ii) Wind energy (iii) Solar energy (iv) Energy obtained biofuels.

Question 8.
Explain the following sentences.
a. Energy obtained from fossil fuels is not green energy.
Answer:
Fossil fuels like petrol, diesel or natural gas when burnt, emit toxic gases and soot particles. Thus, fossil fuels cause air pollution. Burning of fossil fuels cause increased levels of carbon dioxide, carbon monoxide and nitrogen dioxide. The increased carbon dioxide emission results in global warming. Nitrogen oxide results later in acid-rain. Soot particles generated through burning of fuels cause respiratory problems iike asthma.

Moreover, the fossil fuels are non-renewable and exhaustible fuels. They have to be explored from the
deeper layers of the earth causing lots of environmental problems. Green energy is sustainable, renewable and abundant. It never creates any environmental problems and is non-polluting. Thus, energy obtained from fossil fuels is not at all a green energy.

b. Saving energy is the need of the hour.
Answer:
In modern civilization, continuous energy supply is needed for the technology and development. The energy has become a basic need for man. Most of the energy used in India is obtained from thermal power plant. For this energy generation, various fuels are used. The coal and fossil fuels are limited. Due to over-exploitation, these reserves are getting fast depleted. Use of fossil fuels is also resulting in pollution and climate change.

Nuclear energy can be very hazardous. Lot of research is being done in the field of green energy, but the tremendous human population always is in need of more energy. Therefore, each and every person should save the energy, as saving energy is the need of the hour.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 9.
Answer the following questions.
a. How can we get the required amount of energy by connecting solar panels?
Answer:

  • The photovoltaic solar cells can be connected in a series or in parallel to make a solar panel.
  • When solar cells are connected in a series, the potential difference of individual cells are added in the combination, however the currents from individual cells are not added.
  • When solar cells are connected in parallel, the currents of the individual cells are added in the combination, but the potential differences from individual cells are not added.
  • Through such connections the required potential difference and current can be obtained.
  • Many such solar panels are connected in series and in parallel to generate required current and potential difference.
  • When many solar panels connected in series they form a solar string. Many solar strings connected in parallel make a solar array. In such manner we can get the required amount of energy by connecting solar panels.

b. What are the advantages and limitations of solar energy?
Answer:
I. Advantages:

  • While generating the power through solar radiations, no fuel is burnt.
  • Solar energy generation thus does not create any type of pollution. The technology can be completely utilized in regions with abundant sunlight.
  • Solar energy is eco-friendly, green energy.

II. Limitations:

  • Sunlight is available only during day time. Thus solar cells can generate power only during day.
  • In rainy season and in cloudy conditions, solar power generation suffers.
  • The power present in the solar cells is DC while most of the domestic equipments work on AC.

Question 10.
Explain with diagram step-by-step energy conversion in
a. Thermal power plant.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 2a
In thermal power plant the turbines are rotated using steam. Here the coal is burnt. The heat energy liberated from this burning is used to heat the water in the boiler. This water produces steam of very high temperature and pressure. The kinetic energy in the steam rotates the turbines. The rotation of turbines produces its own mechanical kinetic energy.

The generators connected to turbines produce electrical energy. The steam is condensed in a condenser and converted back into water. In this way in thermal power plant, thermal energy to kinetic energy, kinetic energy into mechanical energy and mechanical energy to electrical energy, are the conversions that take place.

b. Nuclear power plant.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 3a
In nuclear power plant, the energy is releasdd by fission of nuclei of atbms like Uranium or Plutonium. This energy is used to generate the steam or high temperature ind high pressure. The kinetic energy in the steam rotates the turbine. The turbine in turn drives the generator to produce electricity.

c. Solar thermal power plant.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 4a
Solar radiation is used to produce thermal energy. For this purpose, many reflectors are used which concentrate the solar radiation on absorbers. The heat energy created due to solar radiations is used to make steam. The steam possesses kinetic energy. This kinetic energy drives turbine and generator. The electrical energy is thus created from this kinetic energy.

d. Hydroelectric power plant:
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 5a
In hydroelectric plant the water stored in the reservoir is used as a source or potential energy. This water is made to fall at a great speed and hence there is production of kinetic energy in flowing water. This fast flowing water ralling down from the reservoir is brought to the turbine at the lower levels. The kinetic energy of the flowing water in turn drives the turbine, The turbine then drives the generator and electrical energy is produced.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 11.
Give scientific reasons:
a. The construction of turbine is different for different types of power plants.
Answer:

  • Generators work on the principles of electromagnetic induction.
  • For this the generator must be rotated.
  • For this purpose, there is a turbine for each generator.
  • This rotation needs energy. The turbines are different according to the type of energy source that is used for its rotation.
  • Therefore, the construction of turbine is different for each power plant.

b. It is absolutely necessary to control the fission reaction in nuclear power plants.
Answer:

  • Nuclear fission reaction is a type of chain reaction.
  • In nuclear power plants these reactions are closely controlled.
  • If these reactions are not managed properly, there can be more production of neutrons in an uncontrolled way.
  • Each released neutron further causes fission of 3 Uranium (U-235) atoms, such uncontrolled reactions can cause hazardous accidents, hence ft is absolutely necessary to control the fission reaction in nuclear power plants.

c. Hydroelectric energy, solar energy and wind energy are called renewable energies. (July ’19, Board’s Model Activity Sheet)
Answer:

  • Hydroelectric energy, solar energy and wind energy is obtained respectively from flowing water, solar radiations and flowing wind.
  • These sources, i.e. water reservoirs, sun and the wind are inexhaustible and sustainable. They will not be finished.
  • On the contrary, the conventional energy sources such as coal and fossil fuels have limited reserves.
  • They cannot be renewed and may get exhausted in future. Hydroelectric energy, solar energy and wind energy can be replenished and hence they are called renewable.

d. It is possible to produce energy from mW to MW using solar photovoltaic cells.
Answer:

  1. Solar panels can be constructed by connecting solar photovoltaic cells in either series or in parallels.
  2. The combinations are done in such a way that it can give the desired potential difference and the current.
  3. Solar strings are then made by joining solar panels in a series.
  4. When solar strings are joined in parallel; they form solar array.
  5. Therefore, by proper combinations, it becomes possible to produce energy from mW to MW using solar photovoltaic cells.

Question 12.
Draw a Schematic diagram of Solar thermal electric energy generation.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 6

Question 13.
Give your opinion about whether hydroelectric plants are environment-friendly or not?
Answer:

  • Hydroelectric plants are advantageous in some respect while in some aspects it does create problems.
  • Hydroelectric power generation does not need burning of fuels. Therefore, there is no problem regarding combustion of fuels and release of toxic pollutants.
  • Electricity can be obtained as and when required if there is enough water in the reservoir.
  • Water is replenished every time when there is sufficient rainfall.
  • All the above facts give an impression that hydroelectric power generation is eco-friendly but it is not.
  • Many villages and settlements are submerged when a dam and reservoir is constructed. The displaced people are given re-settlement, but it causes lot of emotional trauma to people.
  • Biodiversity is affected as forest lands is submerged. The river flow is obstructed by the dam which affects the aquatic organisms residing in such water.
  • Due to excessive pressure of water on land, it is said that the region gets prone to earthquakes.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 14.
Draw a neat labelled diagrams.
a. Energy transformation in solar thermal electric energy generation.
Answer:

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 7a

b. One solar panel produces a potential difference of 18 V and current of 3A. Describe how you can obtain a potential difference of 72 Volts and current of 9 A with a solar array using solar panels. You can use sign of a battery for a solar panel.
Answer:
Given Potential difference is 18 V and current is 3A. The requirement is potential difference of 72 V and current is 9A Voltage remains the same if connected in parallel and gets added it they are connected in series. Current remains the same if connected in series but adds if connected in parallel.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 8

Question 15.
Write a short note on Electrical energy generation and environment.
Answer:
The energy obtained through the fossil fuels as well as nuclear energy can cause degradation of the environment. If such energy sources are used, they can cause harm to the environment.

(1) The burning of fossil fuels cause air pollution. The incomplete combustion of fossil fuels cause release of carbon monoxide. Some more toxic gases and soot particles cause various respiratory diseases. The carbon dioxide produced is creating global warming and climate change. The nitrogen dioxide released through burning is responsible for acid rains.

(2) Fossil fuels are limited. They are getting fast depleted. It has taken millions of years for the fossil fuels to form. The exploration of such fuels also cause environmental degradation and marine pollution too.

(3) In production of nuclear energy, there is a great risk of accidents. The safe disposal of nuclear waste is also a problem.

(4) Hydroelectric power from water reservoirs, wind power from wind, solar energy from sun and electricity from biofuels are eco-friendly alternatives.

Projects: (Do it your self)

Project 1.
Gather information about solar light, solar water heating system and solar cooker.

Project2.
Gather information about a power plant near your locality by visiting the plant.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Can you recall? (Text Book Page No. 47)

Question 1.
What is Energy?
Answer:
The capacity to do work is called energy.

Question 2.
What are different types of Energy?
Answer:
Potential energy and kinetic energy are the two types of energy.

Question 3.
What are different forms of Energy?
Answer:
Heat, light, electric energy, solar energy, chemical energy, nuclear energy, mechanical energy, etc. are different forms of energy.

Use your brain power! (Text Book Page No. 54)

Question 1.
The schematic of hydroelectric plant is shown in Figure 5.17 on text book page no. 54. Water from about middle of the total height of the dam is taken to the turbine, as shown by point B in the diagram.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 9
(i) With reference to point B, potential energy of how much water reservoir in the dam will be converted into kinetic energy?
Answer:
When the sluice gate at point B is opened, the water from reservoir will start flowing. The potential energy of the stored water will become kinetic energy of the quantity of water that is let out through the sluice gates.

(ii) What will be the effect on electricity generation, if the channel taking water to turbine starts at point A?
Answer:
If the channel taking water to turbine starts at point A, then the water will flow with a greater speed. Since point A is at hSight, water will acquire speed. This will result into more efficient rotation of the blades of turbine. The electricity generation will thus become more efficient.

(iii) What will be the effect on electricity generation, if the channel taking water to turbine starts at point C?
Answer:
If the channel taking water to turbine starts at point C, it will affect the electricity generation adversely. Point C is on the lower height as compared to the channel that carries water to the turbine. The flow of the water thus will be affected resulting into improper rotation of blades of turbine. This will certainly affect the electricity generation.

Choose the correct alternative and write its alphabet against the sub-question number:

Question 1.
Large ……….. are used in commercial power generation plants.
(a) machines
(b) generators
(c) turbines
(d) pannels
Answer:
(b) generators

Question 2.
The principle of electromagnetic ……….. was invented by Michael Faraday.
(a) induction
(b) attraction
(c) repulsion
(d) expulsion
Answer:
(a) induction

Question 3.
………… is used to rotate the magnet in the generator.
(a) fan
(b) Generator
(c) Turbine
(d) Panels
Answer:
(c) Turbine

Question 4.
In thermal power plants, the ………… energy in the coal is converted into electrical energy through several steps.
(a) physical
(b) biological
(c) kinetic
(d) chemical
Answer:
(d) chemical

Question 5.
At ………. in Andhra Pradesh power plant based on natural gas has been installed.
(a) Hyderabad
(b) Vishakhapatnam
(c) Samaralkota
(d) Kakinada
Answer:
(c) Samaralkota

Question 6.
Burning of coal may cause serious health problems related to ……….. system.
(a) digestive
(b) respiratory
(c) nervous
(d) excretory
Answer:
(b) respiratory

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 7.
Incomplete combustion of fuels leads to formation of ……….
(a) carbon dioxide
(b) carbon monoxide
(c) carbon tetrachloride
(d) All the above
Answer:
(b) carbon monoxide

Question 8.
Solar cells are made of a special type of material called semiconductor such as ………..
(a) silicon
(b) uranium
(c) borosilicate
(d) hydrogen
Answer:
(a) silicon

Question 9.
……….. of the following is eco-friendly energy resource. (Board’s Model Activity Sheet)
(a) Coal
(b) Hydroelectric power
(c) Fossil fuel
(d) Atomic energy
Answer:
(b) Hydroelectric power

Question 10.
Which is the most abundant and renewable energy?
(a) Thermal power
(b) Solar energy
(c) Fossil fuels
(d) Atomic power
Answer:
(b) Solar energy

Question 11.
What are the two technologies for harnessing solar energy?
(a) Solar photovoltaics and solar thermal
(b) Solar cooker and solar lamp
(c) Heat capturing and Heat conversation
(d) Active and passive technologies
Answer:
(a) Solar photovoltaics and solar thermal

Question 12.
Which of the following is used in solar cooker to harvest the solar energy?
(a) Solar panels
(b) Silicon cell
(c) Mirrors
(d) Glass lid
Answer:
(c) Mirrors

Question 13.
Which of the following is not the source of green energy?
(a) Wind
(b) Natural gas
(c) Sunlight
(d) Fossil fuel
Answer:
(d) Fossil fuel

Question 14.
The solar lamp uses the energy.
(a) Heat
(b) Wind
(c) Light
(d) Sound
Answer:
(c) Light

State whether the following statements are true or false with proper explanation:

Question 1.
In thermal power plants, the turbines work on solar energy.
Answer:
False. (In thermal power plant, the turbines work on steam. The turbines working on solar energy are not used.)

Question 2.
How to dispose the nuclear waste safely is a big challenge before the scientists.
Answer:
True. (Nuclear waste disposal is the greatest problem. It produces highly toxic effects in any ecosystem. Therefore, disposing such radioactive substances becomes a major challenge.)

Question 3.
The efficiency of power generation using coal plant is higher than that of power generation plant based on natural gas.
Answer:
False. (The efficiency of power generation using natural gas plant is higher than that of power generation plant based on coal.)

Question 4.
Energy obtained from nuclear fission is eco-friendly.
Answer:
False. (Energy obtained from nuclear fission is not eco-friendly, because if accidents happen it leads to hazardous accidents.)

Question 5.
In hydroelectric power plant, the kinetic energy in water stored in dam is converted into potential energy of water.
Answer:
False. (In hydroelectric power plant, the potential energy in water stored in dam is converted into kinetic energy of water. The forceful downpour of flowing water causes this kinetic energy.)

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 6.
The turbine is connected to electric generator, therefore the magnet rotates and electric energy is thus produced.
Answer:
True. (The rotating wheels of turbine cause mechanical energy. This energy helps to produce electrical energy.)

Question 7.
Use of energy is unavoidable in our daily life, but we must use it carefully and only in the required amount.
Answer:
True. (The energy Supply for everyday use results into lot of pollution. This causes harmful effects in the surrounding environment. Therefore, energy should be used in minimal amount and with great care.)

Question 8.
The machine which converts the potential energy of wind to electrical energy is called wind-turbine.
Answer:
False. (When wind blows, the kinetic energy is present in it. This kinetic energy is converted into electricity. The flowing wind never has a potential energy.)

Question 9.
The potential difference available from a solar cell is independent of its area.
Answer:
True. (The potential difference available from a solar cell is independent of its area. However, it is dependent on the way in which solar cells are connected.)

Question 10.
The power available from the solar cells is AC.
Answer:
False. (The power available from solar cells is always DC while the domestic appliances that we use work on AC.)

Match the columns:

Question 1.

Column I Column II
(1) Polluting energy (a) Soot particles
(2) Eco-friendly energy (b) Thermal energy
(c) Nuclear energy
(d) Wind energy

Answer:
(1) Polluting energy – Thermal energy
(2) Eco-friendly energy – Wind energy

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 2.

Column I Column II
(1) Pollutants (a) Soot particles
(2) Hazard to ecosystem (b) Thermal energy
(c) Nuclear energy
(d) Wind energy

Answer:
(1) Pollutants – Soot particles
(2) Hazard to ecosystem – Nuclear energy

Question 3.

Type of energy Problem
(1) Nuclear energy (a) Rehabilitation of displaced people
(2) Natural gas (b) Rainy season and darkness
(c) Limited reserves
(d) Disposal of wastes

Answer:
(1) Nuclear energy – Disposal of wastes
(2) Natural gas – Limited reserves

Question 4.

Type of energy Problem
(1) Solar energy (a) Rehabilitation of displaced people
(2) Hydroelectric  energy (b) Rainy season and darkness
(c) Limited reserves
(d) Disposal of wastes

Answer:
(1) Solar energy – Rainy season and darkness
(2) Hydroelectric energy – Rehabilitation of displaced people

Find the odd one out:

Question 1.
Kudankulam, Tarapur, Ravatabhata, Anjanvel
Answer:
Anjanvel. (All others are places having nuclear power plants.)

Question 2.
Samaralkota, Kudankulam, Bavanaa, Kondapalli
Answer:
Kudankulam. (All others are places having power plants based on natural gas.)

Question 3.
Tehari, Koyana, Srishailam, Tarapur
Answer:
Tarapur. (All others are places having hydroelectric projects.)

Question 4.
Edible oil, crude oil, LPG, CNG
Answer:
Edible oil. (All others are fossil fuels.)

Question 5.
Hydroelectric energy, Solar energy, Nuclear energy, Wind energy
Answer:
Nuclear energy. (All others are eco-friendly green energy types.)

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Explain with diagram step-by-step energy conversion in:

Question 1.
Power plant based on natural gas.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 10a
In a power plant based on natural gas, there are three main sections of the plant. There is combustion chamber with compressor in which the steam under pressure is introduced. The natural gas burns in the presence of air in this combustion chamber. This results in a production of a gas which is at very high temperature and pressure. This generated gas from the chamber runs the turbine. The kinetic energy of the turbine drives the generator. The generator produces electrical energy.

Question 2.
Power plant based on wind energy.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 11a
Wind energy is used for moving turbines. The wind with specific speed is used to rotate the large fins of wind turbine. The kinetic energy in these fins is transferred to generator which then produces electrical energy.

Explain the following questions in detail:

Question 1.
What are the advantages of hydroelectric power generation? (March 2019)
Answer:

  1. Hydroelectric energy does not cause pollution.
  2. Generation of hydroelectric energy does not involve burning of fossil fuel.
  3. If sufficient water storage is available then electricity generation can be done as per requirement.
  4. Rainwater can replenish the water storage and power generation can thus be done uninterrupted.

Question 2.
How is nuclear fission reaction carried out in nuclear power plants?
Answer:

  • In nuclear power plants neutrons are bombarded on atom of Uranium – 235.
  • This causes conversion of Uranium – 235 into its isotope U – 236.
  • U-236 is very unstable and thus forms atoms of Barium and Krypton by nuclear fission. This forms 3 neutrons and 200 MeV energy.
  • In a similar way three more Uranium – 235 atoms are subjected to nuclear fission which then releases energy.
  • The neutrons released are again used for further nuclear fission reactions. In this way nuclear fission reactions are carried out in controlled manner in nuclear power plants.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 3.
Draw schematic of power plant based on natural gas and answer the following questions: (July 2019)
(a) At which place natural gas power plant is situated in Maharashtra?
(b) How is pollution reduced in natural gas based power plant?
(c) Give two examples of eco-friendly electricity process.
Answer:
(a) Natural gas power plant is situated at Anjanvel in Maharashtra.
(b) Natural gas does not contain sulfur. Burning of such natural gas does not produce pollution.
(c) Solar energy and wind energy are two examples of eco-friendly energy.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 30

Complete the paragraph by choosing the appropriate words given in the brackets:

Question 1.
(marginal, array, cell, panel, string, current, power station, potential difference).
Many solar panels are connected in series and in parallel to generate required ………… and ……… Solar …………. is the basic unit in solar electric plant. Many solar cells come together to form a solar …………… Many solar panels connected in series form a solar ………., and many solar strings connected in parallel form a solar …………. As we can obtain as much electrical power as needed, they are used in applications which need ……….. power (e.g. calculators that run on solar energy) to ……….. of MW capacity.
Answer:
Many solar panels are connected in series and in parallel to generate required current and potential difference. Solar cell is the basic unit in solar electric plant. Many solar cells come together to form a solar panel. Many solar panels connected in series form a solar string, and many solar strings connected in parallel form a solar array. As we can obtain as much electrical power as needed, they are used in applications which need marginal power (e.g. calculators that run on solar energy) to power station of MW capacity.

Read the paragraph and answer the questions given below:

1. Renewable energy is, energy produced from sources that do not deplete or can be replenished within a human’s life time. The most common examples include wind, solar, geothermal, biorhass, and hydroelectric power. This is in contrast to non-renewable sources such as fossil fuels. Most renewable energy is derived directly or indirectly from the sun. Sunlight can be captured directly using solar technologies. The sun’s heat drives winds, whose energy is captured with turbines. Plants also rely on the sun to grow and their stored energy can be utilized for bioenergy. Not all renewable energy sources rely on the sun. For example, geothermal energy utilizes the Earth’s internal heat, tidal energy relies on the gravitational pull of the moon, and hydroelectric power relies on the flow of water.

Questions and Answers :
Question1.
What is renewable energy?
Answer:
Renewable energy is energy that is produced from sources which will not get exhausted within a human’s life time.

Question 2.
Give the examples of renewable energy.
Answer:
Wind, solar, geothermal, biomass and hydroelectric power are some examples of renewable energy.

Question 3.
Why will energy from fossil fuel be over soon?
Answer:
Fossil fuels are exhaustible in their amount. We have been using these extensively in the past 100 years and hence it may get over soon. It is a non-renewable resource.

Question 4.
Name the renewable sources of energy which are not dependent on sun. What are they dependent upon?
Answer:
Geothermal energy, tidal energy and hydroelectric power are renewable energy resources which are not dependent on sun. Geothermal energy utilizes the Earth’s internal heat, tidal energy relies on the gravitational pull of the moon, and hydropower relies on the flow of water.

Question 5.
Which type of energy do we mostly use in India?
Answer:
The most used energy resource is coal, i.e. fossil fuel based energy followed by hydroelectric energy.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

2. Read the information given below and solve the questions based on it.
Electric energy is produced in various ways like hydroelectric, wind power, solar energy, bio-fuel, etc. These energy sources are inexhaustible, sustainable. Besides, it does not cause any environmental problem.

Questions and Answers:
Question 1.
Above information is about which type of energy?
Answer:
From the above information, we understand about green energy.

Question 2.
Whether the fossil fuel is an example of this energy?
Answer:
Fossil fuels are not green energy.

Question3.
Draw the flow chart of production of electric energy.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 12

Diagram based questions:

Question 1.
Observe the connections of cells shown in the following images.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 13
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 14
(i) Which connection will give maximum potential difference?
Answer:
The solar cells shown in the diagram 5.19 (a) are connected in series. This gives maximum potential difference.

(ii) Give one advantage and one disadvantage of this energy.
Answer:
Advantage of Solar energy: Solar energy is eco-friendly which does not create pollution. It is boundless source.
Disadvantage of solar energy: Solar energy is available only when sun is in the sky. Therefore, it has to be stored in batteries.

Question 2.
Answer the following questions:
(a) Write the name of the device shown in the above diagram.
Answer:
Steam turbine is the device shown in the above diagram.

(b) Write briefly the work of this device.
Answer:
Turbine is a device with the blades. When the flow of liquid or gases is directed on the blades of the turbine, they rotate. The rotation produces kinetic energy. This turbine is then used to rotate the magnet in the electric generator. For this purpose, turbines are connected with the generators. The magnets rotate and produce electric energy by electromagnetic induction. The turbines working on steam are used in large commercial power generation plants.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 3.
Label the given diagram of Electromagnetic induction.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 15

Question 4.
Answer the questions with the help of picture.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 16
(a) Which type of energy is produced?
(b) This power plant is based on which energy source.
(c) Is this power plant eco-friendly? How?
Answer:
(a) In the picture, it is shown that using wind energy electricity is produced.
(b) The power plant shown here is based on kinetic energy of wind which is converted to electric energy by utilizing kinetic energy from rotating turbines.
(c) This power plant is eco-friendly because it does not cause pollution. Wind energy is green energy which is non-exhaustible and perpetual.

Question 5.
Observe the figure and answer the questions given below.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 17
Answer:
(a) Name the reaction.
Answer:
The reaction shown in nuclear fission or chain reaction.

(b) Where is this reaction used?
Answer:
This reaction is used in nuclear power plants where electricity is generated.

(c) Which element is used in it?
Answer:
Uranium-235 is used in the nuclear fission reactions.

(OR)

Identify the process shown in figure and name it. (March 2019)
Answer:
The above figure shows nuclear fission chain reaction of Uranium – 236.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 6.
Observe the diagram and answer the questions : (March 2019)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 18
(a) Which energy is generated from the power plant?
Answer:
The diagram shows electricity generated from natural gas.

(b) State its source.
Answer:
The energy is generated from natural gas.

(c) Which is more eco-friendly – Power generation from coal or Power generation from natural gas? Why?
Answer:
Power generation from natural gas is more eco-friendly. Natural gas does not contain sulfur and hence its burning does not cause major pollution by forming sulphur dioxide. The efficiency of power generation by natural gas is also high.

Question 7.
Write the names of apparatus that is used in thermal power plant.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 19

Question 8.
Label correctly the diagram of Nuclear power plant.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 20

Question 9.
Label correctly the diagram of power plant baded on natural gas.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 21

Question 10.
Label correctly the structures seen in Windmill.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 22

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Question 11.
Sketch two ways in which solar cells can be connected. Also draw the diagrams to show the arrangement of solar cells to form solar? panel and solar array.
a. Solar cells in series.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 23

(b) Solar cells in parallel.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 24

(c) Solar panel.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 25

(d) Solar array.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 26

Question 12.
Observe the figure given below and answer the given questions:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 27
(a) Identify the type of energy generation process shown in this picture.
(b) Name any four equipments which use this type of energy. (Board’s Model Activity Sheet)
Answer:
(a) In this figure solar energy is converted into electrical energy. Solar energy is also called clean energy.
(b) Solar energy is used in following equipment:

  • Solar cooker
  • Solar heater
  • Calculator
  • Solar Photovoltaic cell.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Activity based questions.

Question 1.
Make a table: (Text Book Page No. 47)
Make a table based on forms of energy and corresponding devices.
Answer:

Forms of energy Devices based on this type of energy
(1) Electric Electric iron, Geyser, Heater, Oven, Refrigerator, Fans, Lights, Elevator.
(2) Mechanical Sewing machine, Car, Bicycle, Different machines.
(3) Thermal Chulha, Furnace, Steam engine
(4) Solar Solar cooker, Solar heater.

Question 2.
Let’s Think: (Text Book Page No. 52)
Which electricity generation process is eco-friendly and which not?
Answer:
Electricity generated through solar energy and wind energy are truly eco-friendly. Though it is said that hydroelectricity is non-polluting and eco-friendly, it is not true. Hydroelectric project cause destruction of biodiversity and displacement of the local people. Thermal energy, nuclear energy and energy obtained through natural gas are not at all eco-friendly.

Question 3.
Find out: (Text Book Page No. 55)
What is lake tapping? Why it takes place?
Answer:
A lake tap involves excavating a tunnel at the bottom of the lake. Dynamites are planted therein and blasted carefully. The water flows with greater force through the tunnel after such blasting is done. This increased flow of water is then driven to the hydroelectric power generation plant for increased electricity production. This technique is done to establish waterways for hydropower, for making drinking water available, for irrigation water purposes and also for the landing of oil and gas pipes from offshore fields.

Question 4.
Get information: (Text Book Page No. 56)
Get information about major wind-power stations in India and their capacity. Make a table of their location, state and their power generation capacity in MW.
Answer:

Location State Power generation capacity in MW
Muppandal, Kanyakumari Tamil Nadu 7,684.31
Dhule, Satara, Sangli, Dhalgaon Maharashtra 4,664.08
Bhuj Gujarat 4,227.31
Dangiri Wind Farm Jaisalmer Wind Park Rajasthan 4,123.35
Jogmatti BSES Karnataka 3,082.45
Bhopal at Nagda Hills near Dewas Madhya Pradesh 2,288.60
Tirumala hills Andhra Pradesh 1,866.35
Telangana 98.70
Kanjikode in Palakkad Kerala 43.50
Others 4.30
Total 28, 082.95

Question 5.
Find out: (Text Book Page No. 58)
Gather information about major solar photovoltaic power generating plants and their capacity in India.
Answer:
List of solar power stations:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 28a
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy 29

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 5 Towards Green Energy

Project:

Project 1.
Let’s Discuss: (Text Book Page No. 47)
Make a list of the work that we do in our day-to-day life using energy. Which forms of energy do we use to do this work? Discuss with your friends.

Project 2.
Compare: (Text Book Page No. 51)
Observe the schematic of thermal power plant and the nuclear power plant. Discuss what are the similarities and differences between the two.

Project 3.
Use of ICT: (Text Book Page No. 49)
Prepare a presentation about thermal power plant using computerized presentation, animation, video, pictures, etc. Send it to others and upload on YouTube.

Project 4.
Internet is my friend: (Text Book Page No. 51)
Complete the following table for some important nuclear power plants in India.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Balbharti Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 1.
Complete the following diagram.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution 1
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution 2

Question 2.
Read the following statements and justify same in your own words with the help of suituble examples.
a. Human evolution began approximately 7 crore years ago.
Answer:

  • Approximately around 7 crore years back the ice age began on the earth. In such conditions, dinosaurs became extinct. The evolution and diversity of mammals started during this time. Due to change in climate the forest cover also declined rapidly.
  • Ancestors of monkey-like animals were Lemur like animals which evolved during this time period.
  • The tails of these monkey-like creatures started vanishing very gradually around 4 crore years ago.
  • The body and brain both increased in volume forming first ape like animals. The monkey like ancestors gave rise to two evolutionary links to apes and human like animals.
  • Later, the human evolution took place by changes in the brain volume, the ability to walk upright, excessive use of hand for manipulations.
  • This journey of human evolution began 7 crore years ago. But the true wise and intelligent man arose around 50,000 years ago.

b. Geographical and reproductive isolation of organisms gradually leads to speciation.
Answer:

  • Every species survives in specific geographical conditions. The requirements of food and habitat, is specific for each species. Their reproductive ability and period is also different.
  • Therefore, the individuals from one species cannot reproduce with individuals from other species.
  • When they are separated by a distance or geographical barriers they are said to be isolated geographically.
  • When they cannot reproduce with each other, they are said to be isolated reproductively.
  • The ancestor species of both these subspecies may be the same but due to isolation over a very long-time duration, there is genetic variation between the two. Therefore, the isolation leads to speciation.

c. Study of fossils is an important aspect of study of evolution.
Answer:
Answer:

  • Fossils offer palaeontological evidence for the evolutionary process.
  • Due to some natural calamities the organisms get buried during ancient times.
  • The impressions and remnants of such organisms remain preserved underground. The hot lava also traps some organisms or their impressions. All such formations form fossils.
  • Study of fossils help the researcher to understand the characteristics of the organisms that existed in the past.
  • Carbon dating method also helps in finding out exact age of the fossil. According to the structure of earth’s crust the fossils are obtained at specific depths.
  • The oldest ones are obtained at the depth while the relatively recent ones occupy the upper surface. Thus fossils of invertebrates were seen in very old Palaeozoic era. Later were seen fossils of Pisces, Amphibia and Reptilia. The Mesozoic era was dominated by reptiles while Coenozoic era showed presence of mammals.
  • In this way, study of fossils unfold the evolutionary secrets.

d. There is evidences of fatal Science among chordates.
[Please read the above question as: Among different chordates there are embryological evidences.]
Answer:

  • Very young embryos of fish, amphibians, reptiles, birds and mammals show quite similar structure in the early stages.
  • As the further growth takes place, they acquire different patterns.
  • The initial similarity between the vertebrate embryos is an evidence that during evolution, there was a common ancestor for all the vertebrate classes.
  • This is called embryological evidence for vertebrate evolution.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 3.
complete the statements by choosing correct options from bracket.
(Genes, Mutation, Translocation, Transcription, Gradual development, Appendix)
a. The causality behind the sudden changes was understood due to ………… principle of Hugo de Vries.
Answer:
Mutation

b. The proof for the fact that protein synthesis occurs through ……….. was given by George Beadle and Edward Tatum.
Answer:
Genes

c. Transfer of information from molecule of DNA to mRNA is called as …………… process.
Answer:
Transcription

d. Evolution means ………….
Answer:
Gradual development

e. Vestigial organ ……….. present in human body is proof of evolution.
Answer:
Appendix

Question 4.
Write short notes based upon the information known to you.
a. Lamarckism.
Answer:
(1) Lamarckism consists of two theories which were proposed by Jean Baptiste Lamarck. These are as follows: (a) Use and disuse of the organs (b) Inheritance of acquired characters.
(2) In theory of use and disuse of organs, Lamarck says : The characters of organs develop because specific activities that the organisms perform. If such organ is not used it gets degenerated. Thus the morphological changes take place due to activities or inactivity of a particular organism.
(3) To emphasise this theory, he quoted following examples. Due to constant extension of neck to eat foliage from the top of the trees, giraffe’s neck became long. Similarly blacksmith has strong arms due to constant work. Flightless ostrich and emu did not fly and hence their wings became useless. Aquatic birds like swan and duck made their feet suitable for swimming by living in water. Snake lost limbs as it tried burrowing mode.
(4) Such acquired characters are passed from one parental generation to the offspring. This is called inheritance of acquired characters.
(5) The theory of inheritance of acquired characters is not accepted as such transmission of acquired character does not take place. Only genetic characters are transmitted.

b. Darwin’s theory of natural selection.
Answer:

  • Charles Darwin proposed the theory of natural selection after making many observations on different specimens. He published a concept ‘Survival of the fittest’.
  • Darwin explains this concept as follows: All the organisms reproduce prolifically. Therefore, there is always a competition for food, mate, etc. Only adaptations for sustaining this struggle.
  • Natural selection plays important role by selecting only those organisms which are fit to live. Those that do not have better adaptations, perish. Selected sustaining organisms then perform reproduction and form new species in a very long period of time.
  • Darwin published his views in the book titled ‘Origin of Species’.

c. Embryology.
Answer:

  • Embryology is the study of developing embryos.
  • These embryos in their initial stages are very similar to each other.
  • These similarities decrease later in the development.
  • This similarity in initial stages indicate that these vertebrates have originated from a common ancestor.
  • In evolutionary science, comparative study of embryos of various vertebrates provide evidence for evolution.

d. Evolution.
Answer:

  • The sequential changes in the groups of living organisms that take place very gradually is called evolution.
  • Evolution is also described as the formation of new species due to natural selection.
  • The process of evolution takes millions of years for development and speciation of different organisms.
  • Changes in stars and planets in space and the changes in biosphere occurring on the Earth are all included under study of evolution.
  • Due to evolution organisms become fit, biodiversity is increased, and new species are created.
  • Different scientists have put forth theories to explain the process of evolution. Among these Charles Darwin’s theory of natural selection and speciation is accepted worldwide.

e. Connecting link.
Answer:
Some living organisms possess some characters in them which are the distinctive features of different groups or phyla. Such individuals connect these two groups by sharing the characters of both and hence they are known as connective links.

Examples: (1) Peripatus: Peripatus is the connecting link between Annelida and Arthropoda. It shows characters of both animal phyla. Like annelid worm, it shows segmented body, thin cuticle and parapodia. Like an arthropod, it shows open circulatory system and tracheal system for respiration.
(2) Duck Billed platypus: This is a connecting link between reptiles and mammals. Like reptiles it lays eggs but like mammals it has mammary glands and hairy skin.
(3) Lung fish: Lung fish is a connecting link between fishes and amphibians. Though a fish, it shows lungs for respiration as in amphibian animals.
(4) Connecting links indicate the direction and hierarchy of evolution.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 5.
Define heredity. Explain the mechanism of hereditary changes.
Answer:
(1) Heredity: Heredity is the process by which the biological characters from parental generation are transmitted to the next generation through genes.

(2) The mechanism of hereditary changes:

  • Mutation: Sudden change in the parental DNA can cause mutations. This results into changes in the hereditary characters.
  • At the time of meiosis, the crossing over takes place. This creates new recombination of the genetic information. Therefore, the haploid gametes produced carry changed hereditary characters.

Question 6.
Define vestigial organs. Write names of some vestigial organs in human body and write the names of those animals in whom same organs are functional.
Answer:

  • Vestigial organs are degenerated or underdeveloped organs of organisms which do not perform any function.
  • According to the principle of natural selection, such organs are on the verge of disappearance. But it takes many millions of years for its complete vanishing.
  • The vestigial organs in one animal may be of use but to other kind of the animal as they still perform regular functions.
  • Appendix is vestigial for humans, it does not perform any function but in ruminant animals it is concerned with digestion.
  • Ear muscles are vestigial for us but in monkeys and cattle they are functional.
  • Names of vestigial organs in human body-Appendix, tail-bone or coccyx, wisdom teeth and body hair.

Question 7.
Answer the following questions.
a. How are the hereditary changes responsible for evolution?
Answer:
Hereditary characters are transmitted from parental generation to the offspring. These characters are maintained through inheritance. But the genes which are beneficial for the organisms in helping them to adapt to the environment are transmitted to the next generations in a greater proportion. This happens due to natural selection.

The process of evolution happens at a very slow pace. The favourable genes are preserved in the species as they bring about better survival of the individuals. Such individual reproduces more efficiently and evolve. The individuals with unfavourable genes are not selected by nature and are thus removed from the population through natural death. The fuel for evolution is thus truly supplied by the hereditary changes.

b. Explain the process of formation of complex proteins.
Answer:
The proteins are synthesised in following steps, viz. transcription, translation and translocation. Protein synthesis takes place according to the sequence of nucleotides present on the DNA molecule with the help of RNA molecules. This is known as central dogma of protein synthesis.

1. Transcription: In the process of transcription, mRNA is produced as per the nucleotide sequence on the DNA. For this the two strands DNA are separated. Only one strand participates in the formation of mRNA. The sequence of nucleotides which is complementary to that of present on DNA is copied on mRNA. Instead of thymine present in DNA, uracil is added on the mRNA. Transcription takes place in nucleus but the mRNA leaves nucleus, carries the genetic code and enters the cytoplasm. This genetic code is always in triplet form arid hence is known as triplet codon. The code for each amino acid always consists of three nucleotides.

2. Translation: Each mRNA may carry thousands of codons. But each codon is specific for only one amino acid. The tRNA molecule brings the required amino acid as per the code present on mRNA. There is anticodon on each tRNA which is complementary to the codon on mRNA. This process is known as translation.

3. Translocation: In translocation, the ribosome keeps on moving from one end of mRNA molecule to other end by distance of one triplet codon. While this process is taking place, rRNA, helps in joining the amino acids together by peptide bonds. The peptide chains later come together to form complex protein molecules.

c. Explain the theory of evolution and mention the proof supporting it.
Answer:
1. Theory of evolution:

  • According to the theory of evolution, first living material was in the form of protoplasm which was formed in ocean.
  • Gradually, it gave rise to unicellular organisms. Changes took place in these unicellular organisms which made them evolve into larger and more complex organisms.
  • All evolutionary changes were very slow and gradual taking about 300 crore years to happen.
  • Different types of organisms were developed as the changes and development that occurred in living organisms wefts all round and multi-dimensional.
  • Hence, this overall process of evolution is called organizational and progressive.
  • Variety of plants and animals developed from the ancestors having different structural and functional organization during the process of evolution.

2. Proof here means evidences of evolution.
These evidences are as follows:

  • Morphological evidences
  • Anatomical evidences
  • Vestigial organs
  • Palaentological evidences
  • Connecting links
  • Embryological evidences.

d. Explain with suitable examples importance of anatomical evidences in evolution. (July 2019)
Answer:

  • There are similarities in the structure and anatomy of different animal groups. E.g. human hand, forelimb of bull, patagium of bat and flipper of whale are all similar in their internal anatomy. There is similarity in the bones and joints of all these specimens.
  • External morphology does not show any similarity. Use of each of the organ is also different in different animals. Structurally, they may not be related.
  • However, the similarities in the anatomy is an evidence that they may have a common ancestor.
  • In this way, the anatomical evidence throws light on the process of evolution.

e. Define fossil. Explain importance of fossils as proof of evolution.
Answer:

  • Fossils offer palaeontological evidence for the evolutionary process.
  • Due to some natural calamities the organisms get buried during ancient times.
  • The impressions and remnants of such organisms remain preserved underground. The hot lava also traps some organisms or their impressions. All such formations form fossils.
  • Study of fossils help the researcher to understand the characteristics of the organisms that existed in the.past.
  • Carbon dating method also helps in finding out exact age of the fossil. According to the structure of earth’s crust the fossils are obtained at specific depths.
  • The oldest ones are obtained at the depth while the relatively recent ones occupy the upper surface. Thus fossils of invertebrates were seen in very old Palaeozoic era. Later were seen fossils of Pisces, Amphibia and Reptilia. The Mesozoic era was dominated by reptiles while Coenozoic era showed presence of mammals.
  • In this way, study of fossils unfold the evolutionary secrets.

f. Write evolutionary history of modern man.
Answer:
(1) Ancestors of humans developed from animals which resembled lemur like animals.
(2) Around seven crore years ago, monkey-like animals evolved from some of these lemur like animals.
(3) Then after about 4 crore years ago, in Africa the tails of these monkey like creatures very gradually disappeared.
(4) Simultaneously, there was enlargement in their body and brain volume too. The hands also improved and were provided with opposable thumb. In this way, ape-like animals were evolved.
(5) These ape-like animals independently gave rise to two lines of evolution, one giving rise to apes like gibbon and orangutan in the South and North-East Asia and gorilla and chimpanzee which stayed in Africa around 2.5 crores of years ago.
(6) The other line of evolution gave rise to human like animals around 2 crore years ago.
(7) The climate became dry and this resulted into reduction of forest cover. This made arboreal apes to descend on the land and start terrestrial mode.
(8) Due to this, there were changes in the pefvic
girdle and vertebral column. The hands were also freed from locomotion and thus they became more manipulative.
(9) Later, journey of hominoid species started from around 2 crores years ago. The first record of human like animal is ‘Ramapithecus’ ape from East Africa.
(10) Ramapithecus → Australopithecus → Neanderthal man → Cro-Magnon are the important steps in human evolution.
(11) Neanderthal man was said to be the first wise man. The increasing growth of brain made man more and more intelligent and thinking animal.
(12) Later, more than biological evolution, it was cultural evolution, when man started agriculture, animal , rearing. There was development of civilizations, arts and science etc. About 200 years ago there were industrial inventions and thus man now rules the earth.

Project:

Project 1.
Make a presentation on human evolution using various computer softwares and arrange a group disscussion over it in the class room.

Project 2.
Read the book – ‘Pruthvivur Manus Uparcich’ written by Late Dr. Sureshchandra Nadkarni and note your opinion on evolution.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Can you recall? (Text Book Page No. 1)

Question 1.
Which component of the cellular nucleus of living organisms carries hereditary characters?
Answer:
The chromosomes made up of nucleic acids and proteins, present in the nucleus of the cell are the components that carry hereditary characters in living organisms.

Question 2.
What do we call the process of transfer of physical and mental characters from parents to the progeny?
Answer:
The process of transfer of physical and mental characters from parents to the progeny is called inheritance or heredity.

Question 3.
Which are the components of the DNA molecule?
Answer:
DNA molecule is made up of two helical strands consisting of deoxyribose sugar, phosphoric acid and pairs of nitrogenous bases. These three together is called a nucleotide.

Choose the correct alternative and write its alphabet against the sub-question number:

Question 1.
Darwin has published a book titled …………..
(a) Natural selection
(b) Mutation
(c) Fall of a sparrow
(d) Origin of species
Answer:
(d) Origin of species

Question 2.
The …………. man evolved about 50 thousand years ago.
(a) Cro Magnon
(b) Neanderthal
(c) Java man
(d) Ramapithecus
Answer:
(a) Cro Magnon

Question 3.
About 10 thousand years ago, ………….. started to practise agriculture.
(a) Gorilla
(b) wise man
(c) Ramapithecus
(d) Australopithecus
Answer:
(b) wise man

Question 4.
………………. can be considered as the first example of wise-man.
(a) Australopithecus
(b) Ramapithecus
(c) Cro Magnon
(d) Neanderthal man
Answer:
(d) Neanderthal man

Question 5.
………. is a connecting link between Annelida and Arthropoda. (March 2019)
(a) Duck-billed platypus
(b) Peripatus
(c) Lung fish
(d) Whale
Answer:
(b) Peripatus

Question 6.
………… years ago human brain was sufficiently evolved to call him wise man.
(a) 50,000
(b) 30,000
(c) 20,000
(d) 10,000
Answer:
(a) 50,000

Question 7.
The process by which the gene in the nucleotide suddenly changes its position is called ………. (Board’s Model Activity Sheet)
(a) translation
(b) translocation
(c) mutation
(d) transcription
Answer:
(c) mutation

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 8.
…………. is not the vestigial organ in the human body. (Board’s Model Activity Sheet)
(a) appendix
(b) Coccyx
(c) Canine
(d) Wisdom teeth
Answer:
(c) Canine

Write whether the following statements are true or false with proper justification for your answer:

Question 1.
It takes thousands of years for a useful structure to disappear.
Answer:
False. (The useful structures of the body do not disappear. The functioning of the body is easier due to such organs. It takes thousands of years for a functionless organ to disappear.)

Question 2.
Dr. Har Govind Khorana was awarded Nobel prize for his invention and publication in the journal Radio carbon.
Answer:
False. (Willard Libby was awarded Nobel prize for his invention and publication in the journal Radio carbon.)

Question 3.
Mesozoic era was dominated by variety of mammals.
Answer:
False. (Mesozoic era dominated by variety of reptiles.)

Question 4.
It seems that invertebrates have been slowly originated from vertebrates.
Answer:
False. (Vertebrates have been slowly originated from invertebrates in course of evolution. The primitive type of organisms always give rise to complex life forms. The invertebrates from Palaeozoic era gradually gave rise to vertebrates.)

Question 5.
The decaying process of C-12 occurs continuously from the dead remains of living organisms.
Answer:
False. (The decaying process of C-14 occurs continuously from the dead remains of living organisms. C-12 is not radioactive and hence it does not show decaying process.)

Question 6.
The theory of natural selection which mentions ‘Survival of fittest’ is given by Lamarck.
Answer:
False. (The theory of natural selection which mentions ‘Survival of fittest’ is given by Darwin.)

Question 7.
Changes acquired during life time are transferred to next generation.
Answer:
False. (Changes acquired during life time are not heritable. They are not transferred to next generation. Only the genes are transferred to the next generation.)

Question 8.
Each species grows in specific geographical conditions and has specific food, habitat, reproductive ability and period.
Answer:
True. (Each species has specifically evolved characters due to evolution and speciation.)

Question 9.
Humans walking with upright posture were confined to Africa only during prehistoric period.
Answer:
False. (Humans walking upright existed in Africa and China, Indonesia of Asian continent too.)

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 10.
Industrial society was established about 200 years ago.
Answer:
True. (After the development and specialization of human brain, he started indulging in science and technology. Before; this period the idea of industrialization was not existing.)

Match the columns:

Question 1.

Scientist Discovery
(1) Johann Gregor Mendel (a) Chromosomes of grasshopper
(2) Hugo de Vries (b) DNA is genetic material
(c) Pioneer of the modern genetics
(d) Mutational theory

Answer:
(1) Johann Gregor Mendel – Pioneer of the modern genetics.
(2) Hugo de Vries – Mutational theory.

Question 2.

Scientist Discovery
(1) Walter, Sutton (a) Chromosomes of grasshopper
(2) Mclyn McCarthy (b) DNA is genetic material
(c) Pioneer of the modern genetics
(d) Mutational theory

Answer:
(1) Walter, Sutton – Chromosomes of grasshopper.
(2) Mclyn McCarthy – DNA is genetic material.

Question 3.

Evidences of evolution Examples
(1) Morphological evidences (a) Duck billed Platypus and Peripatus
(2) Anatomical evidences (b) Remnants and impressions
(c) Human hand and fore limb of bull
(d) Shape and venation of leaf

Answer:
(1) Morphological evidences – Shape and venation of leaf.
(2) Anatomical evidences – Human hand and fore limb of bull.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 4.

Evidences of evolution Examples
(1) Palaeontological evidences (a) Duck billed Platypus and Peripatus
(2) Connecting links (b) Remnants and impressions
(c) Coccyx and wisdom tooth
(d) Human hand and fore limb of cat

Answer:
(1) Palaeontological evidences – Remnants and impressions.
(2) Connecting links – Duck billed Platypus and Peripatus.

Find the odd one out:

Question 1.
Transcription, Translation, Translocation, Mutation
Answer:
Mutation. (All others are stages of protein synthesis.)

Question 2.
Bones of the hands, structure of nostrils, position of eyes, structure of ear pinnae
Answer:
Bones of the hands. (All the others are morphological evidences.)

Question 3.
Venation, Shape of seeds, Leaf petiole, Leaf shape
Answer:
Shape of seeds. (All the others are morphological evidences in plants.)

Question 4.
Human hand, wing of cockroach, forelimb of bull, flipper of whale
Answer:
Wing of cockroach. (All others are anatomical evidences, they are homologous organs.)

Identify the correlation between the first two words and suggest the suitable words in the fourth place:

Question 1.
mRNA : Transcription :: tRNA :…………
Answer:
Translation

Question 2.
Peripatus : Connecting link :: Appendix :……….
Answer:
Vestigial organs

Question 3.
Open circulatory system : Arthropods :: Thin cuticle and parapodia :………..
Answer:
Annelida

Question 4.
Between Annelida and Arthropoda : Peripatus ::……….: Lungfish
Answer:
Pisces/Fish and Amphibia

Question 5.
Theory of natural selection : Charles Robert Darwin :: Theory of inheritance of acquired characters :…………
Answer:
Jean Baptiste Lamarck

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 6.
Survival of fittest : Darwin :: Acquired characters :……….
Answer:
Lamark

Question 7.
Wisdom teeth : Vestigial organs :: Lungfish :………..
Answer:
Connecting link.

Define the following:

Question 1.
Heredity.
Answer:
The transfer of biological characters from one generation to another through genes is called heredity.

Question 2.
Transcription.
Answer:

Question 3.
Translation.
Answer:
The process of bringing tRNA possessing anticodon that is complementary to the codon on mRNA for protein synthesis is called translation.

Question 4.
Translocation.
Answer:
The process of movement of the ribosome from one end of mRNA to other end by the distance of one triplet codon is called translocation.

Question 5.
Mutation.
Answer:
Sudden and drastic change that occurs in the genetic material is called mutation.

Question 6.
Species.
Answer:
The group of organisms that cap produce fertile individuals through natural reproduction is called a species.

Name the following:

Question 1.
Three Scientists who proved that except viruses, all living organisms have DNA as genetic material.
Answer:
Oswald Avery, Mclyn McCarthy and Colin MacLeod.

Question 2.
Genetic disorder caused due to mutation:
Answer:
Sickle cell anaemia.

Question 3.
Fish that can breathe with help of lungs:
Answer:
Lung fish.

Question 4.
Vestigial organs in human beings:
Answer:
Appendix, tail-bone or coccyx, wisdom teeth and body hair.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 5.
Important stages in the journey of human evolution:
Answer:

  • Animals like Lemur
  • Egyptopithecus
  • Dryopithecus
  • Ramapithecus
  • Australopithecus
  • Skilled Human
  • Homo erectus i.e. Man with erect posture
  • Neanderthal man
  • Cro-Magnon man.

Distinguish between the following:

Question 1.
Transcription and Translation.
Answer:
Transcription:

  1. In the process of transcription, the sequence of nucleotides present on the DNA molecule is copied
    and carried to the cytoplasm by mRNA.
  2. The process of transcription takes place in nucleus.
  3. During transcription, RNA is produced from DNA.
  4. Only mRNA takes part in transcription.

Translation:

  1. In the process of translation, the specific amino acids are picked up according to the codons brought by mRNA.
  2. The process of translation takes place in ribosomes located in cytoplasm.
  3. During translation, proteins are produced with the help of RNA.
  4. mRNA, tRNA and rRNA take part in translation.

Question 2.
Ape and Human.
Answer:
Ape:

  1. Brain of the apes is smaller in size.
  2. Ape cannot walk upright.
  3. Ape is less intelligent as compared to human.
  4. Apes are arboreal in their habitat and they spend more time on the trees.
  5. The forelimbs of ape are longer than the hind limbs.

Human:

  1. Brain of humans is larger in size.
  2. Humans can walk upright.
  3. Human is considered to be the most intelligent animal.
  4. Humans are terrestrial in their habitat. They cannot stay on the trees.
  5. The forelimbs of humans are shorter than the hind limbs.

Give scientific reasons:

Question 1.
Some of the characters of parents are seen in their offspring.
Answer:

  • The parental genes are transferred to their progeny through male and female gametes.
  • These genes carry hereditary characters.
  • Since they are transmitted from the parents to their offspring, one can see the parental characters in their offspring.

Question 2.
Darwin’s work on evolution has been a milestone.
Answer:
(1) Darwin has proposed two very important theories of evolution, viz. Theory of natural selection and Theory of origin of species.
(2) The evolution has taken place on the earth for last many crores of years.
(3) The exact nature and process of these evolutionary changes become clear after studying Darwinism. (4) The observations made by Darwin at that time are now tested according to the modern development in science and are found to be correct. Thus, his work is said to be a milestone.

Question 3.
Peripatus is said to be a connecting link between Annelida and Arthropoda.
Answer:

  • Peripatus shows segmented body, thin cuticle, and parapodia-like organs.
  • These characters are typical of Annelids.
  • Similarly, it also shows tracheal respiration and open circulatory system which is a characteristic feature of Arthropods.
  • Since Peripatus shares both these characters, it is said to be a connecting link between j Annelida and Arthropoda.

Question 4.
Vertebrates have been slowly originated from invertebrates.
Answer:

  • When the carbon dating method was used to assess the age of fossils, it was understood that invertebrates were present on the earth much before the vertebrates.
  • The fossils of invertebrates are present in lower layers of earth’s strata.
  • They were seen in Palaeozoic era of geological time period. Vertebrates dominated during Coenozoic era.
  • Their fossils are seen in the upper strata of the earth’s crust.
  • The structural complexity also increased in vertebrates. All these facts indicate that Vertebrates have slowly originated from invertebrates.

Question 5.
During human evolution the hands became available for use.
Answer:

  • During human evolution, the climate of earth started becoming dry.
  • This resulted in loss of forest cover.
  • The apes which were arboreal on the trees thus descended and started walking on land.
  • The lumbar bones underwent change and the apes started walking upright on the grasslands.
  • The vertebral column also underwent change. Due to upright posture the forelimbs were freed from locomotion.
  • The legs started bearing the weight of the body and the hands became available for use.

Read the following statements and justify the same in your own words with the help of suitable examples:

Question 1.
Geographical and reproductive isolation of organisms gradually leads to speciation.
Answer:

  • Every species survives in specific geographical conditions. The requirements of food and habitat, is specific for each species. Their reproductive ability and period is also different.
  • Therefore, the individuals from one species cannot reproduce with individuals from other species.
  • When they are separated by a distance or geographical barriers they are said to be isolated geographically.
  • When they cannot reproduce with each other, they are said to be isolated reproductively.
  • The ancestor species of both these subspecies may be the same but due to isolation over a very long-time duration, there is genetic variation between the two. Therefore, the isolation leads to speciation.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 2.
Study of fossils is an important aspect of study of evolution.
Answer:
(1) Fossils offer palaeontological evidence for the evolutionary process.
(2) Due to some natural calamities the organisms get buried during ancient times.
(3) The impressions and remnants of such organisms remain preserved underground. The hot lava also traps some organisms or their impressions. All such formations form fossils.
(4) Study of fossils help the researcher to understand the characteristics of the organisms that existed in the.past.
(5) Carbon dating method also helps in finding out exact age of the fossil. According to the structure of earth’s crust the fossils are obtained at specific depths.
(6) The oldest ones are obtained at the depth while the relatively recent ones occupy the upper surface. Thus fossils of invertebrates were seen in very old Palaeozoic era. Later were seen fossils of Pisces, Amphibia and Reptilia. The Mesozoic era was dominated by reptiles while Coenozoic era showed presence of mammals.
(7) In this way, study of fossils unfold the evolutionary secrets.

Question 3.
There is evidences of fatal Science among chordates.
[Please read the above question as: Among different chordates there are embryological evidences.]
Answer:

  • Very young embryos of fish, amphibians, reptiles, birds and mammals show quite similar structure in the early stages.
  • As the further growth takes place, they acquire different patterns.
  • The initial similarity between the vertebrate embryos is an evidence that during evolution, there was a common ancestor for all the vertebrate classes.
  • This is called embryological evidence for vertebrate evolution.

Question 4.
Human evolution began approximately 7 crore years ago.
Answer:

  • Approximately around 7 crore years back the ice age began on the earth. In such conditions, dinosaurs became extinct. The evolution and diversity of mammals started during this time. Due to change in climate the forest cover also declined rapidly.
  • Ancestors of monkey-like animals were Lemur like animals which evolved during this time period.
  • The tails of these monkey-like creatures started vanishing very gradually around 4 crore years ago.
  • The body and brain both increased in volume forming first ape like animals. The monkey like ancestors gave rise to two evolutionary links to apes and human like animals.
  • Later, the human evolution took place by changes in the brain volume, the ability to walk upright, excessive use of hand for manipulations.
  • This journey of human evolution began 7 crore years ago. But the true wise and intelligent man arose around 50,000 years ago.

Answer the following questions:

Question 1.
Answer the following questions: (March 2019)
(a) What do you mean by central dogma?
Answer:
Information about protein synthesis is present in DNA. As per this information, proteins are produced by DNA through RNA molecules. This is called central dogma.

(b) What is transcription?
Answer:
The process of synthesis of mRNA as per the nucleotide sequence present in DNA is called transcription. The nucleotide sequence on mRNA is complimentary to that of the single DNA strand used in synthesis. Instead of thymine, mRNA possesses uracil.

(c) What is meant by triplet codon?
Answer:
The code for each amino acids always consists of three nucleotides which is known as triplet codon.

Question 2.
Which animal is called a connecting link between Reptiles and Mammals? (Board’s Model Activity Sheet)
Answer:
Duck billed platypus is called a connecting link between Reptiles and Mammals.

Question 3.
In which way is science of heredity useful these days?
Answer:
The science of heredity is useful in the following ways:

  • For diagnosis of hereditary disorders.
  • For treatment of hereditary disorders
  • For prevention of hereditary disorders
  • For production of hybrid varieties of animals and plants
  • For using microbes in the industrial processes.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 4.
What is meant by carbon dating method?
Answer:
(1) Carbon dating method is technique used for determining the age of fossils.
(2) After the death of the organisms, their consumption of carbon stops. But right from that moment the decaying process of C-14 occurs continuously.
(3) This results in change in the ratio between C-14 and C-12. C-12 is not radioactive as C-14.
(4) Thus the time passed since the death of a plant or animal is calculated by measuring the radioactivity of C-14 and ratio of C-14 to C-12 present in their body.
(5) The points noted during carbon dating are:

  • The period after the organism has been dead.
  • The activity of C-14 in the dead organism.
  • Ratio between C-14 and C-12.

Question 5.
Answer the following questions:
(a) Describe briefly the Darwin’s theory of natural selection.
Answer:
Charles Darwin (1809-1882) proposed the theory of natural selection.
Theory of natural selection: ‘The survival of fittest’, i.e., organisms which are fit for survival, evolve while those that are not, perish. The natural selection thus acts to produce new species.

(b) What were the objections raised against Darwinism?
Answer:
Objections raised against Darwinism:

  1. There are other factors too for evolution and just not the Natural Selection.
  2. Arrival of useful and useless modifications were not explained by Darwin, though he said about the survival of the fittest.
  3. He has not given any explanation about slow changes and abrupt changes occurring during evolution.

(c) Which book was published by Darwin to explain this theory? (Board’s Model Activity Sheet)
Answer:
Charles Darwin wrote the book ‘Origin of Species’.

Question 6.
What were the objections raised against Darwinism?
Answer:
Some of the main objections raised against Darwinism are as follows:

  • There are other factors too for evolution and just not the Natural Selection.
  • Arrival of useful and useless modifications were not explained by Darwin, though he said about the survival of the fittest.
  • He has not given any explanation about slow changes and abrupt changes occurring during evolution.

Question 7.
Answer the following questions:
(a) Explain in brief-Lamarck’s principle of ‘use or disuse of organs’.
Answer:
The theory of use and disuse of organs says that the morphological characters of organism develop because of specific activities that the organisms perform. If some organ is not used it gets degenerated. If excessively, used, it develops. Thus, the morphological changes take place due to activities or non-working of a particular body parts in an organism.

(b) Give two examples.
Answer:
Due to constant extension of neck to eat foliage from the top of the trees, giraffe’s neck became long. Similarly, blacksmith has strong arms due to constant work. The flightless ostrich and emu did not fly and hence their wings became useless. Aquatic birds like swan and duck made their feet suitable for swimming by living in water. Snake lost limbs as it tried burrowing mode.

(c) What are acquired characters?
Answer:
Acquired characters are those characters which are obtained during the life time by any organism and passed on to next generations.

Write short notes:
(OR)
Write short notes based upon the information known to you:

Question 1.
Theory of evolution.
Answer:

  • According to the theory of evolution, first living material was in the form of protoplasm which was formed in ocean.
  • Gradually, it gave rise to unicellular organisms. Changes took place in these unicellular organisms which made them evolve into larger and more complex organisms.
  • All evolutionary changes were very slow and gradual taking about 300 crore years to happen.
  • Different types of organisms were developed as the changes and development that occurred in living organisms was all round and multi-dimensional.
  • Hence, this overall process of evolution is called organizational and progressive.
  • Variety of plants and animals developed from the ancestors having different structural and functional organization during the process of evolution.

By choosing appropriate words given in the bracket, complete the paragraph:

Question 1.
(translation, anticodon, tRNA, mRNA, amino acids, triplet codon, transcription, DNA)
The …….. formed in nucleus comes in cytoplasm. It brings in the coded message from DNA. The message contains the codes for amino acids. The code for each amino acid consists of three nucleotides. It is called as ‘………..’. Each mRNA is made up of thousands of triplet codons. As per the message on mRNA, ……… are supplied by the ………. For this purpose, tRNA has ‘…………’ having complementary sequence to the codon on mRNA. This is called ‘………..’.
Answer:
The mRNA formed in nucleus comes in cytoplasm. It brings in the coded message from DNA. The message contains the codes for amino acids. The code for each amino acid consists of three nucleotides. It is called as ‘triplet codon’. Each mRNA is made up of thousands of triplet codons. As per the message on mRNA, amino acids are supplied by the tRNA. For this purpose, tRNA has ‘anticodon’ having complementary sequence to the codon on mRNA. This is called ‘translation’.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 2.
(Cultural, agriculture, fire, brain, Cro-Magnon, Homo sapiens, Neanderthal)
Evolution of upright man continued in the direction of developing its ………. for the period of about 1 lakh years and meanwhile he discovered the ………. Brain of man, 50 thousand years ago had been sufficiently evolved to the extent that it could be considered as member of the species ………… Neanderthal man can be considered as the first example of wise-man. The ……….. man evolved about 50 thousand years ago and afterwards, this evolution had been faster than the earlier. About 10 thousand years ago, wise-man started to practise the ………. It started to rear the cattle-herds and established the cities. ………..development took place later.
Answer:
Evolution of upright man continued in the direction of developing its brain for the period of about 1 lakh years and meanwhile he discovered the fire. Brain of man 50 thousand years ago had been sufficiently evolved to the extent that it could be considered as member of the species Homo sapiens. Neanderthal man can be considered as the first example of wise-man. The Cro-Magnon man eyolved about 50 thousand years ago and afterwards, this evolution had been faster than the earlier. About 10 thousand years ago, wise-man started-to practise the agriculture. It started to rear the cattle-herds and established the cities. Cultural development took place later.

Read the paragraph and answer the questions given below:

With the help of RNA, the genes present in the form of DNA participate in the functioning of cell and thereby control the structure and functioning of the body. Information about protein synthesis is stored in the DNA and synthesis of appropriate proteins as per requirement is necessary for body. These proteins are synthesized by DNA through the RNA. This is called ‘Central Dogma’. mRNA is produced as per the sequence of nucleotides on DNA. Only one of the two strands of DNA is used in this process. The sequence of nucleotides in mRNA being produced is always complementary to the DNA strand used for synthesis. Besides, there is uracil in RNA instead of thymine of DNA. This process of RNA synthesis is called ‘transcription’.

Questions and Answers:

Question 1.
Which part of the cell control the structure and functioning of the body?
Answer:
Genes present in the form of DNA along with RNA control the structure and functioning of the body.

Question 2.
How is a specific protein synthesised in the cell?
Answer:
The information of protein synthesis is stored in the DNA which is utilised as per the requirement of the body. Later the proteins are synthesised by DNA through the RNA.

Question3.
What is the similarity between mRNA and DNA?
Answer:
The sequence of nucleotides on DNA is copied on mRNA. The nucleotide sequence on mRNA is thus complementary to DNA.

Question 4.
Give one difference between RNA and DNA.
Answer:
RNA has uracil instead of thymine which is present in DNA.

Question 5.
Define central dogma.
Answer:
Central dogma is the concept that proteins are synthesised by DNA through the RNA.

Diagram-based questions:

Question 1.
Observe the figure 1.3 of transcription given on page 9 in this chapter and answer the following questions:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution 3
(1) What is the sequence of nucleotides present on one strand of the DNA?
Answer:
A T G C A A T T

(2) According to the above sequence on DNA, what will be the transcribed sequence on the mRNA molecule?
Answer:
U A C G U U A A

(3) Which enzyme is taking part in the above process of transcription?
Answer:
RNA polymerase takes part in the process of transcription.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 2.
Observe the figure 1.5 of translation and translocation, given on page 9 this chapter and answer the following questions:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution 4
(1) Which is the initiation codon? Where is it present?
Answer:
AUG is the initiation codon, which is present on the mRNA.

(2) What are the types of RNA present inside the ribosome? Which triplet codon is present on it?
Answer:
There are two molecules of tRNA present inside the ribosome. The triplet codons present on them are UAC and AAG respectively.

(3) Which genetic code is present on mRNA that is leaving the nucleus? What must be the sequence on the DNA to have such code on mRNA?
Answer:
The mRNA that leaves the nucleus has genetic code: A U G U U C A A A
The genetic code on DNA therefore should be as follows: T A C A A G T T T

Question 3.
Observe the figure 1.6 given on page 10 from this chapter. Answer the following question based on your observations:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution 5
What is the significance of this figure from the viewpoint of evolution? Explain in brief.
Answer:
In the figure, the process of mutation is shown. The original nucleotide sequence of TGC is replaced by new mutated sequence GAT. The change in the nucleotide sequence will change the DNA.

This will result in the change in genes and then changing the hereditary characters. Due to such change in genes, the evolution proceeds. The mutation so formed can be minor or major. The greater the impact of the change, the evolution takes place rapidly. The mutation thereby produce recombinations leading to diversity.

Question 4.
Observe the picture and answer the following questions:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution 6
(1) Which evidence of evolution is shown in the picture?
Answer:
Embryological evidences of evolution are shown in this picture.

(2) What can be proven with this proof?
Answer:
The similarities in the initial embryonic stages of different vertebrates shows that there was a common origin of all of them. Thus embryological evidences prove that there was common vertebrate ancestor.

(3) Give one more example of evidence of evolution.
Answer:
Palaeontological evidences such as vestigial organs and connecting links are another examples of evolutionary evidences.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Question 5.
Which concept/theory do you remember after seeing this picture of Giraffes? Describe it in brief.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution 7
Answer:

  • The picture is based on the Lamarck’s principle of ‘use and disuse of organs’.
  • The morphological characters of organism develop because of specific activities that the organisms perform.
  • If some organ is not used it gets degenerated. If excessively used, it develops further.
  • Thus, the morphological changes take place due to activities or non-working of a particular body parts in an organism. Due to constant extension of neck to eat foliage from the top of the trees, giraffe’s neck became long.

Activity-based Questions:

Try this: (Text Book Page No. 4)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution 8
Observe the above images and note the similarities between given animal images and plant images.
Answer:
The above pictures of the animals show similarities such as structure of mouth, position of eyes, structure of nostrils and ear pinnae and body fur. In pictures of plants there are similarities in characters like leaf shape, leaf venation, leaf petiole, etc.
These above morphological evidences show that there may be a common ancestor for all of the species shown.

Observe and Discuss:

Question 1.
Observe the pictures given below. (Text Book Page No. 5)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution 9
Answer:
(1) Fossils offer palaeontological evidence for the evolutionary process.
(2) Due to some natural calamities the organisms get buried during ancient times.
(3) The impressions and remnants of such organisms remain preserved underground. The hot lava also traps some organisms or their impressions. All such formations form fossils.
(4) Study of fossils help the researcher to understand the characteristics of the organisms that existed in the.past.
(5) Carbon dating method also helps in finding out exact age of the fossil. According to the structure of earth’s crust the fossils are obtained at specific depths.
(6) The oldest ones are obtained at the depth while the relatively recent ones occupy the upper surface. Thus fossils of invertebrates were seen in very old Palaeozoic era. Later were seen fossils of Pisces, Amphibia and Reptilia. The Mesozoic era was dominated by reptiles while Coenozoic era showed presence of mammals.
(7) In this way, study of fossils unfold the evolutionary secrets.

Question 2.
Observe the pictures given and discuss the characters observed. (Text Book Page No. 6)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution 10
Answer:
Some living organisms possess some characters in them which are the distinctive features of different groups or phyla. Such individuals connect these two groups by sharing the characters of both and hence they are known as connective links.

Examples: (1) Peripatus: Peripatus is the connecting link between Annelida and Arthropoda. It shows characters of both animal phyla. Like annelid worm, it shows segmented body, thin cuticle and parapodia. Like an arthropod, it shows open circulatory system and tracheal system for respiration.
(2) Duck Billed platypus: This is a connecting link between reptiles and mammals. Like reptiles it lays eggs but like mammals it has mammary glands and hairy skin.
(3) Lung fish: Lung fish is a connecting link between fishes and amphibians. Though a fish, it shows lungs for respiration as in amphibian animals.
(4) Connecting links indicate the direction and hierarchy of evolution.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 1 Heredity and Evolution

Project: (Do it your self)

Project 1.
Internet is my friend: (Text Book Page No. 3)
Collect the information from the internet about Big-Bang theory related with the formation of stars and planets and present it in your class.

Project 2.
Use of ICT: (Text Book Page No. 4)
Collect the information of geological dating and present it in the classroom.

Project 3.
Use of ICT: (Text Book Page No. 5)
Find how the vestigial organs in certain animals are functional in others. Present the information in your class and send it to others.

Project 4.
Internet is my friend: (Text Book Page No. 8)
Collect the pictures and information of various species of monkeys from internet.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Balbharti Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Question 1.
Reorganize the following food chain. Describe the ecosystem to which it belongs.
Grasshopper – Snake – Paddy field – Eagle – Frog.
Answer:

  • Correct food chain: Paddy field → Grasshopper → Frog → Snake → Eagle.
  • Such food chain is seen in the terrestrial ecosystem. There are many biotic factors in the terrestrial ecosystem, such as insects, birds, mammals etc.
  • The above example mentions about paddy field, so it must be in vicinity of coastal lands. There is water logging in the paddy fields. Therefore, it offers a habitat to the frogs.
  • In the above example, paddy fields are producers in the ecosystem. The primary consumer is grasshopper. Secondary consumer is frog, tertiary consumer is snake and the apex consumer is eagle. On every trophic level the bacteria, fungi and some scavenging worms can act as the decomposers.
  • In this ecosystem. the solar energy is transferred from the paddy crops to eagle in a step wise food
    chain.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Question 2.
Explain the statement – ‘We have got this Earth planet on lease from our future generations and not as an ancestral property from our ancestors.’
Answer:

  • The earth was inhabited by older generations before us. We have replaced them.
  • But during their life time, they have created hazardous impact on the earth. The industrialization, the quest for more and more natural resources, wars fought, the construction activities such as dams, roads and bridges, extensive deforestation, etc. were their thoughtless activities.
  • All these activities were for development of mankind. But most of them have destroyed the delicate balance between the producers and different levels of consumers.
  • Due to ever increasing population of human beings there is shortage of food, clothing and shelter. To procure these basic needs, we have exploited many natural resources causing destruction of the earth’s natural ecosystem.
  • Now it is our turn to protect the earth as on the same planet the next generations have to survive. We have to hand over the ecosystems of the earth which are in perfect balance to the new generations.
  • The future generations need a good quality of air, water and land along with all other living organisms.
  • Due to problems like climate change, global warming, pollution, droughts, etc. the environment is impacted, thus in order to keep sustainability of earth, we have to remember that the earth has not been obtained only as ancestral property but we have to save it for future generations.

Question 3.
Write short notes.
a. Environmental conservation.
Answer:
Due to natural and man-made causes, there are many environmental problems on the earth. These problems affect the existence of various living organisms. In order to save these organisms and maintain the environmental balance, there is need for environmental conservation. If this is not done then there will not be any quality of life for the resident humans. For environmental conservation, the Government has formulated acts and rules. UN has established UNEP for the conservation programs.

The people’s participation in the conservation movement is essential. From school age, the environmental values are inculcated in the young minds. Conservation of environment is the social responsibility of everyone. Judicial use of natural resources conservation also way of environmental conservation.

b. Chipko Movement of Bishnoi.
Answer:
Chipko Movement of Bishnoi or Bishnoi Andolan:
Khejarli or Khejadli is a village in Rajasthan, where Bishnoi community is located. The name of the town is derived from Khejri trees.

The first event of Chipko Movement took place in Khejadli village in 1730 AD. In this village 363 Bishnois, led by Amrita Devi sacrificed their lives for protecting the trees of Khejri trees, which trees are considered as sacred by Bishnoi.

Amrita Devi said, “if a tree is saved even at the cost of one’s head, it’s worth it”. She was killed with the axes that were brought to chop off the trees. The three young daughters Asu, Ratna and Bhagubai also sacrificed their lives for trees.

83 Bishnoi villages came together and villagers sacrificed their lives after hearing about Amrita Devi’s sacrifice. Three hundred and sixty-three Bishnois were killed as they opposed the king. After realizing the mistake, the king ordered stoppage of the felling of trees. Honouring the courage of the Bishnoi community, the ruler of Jodhpur, Maharaja Abhay Singh, apologized. He issued a royal decree to protect trees and wild life.

Chipko movement of 20th century in Uttar Pradesh also followed the same pattern of embracing the trees and saving them from cutting.

c. Biodiversity.
Answer:
Biodiversity means the diverse life forms that inhabit any area. Biodiversity is seen due to variety of life forms and different ecosystems that lodge these organisms. In nature there is biodiversity on the three different levels, viz. genetic diversity, species diversity and ecosystem diversity. This means that there is diversity in the individuals belonging to the same specips due to genetic reasons, there is diversity among the different species of organisms and there is also a diversity in the ecosystems that are present in any region.

Due to development of mankind, the biodiversity is threatened. There are special efforts taken to restore the lost and threatened biodiversity. Some of these are establishing sanctuaries, National Parks, biodiversity hotspots and reserves etc. Certain endangered species are protected by carrying out conservation projects.

d. Sacred Groves.
Answer:
Sacred grove is the green patch of the forest which is conserved by local people in the name of God. It does not belong to forest department. It is like a sanctuary that is conserved by the common people and tribals in the area. It is rich in the biodiversity.

It is conserved as there is a faith that God or deity reside in the sacred grove. Hence in local language, they are known as Deorai. Due to this reason, people do not fell the trees. Also hunting of any wild life is not done here. More than 13000 sacred groves have been reported in India. Most of these are in Western Ghats in Maharashtra, Karnataka and Kerala. Also, in remaining parts of India sacred groves are reported. Role of sacred grove is tremendous in conserving the biodiversity.

e. Disaster and its management.
Answer:

  • To save human life from disasters. To help them for moving away from the place of disasters by rapid action.
  • To supply essential commodities to the affected people. This helps to reduce the gravity of disaster. People are given grains, water and clothes and other basic necessities under this objective.
  • To bring back the conditions of affected people to normalcy.
  • To rehabilitate the affected and displaced victims.
  • To think and execute the protective measures in order to develop capability to face the disasters in
    future.

Question 4.
How will you justify that overcoming the pollution is a powerful way of environmental management?
(OR)
“Solving the problem of pollution is an effective way of environmental management.” Justify the statement.
Answer:
1. Pollution is created only due to human activities. Air, water, soil, noise, radiation, thermal, light, plastic are different types of pollution.
2. All types of pollution affect environment and particularly threatening the survival of living organisms.
3. Pollution must be controlled in order to have good quality of the environment. E.g. When plastic is thrown anywhere, it causes pollution of the land, it clogs the rain water drains, it affects feeding of the animals. Plastic pollution can be completely stopped by us through proper management of plastic waste. By recycling or reusing, we can overcome the plastic pollution. This would be a powerful way of environmental management.
4. Similarly, when we reduce pollution of different types, we automatically help to regain the environmental health.

Question 5.
Which projects will you run in relation to environmental conservatioh? How?
(OR)
Write six strategies implemented by you for conservation of the environment.
Answer:
Initially, assessment of the environmental problems will be done. The nature and severity of these problems will be understood by detailed study of the same. Then the projects can be undertaken to combat these problems.

1. Tree plantation is one such easier project that can be undertaken to conserve environment. The further nurturing of the tree will also be our responsibility. While selecting the tree, the local and sturdy varieties will be selected. Such trees can survive in polluted environment too and even under the pressure of urbanization.

2. Solid waste management is another very important project that should be undertaken by every society, colony or school. Segregation of waste into dry and wet types and then its proper disposal will be taught to all the people in the neighbouring area.

3. To ban the plastic and make people aware about harmful effects of plastic is another very significant project.

4. Fossil fuels are non-renewable and polluting. Therefore, their use should be reduced as far as possible. Therefore, using bicycle, or walking down for shorter distances or using public transport systems are the better alternatives. The awareness drive about these facts will be taken up as a project.

5. To take care of stray animals, provide shelter, feeding endangered birds like sparrows and allowing them to survive with our support is also one of the essential act to conserve other species.

6. Attempts will be made for bringing awareness among minds of everyone. Such small acts can bring about major shift in the attitude of the people. This will certainly help in the environmental conservation.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Question 6.
Answer the following:
a. Write the factors affecting environment.
Answer:

  • The biotic and abiotic- factors affect the environment. Among abiotic factors, the physical and chemical factors can alter the conditions of the environment.
  • Abiotic factors are either natural or man-made.
  • The various interrelationships between different living organisms can also affect environment.
  • The natural disasters such as earthquake, forest fires, cyclones, cloud bursting, drought, etc. change the environment.
  • The human activities such as deforestation, urbanisation, constructions etc. cause permanent damage to the ecosystems. Due to man-made impact, there can be large scale changes in the environment.

b. Human beings have important place in environment.
Answer:

  • Man came last on the earth during evolution of animals. But due to his intelligence, imagination, critical thinking and memory, he made progress in all fields.
  • By virtue of these qualities he became the supreme.
  • All the natural resources on the earth were very rapidly exploited by man.
  • Under the pretext of technology and. development he made degradation of almost all¬natural ecosystems.
  • He never obeys the rules of nature.
  • Phenomena like pollution, urbanization, industrialization and deforestation are exclusively his creations.
  • Hunting and poaching other animals were his contribution to the extinction of many other animals.
  • Except man no other organism on the earth can change the ecosystems in such a drastic way. Therefore, it is rightly said that human beings have important place in environment.

c. Write the types and examples of biodiversity.
Answer:
Biodiversity is documented on the following three levels, viz. genetic diversity, species diversity and ecosystem diversity.
1. Genetic Diversity: Diversity seen among the organisms of same species due to genetic differences is called genetic diversity. E.g. The individual human beings are different from each other. No two animals or plants are exactly alike.

2. Species Diversity: The difference between the different species is the species diversity, e.g. All the species of plants, animals and microbes which are seen in any natural environment.

3. Ecosystem Diversity: In one region there may be different ecosystems, such diversity in the ecosystems is called ecosystem diversity. Ecosystems are natural or artificial. Every region shows different types of ecosystems such as aquatic, terrestrial, desert or forest ecosystems. Each ecosystem has its own habitats with resident flora and fauna.

d. How the biodiversity can be conserved?
Answer:
Biodiversity can be conserved by the following ways:

  • Protection of the rare species of plants and animals.
  • Creating habitats for the animals and plants by establishing National Parkland Sanctuaries.
  • Declaration of bioreserves, the areas which are protected through conservation.
  • Conservation projects for protecting special species.
  • Conservation of all flora and fauna.
  • Strict observance of the acts and rules.
  • Use of traditional knowledge and maintaining record of traditional knowledge.

e. What do we learn from the story of Jadav Molai Payeng? (Board’s Model Activity Sheet)
Answer:
Jadav Molai Payeng is a common man who was just a simple forest worker. But he has conscience about plants and tree plantations. He single-handedly planted thousands of trees. He converted a barren patch of land into forest which is spread over 1360 acres. For these plantations he continuously worked.

He has shown that a single determined person, can establish a new forest! We understand the values of
hard work, sincerity and devotion to the nature through the story of Jadav Molai Payeng. Even a common man can contribute a lot for the conservation and protection of the environment by learning the story of Payeng.

f. Write the names of biodiversity hot spots.
Answer:

  • In entire world, 34 highly sensitive biodiversity spots are reported.
  • These hotspots occupied 15.7% area of the Earth.
  • However, currently about 86% of the sensitive areas are already destroyed.
  • Now about 2.3% area of the Earth still has such sensitive biodiversity spots.
  • There are 1,50,000 plant species which are about 50% of the species in the world.
  • In India, out of 135 species of animals, 85 species are found in the jungles of eastern region.
  • There are about 1,500 endemic plant species in Western Ghats.
  • About 50,000 plants species out of the total plants in the world are said to be endemic.

g. Which are the reasons for endangering the many species of plants and animals? How can we save those diversity?
Answer:

  • The animals and plants species are endangered majorly due to man-made causes.
  • Some natural disasters like earthquakes, climate change, forest fires, drought and cyclones also affect the living organisms due to lack of food and water.
  • In man-made causes, hunting and poaching are the main reasons.
  • Also animal-human conflicts occur due to invasion of human settlements into the habitats of wild animals.
  • Construction of dams, roads, and colonies destroy the habitats of wild life.
  • Industrialization, urbanization and population explosion of humans are putting severe pressure on all the existing biodiversity.
  • In order to save and protect the biodiversity, many scientists and naturalists come together. A stretch of land is protected by declaring it as the sanctuary or a national park by the Government. Even the locals can protect it as a sacred grove.
  • Various acts and rules have been formulated to protect the organisms. The violators of such rules are punished accordingly.

Question 7.
What are the meanings of the following symbols? Write your role accordingly. (July ’19; Board’s Model Activity Sheet)
(OR)
What do these symbols indicate? Explain your opinion about those symbols.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 1
Answer:
1. The first symbol is for giving the message, “Reduce, reuse and recycle”. This is important mantra for the utilization of natural resources.
The second symbol gives the message about ‘Save water’.
The third symbol advocates the use of solar energy.

2. These symbols inculcate the importance of being eco-friendly. The first symbol is essential to maintain the natural resources by reusing and recycling them. As far as possible, one should reduce the excessive use of resources by preventing consumerism.

3. Water problems persist in many major cities and villages. In villages it results in drought like conditions. It also reflects into loss of agricultural produce. Therefore, the message about saving water or to make judicious use of water should be spread far and wide.

4. The solar energy is the renewable energy option which is very easily available in country like India. By using solar energy, we can replace the polluting and exhaustible fuels. Thereby, pollution will also be reduced.

Due to such symbols, important messages about environment conservation reach, us and we can change ourselves into more eeofriendly persons.

Project: (Do it your self)

Project 1.
Make a presentation on pollution of Gangci and Yamuna Rivers and effects of air pollution on Taimuhal.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Can you recall? (Text Book Page No. 36)

Question 1.
What is ecosystem? Which are its different components?
Answer:
In any environment, there are biotic and abiotic components. There are interactions among these components. All such interactions make an ecosystem.

The different components in the ecosystem are as follows:
Abiotic components : Air, water, soil, sunlight, temperature, humidity, etc.
Biotic components: All the types of living organisms, like bacteria, fungi, plants and animals.

Question 2.
Which are the types of consumers? What are the criteria for their classification?
Answer:
Primary consumers, secondary consumers, tertiary consumers or apex consumers are the different types of consumers. These types are according to the trophic level to which they belong.

Question 3.
What may be the relationship between lake and birds on tree?
Answer:
The birds on the tree depend on the aquatic organisms in the lake for their feeding. Birds stay on the trees which are in the vicinity of the lake, so that it is easier for them to capture fishes, frogs, etc. They must also be using the same lake water for drinking.

Question 4.
What is difference between food chain and food web?
Answer:
In every ecosystem, there are always interactions between producers, consumers and decomposers. This sequence of feeding interactions is called food chain. In every food chain there are links between four to five trophic levels constituting the producers, primary consumers, secondary consumers, tertiary consumers, etc. The links of food chain are in linear sequence. But food web is a complex network of many small food chains. In fact, food web is the collection of many small food chains. Thus, when many food chains are interwoven, they form food web.

Think and Answer! (Text Book Page No. 36)

Question 1.
Write the name and category of each of the component shown in picture.
Answer:
By utilizing the solar energy, the green plants perform photosynthesis. Thus, they are producers of the food chain. This food is consumed by the grasshopper. Thus, it is primary consumer. Frog is secondary consumer as its diet consists of insects like grasshopper. Snake is tertiary consumer as it feeds on frogs, while the hawk is apex consumer as it can kill the snake and feed on it. Last picture in the food chain is of fungi which are acting as decomposers. Few bacteria are shown in the picture, act on all the levels and bring about decomposition.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 2

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Question 2.
What is necessary to convert this picture into food web? Why?
Answer:
If this food chain has to be converted into a food web, there should be interactions between the different components. Any living organism can be prey to different predators. Moreover, a predator can also be a prey for other. Frog eats different insects. The same frog can be either eaten by snake or by hawk.

Use your brain power. (Text Book Page No. 40)

Question 1.
Why is it said that pollution control is important?
Answer:
The quantity of pollutants and severity of their effects on the ecosystem have to be taken into consideration constantly. The different methods of pollution control have to be used for checking the hazardous effects of pollution on the living organisms. Especially the impact of pollution on health of human beings is assessed from time to time.

The young children and senior citizens are affected to greater extent by the pollution. If the air and water required for the survival of the people is affected, then exercising the pollution control is to be done immediately. Thus, it is said that pollution control is important.

Enlist and discuss (Text Book Page No. 43)

Question 1.
Find the meaning of given symbols in relation to environment conservation. Make a list of other such symbols.
A. Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 3
Answer:
This symbol tells us to keep our wastes carefully. The garbage should not be strewn anywhere. But it should be properly managed. Waste if managed properly can be a wealth.
B. Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 4
Answer:
This symbol tells us to save electricity. If electricity is carefully used, we can save our natural resources. This message is given through this picture.
C. Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 5
Answer:
Use of bicycle means use of green energy. By riding on a bicycle we save on fuel and use our own muscular energy. It is the best eeofriendly, non polluting vehicle.

Observe and fill the information: (Text Book Page No. 8)

Question 1.
Observe the environment around you. Complete the following flow chart.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 6
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 7

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Complete the Chart: (Text Book Page No. 39)

Question 1.
We have studied the air pollution, water pollution and soil pollution in detail in earlier classes. Based on that, complete the following chart.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 8
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 9

Complete the Chart: (Text Book Page No. 40)

Question 1.
Now a day, we are observing the environmental degradation everywhere. Complete the flow chart given besides with the help of environment.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 10
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 11

(Text Book Page No. 43)

Question 1.
Where are such sacred groves in Maharashtra? Make a list and visit with your teachers.
Answer:
Sacred groves: Sacred groves form an important landscape feature in the deforested hill ranges of the Western Ghats. The felling of timber and the killing of animals in sacred groves is not allowed by the locals. It is considered as taboo.

In Maharashtra, sacred groves are found in tribal as well as non-tribal areas. The sacred groves in the western part are called Devrai or Devrahati, which means the abode of the gods. In eastern parts it is called Devegudi by the madiya tribal people.

In Maharashtra 2820 Devrais have been documented. Maruti, Vaghoba, Vira, Bhiroba, Khandoba and Shirkai are some deities to which sacred groves are dedicated.

In the sacred groves, the most commonly found plant species are Portia tree, Casuarina, Silk cotton tree, Indian laurel, Indian Elm, Bead tree, Indian butter tree, Turmeric and Japanese ginger. In Maharashtra, sacred groves are maximum in district of Sindhudurg, (More than 1500 out of total 2820) followed by Ratnagiri, then Pune and in district of Satara.

Choose the correct alternative and write that alphabet against the sub-question number:

Question 1.
Paddy fields are frequently attacked by
(a) goats
(b) birds
(c) grasshoppers
(d) monkeys
Answer:
(c) grasshoppers

Question 2.
Basic functional unit to study the ecology is termed as ……………
(a) environment
(b) niche
(c) ecosystem
(d) food chain
Answer:
(c) ecosystem

Question 3.
As per ……….. trading of rare animals has been completely banned.
(a) clause 48A
(b) clause 49B
(c) clause 49A
(d) all the above
Answer:
(c) clause 49A

Question 4.
(4) The jungle in Kokilamukh of Jorhat district of Assam is well known as ………….
(a) Molai jungle
(b) Rhino jungle
(c) Rhino forest
(d) Payang jungle
Answer:
(a) Molai jungle

Question 5.
Maintaining record of ………. knowledge is very necessary.
(a) modern
(b) mythical
(c) vedic
(d) traditional
Answer:
(d) traditional

Question 6.
………… is world’s largest organization engaged in environmental activities.
(a) Greenpeace
(b) Hariyali
(c) B. N. H. S.
(d) I. I. T.
Answer:
(a) Greenpeace

Question 7.
……….. sanctuary of West Bengal is reserved for tigers.
(a) Gir
(b) Sunderban
(c) Molai
(d) Corbett
Answer:
(b) Sunderban

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Question 8.
World Biodiversity Day is celebrated on ……… every year.
(a) 22nd April
(b) 5th June
(c) 16th September
(d) 22nd May
Answer:
(d) 22nd May

Question 9.
Out of the total plant species in the entire world, 50,000 are ……………
(a) extinct
(b) endangered
(c) endemic
(d) rare
Answer:
(c) endemic

Question 10.
Giant squirrel is an ………… species.
(a) indeterminate
(b) rare
(c) endemic
(d) endangered
Answer:
(a) indeterminate

Question 11.
In a food chain, autotrophic plants are present at the ……….. level. (March 2019)
(a) tertiary nutrition
(b) secondary nutrition
(c) producer
(d) apex
Answer:
(c) producer

Question 12.
……….. from Manas sanctuary in Assam is under threat. (Board’s Model Activity Sheet)
(a) one horned rhino
(b) Lion
(c) Musk deer
(d) Giant squirrel/Shekru
Answer:
(a) one horned rhino

Write whether the following statements are true or false, giving suitable explanation for the same:

Question 1.
Only abiotic factors play very important role in the ecosystem.
Answer:
False. (Both abiotic and biotic factors play very important role in the ecosystem. Only abiotic factors will not decide the working of an ecosystem.)

Question 2.
Paddy fields are frequently attacked by frogs.
Answer:
False. (Paddy fields are frequently attacked by grasshoppers. Frogs feed on grasshoppers and control the population of these insects that cause destruction of the crops.)

Question 3.
Environmental pollution is necessary and acceptable change in the surrounding environment.
Answer:
False. (Environmental pollution is never acceptable. It is always harmful to the entire ecosystem and thus never necessary.)

Question 4.
X-rays and radiations from atomic energy plants are natural radiations.
Answer:
False. (X-rays are not present in natural radiations. Infra-red and ultra-violet rays are present in natural radiations.)

Question 5.
The person breaching the Environmental Conservation Act is entitled for either one year imprisonment or fine up to ₹ 5 lakh.
Answer:
False. (The person breaching the Environmental conservation Act is fined upto ₹ 1 lakh. He is also entitled to imprisonment for five years.)

Question 6.
Many people come together to establish arnew forest but a single person, if determined can destroy the entire forest!
Answer:
False. (When anything constructive has to be done even a single man can start such action. In case of ‘Molai jungle’, this statement holds true. But when destructive actions are done, many people come together and cause damage.)

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Question 7.
There are clusters of thick forests only in Western Ghats of India.
Answer:
False. (Entire India is rich in biodiversity. Just not in Western Ghats but in entire India one can observe the clusters of thick forests and this is mainly due to suitable tropical climate.)

Question 8.
86 highly sensitive biodiversity spots are reported all over the world.
Answer:
False. (As per the latest information and available data, there are 34 highly sensitive biodiversity spots.)

Question 9.
Flow of nutrients in an ecosystem is unidirectional.
Answer:
False. (Flow of energy in an ecosystem is unidirectional. Flow of nutrients is cyclic.)

Match the columns:

Question 1.

Column I Column II
(1) Physical, chemical and biological factors together form (a) Biodiversity
(2) The science of interactions between biotic and abiotic factors (b) Ecosystem
(c) Ecology
(d) Environment

Answer:
(1) Physical, chemical and biological factors together form – Environment.
(2) The science of interactions between biotic and abiotic factors – Ecology.

Question 2.

Column I Column II
(1) Basic functional unit in the environment (a) Biodiversity
(2) Different types of living organisms (b) Ecosystem
(c) Ecology
(d) Environment

Answer:
(1) Basic functional unit in the environment – Ecosystem.
(2) Different types of living organisms – Biodiversity.

Question 3.

Rules/Act Year
(1) Sound Pollution (Control and Prevention) Rule (a) 1980
(2) Biomedical Waste (Management and Handling) Rule (b) 2011
(c) 1998
(d) 2000

Answer:
(1) Sound Pollution (Control and Prevention) Rule – 2000.
(2) Biomedical Waste (Management and Handling) Rule – 1998.

Question 4.

Rules/Act Year
(1) Forest Conservation Act (a) 1980
(2) Environmental Conservation Act (b) 1986
(c) 2011
(d) 2000

Answer:
(1) Forest Conservation Act – 1980.
(2) Environmental Conservation Act – 1986.

Question 5.

Species Examples
(1) Endangered (a) Red panda, Musk deer.
(2) Rare (b) Tiger, Lion.
(c) Lion tailed monkey, lesser florican.
(d) Monkey, squirrel

Answer:
(1) Endangered Species – Lion tailed monkey, lesser florican.
(2) Rare Species – Red panda, Musk deer.

Question 6.

Species Examples
(1) Vulnerable (a) Giant squirrel (Shekhru)
(2) Indeterminate (b) Red panda, Musk deer
(c) Tiger, Lion
(d) Lesser florican, sparrow

Answer:
(1) Vulnerable Species – Tiger, Lion.
(2) Indeterminate Species – Giant squirrel (Shekhru).

Find the odd one out:

Question 1.
Ash, Carbon dioxide, Lead, Asbestos
Answer:
Carbon dioxide. (All others are solid particulate pollutants.)

Question 2.
Manas sanctuary, Sunderbans sanctuary, The Western Ghats, Tadoba National Park
Answer:
Tadoba National Park. (All others are endangered heritage places of India.)

Question 3.
Lion tailed monkey, White rats, Musk deer, Tiger
Answer:
White rats. (All others are species that are threatened.)

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Question 4.
Conservation, Regulation, Pollution, Prohibition
Answer:
Pollution. (All others are ways of environmental protection.)

Question 5.
IPCC, UNEP, IUCN, BNHS
Answer:
BNHS. (All others are international organizations. BNHS is Bombay Natural History Society.)

Find the correlation:

Question 1.
Rare species : Musk deer : : ………… : Lesser florican.
Answer:
Endangered species

Question 2.
Red panda : Rare species : : Giant Squirrel : …………
Answer:
Indeterminate species

Question 3.
Nitrogen, Oxygen : Gaseous cycle : : Soil and Rocks : …………
Answer:
Sedimentary cycle

Question 4.
Manas : One horned Rhino : : Gir : ………..
Answer:
Asiatic lion

Question 5.
Mumbai : Bombay Natural History Society : : TehriGarhwal : ………….
Answer:
Chipko centre.

Answer the following questions in detail:

Question 1.
Answer the following questions:
If frog population in paddy field declines all of a sudden,
(a) What will be the effect on paddy crop?
Answer:
If the population of frog declines, then there will be rise in the population of grasshoppers. The paddy fields will hence be infested with insect pests.

(b) Number of which consumers will decline and which will increase?
Answer:
The food chain if altered, results in imbalance in the ecosystem. ‘Paddy → Grasshoppers → Frog → Snake’, this food chain is natural. When by any reason there is dec1ine in the number of frogs, thus secondary consumer will also decline. Due to this decline, snake which is at tertiary consumer level will also decline. Theprimary consumers i.e. grasshoppers will increase as there is now no check on their population. Due to increase in their population the paddy production will be reduced. Due to reduced number of snakes, rats and other rodents from neighbouring areas would also rise, which are also secondary consumers.

(c) Name the Indian states where paddy is cultivated on a large scale.
Answer:
West Bengal, Uttar Pradesh, Haryana, Punjab, Tamil Nadu, Andhra Pradesh, Bihar, Chhattisgarh, Odisha, Assam and Maharashtra.

Question 2.
What is radioactive pollution? What are its effects?
Answer:
(1) The radiations emitted either through the natural sources or through man-made sources cause radioactive pollution.
(2) The natural radiations is in the form of ultra violet and infrared radiations.
(3) Artificial or man-made radiations are X-rays and radiations from atomic energy plants.
(4) All radiations are highly hazardous for the living organisms. The impact of radiation is also for a very long time.
(5) It has brought about major accidental mishaps at Chernobyl, Windscale, qpd Three Miles Island. These disasters have affected thousands of people.
(6) Some other effects of radiations are as follows – (i) Due to higher radiations of X-rays, cancerous ulceration occurs, (ii) Radiations destroy the body tissues, (iii) Radiations cause mutations and thus genetic changes occur, (iv) There is adverse effect on the vision.

Question 3.
Give one word for “The forest conserved in the name of God.” (Board’s Model Activity Sheet)
Answer:
Deorai.

Give scientific reasons:

Question 1.
Certain scavenging caterpillars, termites and insects found in the dung are important.
Answer:

  • Scavenging caterpillars and insects are decomposers. They seem to be Worthless due to filthy surrounding in which they thrive.
  • But they carry out most important task of decomposition of complex organic substances into simple inorganic elements.
  • This recycling is possible only due to decomposers.
  • If they are not present, there will be huge accumulation of garbage. Therefore, these living organisms are important.

Question 2.
Destroying trees is to destroy everything.
Answer:

  • When a single huge tree is felled many living organisms which are dependent on it, are exterminated.
  • Many insects, fungi, birds, etc. lose their habitat.
  • Trees take up carbon dioxide from the atmosphere and release oxygen. These natural cycles are also hindered due to loss of trees.
  • Due to trees there is shade, cooler atmosphere and increase in the rainfall. When such trees are destroyed all the components in the ecosystem are destroyed too.

Question 3.
There is no definite information about indeterminate species.
Answer:

  • Indeterminate species do not have substantial information about them.
  • The organisms belonging to such species appear to be endangered due to their some behavioural habits.
  • They are shy and do not come in open so that they can be observed keenly.
  • For example, animals like Giant squirrel also do not provide such information.

Question 4.
Tigers from Sunderbans and Rhinos from Manas are under threat.
Answer:

  • Manas is in the area-of Assam where there are many dams and Indiscriminate use of water.
  • This area is also flood affected. Therefore, rhinos are under threat.
  • In Sunderbans, there are also problems such as deforestation, dams, excessive fishing, and dug out trenches.
  • All of these cause dangers to the tiger population.

Question 5.
There are clusters of thick forests in the Western Ghats of India.
Answer:

  • There are many sacred groves in the region of Western Ghats of India.
  • These forests are not conserved by Government Forest Departments but are cared for by the local people, in the name of God.
  • Due to such faith in the people, the forests are conserved like sanctuaries.
  • Such many clusters are in Western Ghats of Maharashtra.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Question 6.
We can see biodiversity on three levels.
Answer:

  1. There is biodiversity in the living organisms belonging to the same genus.
  2. This diversity is due to different heredity pattern. This is called genetic biodiversity.
  3. The organisms occupying the same area and belonging to the same species also show diversity due to different species. This is species biodiversity.
  4. The organisms occupying different ecosystems also show differences, which is called ecosystem biodiversity. Therefore, we observe biodiversity on three different levels.

Questions based on diagrams:

Question 1.
What is shown in the picture? Write name and trophic level of each component.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 12
Answer:
In this picture, food chain having rive trophic levels is shown.
(1) Trophic level 1 = Producers : Green plant.
(2) Trophic level 2 = Primary consumer (Herbivore): Grasshopper.
(3) Trophic level 3 = Secondary consumer (Carnivore): Bird.
(4) Trophic level 4 = Tertiary consumer (Carnivore) : Snake.
(5) Trophic level 5 = Top or Apex consumer (Carnivore) : Owl.

Question 2.
Explain the meaning of following symbols A and B and C.
A.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 13
Answer:
The symbol show types of green energy such as solar energy and wind energy. It also expresses that people
should use such sources of energy for their use.

B.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 14
Answer:
This symbol is giving the message “Save water”. Sustainable use of water is necessary for our future.

C.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 15
answer:
The symbols of WWF and BNHS are shown here. BNHS stands for Bombay Natural History Society. This institute works for the conservation and documentation of flora and fauna.

WWF means World Wild Life Fund. Also known as World Wide Life Fund. This International Institute is looking after the welfare of wildlife through different conservation projects. WWF symbol shows Panda while BNHS symbol has Giant Hornbill.

Question 3.
(a) Identify the following symbols and state their significance: (March 2019)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 16
Answer:
(i) This symbol is giving the message “Save water”. Sustainable use of water is necessary for our future.
(ii) Use of bicycle means use of green energy. By riding on a bicycle we save on fuel and use our own muscular energy. It is the best ecofriendly, non polluting vehicle.

(b) How can biodiversity be conserved?
Answer:
Biodiversity can be conserved by the following ways:

  • Protection of the rare species of plants and animals.
  • Creating habitats for the animals and plants by establishing National Park and Sanctuaries.
  • Declaration of bio reserves, the areas which are protected through conservation.
  • Conservation projects for protecting special species.
  • Conservation of all flora and fauna.
  • Strict observance of the acts and rules.
  • Use of traditional knowledge and maintaining record of traditional knowledge.

Activity based questions:

Question 1.
Questions based on the charts.
Complete the flow chart: (July 2019)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 17
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management 18

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Question 2.
Collect more information about locations of these hotspots present in the world. (Textbook page no. 44)
Answer:
Students should collect this information.

Question 3.
Where are such sacred groves in Maharashtra? Make a list and visit with your teachers. (Textbook page no. 43)
Answer:
Sacred groves: Sacred groves form an important landscape feature in the deforested hill ranges of the Western Ghats. The felling of timber and the killing of animals in sacred groves is not allowed by the locals. It is considered as taboo.

In Maharashtra, sacred groves are found in tribal as well as non-tribal areas. The sacred groves in the western part are called Devrai or Devrahati, which means the abode of the gods. In eastern parts it is called Devegudi by the madiya tribal people.

In Maharashtra 2820 Devrais have been documented. Maruti, Vaghoba, Vira, Bhiroba, Khandoba and Shirkai are some deities to which sacred groves are dedicated.

In the sacred groves, the most commonly found plant species are Portia tree, Casuarina, Silk cotton tree, Indian laurel, Indian Elm, Bead tree, Indian butter tree, Turmeric and Japanese ginger. In Maharashtra, sacred groves are maximum in district of Sindhudurg, (More than 1500 out of total 2820) followed by Ratnagiri, then Pune and in district of Satara.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 4 Environmental management

Projects: (Do it your self)

Project 1.
Let’s Discuss: (Text Book Page No. 41)
Collect the information about Chipko Movement and discuss between two groups of your class about its importance in present situation.

Project 2.
Collect more information on the organization of Greenpeace. (Text Book Page No. 43)
Answer:
Students are expected to write this answer to this question.

Project 3.
There should be positive attitude of human being towards the environment for welfare of entire living world. For this purpose, following roles are important. You can be a conservator, organizer, guide, plant-friend, etc. Describe about the role you wish to perform and your plans for that role. (Text Book Page No. 42)

Project 4.
Survey the plants and animals in your area. Maintain a record about their characteristics. (Text Book Page No. 45)
Answer:
Students can conduct such surveys with the help of elders.

Project 5.
Internet is my friend! (Collect the information Textbook page no. 41)
(1) Sound Pollution (Control and Prevention) Rule, 2000.
(2) Biomedical Waste (Management and Handling) Rule, 1998.
(3) E-waste (Management and Handling) Rule, 2011.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Balbharti Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 1.
Complete the table.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 1
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 2
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 3
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 4
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 5

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 2.
Write notes.
a. Disaster Management Authority.
Answer:
Disaster Management Authority is the body that works at the level of government from national level to village level. This work is basically about management of any disaster and tackling the problems of the affected people. At National level there is National Disaster Management Authority for which the Prime Minister is the chairman. For every state there is State Disaster Management Authority, where the chief minister of every state is the chairman. Under the state level, there are district level units where district collector is responsible for disaster management and implementation of rehabilitation schemes. Below district level authority there are Taluka and then Village Disaster Management Committees.

The Tahsildar is the chairman for Taluka level while the Sarpanch of the village is responsible for management of disasters at village level. Collector of each district helps in planning, coordinating and controlling the implementation of rehabilitation programme and also gives essential instructions and reviews the entire system.

b. Nature of disaster management.
Answer:
Disaster management involves either prevention of disasters (Pre-disaster management) or creating preparedness to face them (Post-disaster management). The action plans are prepared for managing disasters. This is done after studying the different aspects such as preventive measures, rehabilitation and reconstruction plans. The disasters are tackled by executing action plans in the following steps: Preparation, redemption, preparedness, action during actual disaster, response, resurgence and restoration. At every level there are other voluntary organizations and Government meteorological institutions for their help.

c. Mock drill.
Answer:

  • Mock drill is the practice to check whether there is preparedness for dealing with the sudden attack of disaster.
  • For this purpose, virtual or apparent situations that simulate the disaster are created.
  • The reaction time for any type of disaster is checked by such activity. In the presence of trained personnel, the execution of the rescue plans are observed.
  • People also understand their responsibilities at the time of actual disaster.
  • The experts also check execution of plan designed for disaster redressal.
  • By such mock drills, the efficacy of the system can be understood. In future, when actual calamity strikes, there is already preparation for disaster redressal. Therefore, mock drill is useful.

d. Disaster Management Act, 2005.
Answer:
Government of India has made Disaster Management Act in 2005. The affected people are given all necessary help as per this act. With the humanitarian view, people are rehabilitated and helped them to come back to normalcy after the disaster.

As per this Act, National Disaster Response Force has been established. This force consists of 12 divisions in entire India which are attached with Indian Army. The headquarter is located in Delhi, but the action is taken all over the country with the help of army. As per the Act, in Maharashtra National Disaster Response Force is in action through State Reserve Polioe Force. The personnel of this force are trained accordingly, and they take part in the rescue work during different disasters.

Question 3.
Answer the following questions.
a. Explain the role of district disaster control unit after occurrence of any disaster.
Answer:
(1) District control unit looks after the ; disaster management of the district.
(2) It is immediately formed either after the impact of disaster or if warning is given about some upcoming disaster.

District-wise Disaster Control Unit performs following role:

  • The review of various aspects of disasters is done.
  • Through the disaster control unit there is continuous contact established with various agencies like army, air force, navy, telecommunication department, paramilitary forces, etc. for obtaining help.
  • The unit also coordinates with various voluntary organizations for their help in disaster management.

b. Give the reasons for increase in human disasters after the World War-II.
Answer:

  • After Second World War, the feelings of peace and brotherhood among the global citizens were lost. The geographic, religious, racial and ethnic differences sprang up tremendously.
  • Atrocities that Nazi has performed made deep impact on the minds of people. Terrorism, abduction, robberies and social unrest increased in almost all the countries.
  • The financial losses had incurred in the World War II. The misuse of science and technology was done to retrieve these deficits.
  • At the end of World War II, the atomic bombs were dropped in Japan. This has created health problems in the entire world.
  • Social inequality, economic disparity, racial and religious differences were some adversaries that created unrest in the country.
  • Later, the neighbouring nations kept on fighting. The geographical boundaries were changed. People always had feelings of insecurity. The terrorism flourished. All such instances gave rise to man-made disasters.

c. What are the objectives of disaster management?
(OR)
State any four objectives of disaster management. (March ’19)
Answer:
Objectives of disaster management:

  • To save human life from disasters. To help them for moving away from the place of disasters by rapid action.
  • To supply essential commodities to the affected people. This helps to reduce the gravity of disaster. People are given grains, water and clothes and other basic necessities under this objective.
  • To bring back the conditions of affected people to normalcy.
  • To rehabilitate the affected and displaced victims.
  • To think and execute the protective measures in order to develop capability to face the disasters in future.

d. Why is it essential to get the training of first aid? (July ’19)
Answer:
When there is a disaster, we need to immediately help the victim. Till the medical help arrives, one should be in position to treat the injured and save his or her life. In such cases; knowing first- aid is essential. Such kind of a need may arise in case of our parents, our siblings at home or with friends in school. Those who are injured should be treated at once. If we know about techniques of first aid, we can save such person before the medical help arrives. Therefore, it is essential to get the training of the first aid.

e. Which different methods are used for transportation of patients? Why?
Answer:
For the transportation of patients following methods are used:

  • Cradle method: This method is used for children and persons with less weight.
  • Carrying piggy back: This method is useful in carrying the unconscious persons.
  • Human crutch method: If one leg of the person is injured, then the victim is supported with minimum load on the other leg. This is called human crutch method.
  • Pulling or lifting method: For carrying an unconscious person for a short distance this method is used.
  • Carrying on four-hand chair: This method is used when the support is needed for a part below waist region.
  • Carrying on two-hand chair: Patients that cannot use their hands but can hold their body upright, are carried by such method.
  • Stretcher: By making temporary stretcher in case of emergency, the unconscious patient can be moved. Such temporary stretchers are made by using bamboos, blanket, etc.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 4.
On the basis of the structure of disaster management authority, form the same for your school.
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 6

Question 5.
Write down the reasons, effects and remedial measures taken for any two disasters experienced by you.
Answer:
Students are expected to write the answer based on their own experiences.

Question 6.
Which different aspects of disaster management would you check for your school? Why?
Answer:
For the pre-disaster management at school following aspects would be inspected.

  • Are the telephones 6f the school working properly?
  • Is there a first-aid box in each class?
  • Are there any basic medicines in the school?
  • Is the team ready for rescue of smaller children from lower classes?
  • Has monitor or prefect participated in a mock drill? Does he/she know about first aid?
  • Is the contact of parent representative available in emergency situations?
  • Is the Medical Officer/Doctor present on the school campus?
  • Is there enough drinking water and some dry snacks available in the school?
  • Are the staircases and corridors suitable for quick evacuation of the children?

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 7.
Identify the type of disaster.
a. Terrorism.
Answer:
Man-made, intentional.
Due to the activities of terrorism, many innocent lives are lost. Many are seriously injured. Some become crippled for their entire life. Buildings, monuments, vehicles everything is completely destroyed. There is rift between different religions or sects. The peaceful atmosphere is disturbed. The entire society is under the constant fear of insecurity.

b. Soil erosion.
Answer:
Natural, geophysical, geological.
When the upper fertile layer of soil is lost, it becomes barren. The trees are uprooted. The fertility of the area is lost. The land becomes unsuitable for cultivation or farming. Due to wind, flowing water or grazing animals the naturally occurring soil erosion becomes hazardous for the environment.

c. Hepatitis.
Answer:
Natural, biological, animal-origin.
Hepatitis is a viral disease which spreads through the contaminated food and water. The outburst of epidemic of hepatitis is difficult to control. As in big cities the quality of road side food is often consumed, the spread of hepatitis is. fast. People suffer due to hepatitis.

d. Forest fire.
Answer:
Natural, biological, plant-origin.
Due to heat and wind, the dry grass and the shrubs catch fire in the forests, resulting in forest fires. Such rapidly spreading forest fire can finish the biodiversity within a very short span of time. It is difficult to extinguish the naturally lit forest fires. Many trees and other vegetation, animals and birds along with their habitats are destroyed due to forest fire. The smoke emanating causes the air pollution.

e. Famine.
Answer:
Natural, climatic.
Due to famine there is severe water scarcity. In absence of water, the fields and farms become barren as the crops cannot grow without water. There is shortage of food grains. The cattle dies due to want of water and grass. Local people have to migrate in search of food, water and shelter.

f. Theft.
Answer:
Man-made, intentional.
Theft causes economic loss for the one whose money or valuables are looted. The person who suffers the loss also undergo mental and emotional shock. Sometimes the thief may also cause physical harm. It may cost on life too.

Question 8.
Some symbols are given below. Explain those symbols. Which disasters may occur if those symbols are ignored?
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 7
Answer:
The above signs are warning symbols which should never be ignored.
The meaning of each is given below. They are giving warnings about explosive, inflammable, oxidizing, compressed gas, corrosive, toxic, irritant, environmentally hazardous and health hazard.

(1) Explosive: Some materials are explosive. While handling such materials care should be taken. We should not take anything that would cause fire leading to explosion. If explosion occurs, there would be a major disaster causing great loss of life and property. Thus if this sign is seen, great care has to be taken.

(2) Inflammable: Similar to explosive substances, the inflammable materials can also catch fire easily. Therefore, to warn people such sign is given on materials that can cause hazard by burning.

(3) Oxidizing: Some chemical substances are oxidizing. They carry out chemical reactions with a rapid speed. E.g. If potassium permanganate falls on the cloth, it starts the reaction on its C-C bonds. Due to such property of carrying out reactions, the cloths may catch fire. Therefore, oxidizing substances should be handled with care.

(4) Compressed: Compressed substances are filled under pressure in some container. If mishandled, they can come out of the container by bursting it open. This can cause some injuries.

(5) Corrosive: The corrosive substances are very reactive. The mere touch of corrosive substances can cause destruction of skin, eyes, respiratory passages, digestive organs, etc. rapidly. Just touching or smelling of such substances can cause major injury and thus warning sign of corrosive substance should never be ignored.

(6) Toxic: To taste a toxic substance or even to smell it, can lead to death. The packing of these substances are therefore marked as dangerous. They should be avoided as far as possible.

(7) Irritant: When skin or any delicate part of the body comes in contact with the irritant substance, it can cause harmful reaction. Especially, eyes, nasal mucosa and skin are affected by contact with corrosive substances.

(8) Environmentally hazardous: Many sub¬stances cause harm to the environment due to their toxicity. Air, water or soil can be polluted due to such pollutants. When environment is affected, ultimately these hazardous effects come back to human species. Therefore, such substances should be carefully used. Their use should be judicious and controlled.

(9) Health hazard: The substances that can cause hazard to our health should always be distanced from us. Such substances should not be kept in proximity. As far as possible they should be kept away and handled with great care if needed for any work. Materials marked with health hazard can cause severe toxicity.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 9.
Explain that why is it said like that?
a. Mock drill is useful.
Answer:

  • Mock drill is the practice to check whether there is preparedness for dealing with the sudden attack of disaster.
  • For this purpose, virtual or apparent situations that simulate the disaster are created.
  • The reaction time for any type of disaster is checked by such activity. In the presence of trained personnel, the execution of the rescue plans are observed.
  • People also understand their responsibilities at the time of actual disaster.
  • The experts also check execution of plan designed for disaster redressal.
  • By such mock drills, the efficacy of the system can be understood. In future, when actual calamity strikes, there is already preparation for disaster redressal. Therefore, mock drill is useful.

b. Effective disaster management makes us well prepared for future.
Answer:

  • Disaster can strike any time. The sudden disasters can be man-made with some bad intentions or may be accidental.
  • When natural calamity strikes suddenly with a huge impact, large scale devastation of property and general environment degradation occurs along with substantial mortality of people and animals.
  • Therefore, it is most appropriate to have the preparedness to reduce the impact of any future disasters.
  • We cannot control the onset of the natural disaster, but we can definitely reduce the harsh effects of the disaster by following disaster management plan.

Question 10.
Complete the following chart.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 8
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 9

Question 11.
Following are the pictures of some disasters. How will be your pre and post-disaster management in case you face any of those disasters?
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 10
Answer:
In the pictures given, following disasters are shown:
(1) Two groups of children are fighting with each other.
(2) There is gas leakage from the LPG cylinder.
(3) There is heavy downpour due to cloud bursting which has led to waterlogging in the town.
(4) There is cyclone causing a tornado. (Commonly called a twister)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 11
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 12

Projects:

Project 1.
Demonstrate the activities shown on page no. 106 of Std. IX Science and Technology textbook in front of the students of other classes. Make a video clip and send it to others.

Project 2.
Form a group of students from your school to demonstrate the mock drill and demonstrate it in the school

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Can you recall? (Text Book Page No. 109)

Question 1.
What is disaster?
Answer:
Disaster is the incidence that occurs suddenly causing heavy damage to life and property. The disaster can be man-made or due to natural reason.

Question 2.
Which disasters have you experienced in your area?
Answer:
On September 2019, there was a heavy downpour in Pune. This disaster has been experienced recently.
On 26th November 2008 there was attack at several places by the Pakistani terrorists. The stories about the deaths and damage caused by this disaster were seen in films and learnt about this from our elders.

Question 3.
What are the effects of that disaster on local and surrounding conditions?
Answer:
Due to a heavy downpour in Pune, there was waterlogging in all the shallow areas. All the transport systems collapsed on that day. Large trees fell down injuring the people. The water logging caused condition like floods. Schools, colleges and offices were shut down. People were caught in troublesome situation.

On 26th November 2008 many innocent people lost their lives. There was tremendous damage caused to some of the important places like Taj Palace Hotel and Chabad house.

Use your brain power: (Text Book Page No. 111)

Question 1.
Depending upon information given on page 111, explain the various effects of the disaster of railway accident.
Answer:
The effects of disastrous railway accident:
The effect will be dependent upon the nature of the accident that has occurred. Whether, it is a collapse of bridge or due to derailment of the train, or due to collision of two moving trains, whether it is due to failure in signaling system, due to land slide or due to obstacle in the tunnel, that has to be understood. The impact of such railway accident will be dependent on the way that accident has occurred. Based on this impact the effects will take place.

(1) Environmental The entire surroundings will show destruction.
(2) Administrative/ Managerial The railway department will have stress and the time table will collapse. The regular use of tracks will hamper, resulting into delay in railway traffic.
(3) Political Ministry of railways is considered to be responsible for the accident. Sometimes the Railway Minister resigns.
(4) Medical The passengers commuting in the train die or suffer from serious injuries.
(5) Economic The railways suffer huge financial loss.
(6) Social The railway traffic is disturbed. Passengers are troubled as they get held up at some place.

Observe/Discuss:
Let’s Discuss: (Text Book Page No. 110)
Question 1.
observe the images on textbook page no. 110. whether the places of disasters are known to you? Discuss the emfects of these disasters on public lire. How people could lave been saved from these disasters? Discuss with your friends in the classroom.
Answer:
Students should discuss the disasters given in the pictures by themselves after collecting the information.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Observe: (Text Book Page No. 114)

Question 1.
Observe the disaster cycle given below and explain each aspect of the disaster of earthquake.
Answer:
The main aspects of disaster cycle to tackle disaster of earthquake are as follows:
(1) Preparation : With the help of seismograph, the warning about forthcoming earthquake can be obtained these days. The intensity of the earthquake is also predicted with the help of technology. If the estimate of the Richter scale is on the higher sides, there would be more preparatory measures taken to tackle the forthcoming problem of earthquake.

(2) Redemption: Once this information is obtained the possible impact of the earthquake on the houses, buildings, people can be studied by the geological experts. The meetings of the Disaster Management Authority will be organized for same.

(3) Preparedness: What the general public should do and what action the reserved forces should take, will be decided in case of actual incidence of the earthquake. The schemes and plans will be made ready in this direction.

(4) Impact of Earthquake: In case of disaster of earthquake, people will be helped to safety. The trapped people will be rescued. First aid and other necessary help will be provided. The data about the losses and the intensity of this disaster will be noted and reported for the further process.

(5) Response: In this phase the response of the people as well as the action of Government can be well studied. The response should be quick and positive. The maximum lives and property should be saved by such responses. The disaster of earthquake should be managed with positivity and through help given to the sufferers.

(6) Resurgence: Earthquakes can destroy the entire households or even entire community. Such homeless people should be given the place to stay. Resurgence is important phase for the national welfare. If the citizens of India are cared for, the nation too will progress.

(7) Restoration: The earthquake victims should be settled by providing them with new settlements. Sometimes, entire village is to be settled. E.g. In Latur or Kutch, there twas very large scale devastation. But Government of India as well as some NGOs helped to reconstruct the houses. In such earthquake-prone areas, houses are built in specific pattern to withstand any possible future calamities.

Observe: (Text Book Page No. 117)

Question 1.
Give the reference of following pictures and explain importance of each of those in disaster management. Which are other such activities ?
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 13
Answer:
The actions shown in the above pictures are as follows:
(a) The patient is made to lie on the stretcher. He must be unconscious and injured to greater extent, so that he cannot move by himself.
(b) The patient is helped by giving artificial respiration. Probably the victim is suffocated and needs oxygen supply.
(c) and (d) The patient is being picked up. Most probably the patient is unconscious.
The unconscious person who cannot move by himself is carried by these two methods. In method ‘c’, the weight of the patient is less and hence he can be lifted as shown in the picture. In picture ‘d’ the victim has to be lifted in other way, may be due to his greater body weight.
(e) The patient is carried on the back as in ‘carrying piggy back’ position. He too is unconscious and needs to be shifted for medical treatment.
(f) The patient in this picture is carried by ‘human crutch method’. When victim’s one leg is injured, he cannot walk without support. Hence, he needs to be carried in such a way.

In all the above methods, the injured person at the time of disaster is transported to hospital or dispensary for further medical help. The primary first-aid is given to the victim. Now the volunteer is taking him for further treatment. Such rescue activities depend upon the type of disaster and the extent of the injury. Hence the methods will be of different nature.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Let’s Think: (Text Book Page No. 111)

Question 1.
What will be the effect on yourself and surrounding, if any accident-like disaster occurs during the sports on playground or in school?
Answer:
When in school, there is an accident, first of all we get scared. But with caring help of the teacher, we will give the first aid to the injured friends by using first aid kit. If the injury is serious, we will take him to the medical centre of the school. While playing or during sports event, children flock around and make unnecessary crowding. In case of such accident, first of all the crowd will have to be dispersed. If there is major disaster, one should not fumble but manage the disaster in a wise way with the help of teachers.

Let’s Think: (Text Book Page No. 112)

Question 1.
Explain the nature and scope of the disaster of flood with the help of six points given on text book page no. 112.
Answer:
The nature and the scope of the disaster of flood can be described according to the six points:
(1) Pre-disaster phase: Due to Indian Meteorological Department the warning predictions are received before any climatic disaster strikes. If the scope of the flood is predicted to be high, then the people who may be affected by the calamity are relocated to a safer area.

(2) Warning phase: In the warning phase the Government warns the general public about the forthcoming disaster of floods through mass media like radio, television, newspapers, etc. In recent times, even the cellphone messages are sent to people for warning them. The people living in coastal areas will be worst affected and hence such people are given greater care and they are immediately made to leave their houses. They are taken to the safe places.

(3) Emergency phase: When the flood waters actually start rising up, the low-lying areas are submerged. Houses, roads and shops everything goes under water. The rescue operations are carried out by army men from National Disaster Rescue Force. They take every possible effort to rescue the trapped people. The emergency continues till the water does not recede. Later after the water starts receding, people who had been taken to places on heights, start coming back. During this phase, search, rescue operations, medical treatment, and first aid are all the aspects on which the attention is focussed.

(4) Rehabilitation phase: The people affected due to floods are given emotional and financial support. The fields, farms, houses or cattle-shed are under water. Such people are given transient accommodations. Many cattle and other animals die by drowning. Their rotting carcasses have to be disposed as soon as possible because the decaying process spreads epidemics of diseases. People are given vaccinations to protect them from diseases of such kind. Special care of young children and senior citizens is taken during this period. Supply of food and drinking water is also very important task during this time.

(5) Recovery phase: During recovery phase, the life comes gradually back to normalcy. The removal of dead, decaying material and the debris is the first priority. The water connections and electricity is restored back. Various NGOs or Government organizations provide help of various kind to the affected people. This help is to be distributed to those who are in real need. This work is also done by Disaster Management Department.

(6) Reconstruction phase: The houses and building that collapse due to floods are built back. Agricultural activities start again. Roads and water supply is once again normalized. Schools and colleges start once again. Thus, the once flood affected area comes back to routine functioning again.

Let’s Think: (Text Book Page No. 117)

Question 1.
Following are some pictures of disasters. Which precautions would you take during those disasters?
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 14
Answer:
The pictures shown above are showing earthquake, fire and snake bite respectively.
In the above disasters, the initial precautions to be taken are as follows:
(1) Earthquake: In case of earthquake, one should immediately come out of house and stand in the open ground. If this is not possible, one has to go below table or any other cover. During collapse of the building, there should not be a head injury. This precaution is basically for prevention of dangerous injuries and saving our life. Switch off the power supply. If in journey, stay inside the vehicle.

(2) Fire: First and foremost is to save ourselves from fire. Then one can help others in rescue operations. Help others to extinguish fire. Call the fire department for immediate action.

(3) Snake bite: Many a times the biting snake can be non-venomous too. But the victim is psychologically affected too. The tourniquet should be tied in the region above the snake bite. The rope, piece of cloth or even handkerchief can be used for this purpose, so that the venom, if any should not rise and reach vital organs. The wound should be made near the bite-wound so that the blood will ooze out and some venom can automatically flow out. Though these are first-aid measures, the victim should be rushed to a qualified doctor for an injection of antivenin.

Choose the correct alternative and write its alphabet against the sub-question number:

Question 1.
Disasters definitely affect the ………… of the nation.
(a) people
(b) economy
(c) security
(d) employment
Answer:
(b) economy

Question 2.
If local ………… is not strong enough, citizens become confused.
(a) leadership
(b) women
(c) politicians
(d) cattle
Answer:
(a) leadership

Question 3.
…………… problems arise diming the disaster.
(a) Local
(b) Global
(c) Administrative
(d) Private
Answer:
(c) Administrative

Question 4.
Stinking pollution caused due to decomposing corpses of humans and other animal is ………… disaster.
(a) environmental
(b) health
(c) necessary
(d) effective
Answer:
(a) environmental

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 5.
After the subsidence of any type of disaster, rehabilitation work is started in ………… phase.
(a) later
(b) transitional
(c) terminal
(d) ultimate
Answer:
(b) transitional

Question 6.
…………. phase is highly complicated phase.
(a) Reconstruction
(b) Recycling
(c) Reuse
(d) Redevelopment
Answer:
(a) Reconstruction

Question 7.
There had been a huge ……….. in the village Malin, Tal. Ambegaon in 2014.
(a) earthquake
(b) storm
(c) landslide
(d) change
Answer:
(c) landslide

Question 8.
The atomic energy plant at Chernobyl was used only for generating ………….
(a) electricity
(b) solar power
(c) atomic energy
(d) agriculture
Answer:
(a) electricity

Question 9.
Supply of essential ………….. to the affected people can reduce the effect of the disaster.
(a) food
(b) water
(c) commodities
(d) money
Answer:
(c) commodities

Question 10.
Keeping …………. ready is a practice to check the preparedness of facing the disaster.
(a) First aid
(b) Mock drill
(c) Ambulance
(d) Fire brigade
Answer:
(b) Mock drill

Question 11.
Which of the following is man-made disaster. (March, July ’19)
(a) Earthquake
(b) Flood
(c) Meteor
(d) Leakage of toxic gases
Answer:
(d) Leakage of toxic gases

Question 12.
What should be done if gas cylinder at your house catches fire?
(a) Water should be sprinkled
(b) Sand, soil should be put on it
(c) Cylinder should be covered with wet blanket
(d) one should run away
Answer:
(c) Cylinder should be covered with wet blanket

Which type of disaster is described in the following statements:

Question 1.
On 26th July 2005, entire suburban Mumbai was waterlogged.
Answer:
Cloudbursting and severe downpour

Question 2.
Elephants in the Bandipur forest started running helter and skelter due to smoke.
Answer:
Forest fires

Question 3.
Many innocent people died in the bomb blast that occurred on 11th July 2006 in local trains.
Answer:
Bomb explosion-Terrorism

Question 4.
In Kutch, suddenly many school children were buried under the rubble.
Answer:
Earthquake

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 5.
Because of lack of crops, people from Vidarbha are migrating to other regions.
Answer:
Dry famine

Question 6.
The huge waves in Chennai engulfed many human lives in December 2004.
Answer:
Tsunami.

Find the correlation:

Question 1.
Earthquake in recent times : Gujarat, Latur : : Devastating floods in 2018 : ………….
Answer:
Earthquake in recent times : Gujarat, Latur : : Devastating floods in 2018 : Kerala/Assam

Question 2.
Toxic gas leakage: Accidental disaster : : war : …………..
Answer:
Toxic gas leakage: Accidental disaster : : war : Intentional

Question 3.
Sun spots : Atmospheric type of disaster : : Salinization : …………..
Answer:
Sun spots : Atmospheric type of disaster : : Salinization : Geological type of disaster

Question 4.
Pre-disaster management : Preparation and warning : : Post-disaster management : ………..
Answer:
Pre-disaster management : Preparation and warning : : Post-disaster management : Resurgence and restoration.

Match the columns:

Question 1.

Column A: Disaster Column B: Type
(1) Earthquake and volcano (a) Animal origin
(2) Snowfall and snowstorms (b) Geological
(c) Climatic
(d) Terrorism

Answer:
(1) Earthquake and volcano – Geological.
(2) Snowfall and snowstorms – Climatic.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 2.

Column A: Disaster Column B: Type
(1) Aquatic weeds (a) Animal origin
(2) Attack by locusts (insects) (b) Plant origin
(c) Geological
(d) Climatic

Answer:
(1) Aquatic weeds – Plant origin
(2) Attack by locusts (insects) – Animal origin.

Question 3.

Column A: Disaster Column B: Type
(1) Atomic tests (a) Intentional
(2) Terrorism (b) Unintentional
(c) Geological
(d) Animal origin

Answer:
(1) Atomic tests – Unintentional
(2) Terrorism – Intentional.

Question 4.

Column A: Effect Column B: Effect
(1) Contamination of water (a) Economical
(2) Collapsing of transport system (b) Environmental
(c) Administrative
(d) Geological

Answer:
(1) Contamination of water – Environmental
(2) Collapsing of transport system – Administrative.

Question 5.

Column A: Effect Column B: Problem
(1) Spread of epidemics (a) Economical
(2) Shortage of funds (b) Administrative
(c) Medical
(d) Physical

Answer:
(1) Spread of epidemics – Medical
(2) Shortage of funds – Economical.

Question 6.

Column A: Effect Column B: Problem
(1) Rift due to religions (a) Economical
(2) Citizens getting confused (b) Social
(c) Political
(d) Environmental

Answer:
(1) Rift due to religions – Social
(2) Citizens getting confused – Political.

Identify the type of disaster and describe the effects of the same in brief:

Question 1.
Accident at Chernobyl.
Answer:
Man-made, unintentional. At Chernobyl in Russia there was the atomic energy plant, where disastrous accident took place. The radiations emitted through the reactors caused tremendous radiation pollution. These hazardous effects are even seen today.

Give reasons:

Question 1.
When there are riots, the cities, towns or villages show signs of tense atmosphere.
Answer:

  • During riots, there is financial loss for all the rioting groups.
  • The belongings, houses, shops, etc. are destroyed or damaged.
  • Property is looted. There is no guarantee of safety and security for anyone.
  • Women and children suffer the most as they are easily victimized. Therefore, when there are riots, the cities, towns or villages show signs of tense atmosphere.

Answer the following questions in detail:

Question 1.
which are the disaters that make Impact for longer duration? Give examples.
Answer:
Those disasters that make the impact for long duration and those disasters, whose after-elfbcts are either severe are long term disasters. Their severity increases with thme. Such disasters are famine, various problems of growth of crop, strikes of workers, rising levels of oceans, desertification, etc.

Question 2.
What types of disaster are the following? Explain their impacts.
(a) Floods (b) War. (Board’s Model Activity Sheet)
Answer:
(a) Flood is geophysical climatic disaster.
(b) War is man-made intentional disaster.

Impact of flood : The low-lying and the coastal areas are seen to be submerged. The entire region is waterlogged.
Impact of war: Tremendous destruction causing loss. Many lives are lost. The costs of all the items rise due to war conditions. Entire nation faces insecurity.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 3.
Explain in brief the sensitive issues of general public about disaster.
(OR)
Which are the three aspects of disaster tjiat are important for common citizens?
Answer:
The phase of emergency, transitional phase and reconstruction phase are the three phases of disaster that are important for common citizens.

(1) Phase of emergency: If timely and rapid action is taken during this phase, maximum lives can be saved. Search and rescue operations, medical help, first aid, restoring communication services, removing the people from affected area are done during this phase. The gravity of disaster can be estimated during this phase.

(2) Transitional Phase: The disaster subsides and then the work of transitional phase starts. The main concern is rehabilitation work for the affected and displaced people. This work includes clearing of debris, restoring water supply, repairing roads, etc. to bring normalcy in public life. Help from different voluntary and Government institute is taken to offer the monetary provision and essential commodities to affected victims. Permanent means of livelihood is given to the people to reduce their mental and emotional stress. The victims are truly rehabilitated.

(3) Reconstruction Phase: Reconstruction phase is a highly complicated phase which actually overlaps with transition stage. Help is offered to people to reconstruct their buildings. Other facilities like roads and water supply are restored. Farming practices are restarted. It is a very gradual phase that makes the victims to completely rehabilitate.

Question 4.
What are the objectives of mock drill?
Answer:
Objectives of Mock Drill:

  • To evaluate the response of the people to the disaster.
  • To improve the coordination between various departments of disaster control.
  • To identify one’s own abilities if disaster approaches.
  • To improve the ability to quick response to disaster and taking rapid action.
  • To check the competency of the planned actions.
  • To identify the possible errors and risks while dealing with disasters.

Question 5.
Write down the names of international organizations that work for disaster management.
Answer:
Following international organizations work for disaster management.

  • United Nations Disaster Relief Organization
  • United Nations Centre for Human Settlements
  • Asian Disaster Reduction Centre.
  • Asian Disaster Preparedness Centre.
  • World Health Organization.
  • United Nations Educational, Scientific and Cultural Organization.

Question 6.
The building in which you are residing ( has caught fire on the ground floor. What necessary rescue steps will you take? (July ’19)
Answer:

  • We shall call out for help.
  • We shall immediately call fire brigade.
  • We shall try to extinguish fire with the help of other people.
  • We will give first aid to people who are injured, fill the medical help arrives.
  • We will cover our nose and mouth with moist cloth to prevent suffocation.

Write short notes:

Question 1.
Pre-disaster management.
Answer:
The management measures taken before onset of a disaster is called pre-disaster management.
In pre-disaster management, complete preparation and planning to face any type of disaster is done. For this purpose, following steps are taken.

  • Identifying the areas where the disaster can strike. Such disaster-prone areas are to be thoroughly studied.
  • Through predictive intensity maps and hazard maps, the information is collected about the intensity of disaster and probable sites of disasters respectively.
  • Special training for disaster management is given to the concerned people.
  • The mass awareness is created about disaster management through training programmes, mass media and internet, etc.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 2.
Post-disaster management.
Answer:
The management measures taken after the striking of a disaster is called post-disaster management.
Following steps are taken during post-disaster management:

  • Helping the victims of disasters by giving all possible help needed for their survival.
  • Local people are trained to take part in the disaster management so that affected people can be saved rapidly.
  • Establishing the help centres that could provide all the necessary help. Such centres will be different in case of different disasters.
  • Collection and categorization of the material received from control centre for helping the victims. Distributing the same and reviewing the measures continuously.
  • Disaster rescue programmes are mainly focused.

Some symbols are given below. Explain those symbols. Which disasters may occur if those symbols are ignored?

Question 1.
Write what the signs indicate:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 15
Answer:

  • Figure A indicates inflammable substances. They can catch fire if they come in contact with oxygen-rich air.
  • Figure B indicates corrosive substances which can cause damage to tissues of skin, eyes and other delicate organs etc.
  • Both the symbols are warning signs for people to keep away or handle carefully such substances.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Question 2.
What does the symbols below indicate? Write in brief. (Board’s Model Activity Sheet)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 16
Answer:
(1) Symbol ‘A’ indicates Irritant. When skin or any delicate part of the body comes in contact with the irritant substance, it can cause harmful reaction. Especially, eyes, nasal mucosa and skin are affected by contact with corrosive substances.
(2) Symbol ‘B’ indicates toxic substance. To taste a toxic substance or even to smell it, can lead to death. The packing of these substances are therefore marked as dangerous. They should be avoided as far as possible.

Complete the paragraph by choosing the appropriate words given in the brackets:

(Capability, Rehabilitation, Commodities, Human, objectives, normalcy, amusements)
The ………. of disaster management comprise of the following aspects …………. life is saved from the disasters. People are helped to move away from the place of disasters. They are given essential ……….. by the government so that the gravity of disaster is reduced. The disaster conditions are brought back to ………… of the affected and displaced victims is done. Moreover, protective measures for future are also planned to develop ………… among the people to face any possible disasters in future.
Answer:
The objectives of disaster management, comprise of the following aspects. Human life is saved from the disasters. People are helped to move away from the place of disasters. They are given essential commodities by the government so that the gravity of disaster is reduced. The disaster conditions are brought back to normalcy. Rehabilitation of the affected and displaced victims is done. Moreover, protective measures for future are also planned to develop capability among the people to face any possible disasters in future.

Paragraph based questions:

1. Read the paragraph and answer the questions given below:
Disasters can be properly classified into three categories, viz. natural disasters, technological disasters and man-made disasters. The forces that cause natural disasters cannot be controlled. Moreover, they are becoming more frequent in the current years due to phenomena of climate change. On and off incidences of cyclones, cloud bursting, floods, etc. am creating havoc in the lives of people. Technological disasters are due to improper and callous behaviour at the different processes carried out in technical establishments. Man-made disasters are conflicts arising due to different religions, regions and-terrorism.

Questions and Answers:

Question 1.
What are three broad areas of disasters?
Answer:
Natural disasters, technological disasters and manmade disasters are three broad areas of disasters.

Question 2.
Which disasters cannot be controlled? Why?
Answer:
Natural disasters cannot be controlled as they are due to natural phenomena beyond the human power to stop them.

Question 3.
Which type of disasters were very common in Western Maharashtra in recent times? Why?
Answer:
Cloud bursting and floods were very common in Western Maharashtra caused due to climate change.

Question 4.
Give any one example of technological disaster that shook the entire India.
Answer:
Bhopal gas tragedy that occurred in 1984 was a worst disaster that shook the entire India.

Question 5.
Which types of disasters can be controlled in order to lead happy, peaceful and secured life? How?
Answer:
We have to control manmade disasters such as wars, riots, terrorism, etc. by having peaceful negotiations, respect for each human being and feeling of brotherhood among all.

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Questions based on tables and charts:

Question 1.
Complete the chart: (Text Book Page No. 111)
Different problems occur with disasters. In the concept map different effects are mentioned. Read it and fill the blank places.
Answer:
(Answers are given directly in bold.)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 17

Question 2.
Complete the chart: (Text Book Page No. 117)
Complete the chart as per the objectives of the first aidr:t
Answer:
(Answers are given directly in bold.)
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 18

Activity based questions:

Question 1.
Observe the images ‘A’ and ‘B’ and answer the following questions.
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 19
(i) Which disasters are shown in the images ?
Answer:
Image A is showing damage due to earthquake. Image B is showing house on fire.

(ii) Which primary precautions will you take in case of disaster shown in ‘A’?
Answer:
In the above disasters, the initial precautions to be taken are as follows :
Earthquake: In case of earthquake, one should immediately come out of house and stand in the open ground. If this is not possible, one has to go below table or any other cover. During collapse of the building, there should not be a head injury. This precaution is basically for prevention of dangerous injuries and saving our life. Switch off the power supply. If in journey, stay inside the vehicle.

(iii) Which type of first-aid is offered to the injured people in disaster ‘B’?
Answer:
First aid given to burn victim:

  • The person who is injured by fire should be dotised with cold water on his/her body. This will extinguish fire and give some relief caused due to inflammation. Do not break the blisters. Give water to drink.
  • Cover the burnt part by wet and moist cloth. Wash the wounds with antiseptic solution.
  • If the person is severely burnt, transfer him/her immediately to hospital.

Question 2.
Correct the following diagram:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 20
Answer:
Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management 21

Maharashtra Board Class 10 Science Solutions Part 2 Chapter 10 Disaster Management

Projects:

Project 1.
Can you tell? ( Textbook page no. 118)
Whether there had been mock drill by fire fighters under the disaster management scheme in your school? Which techniques did you see during the drill?

Project 2.
Try this: (Textbook page no. 115)
Which factors will you consider while designing the pre-disaster management plan for your school/home? Prepare a survey report with the help of your teacher.

Project 3.
Get information:
(1) Visit the district collector or Taluka Tehasildar office and collect the information about disaster management. (Textbook page no. 115)
(2) Meet the medical officer/doctor from your village and collect information about providing the first aid. (Textbook page no. 118)

Project 4.
Internet is my friend:
(1) Search for the video clips of disasters. Discuss in your class about effects of disasters and remedies over it. (Textbook page no. 110)
(2) Find out more about the activities of international organizations that work for disaster management.
(Textbook page no. 116)
1. United Nations Disaster Relief Organization.
2. United Nations Centre for Human Settlements.
3. Asian Disaster Reduction Centre.
4. Asian Disaster Preparedness Centre.
5. World Health Organization.
6. United Nations Educational, Scientific and Cultural Organization.

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Balbharti Maharashtra State Board Class 8 History Solutions Chapter 2 Europe and India Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 8 History Solutions Chapter 2 Europe and India

Class 8 History Chapter 2 Europe and India Textbook Questions and Answers

1. Rewrite the statements by choosing the appropriate options:

Question 1.
In 1453, the city of was conquered by Ottoman Turks.
(a) Venice
(b) Constantinople
(c) Rome
(d) Paris
Answer:
(b) Constantinople

Question 2.
The Industrial Revolution began in
(a) England
(b) France
(c) Italy
(d) Portugal
Answer:
(a) England

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 3.
…….. tried to put restrictions on the illegal trade of British.
(a) Siraj-ud-Daulah
(b) Mir Kasim
(c) Mir Jafar
(d) Shah Alam
Answer:
(b) Mir Kasim

2. Explain the following concepts:

Question 1.
Colonialism:
Answer:
1. Exploitation of one country by another and making it into a colony is called Colonialism.
2. On the basis of economic and military strength one country occupies a region of another country and establishes its political supremacy.
3. Many European nations established their colonies in various parts of the continents of America, Asia, Africa and Australia.
4. They grabbed the power by using force to exploit the colonies systematically. This gave rise to Imperialism.

Question 2.
Imperialism:
Answer:

  1. Imperialism means a powerful country controls other country by establishing its overall domination.
  2. The objective of imperialism is to establish more and more colonies.
  3. European countries with strong military power and imperialist aspirations enslaved the countries in Asia and Africa.
  4. Imperialism gained momentum after industrial revolution and came to an end in twentieth century.

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 3.
Age of Renaissance:
Answer:
(1) Renaissance literally means rebirth or revival. In the latter phase of medieval Europe, reformation, religious reform movement and geographical discoveries gained momentum.
(2) It was a comprehensive movement which touched all aspects of human life. The Greek and Roman traditions in art, architecture and philosophy were revived in the Age of Renaissance.
(3) Humanitarianism got great impetus.
(4) Renaissance inspired all round progress and ushered a new era in the history of world.
(5) This developments took place from 13th century to 16th century in Europe. This period is known as the Age of Renaissance.

Question 4.
Capitalism:
Answer:
1. Many traders participated in the competition for trade with Asia after the discovery of the new sea routes to the east.
2. As it was not possible to carry out trade single-handedly, it was decided by the traders to pool their resources to raise capital for trade.
3. Many trading companies like the East India Company were formed.
4. Trade with Oriental countries was very profitable and responsible for economic prosperity.
5. The ruling powers gave protection and trade concessions to these companies.
6. This led to the accumulation of wealth in Europe. This wealth was used as capital for trade and commerce which gave rise to capitalism in Europe.

3. Explain the following statements with reasons:

Question 1.
Siraj-ud-Daulah was defeated in the Battle of Plassey.
Answer:
1. The officers of the British East India Company misused the trade concessions and built fortification around the factory in Kolkata.
2. Siraj-ud-Daulah captured the factory at Kolkata.
3. This created discontent in England.
4. Robert Clive diplomatically bribed Mir Jafar, Commander in Chief of Nawab’s army and promised to make him Nawab of Bengal.
5. So. the Army of Siraj-ud-Daulah under the command of Mir Kasim did not join the battle against the British at Plassey in 1757 AD.
6. Thus, the British won the battle of Plassey by treachery and deceit.

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 2.
The European countries felt the necessity of finding new sea routes to Asia.
Answer:

  1. The Ottoman Turks captured Constantinople. the capital of Byzantine Empire. in 1453 AD.
  2. All land trade routes joining Asia and Europe passed through this city.
  3. It stopped the flow of valuable goods from the countries in the east. Therefore, the European countries felt the necessity of finding new sea routes to Asia.

Question 3.
European rulers started giving military protection and trade concessions to the trading companies.
Answer:
1. With the discovery of new sea routes to the east, trade with oriental countries became very profitable. Thus, European trade prospered.
2. Competition for trade began among many European nations.
3. The traders pooled their resources and formed trading companies like the East India Company.
4. As this trade brought economic prosperity, the European rulers started giving military protection and trade concessions to these trading companies.

4. Complete the following table.

Question 1.
Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India 1
Answer:
Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India 2

Leonardo Da Vinci :

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India 3

  1. A famous personality of the Renaissance period who was well versed in different branches of science and arts.
  2. He had mastery over varied subjects such as sculpture, architecture, mathematics, engineering, music, astronomy, etc.
  3. His paintings ‘Monalisa’ and ‘The Last Supper’ became immortal.

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Let us Know:

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India 4

Project:

Collect information and pictures about the work of famous painters, writers, scientists during renaissance period with the help of reference books and internet. Present a project on it in the classroom.

Class 8 History Chapter 2 Europe and India Additional Important Questions and Answers

Rewrite the statements by choosing the appropriate options:

Question 1.
American colonies organised the army under the leadership of and won against England.
(a) Thomas Jefferson
(b) Robert Clive
(c) George Washington
(d) Johannes Gutenberg
Answer:
(c) George Washington

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 2.
The British East India Company established its factory at
(a) Kolkata
(b) Cochin
(c) Mumbai
(d) Surat
Answer:
(d) Surat

Question 3.
Siraj-ud-Daulah was defeated because diplomatically bribed Mir Jafar.
(a) Robert Clive
(b) Lord Wellesley
(c) Lord Dalhousie
(d) Lord Cornwallis
Answer:
(a) Robert Clive

Question 4.
Tipu Sultan died in the battle of in 1799.
(a) Mysore
(b) Bengaluru
(c) Srirangapatna
(d) Buxar
Answer:
(c) Srirangapatna

Question 5.
The chieftain of rose against the British.
(a) Multan
(b) Bengal
(c) Carnatic
(d) Jhansi
Answer:
(a) Multan

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 6.
was the first Portuguese sailor who landed on the western coast of India.
(a) Christopher Columbus
(b) Bartolomeu Días
(c) Vasco-da- Gama
(d) Leonardo da Vinci
Answer:
(c) Vasco-da- Gama

Question 7.
England established colonies on the eastern coast of America.
(a) ten
(b) thirteen
(c) eight
(d) seventeen
Answer:
(b) thirteen

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Name the following:

Question 1.
Invented printing press
Answer:
Johannes Gutenberg

Question 2.
Empire of Ottoman Turks
Answer:
Byzantine

Question 3.
The Bill which laid limitations on powers of the King in England.
Answer:
Bill of Rights

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 4.
Mughal Emperor who gave permission to Britishers to establish factory at Surat.
Answer:
Emperor Jahangir

Question 5.
Came to be known as ‘World Factory’.
Answer:
England.

Answer the following in one sentence:

Question 1.
Which period in the history of Europe is known as Period of Renaissance?
Answer:
In the history of Europe, the last phase of medieval period i.e. 13th to century in Europe is known as the Period of Renaissance.

Question 2.
Name the developments that laid the foundation of modern era.
Answer:
The Renaissance, the Reformation and the geographical discoveries laid the foundation of the modern era.

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 3.
State the significance of the invention of printing press.
Answer:
It became possible to take new ideas, new concepts and knowledge to all the sections of society due to the invention of the printing press.

Question 4.
What was the effect of the Reformation movement in the area of religion?
Answer:
Individual freedom and rationalism gained importance in the area of religion due to the Reformation movement.

Question 5.
State the principles that the French Revolution gave to the world.
Answer:
The French Revolution gave the principles of liberty equality and fraternity to the world.

Question 6.
Why did the British establish East India Company?
Answer:
The British established the East India Company to carry out trade in India.

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 7.
What was the outcome of the American War of Independence?
Answer:
Due to American War of Independence, a new nation known as the United States of America with a federal government, written constitution and based on the principles of democracy was formed.

Do as Directed: 

1. Complete the concept Map:

Question 1.
Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India 5
Answer:
Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India 6

Question 2.
Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India 7
Answer:
Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India 8

2. Arrange the following events in chronological order on timeline:
1. Battle of Srirangapatna
2. Second Anglo-Sikh War
3. Battle of Buxar
4. Battle of Plassey
Answer:
Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India 9

Write short notes:

Question 1.
Leonardo-da-Vinci:
Answer:

  1. Leonardo-da-Vinci is regarded as an all round personality of the Renaissance period.
  2. He was well versed with the different branches of science and art.
  3. He had mastery over varied subjects such as sculpture, architecture, mathematics, engineering, music, astronomy, etc.
  4. But he became world-famous as a painter.
  5. His paintings ‘Monalisa’ and ‘The Last Supper’ became immortal.

Question 2.
Carnatic Wars :
Answer:

  1. There was competition among the European nationals to secure monopoly of trading rights in India.
  2. Due to this three Cainatic wars were fought between England and France.
  3. England defeated France in the third Carnatic War.
  4. Alter this, there was no strong European competitor for British East India Company in India.

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 3.
The Battle of Buxar:
Answer:

  1. Mir Kasim was replaced by Mir Jafar when he tried to put restrictions on illegal practices of the British.
  2. Mir Kasim, the deposed Nawab of Bengal, Shuja-ud-Daulah, the Nawab of Ayodhya and Mughal Emperor Shah Alam formed an affiance.
  3. They undertook a campaign to restrain the activities of the British in Bengal.
  4. They were defeated by the British in the Battle of Buxar in 1764 in Bihar.
  5. The Treaty of Allahabad was signed after the Battle of Buxar. The British secured the right to collect revenue from Bengal province by this treaty.

Explain the following statements with reasons:

Question 1.
The period between 18th and 19th century came to be known as ‘Age of Revolutions’.
Answer:
1. The British Parliament passed The Bill of Rights in 1689. It established sovereignty of Parliament and curtailed powers of the King.
2. This gave momentum to the development of Parliamentary Democracy in England.
3.  The thirteen British colonies in America won the War of Independence in 1783.
4. These thirteen colonies established the first federal republic, known as the United States of America.
5. The people of France revolted against the unjust and uncontrolled monarchy and feudalism. They established a Republic.
6. The Industrial Revolution in Europe in the latter part of the 18th century brought revolutionary changes in Europe.
7. These changes had long-lasting effect on the entire world.
8. All these revolutionary events took place during 18th and 19th century period. Hence it is known as the ‘Age of Revolutions’.

Question 2.
England was described as World Factory.
Answer:

  1. There were many revolutionary changes in the latter part of the 18th century in Europe.
  2. Many technological innovations in Europe gave enormous outputs
  3. Goods were produced with the help of machines running on steam and later on electricity. It was the dawn of the age of machines.
  4. Though the industrial revolution started in England it gradually spread to other ports of the western world.
  5. During this period. England enjoyed industrial prosperity and was described as World Factory.

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 3.
The British captured Sindh in 1843.
Answer:

  1. The British were afraid of Russian aggression on India via Afghanistan.
  2. They decided to bring Afghanistan under their control to ensure the safety of their Indian Empire.
  3. The province of Sindh was located at the Northwest frontier.
  4. All routes to Afghanistan passed through Sindh.
  5. Realising its strategic importance, the British captured Sindh in 1843.

Answer the following questions in 25 to 30 words:

Question 1.
Write about the Religious Reform Movement.
Answer:

  1. The independent intellectuals attacked the old religious ideologies and beliefs of Roman Catholic Church.
  2. The Christian priests used to give undue importance to religious rites and practices by taking advantage of the ignorance of the people.
  3. They robbed people in the name of religion.
  4. The movement which started against this is known as Religious Reform Movement.

Question 2.
What is Intellectual Revolution?
Answer:

  1. Due to Renaissance, the European society stepped out of past ignorance and blind faith.
  2. The pre-determined customs and traditions came to be seen from a critical point of view.
  3. These changes are addressed as Intellectual Revolution.

Question 3.
State the significance of French Revolution.
Answer:

  1. The French Revolution was the first event in world history in which the might of the people’s power was witnessed.
  2. It had put an end to uncontrolled and unjust monarchy and the feudalism.
  3. France became a Republican state. It gave the world principles of liberty, equality and fraternity.
  4. The spread of democratic form of government began with the French Revolution.

Question 4.
What were the changes brought about by the Industrial Revolution in the system of production?
Answer:

  1. The latter part of 18th century saw many technological innovations in Europe.
  2. The production started with the help of machines running on steam.
  3. The big factories replaced cottage industries.
  4. Handlooms were replaced by machines.
  5. New modes of transport like railways and steamer were available.

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 5.
How did the conflict between Siraj- ud-Daulah and the British start?
Answer:

  1. Siraj-ud-Daulah became the Nawab of Bengal in 1756.
  2. The British traders misused trade concessions and fortified their factories in Kolkata without seeking permission from the Nawab.
  3. So, Siraj-ud-Daulah captured the factory. This was the beginning of conflict between Siraj-ud-Daulah and the British.

Question 6.
Why were the Sikhs defeated in the First Anglo-Sikh War?
Answer:

  1. Ranjitsingh, the ruler of Punjab was succeeded by his minor son Duleep Singh.
  2. Queen Jindan assumed the reins of administration on behalf of her minor son.
  3. Taking advantage of the inability of Queen Jindan to control the officers, the British lured some of them to their side.
  4. The Sikhs attacked the British under the impression that the British would invade Punjab.
  5. Thus, the Sikhs were defeated in the first Anglo-Sikh war.

Question 7.
What brought an end to the Sikh rule in Punjab in 1849?
Answer:

  1. After the First Anglo-Sikh War Duleep Singh remained on throne, but the power rested in the hands of the British.
  2. The Sikhs could not accept the growing impact of the British over Punjab.
  3. The growing influence of the British led to the revolt by Mulraj, the chieftain of Multan.
  4. Thousands of Sikh soldiers participated in this war.
  5. The British defeated the Sikhs in the Second Anglo-Sikh war and annexed the whole of Punjab in 1849.

Answer the following questions in detail: (4 marks each)

Question 1.
Give detailed account of Renaissance.
Answer:
The foundation of Renaissance period was laid between 13th century and 16th century in Europe.

  1. It revived the Greek and Roman traditions.
  2. The changes were seen in the field of art, architecture and philosophy in Europe.
  3. Humanitarianism gained great momentum.
  4. There was a change in the outlook of treating each other as a human being.
  5. Man became the centre of all ideologies instead of religion.
  6. The sentiments and emotions of human being found expressions in the art and literature.
  7. The reform movement could be found in science and different art forms.
  8. Literature was produced in local languages for the better understanding of the people.
  9. Renaissance was a comprehensive movement which pervaded all sectors of human life.

Maharashtra Board Class 8 History Solutions Chapter 2 Europe and India

Question 2.
Give information about American War of Independence.
Answer:
1. After the discovery of American continent, the imperialist European powers took control of different regions of America and established their colonies.
2. England established 13 colonies on the East coast of America.
3. Initially, England kept nominal domination but later British Parliament laid oppressive restrictions and taxes on the colonies.
4. This created discontent among the people and the colonies revolted.
5. George Washington led the American army in the war against England.
6. The colonies won the war and established the first federal democratic republic, known as the United States of America.
7. USA became the first country in the world to have a written constitution and was based on the principles of Democracy.

Question 3.
What according to you are the advantages of Religious Reform Movement?
Answer:
With changing times we find changes in every field. Religious reforms are part of this process. I feel the following are the advantages of Religious Reforms Movement.

  1. Superstitions give way to rational thinking.
  2. Priest cannot take advantage of people’s ignorance.
  3. People will not indulge in unnecessary rituals.
  4. They will engage themselves in constructive work which will help them eventually.
  5. Some people take advantage in the name of religion and exploit others. Religious Reforms will stop such malpractices.

Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8

Balbharati Maharashtra State Board 11th Commerce Maths Solution Book Pdf Chapter 8 Linear Inequations Miscellaneous Exercise 8 Questions and Answers.

Maharashtra State Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8

Solve the following system of inequalities graphically.

Question 1.
x ≥ 3, y ≥ 2
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q1
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q1.1
The shaded portion represents the graphical solution.

Question 2.
3x + 2y ≤ 12, x ≥ 1, y ≥ 2
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q2
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q2.1
The shaded portion represents the graphical solution.

Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8

Question 3.
2x + y ≥ 6, 3x + 4y < 12
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q3
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q3.1
The shaded portion represents the graphical solution.

Question 4.
x + y ≥ 4, 2x – y ≤ 0
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q4
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q4.1
The shaded portion represents the graphical solution.

Question 5.
2x – y ≥1, x – 2y ≤ -1
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q5
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q5.1
The shaded portion represents the graphical solution.

Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8

Question 6.
x + y ≤ 6, x + y ≥ 4
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q6
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q6.1
The shaded portion represents the graphical solution.

Question 7.
2x + y ≥ 8, x + 2y ≥ 10
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q7
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q7.1
The shaded portion represents the graphical solution.

Question 8.
x + y ≤ 9, y > x, x ≥ 0
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q8
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q8.1
The shaded portion represents the graphical solution.

Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8

Question 9.
5x + 4y ≤ 20, x ≥ 1, y ≥ 2
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q9
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q9.1
The shaded portion represents the graphical solution.

Question 10.
3x + 4y ≤ 60, x +3y ≤ 30, x ≥ 0, y ≥ 0
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q10
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q10.1
The shaded portion represents the graphical solution.

Question 11.
2x + y ≥ 4, x + y ≤ 3, 2x – 3y ≤ 6
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q11
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q11.1
The shaded portion represents the graphical solution.

Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8

Question 12.
x – 2y ≤ 3, 3x + 4y ≥ 12, x ≥ 0, y ≥ 1
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q12
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q12.1
The shaded portion represents the graphical solution.

Question 13.
4x + 3y ≤ 60, y ≥ 2x, x ≥ 3, x, y ≥ 0
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q13
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q13.1
The shaded portion represents the graphical solution.

Question 14.
3x + 2y ≤ 150, x + 4y ≥ 80, x ≤ 15, y ≥ 0, x ≥ 0
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q14
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q14.1
The shaded portion represents the graphical solution.

Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8

Question 15.
x + 2y ≤ 10, x + y ≥ 1, x – y ≤ 0, x ≥ 0, y ≥ 0
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q15
Maharashtra Board 11th Commerce Maths Solutions Chapter 8 Linear Inequations Miscellaneous Exercise 8 Q15.1
The shaded portion represents the graphical solution.