Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4

Balbharti 12th Maharashtra State Board Maths Solutions Book Pdf Chapter 1 Differentiation Ex 1.4 Questions and Answers.

Maharashtra State Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4

Question 1.
Find \(\frac{d y}{d x}\) if
(i) x = at2, y = 2at
Solution:
x = at2, y = 2at
Differentiating x and y w.r.t. t, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q1 (i)

(ii) x = a cot θ, y = b cosec θ
Solution:
x = a cot θ, y = b cosec θ
Differentiating x and y w.r.t. θ, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q1 (ii)

(iii) x = \(\sqrt{a^{2}+m^{2}}\), y = log (a2 + m2)
Solution:
x = \(\sqrt{a^{2}+m^{2}}\), y = log (a2 + m2)
Differentiating x and y w.r.t. m, we get
\(\frac{d x}{d m}=\frac{d}{d m}\left(\sqrt{a^{2}+m^{2}}\right)\)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q1 (iii)

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4

(iv) x = sin θ, y = tan θ
Solution:
x = sin θ, y = tan θ
Differentiating x and y w.r.t. θ, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q1 (iv)

(v) x = a(1 – cos θ), y = b(θ – sin θ)
Solution:
x = a(1 – cos θ), y = b(θ – sin θ)
Differentiating x and y w.r.t. θ, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q1 (v)

(vi) x = \(\left(t+\frac{1}{t}\right)^{a}\), y = \(a^{t+\frac{1}{t}}\), where a > 0, a ≠ 1 and t ≠ 0
Solution:
x = \(\left(t+\frac{1}{t}\right)^{a}\), y = \(a^{t+\frac{1}{t}}\) ………(1)
Differentiating x and y w.r.t. t, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q1 (vi)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q1 (vi).1

(vii) x = \(\cos ^{-1}\left(\frac{2 t}{1+t^{2}}\right)\), y = \(\sec ^{-1}\left(\sqrt{1+t^{2}}\right)\)
Solution:
x = \(\cos ^{-1}\left(\frac{2 t}{1+t^{2}}\right)\), y = \(\sec ^{-1}\left(\sqrt{1+t^{2}}\right)\)
Put t = tan θ Then θ = tan-1t
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q1 (vii)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q1 (vii).1

(viii) x = cos-1(4t3 – 3t), y = \(\tan ^{-1}\left(\frac{\sqrt{1-t^{2}}}{t}\right)\)
Solution:
x = cos-1(4t3 – 3t), y = \(\tan ^{-1}\left(\frac{\sqrt{1-t^{2}}}{t}\right)\)
Put t = cos θ. Then θ = cos-1t
x = cos-1(4cos3θ – 3cos θ)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q1 (viii)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q1 (viii).1

Question 2.
Find \(\frac{d y}{d x}\), if
(i) x = cosec2θ, y = cot3θ at θ = \(\frac{\pi}{6}\)
Solution:
x = cosec2θ, y = cot3θ
Differentiating x and y w.r.t. θ, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q2 (i)

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4

(ii) x = a cos3θ, y = a sin3θ at θ = \(\frac{\pi}{3}\)
Solution:
x = a cos3θ, y = a sin3θ
Differentiating x and y w.r.t. θ, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q2 (ii)

(iii) x = t2 + t + 1, y = sin(\(\frac{\pi t}{2}\)) + cos(\(\frac{\pi t}{2}\)) at t = 1
Solution:
x = t2 + t + 1, y = sin(\(\frac{\pi t}{2}\)) + cos(\(\frac{\pi t}{2}\))
Differentiating x and y w.r.t. t, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q2 (iii)

(iv) x = 2 cos t + cos 2t, y = 2 sin t – sin 2t at t = \(\frac{\pi}{4}\)
Solution:
x = 2 cos t + cos 2t, y = 2 sin t – sin 2t
Differentiating x and y w.r.t. t, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q2 (iv)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q2 (iv).1

(v) x = t + 2 sin(πt), y = 3t – cos(πt) at t = \(\frac{1}{2}\)
Solution:
x = t + 2 sin(πt), y = 3t – cos(πt)
Differentiating x and y w.r.t. t, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q2 (v)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q2 (v).1

Question 3.
(i) If x = \(a \sqrt{\sec \theta-\tan \theta}\), y = \(a \sqrt{\sec \theta+\tan \theta}\), then show that \(\frac{d y}{d x}=-\frac{y}{x}\)
Solution:
x = \(a \sqrt{\sec \theta-\tan \theta}\), y = \(a \sqrt{\sec \theta+\tan \theta}\)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (i)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (i).1

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4

(ii) If x = \(e^{\sin 3 t}\), y = \(e^{\cos 3 t}\), then show that \(\frac{d y}{d x}=-\frac{y \log x}{x \log y}\)
Solution:
x = \(e^{\sin 3 t}\), y = \(e^{\cos 3 t}\)
log x = log \(e^{\sin 3 t}\), log y = log \(e^{\cos 3 t}\)
log x = (sin 3t)(log e), log y = (cos 3t)(log e)
log x = sin 3t, log y = cos 3t ….. (1) [∵ log e = 1]
Differentiating both sides w.r.t. t, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (ii)

(iii) If x = \(\frac{t+1}{t-1}\), y = \(\frac{1-t}{t+1}\), then show that y2 – \(\frac{d y}{d x}\) = 0.
Solution:
x = \(\frac{t+1}{t-1}\), y = \(\frac{1-t}{t+1}\)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (iii)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (iii).1

(iv) If x = a cos3t, y = a sin3t, then show that \(\frac{d y}{d x}=-\left(\frac{y}{x}\right)^{\frac{1}{3}}\)
Solution:
x = a cos3t, y = a sin3t
Differentiating x and y w.r.t. t, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (iv)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (iv).1
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (iv).2

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4

(v) If x = 2 cos4(t + 3), y = 3 sin4(t + 3), show that \(\frac{d y}{d x}=-\sqrt{\frac{3 y}{2 x}}\)
Solution:
x = 2 cos4(t + 3), y = 3 sin4(t + 3)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (v)

(vi) If x = log (1 + t2), y = t – tan-1t, show that \(\frac{d y}{d x}=\frac{\sqrt{e^{x}-1}}{2}\)
Solution:
x = log (1 + t2), y = t – tan-1t
Differentiating x and y w.r.t. t, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (vi)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (vi).1

(vii) If x = \(\sin ^{-1}\left(e^{t}\right)\), y = \(\sqrt{1-e^{2 t}}\), show that sin x + \(\frac{d y}{d x}\) = 0
Solution:
x = \(\sin ^{-1}\left(e^{t}\right)\), y = \(\sqrt{1-e^{2 t}}\)
Differentiating x and y w.r.t. t, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (vii)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (vii).1

(viii) If x = \(\frac{2 b t}{1+t^{2}}\), y = \(a\left(\frac{1-t^{2}}{1+t^{2}}\right)\), show that \(\frac{d x}{d y}=-\frac{b^{2} y}{a^{2} x}\)
Solution:
x = \(\frac{2 b t}{1+t^{2}}\), y = \(a\left(\frac{1-t^{2}}{1+t^{2}}\right)\)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q3 (viii)

Question 4.
(i) Differentiate x sin x w.r.t tan x.
Solution:
Let u = x sinx and v = tan x
Then we want to find \(\frac{d u}{d v}\)
Differentiating u and v w.r.t. x, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (i)

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4

(ii) Differentiate \(\sin ^{-1}\left(\frac{2 x}{1+x^{2}}\right)\) w.r.t \(\cos ^{-1}\left(\frac{1-x^{2}}{1+x^{2}}\right)\)
Solution:
Let u = \(\sin ^{-1}\left(\frac{2 x}{1+x^{2}}\right)\) and v = \(\cos ^{-1}\left(\frac{1-x^{2}}{1+x^{2}}\right)\)
Then we want to find \(\frac{d u}{d v}\)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (ii)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (ii).1

(iii) Differentiate \(\tan ^{-1}\left(\frac{x}{\sqrt{1-x^{2}}}\right)\) w.r.t \(\sec ^{-1}\left(\frac{1}{2 x^{2}-1}\right)\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (iii)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (iii).1

(iv) Differentiate \(\cos ^{-1}\left(\frac{1-x^{2}}{1+x^{2}}\right)\) w.r.t. tan-1x
Solution:
Let u = \(\cos ^{-1}\left(\frac{1-x^{2}}{1+x^{2}}\right)\) and v = tan-1x
Then we want to find \(\frac{d u}{d v}\)
Put x = tan θ. Then θ = tan-1x.
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (iv)

(v) Differentiate 3x w.r.t. logx3.
Solution:
Let u = 3x and v = logx3.
Then we want to find \(\frac{d u}{d v}\)
Differentiating u and v w.r.t. x, we get
\(\frac{d u}{d x}=\frac{d}{d x}\left(3^{x}\right)=3^{x} \cdot \log 3\)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (v)

(vi) Differentiate \(\tan ^{-1}\left(\frac{\cos x}{1+\sin x}\right)\) w.r.t. sec-1x.
Solution:
Let u = \(\tan ^{-1}\left(\frac{\cos x}{1+\sin x}\right)\) and v = sec-1x
Then we want to find \(\frac{d u}{d v}\).
Differentiating u and v w.r.t. x, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (vi)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (vi).1

Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4

(vii) Differentiate xx w.r.t. xsin x.
Solution:
Let u = xx and v = xsin x
Then we want to find \(\frac{d u}{d x}\).
Take, u = xx
log u = log xx = x log x
Differentiating both sides w.r.t. x, we get
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (vii)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (vii).1

(viii) Differentiate \(\tan ^{-1}\left(\frac{\sqrt{1+x^{2}}-1}{x}\right)\) w.r.t. \(\tan ^{-1}\left(\frac{2 x \sqrt{1-x^{2}}}{1-2 x^{2}}\right)\)
Solution:
Let u = \(\tan ^{-1}\left(\frac{\sqrt{1+x^{2}}-1}{x}\right)\) and v = \(\tan ^{-1}\left(\frac{2 x \sqrt{1-x^{2}}}{1-2 x^{2}}\right)\)
Then we want to find \(\frac{d u}{d v}\)
u = \(\tan ^{-1}\left(\frac{\sqrt{1+x^{2}}-1}{x}\right)\)
Put x = tan θ. Then θ = tan-1x and
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (viii)
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (viii).1
Maharashtra Board 12th Maths Solutions Chapter 1 Differentiation Ex 1.4 Q4 (viii).2

Maharashtra Board Class 11 Hindi व्याकरण मुहावरे

Balbharti Maharashtra State Board Hindi Yuvakbharati 11th Digest व्याकरण मुहावरे Notes, Questions and Answers.

Maharashtra State Board 11th Hindi व्याकरण मुहावरे

भाषा को स्पष्ट और प्रभावशाली बनाने के लिए मुहावरों का प्रयोग किया जाता है। मुहावरा ऐसा वाक्यांश होता है जो सामान्य अर्थ से भिन्न किसी विशेष अर्थ का बोध कराता है। उसके अंत में प्राय: किसी क्रिया का सामान्य रूप लगा होता है। इनके प्रयोग से भाषा में सरसता, सुंदरता और स्वाभाविकता आती है।

Maharashtra Board Class 11 Hindi व्याकरण मुहावर

मुहावरों की विशेषताएँ :

  1. मुहावरे लोक जीवन की धरोहर हैं।
  2. इनके अंत में प्राय: ‘ना’ होता है।
  3. मुहावरे पूर्ण वाक्य नहीं होते।
  4. मुहावरों के अर्थ प्रकट करने के लिए क्रियापद का विशेष महत्त्व होता है।
  5. मुहावरे भाषा में कलात्मक अभिव्यक्ति की एक शैली है।
  6. अन्य भाषा में मुहावरों का शाब्दिक अनुवाद नहीं हो सकता।
  7. वाक्य में प्रयुक्त होने पर मुहावरों के शब्दों में रूपांतर हो जाता है। क्रिया लिंग, वचन, कारक आदि के अनुसार बदल जाती है। मुहावरे वाक्य में सरसता, विलक्षणता, तीखापन और प्रवाह उत्पन्न करते हैं। इससे हमारी अभिव्यक्ति में निखार आता है।

मुहावरों के प्रयोग में सावधानी :

  • मुहावरों का वाक्यों में प्रयोग करते समय इनके लाक्षणिक अर्थ की पूर्ण जानकारी होनी चाहिए अन्यथा अर्थ के अनर्थ होने की संभावना रहती है।
  • मुहावरे ज्यों के त्यों वाक्य में प्रयुक्त नहीं होते इसलिए प्रयोग के अनुसार उसके लिंग, वचन, कारक के अनुसार क्रिया में परिवर्तन करना चाहिए।

पाठ में प्रयुक्त मुहावरे तथा उनके वाक्य प्रयोग :

अंकुर जमाना : प्रारंभ करना
वाक्य : भाई के मन में कपट का अंकुर ऐसा जम गया था कि अब वह वृक्ष बन गया था।

अपने पैरों पर खड़ा होना : आत्मनिर्भर होना।
वाक्य : पढ़-लिखकर सीया अपने पैरों पर खड़ा होना चाहती है।

Maharashtra Board Class 11 Hindi व्याकरण मुहावर

आँच न आने देना : संकट न आने देना।
वाक्य : गरीबी में भी माता-पिता ने अपने बच्चों पर आँच न आने दी

आँखों में सैलाब उमड़ना : फूट-फूटकर रोना।
वाक्य : पति की मृत्यु पर पत्नी की आँखों में सैलाब उमड़ आया था।

आँखें फटी रहना : आश्चर्यचकित रह जाना।
वाक्य : बालक कृष्ण के मुख में ब्रह्मांड को देखकर यशोदा मैया की आँखें फटी रह गईं।

आईने में मुँह देखना : अपनी योग्यता जाँचना।
वाक्य : आईने में मुँह देखकर काम करना चाहिए ताकि सफलता का फल प्राप्त हो।

आसमान के तारे तोड़ना : असंभव कार्य करना।
वाक्य : यह प्रतियोगिता जीतकर भार्गव ने आसमान के तारे तोड लाए हैं।

ईंट का जवाब पत्थर से देना : कड़ा जवाब देना।
वाक्य : हमारी टीम ने खेल जीतने के लिए ईंट का जवाब पत्थर से दिया

उधेड़ वुन में लगना : सोच-विचार करना।
वाक्य : पैसों की उधेड-बून में लगे लोग जीवन का मजा नहीं उठा पाते।

एक आँख से देखना : सामान्य रूप से देखना, पक्षपात न करना।
वाक्य : माँ अपने सभी बच्चों को एक आँख से देखती है

Maharashtra Board Class 11 Hindi व्याकरण मुहावर

एक और एक ग्यारह होना : एकता में बल होना।
वाक्य : जब दोनों भाई एक और एक ग्यारह हो गए तो उनका बुरा चाहने वाले उनका कुछ नहीं बिगाड़ सके।

कदम बढ़ाना : प्रगति करना।
वाक्य : समस्या को पीछे छोड़कर कदम बढाना जीवन का सही मार्ग है।

कमर कसना : पूरी तरह तैयार होना।
वाक्य : बरसाती समस्याओं से निपटने के लिए हमने बरसात आने से पहले ही कमर कस ली है।

कमर सीधी करना : आराम करना, सुस्ताना।
वाक्य : इतना पसीना बहाने के बाद कमर सीधी करने का मौका मिला तो नई समस्या खड़ी हो गई।

कलई खुलना : भेद प्रकट होना, राज या रहस्य खुलना।
वाक्य : कोई कितना भी धूर्त क्यों न हो एक न एक दिन उसकी कलई खुल जाती है।

कान देना : ध्यान से सुनना।
वाक्य : अध्यापक की बात पर विद्यार्थी कान देंगे तो सफलता अवश्य मिलेगी।

किस्मत खुलना : भाग्य चमकना।
वावय : आज तो मेरी किस्मत खुल गई जो आपके दर्शन हुए।

गले का हार होना : अत्यंत प्रिय होना।
वाक्य : छोटा शेख घर में सभी के गले का हार था।

Maharashtra Board Class 11 Hindi व्याकरण मुहावर

गागर में सागर भरना : थोड़े में बहुत कहना।
वाक्य : बिहारी जी ने अपने दोहों में गागर में सागर भर दिया है इस बात को सभी हिंदी प्रेमियों ने स्वीकारा है।

घी के दीये जलाना : खुशी मनाना।
वाक्य : जब श्रीराम जी 14 वर्ष के वनवास के बाद अयोध्या लौटे तो अयोध्या वासियों ने घी के दीये जलाए

चिकना घड़ा होना : निर्लज्ज होना, किसी बात का असर न होना।
वाक्य : रमेश को समझाना बेकार है क्योंकि वह तो चिकना घड़ा है।

चुटकी लेना : व्यंग्य करना।
वाक्य : चुटकी लेने की आदत कभी-कभी भारी पड़ जाती है।

जबान देना : वचन देना।
वाक्य : रमेश ने अगर जबान दी है तो वह जरूर निभाएगा।

झंडे गाड़ना : पूर्ण रूप से प्रभाव जमाना।
वाक्य : छोटी उम्र में ही शिवाजी महाराज ने 12 मावलों के साथ मुगलो के आधे किले पर झंडे गाड़ दिए थे।

डंका पीटना : प्रचार करना।
वाक्य : अपनी छोटी सी सफलता का भी डंका पीटने में सीया पीछे नहीं हटती।

तितर-बितर होना : बिखर जाना।
वाक्य : माँ की मृत्यु के बाद परिवार तितर-बितर हो गया।

Maharashtra Board Class 11 Hindi व्याकरण मुहावर

हजारों दीप जल उठना : आनंदित हो उठना।
वाक्य : विदेश जाने के लिए वीजा मिल गया तो रमेश के मन में हजारों दीप जल उठे

रुपये दाँत से पकड़ना : कंजूसी करना।
वाक्य : इस महँगाई के दौर में हर कोई रुपये दाँत से पकडकर जी रहा है।

दूध का दूध, पानी का पानी करना : इंसाफ करना, न्याय करना।
वाक्य : रंगे हाथ पकड़े जाने पर सच्चाई सबके सामने आ गई और दूध का दूध और पानी का पानी हो गया।

नाम कमाना : यश प्राप्त करना।
वाक्य : कड़ी मेहनत करके राज ने नाम कमाया इसलिए सब उसकी इज्जत करते हैं।

पाँचों उँगलियाँ घी में होना : हर तरफ से लाभ होना।
वाक्य : अब बेटा भी बराबरी से काम करने लगा तो लाला जी की पाँचो उँगलियाँ घी में है।

फला न समाना : अत्यधिक प्रसन्न होना।
वाक्य : मनोकामना पूरी होने पर सीया फूली न समाई

वीडा उठाना : किसी काम को करने की ठान लेना।
वाक्य : देश के नागरिकों को पर्यावरण सुरक्षा का बीड़ा उठाना होगा।

वाँछे खिलना : अत्यधिक प्रसन्न होना।
वाक्य : चुनाव जीतने के बाद नेता की बाँछे खिल उठीं।

मरजीवा होना : कठोर साधना से लक्ष्य तक पहुँचने वाला होना।
वाक्य : अलवर में सात नदियों को जीवित कर श्री राजेंद्र सिंह जी मरजीवा हो गए

Maharashtra Board Class 11 Hindi व्याकरण मुहावर

मल्हार गाना : आनंद मनाना।
वाक्य : समय पर बारिश होने से किसान मल्हार गाने लगे

राई का पहाड़ बनाना : बात को बढ़ा-चढ़ाकर कहना।
ताक्य : रमेश ने बात को इस ढंग से बताया कि राई का पहाड बन गया।

लोहा मानना : श्रेष्ठता स्वीकार करना।
वाक्य : औरंगजेब भी शिवाजी के युद्ध कौशल का लोहा मानता था।

सफेद झूठ बोलना : पूरी तरह से झूठ बोलना।
वाक्य : दुष्ट प्रवृत्ति के लोग सफेद झूठ बोलने से बाज नहीं आते।

सिर खपाना : ऐसे काम में समय लगाना जिसमें कोई लाभ नहीं।
वाक्य : सुबह से शाम तक सिर खपाते रहे लेकिन पिताजी ने दी पहेली हल नहीं कर पाए।

सिर पर सेहरा बाँधना : अधिक यश प्राप्त करना।
वाक्य : काव्य गायन प्रतियोगिता में रमेश केवल सफल ही नहीं हुआ बल्कि उसके सिर पर सेहरा बँधा।

सोना उगलना : बहुत अधिक लाभ होना।
वाक्य : मेरे देश की मिट्टी ऐसी उपजाऊ है कि सोना उगलती है।

सौ वात की एक वात : असली बात, निचोड़।
वाक्य : सौ बात की एक बात कहूँ, मुझे बेटा-बेटी में भेदभाव बिलकुल पसंद नहीं।

Maharashtra Board Class 11 Hindi व्याकरण मुहावर

हाथ-पैर मारना : बहुत प्रयत्न करना।
वाक्य : इधर-उधर हाथ-पैर मारने के बाद मेरा लोन सेंक्शन हुआ।

हौसले बुलंद होना : उत्साह बने रहना।
वाक्य : शरीर कमजोर हो गया है लेकिन अभी भी राय साहब के हौसले बुलंद हैं

श्रीगणेश करना : कार्य आरंभ करना।
वाक्य : दो पैसे जमा होते ही रमेश ने अपने व्यवसाय का श्रीगणेश किया

दाँतों तले उँगली दबाना : आश्चर्यचकित होना।
वाक्य : रणभूमि में अभिमन्यु की वीरता देखकर कौरवों ने दाँतों तले उँगली दबाई

अंधे की लाठी होना : निराधार का सहारा बनाना।
वाक्य : मदर टेरेसा भारत आकर अंधे की लाठी बनकर अपना कार्य करने लगी।

आग से खेलना : मुसीबत मोल लेना।
वाक्य : आज़ादी की लड़ाई लड़ते समय आग से खेलकर कई देशवासियों ने अपना घर-परिवार दाँव पर लगा दिया था।

मुट्ठी गर्म करना : रिश्वत देना।
वाक्य : भ्रष्टाचार की जड़ें इतनी गहराई तक पहुँच गई हैं कि जब तक मुट्ठी गर्म न करो कोई काम ही नहीं करता।

इतिश्री होना : समाप्त होना।
वाक्य : 15 अगस्त 1947 को देश आज़ाद हुआ और अंग्रेज शासन की इतिश्री हुई

उड़ती चिड़िया पहचानना : तीक्ष्ण बुद्धि वाला होना।
वाक्य : बीरबल उडती चिडिया पहचान लेते थे और हर समस्या को सुलझाने में अकबर की सहायता करते है।

Maharashtra Board Class 11 Hindi व्याकरण मुहावर

हथेली पर सरसों जमाना : कठिन कार्य करना।
वाक्य : दुश्मनों की छावनी में जाकर उनके भेद जानना मतलब हथेली पर सरसों जमाना है।

कंचन बरसना : धन-दौलत से परिपूर्ण होना।
वाक्य : कभी हमारे देश में कंचन बरसता था परंतु विदेशी आक्रमण ने इसे खोखला कर दिया।

कानों कान खबर न होना : बिल्कुल पता न चलना।
वाक्य : सेठ जी ने बेटी का विवाह कर दिया लेकिन किसी को कानों कान खबर न हुई

गाल बजाना : अपनी प्रशंसा आप करना।
वाक्य : मोहन अपनी सफलता पर खूब गाल बजाता था परंतु परिणाम सामने आने पर शर्मिंदा हुआ।

घड़ों पानी पड़ना : बहुत लज्जित होना।
वाक्य : बेटे की करतूतों का भेद खुलते ही पिता पर घडों पानी पड़ गया।

चिकनी-चुपड़ी बातें करना : चापलूसी करना, मीठी-मीठी बातें बोलना।
वाक्य : अब चिकनी-चुपड़ी बातें करने से कोई लाभ नहीं, सच्चाई सब जान गए हैं।

छाती पर साँप लोटना : ईर्ष्या होना।
वाक्य : गीता के कक्षा में प्रथम आने की खबर सुनते ही मीता की छाती पर साँप लोटने लगा।

तूती बोलना : प्रभाव होना।
वाक्य : मंत्री महोदय के खास आदमी होने की वजह से उसकी तूती बोलती है।

Maharashtra Board Class 11 Hindi व्याकरण मुहावर

दो टुक जवाब देना : स्पष्ट बोलना।
वाक्य : मैंने आपसे दो टुक बात कर ली है, आगे आपकी मर्जी।

नुक्ताचीनी करना : आलोचना करना।
वाक्य : हर बात में नुक्ताचीनी करने की आदत के चलते रमेश के दोस्त कम और दुश्मन ही अधिक है।

Maharashtra Board Class 11 Hindi व्याकरण काल परिवर्तन

Balbharti Maharashtra State Board Hindi Yuvakbharati 11th Digest व्याकरण काल परिवर्तन Notes, Questions and Answers.

Maharashtra State Board 11th Hindi व्याकरण काल परिवर्तन

काल परिवर्तन के लिए सबसे पहले क्रिया का जानना अनिवार्य है।
क्रिया : वाक्य में जिस शब्द से किसी कार्य का करना या होना ज्ञात होता है। उसे क्रिया कहते हैं।
जैसे : पढ़ना, लिखना, बोलना, कहना, सुनना, जानना आदि। क्रिया हमेशा काल से जुड़ी रहती है।
काल : काल क्रिया के उस रूपांतरण को कहते हैं जिससे कार्य का समय और उसके पूर्ण अथवा अपूर्ण अवस्था का बोध हो।
जैसे : राम खाता है, राम जाएगा, मोहन ने किताब पढ़ा आदि।

Maharashtra Board Class 11 Hindi व्याकरण काल परिवर्तन 1

काल के भेद : क्रिया के मुख्यत: तीन काल है।

  • वर्तमान काल
  • भूतकाल
  • भविष्यत् काल

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

  1. सामान्य वर्तमान काल (Simple Present Tense)
  2. अपूर्ण वर्तमान काल (Present Continuous Tense)
  3. पूर्ण वर्तमान काल (Present Perfect Tense)
  4. सामान्य भूतकाल (Simple Past Tense)
  5. अपूर्ण भूतकाल (Past Continuous Tense)
  6. पूर्ण भूतकाल (Past Perfect Tense)
  7. सामान्य भविष्यत् काल (Simple Future Tense)

विशेष : हिंदी में अपूर्ण और पूर्ण भविष्यत् काल नहीं होता है।

(1) सामान्य वर्तमान काल : सामान्य वर्तमान काल उसे कहते हैं जिसमें क्रिया के होने का बोध होता है। सामान्य वर्तमान काल में कर्ता के लिए ‘ने’ विभक्ति नहीं लगती। क्रिया कर्ता के लिंग-वचन के अनुसार होती है। यदि क्रिया के अंत में ता / ती / ते + है / हैं / हो / हूँ लगा हो तो वह वाक्य सामान्य वर्तमान काल का होता है।
जैसे –

  • मोनिका विद्यालय जाती है।
  • मैं चलता हूँ।
  • तुम बहुत सोते हो।
  • बच्चे खेलते हैं।

कभी-कभी है / हैं / हो / हूँ अपने आप में क्रिया होते हैं जो सामान्य वर्तमान काल में होते हैं। जैसे –

  • वह मेधावी छात्र है।
  • वे राजनीतिज्ञ हैं।
  • तुम बहुत शरारती हो।
  • मैं मूर्ख नहीं हूँ।

(2) अपूर्ण वर्तमान काल : क्रिया के जिस रूप से इस बात का बोध होता है कि कार्य वर्तमान में जारी है या हो रहा है वह अपूर्ण वर्तमान काल कहलाता हैं। जब क्रिया के साथ रहा / रही / रहे + है / हैं / हो / हूँ लगा हो तो वह वाक्य अपूर्ण वर्तमान काल का कहलाता है।

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

जैसे –

  • भीड़ जमा हो रही है।
  • लोग मतदान कर रहे हैं।
  • माँ खाना पका रही है।
  • मैं शहर जा रहा हूँ।
  • तुम किसे डाँट रहे हो?

(3) पूर्ण वर्तमान काल : क्रिया के जिस रूप से वर्तमान काल में कार्य के पूर्ण होने का ज्ञान होता है वह वाक्य पूर्ण वर्तमान काल कहलाता हैं।
प्राय: सामान्य भूतकाल के वाक्य में आगे है / हैं / हो / हूँ लगाकर पूर्ण वर्तमान काल बनाते हैं। क्रिया के साथ चुका / चुकी / चुके या / यी / ये / + है / हैं / हो / हूँ लगाकर भी पूर्ण वर्तमान काल बनाते हैं।

जैसे –

  • यह गीत लताजी ने गाया है।
  • माँ तीर्थ यात्रा पर गई है।
  • महात्मा गाँधी जी असहयोग आंदोलन का मार्ग सिखा गए हैं।
  • मैं सबकुछ जान चुका हूँ।
  • तुम कहाँ से आए हो?
  • अब सबकुछ खत्म हो चुका है।
  • सभी सदस्य खाना खा चुके हैं।

(4) सामान्य भूतकाल : क्रिया के जिस रूप से कार्य के बीते हुए समय में होने का बोध होता है वह सामान्य भूतकाल कहलाता है। इसमें प्राय: क्रिया का भूतकालिक रूप लगता है। लिंग, वचन के अनुसार क्रिया के मूल रूप में आ / ए / ई / ईं जोड़ने से सामान्य भूतकाल के रूप बनते हैं। जैसे – खाया, पढ़ा, सोया, विचारा, सोए, गाए, निकले, पूछे, नाची, चढ़ी, पाई, सोची आदि।

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

उदाहरणार्थ :

  • रमा कार्यालय गई।
  • बच्चे परीक्षा देने गए।
  • इतने प्रयास पर भी बात नहीं बनी।

विशेष: कभी-कभी था / थी / थे भी जब क्रिया का रूप लेते हैं तो वाक्य सामान्य भूतकाल में होता है।

  • रानी लक्ष्मीबाई बहुत महान थीं।
  • वह एक शरारती छात्र था।
  • जनक जी सीता के पिता थे।

(5) अपूर्ण भूतकाल : क्रिया के जिस रूप से यह बोध हो कि कार्य भूतकाल में हो रहा था तो वह वाक्य अपूर्ण भूतकाल कहलाता है। इसमें प्राय: क्रिया के साथ रहा / रही / रहे + था / थी / थे लगाकर अपूर्ण भूतकाल बनाते हैं।
जैसे –

  • आजादी की लड़ाई चल रही थी।
  • सारे खिलाड़ी अच्छा खेल रहे थे।.
  • अरुण परीक्षा की तैयारी कर रहा था।

विशेष : यदि क्रिया के अंत में ता / ती / ते के साथ था / थी / थे लगा हो तो वाक्य अपूर्ण भूतकाल में होता है।
जैसे –

  • वह हमेशा पढता था।
  • उसे सबकी सेवा करनी पड़ती थी।
  • वे जंगल में घूमते थे।

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

(6) पूर्ण भूतकाल : जिस वाक्य में क्रिया के बीते हुए समय में पूर्ण होने का आभास हो वह पूर्ण भूतकाल कहलाता है। सामान्य भूतकाल के आगे था / थी / थे लगाकर पूर्ण भूतकाल बनाते हैं। कभी-कभी क्रिया के साथ चुका / चुकी / चुके + या / ई / ए / या / + था / थी / थे लगाकर भी पूर्ण भूतकाल बनाते हैं।
जैसे –

  • मोहन पर्वतारोहण के लिए गया था।
  • माँ ने कई बार बेटे को समझाया था।
  • सारे छात्रों ने कहानी लिखी थी।
  • रमा खाना बना चुकी थी।
  • देव देश के लिए कई बार जेल जा चुका था।
  • पुलिस के जवान मोर्चे पर डॅट चुके थे।

(7) सामान्य भविष्यत्काल : इसमें क्रिया के भविष्य में होने का ज्ञान होता है। क्रिया के अंत में गा / गी / गे जोड़कर सामान्य भविष्यत काल बनाते हैं।
जैसे –

  • माँ तीर्थ यात्रा पर जाएगी।
  • वह खेल प्रतियोगिता में भाग लेगा।
  • इस खबर से सभी चौकन्ने हो जाएँगे।

विशेष : भविष्य में क्रिया की केवल सामान्य, संभाव्य तथा हेतु भविष्यत् अवस्थाएँ होती हैं। इसमें अपूर्ण और पूर्ण की बात नहीं होती है।

प्रश्न 1.
कोष्ठक की सूचना के अनुसार निम्न वाक्यों का काल परिवर्तन करके वाक्य फिर से लिखिए :

(1) उषा की आँखों में हजारों दीप जल उठे। (सामान्य वर्तमानकाल)
उत्तर :
उषा की आँखों में हजारों दीप जल उठते हैं।

(2) दुकानदार ने रद्दी तौलकर किनारे रखी। (अपूर्ण वर्तमानकाल)
उत्तर :
दुकानदार रद्दी तौलकर किनारे रख रहा है।

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

(3) वे मुझे योगा के फायदे समझाते हैं। (पूर्ण वर्तमानकाल)
उत्तर :
उन्होंने मुझे योगा के फायदे समझाए हैं।

(4) मैं मनोरंजन के लिए टी. वी. ऑन करता हूँ। (सामान्य भूतकाल)
उत्तर :
मैंने मनोरंजन के लिए टी.वी. ऑन किया।

(5) चिल्ला-चिल्लाकर स्पीकर पर सूचना दी गई। (अपूर्ण भूतकाल)
उत्तर :
चिल्ला-चिल्लाकर स्पीकर पर सूचना दी जा रही थी।

(6) वे सामाजिक और आर्थिक समस्याओं को प्रमुखता देते हैं। (पूर्ण भूतकाल)
उत्तर :
उन्होंने सामाजिक और आर्थिक समस्याओं को प्रमुखता दी थी।

(7) वहाँ एक बड़े पेड़ की छाँह में उन्होंने वास किया। (सामान्य भविष्यकाल)
उत्तर :
वहाँ एक बड़े पेड़ की छाँह में वे वास करेंगे।

(8) तुमने यह कैसे जाना कि कोई वन है। (सामान्य वर्तमानकाल)
उत्तर :
तुम यह कैसे जानते हो कि कोई वन है।

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

(9) मछुवी रानी बनकर महल में घूम रही है। (अपूर्ण भूतकाल)
उत्तर :
मछुवी रानी बनकर महल में घूम रही थी।

(10) मल्लिका ने देखा तो आँखें फटी रह गईं। (सामान्य भविष्यकाल)
उत्तर :
मल्लिका देखेगी तो आँखें फटी रह जाएँगी।

Maharashtra Board Class 11 Hindi व्याकरण वाक्य शुद्धिकरण

Balbharti Maharashtra State Board Hindi Yuvakbharati 11th Digest व्याकरण वाक्य शुद्धिकरण Notes, Questions and Answers.

Maharashtra State Board 11th Hindi व्याकरण वाक्य शुद्धीकरण

वाक्य में लिंग, वचन, कारक तथा मानकवर्तनी की गलतियाँ सही करने हेतु यह प्रश्न पूछा जाता है। वाक्य में गलतियाँ ढूँढ़कर उन्हें सही करते समय इस बात का भी ध्यान रखना चाहिए कि अन्य गलतियाँ न करते हुए शुद्ध वाक्य ही लिखना है।

Maharashtra Board Class 11 Hindi व्याकरण वाक्य शुद्धिकरण

प्रश्न 1.
निम्नलिखित वाक्य शुद्ध करके फिर से लिखिए :

(1) घर पकवान के खुशबू में तरबतर था।
उत्तर :
घर पकवान की खुशबू से तरबतर था।

(2) बबन के आँखों में खुशी के आँसू छलक आएँ।
उत्तर :
बबन की आँखों में खुशी के आँसू छलक आए

(3) बबलू की नजर उन किताबों पे थी जो रद्दी में बेचा जा रहा था।
उत्तर :
बबलू की नजर उन किताबों पर थी जो रद्दी में बेची जा रही थी

(4) वह ने जगह बताकर मेरा हस्ताक्षर करवा लिया।
उत्तर :
उसने जगह बताकर मेरे हस्ताक्षर करवा लिए

(5) एक लम्बी कतार ने मेरा ध्यान आकर्शित कर लिया।
उत्तर :
एक लंबी कतार ने मेरा ध्यान आकर्षित कर लिया।

(6) व्यस्तता का यह आलम है कि आदमी सड़क पे चलते चलते फोन कर रहा है।
उत्तर :
व्यस्तता का यह आलम है कि आदमी सड़क पर चलते-चलते फोन कर रहा है।

(7) प्रेमचंद किसी अक धारा या वाद से बँध कर नहीं चले।
उत्तर :
प्रेमचंद किसी एक धारा या वाद में बँधकर नहीं चले।

Maharashtra Board Class 11 Hindi व्याकरण वाक्य शुद्धिकरण

(8) उनका मूल उद्देश समाज के क्रमिक विकास का दर्शन कराना है।
उत्तर :
उनका मूल उद्देश्य समाज के क्रमिक विकास के दर्शन कराना है।

(9) वह भयावने वन को तो मैं ने भी नहीं देखी।
उत्तर :
उस भयावने वन को तो मैंने भी नहीं देखा

(10) गुस्से से कही ग्यान हासिल होता है?
उत्तर :
गुस्से में कहीं ज्ञान हासिल होता है?

(11) दो नए पत्तों का जोड़ी आसमान के तरफ मुस्कराती हुई देख रही थी।
उत्तर :
दो नए पत्तों की जोड़ी आसमान की तरफ मुस्कराती हुई देख रही थी।

(12) तुम रोज उसी एक घाट पे क्यों जाता है?
उत्तर :
तुम रोज उसी एक घाट पर क्यों जाते हो?

(13) इच्चाओं की क्या कुछ सीमा है?
उत्तर :
इच्छाओं की क्या कोई सीमा है?

Maharashtra Board Class 11 Hindi व्याकरण वाक्य शुद्धिकरण

(14) वह ने मछुवे को यह क्यों नहीं कहा।
उत्तर :
उसने मछुवे से यह क्यों नहीं कहा।

(15) वेणी प्रसाद भी उसी को जा मिला और स्कूल घर में ही उठवा लाए।
उत्तर :
वेणी प्रसाद भी उसी से जा मिला और स्कूल घर पर ही उठवा लाए।

(16) उन्होंने नारी के उध्दार के लिए अपना स्वर्वस्व न्यौछावर कर दिया था।
उत्तर :
उन्होंने नारी के उद्धार के लिए अपना सर्वस्व न्यौछावर कर दिया था।

(17) आज भी बच्चों को र्सिफ पाणी पिला कर सुलाना पड़ेगा।
उत्तर :
आज भी बच्चों को सिर्फ पानी पिलाकर सुलाना पड़ेगा।

(18) रेगिस्थान में बर्फ पड़ रहा है।
उत्तर :
रेगिस्तान में बर्फ पड़ रही है।

Maharashtra Board Class 11 Hindi व्याकरण वाक्य शुद्धिकरण

(19) आप तो ठीक-ठाक काम-धंदेवाले लगते हो।
उत्तर :
आप तो ठीक-ठाक काम-धंधे वाले लगते हैं।

(20) हिन्दी में निपुणता प्राप्त व्यक्ति सफल हो सकती है।
उत्तर :
हिंदी में निपुणता प्राप्त व्यक्ति सफल हो सकता है।

(21) इंग्रजी से हिंदी अनुवादक की माँग तेजी से बडी।
उत्तर :
अंग्रेजी से हिंदी अनुवादक की माँग तेजी से बढ़ी

(22) कुछ महत्त्वपूर्ण घटना की जानकारी देने के लिए पर्लेख तैयार किए जाते हैं।
उत्तर :
कोई महत्त्वपूर्ण घटना की जानकारी देने के लिए प्रलेख तैयार किया जाता है।

(23) आज विश्वीकरण के युग में समाचार का बहोत महत्व है।
उत्तर :
आज वैश्वीकरण के युग में समाचार का बहुत महत्त्व है।

(24) मुद्रित शोधण के कई विशिष्ट संकेत होते हैं।
उत्तर :
मुद्रित शोधन के कुछ विशिष्ट संकेत होते हैं।

Maharashtra Board Class 11 Hindi व्याकरण वाक्य शुद्धिकरण

(25) यह ध्यान रखे की घोड़दौड़ में खुदका घोड़ा सब के आगे रहे।
उत्तर :
यह ध्यान रखे कि घुडदौड़ में खुद का घोड़ा सबसे आगे रहे।

(26) इस क्शेत्र में रोजगार का विपुल औसर उपलब्द है।
उत्तर :
इस क्षेत्र में रोजगार के विपुल अवसर उपलब्ध हैं।

(27) कम्प्यूटर को तो ज्ञान के श्रोत के रूप में देख रहे हैं।
उत्तर :
कंप्यूटर को तो ज्ञान के स्त्रोत के रूप में देख रहे हैं।

(28) भारत में इंटरनेट का कार्य और महत्त्व निरन्तर वढ़ रहे हैं।
उत्तर :
भारत में इंटरनेट का कार्य और महत्त्व निरंतर बढ़ रहा है।

(29) जवाब में आपको एक ई-मेल आती है जिसमें एक ‘लिंक’ दिया जाता है।
उत्तर :
जवाब में आपको एक ई-मेल आता है जिसमें एक ‘लिंक’ दी जाती है।

Maharashtra Board Class 11 Hindi व्याकरण वाक्य शुद्धिकरण

(30) उज्वल भविष्य के लिए सव को ई-अद्ययन का उपयोग करना चाहिए।
उत्तर :
उज्ज्वल भविष्य के लिए सभी को ई-अध्ययन का उपयोग करना चाहिए।

Maharashtra Board Class 11 Hindi व्याकरण अलंकार (शब्दालंकार)

Balbharti Maharashtra State Board Hindi Yuvakbharati 11th Digest व्याकरण अलंकार (शब्दालंकार) Notes, Questions and Answers.

Maharashtra State Board 11th Hindi व्याकरण अलंकार (शब्दालंकार)

अलंकार का अर्थ है – आभूषण, गहने, सजावट आदि। सुंदर वस्त्र, आभूषण जैसे मानव शरीर की शोभा बढ़ाते हैं वैसे ही काव्य में अलंकार काव्य की शोभा बढ़ाते हैं। शब्द और अर्थ के माध्यम से अलंकार कविता का आकर्षण बढ़ाते हैं।

Maharashtra Board Class 11 Hindi व्याकरण अलंकार (शब्दालंकार)

अलंकार के भेद : अलंकार के मुख्य भेद तीन हैं।

  1. शब्दालंकार
  2. अर्थालंकार
  3. उभयालंकार

शब्दालंकार : जहाँ पर काव्य के सौंदर्य में शब्दों के माध्यम से वृद्धि होती है वहाँ शब्दालंकार होता है।
शब्दालंकार के भेद : शब्दालंकार के चार भेद हैं।

  1. अनुप्रास
  2. यमक
  3. श्लेष
  4. वक्रोक्ति

1. अनप्रास : जहाँ काव्य में किसी वर्ण की या अनेक वर्षों की दो या दो से अधिक बार आवृत्ति होती है, वहाँ अनुप्रास अलंकार होता है।
उदा. :
लाली मेरे लाल की जित देखो तित लाल।
लाली देखन मैं चली मैं भी हो गई लाल।।

– कबीर

मुदित महापति मंदिर आए।
सेवक सचिव सुमंत्रु बोलाए।।

– तुलसीदास

विमल वाणी ने वीणा ली
कमल कोमल कर में सप्रीत।

– जयशंकर प्रसाद

रघुपति राघव राजा राम
पतित पावन सीता राम।

– लक्ष्मणाचार्य

Maharashtra Board Class 11 Hindi व्याकरण अलंकार (शब्दालंकार)

2. यमक : काव्य में किसी शब्द की आवृत्ति हो और हर बार उस शब्द का अर्थ भिन्न हो वहाँ यमक अलंकार होता है। काव्य का सौंदर्य बढ़ाने हेतु यहाँ शब्द की बार-बार आवृत्ति होती है।
उदा. :
तो पर बारों उरबसी, सुनि राधिके सुजान।
तू मोहन के उर बसी, हवै उरबसी समान।। – बिहारी

  • उरबसी = अप्सरा
  • उर्वशी उरबसी = हृदय में बसी हुई।

माला फेरत जग मुआ, गया न मन का फेर।
कर का मनका डारि के, मन का मनका फेर।। – कबीर

  • मन का = हृदय से
  • मनका = माला का मोती।

काली घटा का घमंड घटा, नभ मंडल तारक वृंद बुझे

  • घटा = बादलों का समूह,
  • घटा = कम हुआ।

जगती जगती की मूक प्यास
रूपसि, तेरा घन केश पाश। – महादेवी वर्मा

  • जगती = जाग जाती है।
  • जगती = जगत या संसार

Maharashtra Board Class 11 Hindi व्याकरण अलंकार (शब्दालंकार)

3. श्लेष : श्लेष का शाब्दिक अर्थ है – मिलना अथवा चिपकना। जहाँ अनेकार्थक शब्दों के प्रयोग से चमत्कार उत्पन्न होता है, वहाँ श्लेष अलंकार होता है। अर्थात एक ही शब्द के अनेक अर्थ होते हैं।

उदा. :
मधुबन की छाती को देखो,
सूखी कितनी इसकी कलियाँ – हरिवंशराय बच्चन

  • कलियाँ = फूल की कलियाँ
  • कलियाँ = यौवन से पहले की अवस्था

चरण धरत चिंता करत, चितवत चारहु ओर।
सुबरन को ढूँढ़त फिरत, कवि, व्यभिचारी, चोर।। – केशवदास

  • सुवरन = अच्छा वर्ण (शब्द) (कवि के लिए)
  • सुबरन = सुंदर रंग (व्यभिचारी के लिए)
  • सुबरन = स्वर्ण (चोर के लिए)

रो-रोकर, सिसक-सिखककर कहता मैं करूण कहानी
तुम सुमन नोचते, सुनते करते जानी अनजानी।

  • सुमन = सुंदर मन
  • सुमन = फूल

यह दीप अकेला स्नेह भरा
है गर्व भरा मदमाता पर
इसको भी पंक्ति को दे दो – अज्ञेय

  • स्नेह = तैल
  • स्नेह = प्रेम

Maharashtra Board Class 11 Hindi व्याकरण अलंकार (शब्दालंकार)

4. वक्रोक्ति : वक्रोक्ति शब्द वक्र + उक्ति से बना है जिसका सहज अर्थ है टेढ़ा कथन। वक्ता के कथन का श्रोता द्वारा अभिप्रेत आशय से भिन्न अर्थ लगाया जाता है। वहाँ वक्रोक्ति अलंकार होता है।
उदा. :
‘एक कबूतर देख हाथ में पूछा कहाँ अपर है?
कहाँ अपर कैसा? वह उड़ गया सपर है।’

यहाँ अपर का अर्थ दूसरा कबूतर के संबंध में पूछा गया था पर जवाब में अपर का अर्थ बिना पंख वाला लिया गया है।

पर्वतजा ! पशुपाल कहाँ है?
कमला ! जमुना तट ले धेनु।

पार्वती और लक्ष्मी में हास-परिहास हो रहा है। लक्ष्मी जी ने पूछा पशुपाल (पशुओं के स्वामी – शिव) कहाँ है? पार्वती जी ने परिहास करते हुए कहा यमुना नदी के तट पर गायों को चराने गए हैं (विष्णु जी का कृष्णावतार)

आने को मधुमास, न आएँगे प्रियतम !
आने को मधुमास, न आएँगे प्रियतम?

Maharashtra Board Class 11 Hindi व्याकरण अलंकार (शब्दालंकार)

यहाँ प्रथम पंक्ति में प्रियतम के न आने की बात कही है तो द्वितीय पंक्ति में प्रश्नचिह्न लगाकर प्रियतम के अवश्य आने की (कैसे नहीं आएंगे, अवश्य आएँगे) बात कही है।

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C)

Balbharti 12th Maharashtra State Board Maths Solutions Book Pdf Chapter 3 Indefinite Integration Ex 3.2(C) Questions and Answers.

Maharashtra State Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C)

I. Evaluate:

Question 1.
\(\int \frac{3 x+4}{x^{2}+6 x+5} d x\)
Solution:
Let I = \(\int \frac{3 x+4}{x^{2}+6 x+5} d x\)
Let 3x + 4 = A[\(\frac{d}{d x}\)(x2 + 6x + 5)] + B
= A(2x + B) + B
∴ 3x + 4 = 2Ax + (6A + B)
Comparing the coefficient of x and constant on both sides, we get
2A = 3 and 6A + B = 4
∴ A = \(\frac{3}{2}\) and 6(\(\frac{3}{2}\)) + B = 4
∴ B = -5
3x + 4 = \(\frac{3}{2}\) (2x + 6) – 5
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q1

Question 2.
\(\int \frac{2 x+1}{x^{2}+4 x-5} d x\)
Solution:
Let I = \(\int \frac{2 x+1}{x^{2}+4 x-5} d x\)
Let 2x + 1 = A[\(\frac{d}{d x}\)(x2 + 4x – 5)] + B
2x + 1 = A(2x + 1) + B
∴ 2x + 1 = 2Ax + (4A + B)
Comparing the coefficient of x and constant on both sides, we get
4A = 2 and 4A + B = 4
∴ A = \(\frac{3}{2}\) and 6(\(\frac{3}{2}\)) + B = 4
∴ B = -5
∴ 2x + 1 = \(\frac{3}{2}\)(2x + 1) – 5
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q2
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q2.1

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C)

Question 3.
\(\int \frac{2 x+3}{2 x^{2}+3 x-1} d x\)
Solution:
Let I = \(\int \frac{2 x+3}{2 x^{2}+3 x-1} d x\)
Let 2x+ 3 = A[\(\frac{d}{d x}\)(2x2 + 3x – 1)] + B
2x + 1 = A(4x + 3) + B
∴ 2x + 1 = 4Ax + (3A + B)
Comparing the coefficient of x and constant on both sides, we get
4A = 2 and 3A + B = 3
∴ A = \(\frac{1}{2}\) and 3(\(\frac{1}{2}\)) + B = 3
∴ B = \(\frac{3}{2}\)
∴ 2x + 3 = \(\frac{1}{2}\)(4x + 3) + \(\frac{3}{2}\)
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q3
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q3.1

Question 4.
\(\int \frac{3 x+4}{\sqrt{2 x^{2}+2 x+1}} d x\)
Solution:
Let I = \(\int \frac{3 x+4}{\sqrt{2 x^{2}+2 x+1}} d x\)
Let 3x + 4 = A[\(\frac{d}{d x}\)(2x2 + 2x + 1)] + B
∴ 3x + 4 = A (4x + 2) + B
∴ 3x + 4 = 4Ax + (2A + B)
Comparing the coefficient of x and the constant on both the sides, we get
4A = 3 and 2A + B = 4
∴ A = \(\frac{3}{4}\) and 2(\(\frac{3}{4}\)) + B = 4
∴ B = \(\frac{5}{2}\)
∴ 3x + 4 = \(\frac{3}{4}\) (4x + 2) + \(\frac{5}{2}\)
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q4
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q4.1

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C)

Question 5.
\(\int \frac{7 x+3}{\sqrt{3+2 x-x^{2}}} d x\)
Solution:
Let I = \(\int \frac{7 x+3}{\sqrt{3+2 x-x^{2}}} d x\)
Let 7x + 3 = A[\(\frac{d}{d x}\)(3 + 2x – x2)] + B
7x + 3 = A(2 – 2x) + B
∴ 7x + 3 = -2Ax + (2A + B)
Comparing the coefficient of x and constant on both the sides, we get
-2A = 7 and 2A + B = 3
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q5
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q5.1

Question 6.
\(\int \sqrt{\frac{x-7}{x-9}} d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q6
Comparing the coefficients of x and constant term on both sides, we get
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q6.1
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q6.2

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C)

Question 7.
\(\int \sqrt{\frac{9-x}{x}} d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q7
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q7.1
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q7.2

Question 8.
\(\int \frac{3 \cos x}{4 \sin ^{2} x+4 \sin x-1} d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q8
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q8.1

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C)

Question 9.
\(\int \sqrt{\frac{e^{3 x}-e^{2 x}}{e^{x}+1}} d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q9
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q9.1
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(C) Q9.2

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

Balbharti Maharashtra State Board Hindi Yuvakbharati 11th Digest व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक Notes, Questions and Answers.

Maharashtra State Board 11th Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

रस का शाब्दिक अर्थ है – निचोड़। रस काव्य की आत्मा है। काव्य को पढ़ने या सुनने से जिस आनंद की अनुभूति होती है उसे रस कहा जाता है। विभाव, अनुभाव तथा संचारी भावों के संयोग से रस की निष्पत्ति होती है।

रस के चार अंग या अवयव हैं :

  1. स्थायी भाव
  2. विभाव
  3. अनुभाव
  4. संचारी भाव

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

स्थायी भाव : स्थायी भाव का तात्पर्य है प्रधान भाव। जो भावना स्थिर और सार्वभौम होती है उसे स्थायी भाव कहते हैं। स्थायीं भाव से ही रस का जन्म होता है। स्थायी भाव 11 माने गए हैं और रसों की संख्या भी 11 मानी जाती हैं। वे इस प्रकार हैं :

रसस्थायी भाव
1. शृंगाररति (प्रेम)
2. शांतनिर्वेद
3. करूणशोक
4. हास्यहास
5. वीरउत्साह
6. रौद्रक्रोध
7. भयानकभय
8. बीभत्सघृणा, जुगुप्सा
9. अद्भुतआश्चर्य
10. वात्सल्यममत्व
11. भक्तिअनुराग

विभाव : जो व्यक्ति, वस्तु अन्य व्यक्ति के हृदय में भाव जगाते हैं उन्हें विभाव कहते हैं। इनके आश्रय से ही रस प्रकट होते हैं। ये दो तरह के होते हैं – आलंबन विभाव तथा उद्दीपन विभाव। जिसका सहारा पाकर स्थायी भाव जगते हैं उसे आलंबन विभाव कहते हैं और जिन वस्तुओं या परिस्थितियों को देखकर स्थायी भाव उद्दीप्त होते हैं उन्हें उद्दीपन विभाव कहते हैं।

अनुभाव : वे गुण और क्रियाएँ जिनसे रस का बोध होता है अनुभाव कहलाते हैं। इनकी संख्या 8 मानी गई हैं – स्तंभ, स्वेद, रोमांच, स्वर भंग, कंप, विवर्णता (रंगहीनता), अश्रु, प्रलय। वाणी और अभिनय द्वारा इनसे अर्थ प्रकट होता है।

संचारी भाव : मन में संचरण करने वाले अर्थात आने-जाने वाले भावों को संचारी भाव कहते हैं। ये भाव पानी के बुलबुलों की तरह उठते और विलीन हो जाते हैं। इनकी संख्या 33 मानी गई है। हर्ष, विषाद, भय, लज्जा, ग्लानी, चिंता, शंका, मोह, गर्व, उत्सुकता, उग्रता, निद्रा, स्वप्न, आलस्य, मद, उन्माद आदि।

वात्सल्य रस : जब काव्य में अपनों से छोटों के प्रति स्नेह या ममत्व का भाव अभिव्यक्त होता है, वहाँ वात्सल्य रस का निर्माण होता है। माता का पुत्र के प्रति स्नेह, बड़ों का बच्चों के प्रति प्रेम, गुरु का शिष्य के प्रति प्रेम, भाई का भाई के प्रति या बहन का भाई के प्रति स्नेह आदि की परिपुष्टि होकर वात्सल्य रस का निर्माण होता है।

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

वात्सल्य रस के अंग (अवयव)

  • स्थायी भाव : ममत्व, वत्सलता।
  • अवलंबन : पुत्र, शिशु, शिष्य आदि।
  • उद्दीपन : बाल लीलाएँ, बाल हठ आदि।
  • अनुभाव : बालक को गोद में लेना, थपथपाना, सिर पर हाथ फेरना आदि।

संचारी भाव : हर्ष, गर्व, मोह, चिंता, आवेश आदि।
उदा. :
मैया मोहिं दाऊ बहुत खिझायो।
मोसो कहत मोल को लीन्हों तू जसुमति कब जायो।।

– सूरदास

मधुरता मय था मृदु बोलना।
अमृत सिंचित सी मुस्कान थी।
समद थी जनमानस मोहती।
कमल लोचन की कमनीयता।।

– अयोध्यासिह उपाध्याय ‘हरिऔध’

वीर रस : किसी पद में वर्णित प्रसंग हमारे हृदय में ओज, उमंग, उत्साह का भाव उत्पन्न करते हैं, तब वीर रस का निर्माण होता है। ये भाव शत्रुओं के प्रति विद्रोह, अधर्म, अत्याचार का विनाश असहायों को कष्ट से मुक्ति दिलाने में व्यंजित होते हैं।

वीर रस के अंग (अवयव)

  • स्थायी भाव : उत्साह।
  • अवलंबन : अत्याचारी शत्रु।
  • उद्दीपन : शत्रु का पराक्रम, शत्रु का अहंकार, रणभेरी, यश की इच्छा आदि।
  • अनुभाव : गर्वपूर्ण उक्ति, प्रहार, रोमांच आदि।
  • संचारी भाव : आवेग, उग्रता, गर्व, चपलता आदि।

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

उदा. :
आजादी की राह चले तुम,
सुख से मुख को मोड़ चले तुम,
“नहीं रहूँ परतंत्र किसी का’
तेरा घोष अति प्रखर है
राजा तेरा नाम अमर है।

– डॉ. जयंत निर्वाण

बुझी राख मत हमें समझना, अंगारों के गोले हैं।
देश आन पर मिटने वाले, हम बारूदी शोले हैं।

– सुरेंद्रनाथ सिंह

करूण रस : किसी प्रियजन या इष्ट के कष्ट, शोक, दुख, मृत्युजनित प्रसंग के कारण अथवा किसी प्रकार की अनिष्ट आशंका के कारण हृदय में पीड़ा या क्षोभ का भाव उत्पन्न होता है, वहाँ करूण रस की अभिव्यंजना होती है।

करूण रस के अंग (अवयव)

  • स्थायी भाव : शोक।
  • आलंबन : विनष्ट व्यक्ति अथवा वस्तु आदि।
  • उद्दीपन : आलंबन का दाहकर्म, इष्ट के गुण तथा उससे संबंधित वस्तुओं का वर्णन आदि।
  • अनुभाव : भूमि पर गिरना, नि:श्वास, छाती पीटना, रूदन, प्रलाप, मूर्छा, कंप आदि।
  • संचारी भाव : निर्वेद, मोह, व्याधि, ग्लानि, स्मृति श्रम, विषाद, जड़ता, दैन्य, उन्माद आदि।

उदा. :
हाय राम कैसे झेलें हम अपनी लज्जा अपना शोक,
गया हमारे ही हाथों से अपना राष्ट्र पिता परलोक

– अज्ञात

मरते कोमल वत्स यहाँ
बचती न जवानी परदेशी!
माया के मोहक वन की
क्या कहूँ कहानी परदेशी?

– रामधारी सिंह ‘दिनकर’

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

हास्य रस : जब काव्य में किसी की विचित्र वेशभूषा, अटपटी आकृति, क्रिया कलाप, रूप-रंग, वाणी एवं व्यवहार को देखकर, सुनकर, पढ़कर हृदय में हास्य का भाव उत्पन्न होता है, वहाँ हास्य रस की निर्मिति होती है। स्वभावत: सबसे अधिक सुखात्मक रस है यह।

हास्य रस के अंग (अवयव)

  • स्थायी भाव : हास
  • आलंबन : विकृत वेशभूषा, आकार एवं चेष्टाएँ
  • उद्दीपन : आलंबन की अनोखी आकृति, बातचीत, चेष्टाएँ आदि।
  • अनुभाव : आश्रय की मुस्कान, नेत्रों का मिचमिचाना, अट्टाहास आदि।
  • संचारी भाव : हर्ष, आलस्य, निद्रा, चपलता, कंपन, उत्सुकता

उदा. :
मच्छर, खटमल और चूहे घर मेरे मेहमान थे,
मैं भी भूखा और भूखे ये मेरे भगवान थे।
रात को कुछ चोर आए, सोचकर चकरा गए
हर तरफ चूहे ही चूहे, देखकर घबरा गए।

– हुल्लड़ मुरादाबादी

सुबह से शाम तक पप्पू जप रहा भगवान का नाम।
खा रहा बार-बार बादाम, लगा रहा कोई बाम।।
घर वाले समझ गए कि आ गया है एग्जाम।
आ गया है एग्जाम अत: पप्पू का सिर है जाम।।

– सुरेंद्र रघुवंशी

भयानक रस : जब काव्य में भयानक वस्तुओं या दृश्यों के प्रत्यक्षीकरण के फल स्वरूप हृदय में भय का भाव उत्पन्न होता है, तब भयानक रस की अभिव्यंजना होती है। इसके अंतर्गत कंपन, पसीना छूटना, मुँह सूखना, चिंता आदि भाव उत्पन्न होते हैं।

भयानक रस के अंग (अवयव)

  • स्थायी भाव : भय
  • आलंबन : भयंकर पशु, स्थान, वस्तु के दर्शन आदि।
  • उद्दीपन : भयानक वस्तु का स्वर, भयंकर स्वर, ध्वनि, चेष्टाएँ, डरावना पन आदि।
  • अनुभाव : कंपन, पसीना छूटना, मुँह सूखना, चिंता होना, रोमांच, मूर्छा, पलायन, रूदन आदि।
  • संचारी भाव : दैन्य, सभ्रम, चिंता, सम्मोह आदि।

Maharashtra Board Class 11 Hindi व्याकरण रस वात्सल्य, वीर, करुण, हास्य, भयानक

उदा. :
चिंग्घाड भगा भय से हाथी,
लेकर अंकुश पिलावन गिरा।
झटका लग गया, फटी झालर
हौदा गिर गया, निशान गिरा।।

– अज्ञात

आगे पहाड़ को पा धारा रूकी हुई है।
बल-पुंज केसरी की ग्रीवा झुकी हुई है।
अग्निस्फुलिंग रज का बुझ ढेर हो रहा है।
है रो रही जवानी, अंधेर हो रहा है।

– रामधारी सिंह ‘दिनकर’

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B)

Balbharti 12th Maharashtra State Board Maths Solutions Book Pdf Chapter 3 Indefinite Integration Ex 3.2(B) Questions and Answers.

Maharashtra State Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B)

I. Evaluate the following:

Question 1.
\(\int \frac{1}{4 x^{2}-3} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q1
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q1.1

Question 2.
\(\int \frac{1}{25-9 x^{2}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q2

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B)

Question 3.
\(\int \frac{1}{7+2 x^{2}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q3

Question 4.
\(\int \frac{1}{\sqrt{3 x^{2}+8}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q4
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q4.1

Question 5.
\(\int \frac{1}{\sqrt{11-4 x^{2}}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q5

Question 6.
\(\int \frac{1}{\sqrt{2 x^{2}-5}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q6
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q6.1

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B)

Question 7.
\(\int \sqrt{\frac{9+x}{9-x}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q7

Question 8.
\(\int \sqrt{\frac{2+x}{2-x}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q8
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q8.1

Question 9.
\(\int \sqrt{\frac{10+x}{10-x}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q9
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q9.1

Question 10.
\(\int \frac{1}{x^{2}+8 x+12} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q10

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B)

Question 11.
\(\int \frac{1}{1+x-x^{2}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q11

Question 12.
\(\int \frac{1}{4 x^{2}-20 x+17} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q12
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q12.1

Question 13.
\(\int \frac{1}{5-4 x-3 x^{2}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q13
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q13.1

Question 14.
\(\int \frac{1}{\sqrt{3 x^{2}+5 x+7}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q14
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q14.1

Question 15.
\(\int \frac{1}{\sqrt{x^{2}+8 x-20}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q15

Question 16.
\(\int \frac{1}{\sqrt{8-3 x+2 x^{2}}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q16

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B)

Question 17.
\(\int \frac{1}{\sqrt{(x-3)(x+2)}} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q17
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q17.1

Question 18.
\(\int \frac{1}{4+3 \cos ^{2} x} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q18

Question 19.
\(\int \frac{1}{\cos 2 x+3 \sin ^{2} x} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q19
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q19.1

Question 20.
\(\int \frac{\sin x}{\sin 3 x} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) I Q20

II. Integrate the following functions w. r. t. x:

Question 1.
\(\int \frac{1}{3+2 \sin x} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q1
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q1.1

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B)

Question 2.
\(\int \frac{1}{4-5 \cos x} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q2
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q2.1

Question 3.
\(\int \frac{1}{2+\cos x-\sin x} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q3
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q3.1

Question 4.
\(\int \frac{1}{3+2 \sin x-\cos x} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q4

Question 5.
\(\int \frac{1}{3-2 \cos 2 x} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q5
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q5.1

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B)

Question 6.
\(\int \frac{1}{2 \sin 2 x-3} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q6
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q6.1

Question 7.
\(\int \frac{1}{3+2 \sin 2 x+4 \cos 2 x} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q7
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q7.1

Question 8.
\(\int \frac{1}{\cos x-\sin x} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q8

Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B)

Question 9.
\(\int \frac{1}{\cos x-\sqrt{3} \sin x} \cdot d x\)
Solution:
Maharashtra Board 12th Maths Solutions Chapter 3 Indefinite Integration Ex 3.2(B) II Q9

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Balbharti Maharashtra State Board 11th Biology Important Questions Chapter 13 Respiration and Energy Transfer Important Questions and Answers.

Maharashtra State Board 11th Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 1.
What is Phosphorylation?
Answer:
It is the formation of ATP, by the addition of inorganic phosphate to ADP.
ADP + Pi → ATP
Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer 1

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 2.
What are the different ways of Phosphorylation?
Answer:
Phosphorylation occurs in three different ways – photophosphorylation, substrate-level phosphorylation, and oxidative phosphorylation.

Question 3.
What is Substrate-level phosphorylation? Where does it occur?
Answer:
Substrate-level phosphorylation is a direct phosphorylation of ADP by transfer of a phosphate group from any suitable substrate. It occurs in cytoplasm of the cells and matrix of mitochondria.

Question 4.
What is oxidative phosphorylation? Mention the site of this reaction.
Answer:
In oxidative phosphorylation ATP is synthesize by using the energy released during the oxidation of substrates like NADH + H+ and FADH2. This occurs on the inner mitochondrial membrane only.

Question 5.
When is ATP hydrolysed?
Answer:
ATP is hydrolysed whenever energy is required for any metabolic reactions.

Question 6.
What is respiration?
Answer:
Respiration is a catabolic process wherein complex organic substrate is oxidized to simple components to generate biological energy, i.e. ATP.

Question 7.
Give an example for anabolic and catabolic process.
Answer:
Anabolic process- Photosynthesis (Biosynthetic process).
Caiabolic process- Respiration (Breakdown process).

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 8.
Name the following.

  1. The substrate that undergoes oxidation during oxidative phosphorylation
  2. The phosphorylation that occurs only in inner mitochondria! membrane
  3. Two ways of cellular respiration

Answer:

  1. NADH+H+ and FADH2
  2. Oxidative phosphorylation
  3. Anaerobic and aerobic respiration

Question 9.
What is anaerobic respiration?
Answer:
1. Anaerobic respiration is the cellular respiration that does not involve the atmospheric oxygen. It is also called as fermentation.
2. It involves glycolysis where the product of glycolysis i.e. pyruvate is converted to either lactic acid or ethanol.

Question 10.
What is glycolysis? Describe various steps involved in glycolysis.
OR
Describe the process involved in formation of pyruvic acid from glucose molecule.
OR
What is glycolysis? Describe the process of glycolysis with the help of schematic representation.
Answer:
Glycolysis is a process where glucose is broken down into two molecules of pyruvic acid, hence called glycolysis (glucose-breaking). It is common to both aerobic and anaerobic respiration. It occurs in the cytoplasm of the cell. It involves ten steps.
Glycolysis consists of two major phases:
1. Preparatory phase (1-5 steps).
2. Payoff phase (6-10 steps).
1. Preparatory phase:
a. In this phase, glucose is phosphorylated twice by using two ATP molecules and a molecule of fructose 1,6-bisphosphate is formed.
b. It is then cleaved into two molecules of glyceraldehyde-3-phosphate and dihydroxy acetone phosphate. These two molecules are 3-carbon carbohydrates (trioses) and are isomers of each other.
c. Dihydroxy acetone phosphate is isomerised to second molecule of glyceraldehyde-3-phosphate.
d. Therefore, two molecules of glyceraldehyde-3- phosphate are formed.
e. Preparatory phase of glycolysis ends.

2. Payoff phase:
a. In this phase, both molecules of glyceraldehyde-3-phosphate are converted to two molecules of 1,3- bisphoglycerate by oxidation and phosphorylation. Here, the phosphorylation is brought about by inorganic phosphate instead of ATP.
b. Both molecules of 1, 3-bisphosphoglycerate are converted into two molecules of pyruvic acid through series of reactions accompanied with release of energy. This released energy is used to produce ATP (4 molecules) by substrate-level phosphorylation.
Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer 2

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 11.
Write down the overall chemical reaction of a process in which glucose in broken down to two molecules of pyruvic acid.
Answer:
Overall reaction of glycolysis:
Glucose + 2 ATP + 2iP + 4 ADP + 2 NAD+ → 2 Pyruvate + 2 ADP + 4 ATP + 2 NADH + 2 Ha+ + 2 H2O

Question 12.
Write explanatorv notes on: Glycolysis
Answer:
Glycolysis is a process where glucose is broken down into two molecules of pyruvic acid, hence called glycolysis (glucose-breaking). It is common to both aerobic and anaerobic respiration. It occurs in the cytoplasm of the cell. It involves ten steps.
Glycolysis consists of two major phases:
1. Preparatory phase (1-5 steps).
2. Payoff phase (6-10 steps).
1. Preparatory phase:
a. In this phase, glucose is phosphorylated twice by using two ATP molecules and a molecule of fructose 1,6-bisphosphate is formed.
b. It is then cleaved into two molecules of glyceraldehyde-3-phosphate and dihydroxy acetone phosphate. These two molecules are 3-carbon carbohydrates (trioses) and are isomers of each other.
c. Dihydroxy acetone phosphate is isomerised to second molecule of glyceraldehyde-3-phosphate.
d. Therefore, two molecules of glyceraldehyde-3- phosphate are formed.
e. Preparatory phase of glycolysis ends.

2. Payoff phase:
a. In this phase, both molecules of glyceraldehyde-3-phosphate are converted to two molecules of 1,3- bisphoglycerate by oxidation and phosphorylation. Here, the phosphorylation is brought about by inorganic phosphate instead of ATP.
b. Both molecules of 1, 3-bisphosphoglycerate are converted into two molecules of pyruvic acid through series of reactions accompanied with release of energy. This released energy is used to produce ATP (4 molecules) by substrate-level phosphorylation.

Question 13.
How glycolysis is regulated?
Answer:
Glycolysis is strongly regulated by the complex interplay between ATP consumption, NADH2 regeneration and regulation of various glycolytic enzymes like hexokinase, PFK-1, pyruvate kinase, etc. Besides, it is also controlled by hormones like glucagon, epinephrine and insulin.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 14.
Where does glycolysis take place in a cell?
Answer:
Glycolysis takes place in the cytoplasm of a cell.

Question 15.
What are the products of cleavage in glycolysis?
Answer:
Dihydroxyacetone phosphate (DHAP) and 3-phosphoglyceraldehyde (3-PGAL) are the products of cleavage in glycolysis.

Question 16.
Where does dehydration occur in glycolysis?
Answer:
In glycolysis, dehydration occurs when 2-Phosphoglyceric acid loses a water molecule (dehydration) to form phosphoenol pyruvic acid in presence of the enzyme enolase.

Question 17.
Name the process which is common to both aerobic and anaerobic respiration.
Answer:
Glycolysis is common to both aerobic and anaerobic respiration.

Question 18.
Name the enzymes that catalyse the irreversible reactions.
Answer:
Hexokinase, Phosphoffuctokinase, Phosphoglycerate kinase and Pyruvate kinase are the enzymes that catalyse the irreversible reactions.

Question 19.
Where glycolysis is the only source of energy production?
Answer:
Glycolysis is only source of energy production in erythrocytes, renal medulla, brain and sperm.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 20.
Which type of muscle fibres are rich in myoglobin?
Answer:
Red muscles are rich in myoglobin.

Question 21.
Which type of muscle fibre mainly performs anaerobic respiration?
Answer:
White muscle fibres mainly performs anaerobic respiration.

Question 22.
What is lactic acid fermentation?
Answer:
It is a process of anaerobic respiration where the pyruvic acid undergoes reduction by addition of one proton and two electrons donated by NADH+H+ to form lactic acid as the product and NAD+ as the byproduct of oxidation. Skeletal muscles usually derive energy by this process. It is represented as follows:
Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer 3

Question 23.
What is the fate of pyruvate in yeast?
Answer:
Yeast shows both aerobic and anaerobic respiration depending upon the presence or absence of oxygen.
1. In absence of oxygen, the pyruvate undergoes anaerobic respiration where it is decarboxylated to acetaldehyde. The acetaldehyde is then reduced by NADH+H to ethanol and carbon dioxide. This type of anaerobic respiration is termed alcoholic fermentation.
2. In the presence of oxygen however, it can respire aerobically to produce C02 and H20.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 24.
What is alcoholic fermentation?
Answer:
Alcoholic fermentation is a type of anaerobic respiration where the pyruvate is decarboxylated to acetaldehyde. The acetaldehyde is then reduced by NADH+H+ to ethanol and Carbon dioxide. Since ethanol is produced during the process, it is termed alcoholic fermentation. It is represented as follows:
Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer 4

Question 25.
Name the process of respiration which does not involve intake of oxygen (02) and release of carbon dioxide (C02).
Answer:
Lactic acid fermentation is the process of anaerobic respiration which does not involve intake of oxygen (02) and release of carbon dioxide (C02).

Question 26.
Why yeast stops multiplying in the culture after alcoholic fermentation?
Answer:
After alcoholic fermentation the multiplication of yeast stops because the alcohol formed during the process kills the yeast cells.

Question 27.
What is aerobic respiration?
Answer:

  1. Aerobic respiration occurs in the presence of free molecular oxygen during oxidation of glucose.
  2. In this type of respiration, the glucose is completely oxidized to C02 and H20 with release of large amount of energy.
  3. It involves glycolysis, acetyl CoA formation (connecting link reaction), Krebs cycle, electron transfer chain reaction and terminal oxidation.

Question 28.
Where does aerobic respiration occur in eukaryotic cell?
Answer:
Aerobic respiration occurs in the mitochondria in eukaryotes.

Question 29.
Explain the conversion of pyruvic acid to acetyl CoA.
OR
Describe the connecting link between glycolysis and Krebs cycle.
Answer:

  1. The conversion of pyruvic acid to acetyl CoA is an oxidative decarboxylation reaction.
  2. It is catalyzed by a multienzyme complex-pyruvate dehydrogenase complex (PDH). This enzyme is present in mitochondria of eukaryotes and cytosol of prokaryotes.
  3. This reaction is called as ‘connecting link’ reaction between glycolysis and Krebs cycle.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer 5

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 30.
Name the following.
1. Which enzymes converts pyruvic acid to acetyl CoA?
2. Name the coenzyme required by pyruvate dehydrogenase.
Answer:
1. Pyruvate dehydrogenase
2. Thiamin (vitamin Bi)

Question 31.
Why is acetyl Co-A called connecting link between glycolysis and Krebs cycle?
Answer:

  1. The conversion of pyruvic acid to acetyl CoA is an oxidative decarboxylation reaction.
  2. It is catalyzed by a multienzyme complex-pyruvate dehydrogenase complex (PDH). This enzyme is present in mitochondria of eukaryotes and cytosol of prokaryotes.
  3. This reaction is called as ‘connecting link’ reaction between glycolysis and Krebs cycle.

Question 32.
Why vitamin Bi is important for maintaining good health?
Answer:
1. Pyruvate dehydrogenase (PDH) requires thiamin (vitamin Bi) as a co-enzyme. It cannot function in absence of vitamin B1.
2. Thiamin deficiency causes many disorders such as pyruvic acidosis and lactic acidosis, which are life threatening conditions. Hence, it is required to maintain good health.

Question 33.
Describe Citric acid cycle.
OR
With the help of schematic representation explain Krebs cycle.
Answer:

  1. Krebs cycle or citric acid cycle is the second phase of aerobic respiration which takes place in the matrix of the mitochondria.
  2. The acetyl CoA formed during the link reaction undergoes aerobic oxidation.
  3. This cycle serves a common oxidative pathway for carbohydrates, fats and proteins.
  4. In mitochondria pyruvic acid is decarboxylated and the remaining 2-carbon fragment is combined with a molecule of coenzyme A to form acetyl-CoA.
  5. This reaction is an oxidative decarboxylation process and produces H+ ions and electrons along with carbon dioxide.
  6. During the process NAD+ is reduced to NADH+H+.
  7. P-oxidation of fatty acids also produces acetyl-CoA as the end product.
  8. Acetyl-CoA from both sources is condensed with oxaloacetic acid to form citric acid. Citric acid is oxidized step-wise by mitochondrial enzymes, releasing carbon dioxide.
  9. Regeneration of oxaloacetic acid occurs to complete the cycle.
  10. There are four steps of oxidation in this cycle, catalyzed by dehydrogenases (oxidoreductases) using NAD+ or FAD+ as the coenzyme.
  11. The coenzymes are consequently reduced to NADH+H+ and FADH2 respectively. These transfer their electrons to the mitochondrial respiratory chain to get reoxidised.
  12. One molecule of GTP (ATP) is also generated for every molecule of citric acid oxidized.

Question 34.
What is the site of Krebs cycle in mitochondria?
Answer:
Krebs cycle takes place in the mitochondrial matrix.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 35.
Match the following:

Column IColumn IIColumn III
1. Krebs cycle(a) 1,3-Bisphosphoglycerate → 3-Phosphoglycerate(p) Pyruvate dehydrogenase
2. Glycolysis(b) Succinyl CoA → Succinate(q) NADH dehydrogenase
3. ETS(c) Pyruvic acid → Acetyl CoA(r) Two ATP are produced
4. Link reaction(d) Transfer of electrons from Complex to Ubiquinone(s) Succinyl CoA – synthetase

Answer:

Column IColumn IIColumn III
1. Krebs cycle(b) Succinyl CoA → Succinate(s) Succinyl CoA – synthetase
2. Glycolysis(a) 1,3-Bisphosphoglycerate → 3-Phosphoglycerate(r) Two ATP are produced
3. ETS(d) Transfer of electrons from Complex I to Ubiquinone(q) NADH dehydrogenase
4. Link reaction(c) Pyruvic acid → Acetyl CoA(p) Pyruvate dehydrogenase

Question 36.
Explain ETS.
OR
Illustrate the mechanism of electron transport system.
OR
Give an account of ATP generation steps during ETS.
OR
Explain the mechanism of electron transportation system (ETS).
OR
Explain terminal oxidation.
Answer:

  1. NADH2 and FADH2 produced during glycolysis, connecting link reaction and Krebs cycle are oxidized with the help of various electron carriers and enzymes.
  2. These carriers and enzymes are arranged on inner mitochondrial membrane in the form of various complexes as complex I, II, III, VI and V.
  3. NADH+H+ is oxidised by NADH dehydrogenase (complex I) and it’s electrons are transferred to ubiquinone (coenzyme Q-CoQ) present on inner membrane of mitochondria. Reduced ubiquinone is called as ubiqunol.
  4. FADH2 is oxidised by complex II (Succinate dehydrogenase) and these electrons are also transferred to CoQ.
  5. The open end of the glass tube (delivery tube) is dipped into lime water containing in a test tube (Tube B).
  6. Stoppers of both the tubes are fitted tightly to prevent leakage of gases. First test tube is placed in warm water (37° C-38° C) in a beaker.
  7. Lime water gradually turns milky, indicating the evolution of carbon dioxide from the yeast preparation.
  8. Level of the lime water in the delivery tube does not rise, showing that there is no decline in volume of gas in test tube A and consequently no utilization of oxygen by yeast. Preparation is stored for a day or two.
  9. When we open the stopper of tube A we will notice a smell of alcohol indicating the formation of ethanol.
  10. From this activity it may be inferred that yeast respires anaerobically to ferment glucose to ethanol and carbon dioxide.

Question 37.
Explain the significance of electron transport system.
Answer:
Significance of ETS:

  1. Major amount of energy is generated through ETS or terminal oxidation in the form of ATP molecules.
  2. Per glucose molecule 38 ATP molecules are formed, out of which 34 ATP molecules are produced through ETS.
  3. Oxidized coenzymes such as NAD and FAD are regenerated from their reduced forms (NADH+H+ and FADH2) for recycling.
  4. In this process, energy is released in a controlled and stepwise manner to prevent any damage to the cell.
  5. ETS produces water molecules.

Question 38.
What is oxidative phosphorylation?
Answer:
Oxidative phosphorylation: It is a metabolic pathway that uses energy released by the oxidation of substrates to produce ATP.

  1. Oxidative phosphorylation takes place in the mitochondrial membrane.
  2. Many intermediate products during respiration are oxidised and release 2H+.
  3. The released hydrogen is trapped by NAD+ or FAD+.
  4. Electrons pass through electron transport system to produce ATP and metabolic water.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 39.
Give the balance sheet of ATP formed in aerobic respiration.
Answer:

Step of RespirationConsumptionProductionTotalNet
benefit
Substrate level phosphorylation1 Oxidative Phosphorylation
NADH+ H+FADH2Total
Glycolysis242 × 3 = 6___________6108
Pyruvate → AcetylCoA__________________________2 × 3 = 6___________666
Krebs cycle_______________1 × 2 = 26 × 3 = 182×2 = 4222424
Total2            [6]            30 + 4 = [34]            m            38

Question 40.
With the help of an experiment explain how yeast respires anaerobically.
Answer:
Respiration in yeast can be demonstrated with the help of an experiment.
Anaerobic respiration in yeast:

  1. A pinch of dry baker’s yeast suspended in water containing 10ml of 10% glucose in a test tube (test tube A).
  2. The surface of the liquid is covered with oil to prevent entry of air and the test tube is closed tightly with rubber stopper to prevent leakage.
  3. One end of a short-bent glass tube is inserted through it to reach the air inside the tube.
  4. Other end of the glass tube is connected by a polyethylene or rubber tubing to another bent glass tube fitted into a stopper.
  5. The open end of the glass tube (delivery tube) is dipped into lime water containing in a test tube
    (Tube B).
  6. Stoppers of both the tubes are fitted tightly to prevent leakage of gases. First test tube is placed in warm water (37° C-38° C) in a beaker.
  7. Lime water gradually turns milky, indicating the evolution of carbon dioxide from the yeast preparation.
  8. Level of the lime water in the delivery tube does not rise, showing that there is no decline in volume of gas in test tube A and consequently no utilization of oxygen by yeast. Preparation is stored for a day or two.
  9. When we open the stopper of tube A we will notice a smell of alcohol indicating the formation of ethanol.
  10. From this activity it may be inferred that yeast respires anaerobically to ferment glucose to ethanol and carbon dioxide.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer 6

Question 41.
With the help of an experiment explain how germinating seeds respire.
Answer:

  1. Seed coats of a few germinating seeds (peas, beans or gram) are removed and are then put in a test tube filled with mercury.
  2. After closing the test tube with the thumb, it is vertically inverted in a trough of mercury and the thumb is carefully removed.
  3. Being lighter than mercury, the seeds rise to the closed upper end of the test Uibe. No gas is seen at first in the test tube.
  4. As germination proceeds, a gas begins to collect at the top of the mercury in the test tube.
  5. On introducing a pellet of potassium hydroxide into the tube, it rises to the top and absorbs the gas. The mercury again fills the tube.
  6. The potassium hydroxide reacts with carbon dioxide gas to produce potassium carbonate and water.
  7. The gas therefore disappears. Evidently germinating seeds produce carbon dioxide by anaerobic respiration in the absence of oxygen in the mercury column.

[Note: Mercury is toxic chemical. Proper precautions must be taken while performing this experiment ]
[Note: Students can scan the adjacent QR code to get conceptual clarity with the aid of a relevant example.]

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 42.
Give the significance of respiration.
OR
Write a short note on significance of respiration.
Answer:

  1. Respiration provides energy for biosynthesis of biomolecules.
  2. It is also a source of energy for cell division, growth, repairs and replacement of worn out parts, movements,
    locomotion etc.
  3. Various intermediates of Krebs cycle are used as building blocks for synthesis of other complex compounds.
  4. Coupled with photosynthesis, it helps to maintain the balance between C02 and O2 in the atmosphere.
  5. Anaerobic respiration (fermentation) is used in various industries such as dairies, bakeries, distilleries, leather industries, paper industries etc. It is used in the commercial production of alcohol, organic acids, vitamins, antibiotics etc.

Question 43.
Match the following:

Column IColumn IIColumn III
1. Krebs cycle(a) 1,3-Bisphosphoglycerate → 3-Phosphoglycerate(p) Pyruvate dehydrogenase
2. Glycolysis(b) Succinyl CoA Succinate(q) NADH dehydrogenase
3. ETS(c) Pyruvic acid → Acetyl CoA(r) Two ATP are produced
4. Link reaction(d) Transfer of electrons from Complex I to Ubiquinone(s) Succinyl CoA – synthetase

Answer:

Column IColumn IIColumn III
1. Krebs cycle(b) Succinyl CoA Succinate(s) Succinyl CoA – synthetase
2. Glycolysis(a) 1,3-Bisphosphoglycerate → 3-Phosphoglycerate(r) Two ATP are produced
3. ETS(d) Transfer of electrons from Complex I to Ubiquinone(q) NADH dehydrogenase
4. Link reaction(c) Pyruvic acid → Acetyl CoA(p) Pyruvate dehydrogenase

Question 44.
Apply Your Knowledge

Question 1.
While teaching respiration professor said that oxygen is important for respiration in humans, Rakesh kept thinking, where exactly oxygen is required during cellular respiration? What would be the correct explanation for his doubt?
Answer:
Oxygen is very important for life, we humans cannot survive without oxygen. Glycolysis, link reaction and Krebs cycle do not involve oxygen. In cellular reaction, oxygen is required only during ETS where it acts as an electron acceptor hence leading to terminal oxidation where it gets converted into water called metabolic water.

The process of respiration is very fast and occurs continuously as cell require continuous supply of energy to carry out metabolic activities, thus, we require oxygen for cellular respiration even when we are sleeping.

Question 2.
Sonal while studying ETS had a doubt, why FADH2 yields only 2 ATP’s whereas NADH2 yields three ATP’s? What would be the correct explanation for her doubt?
Answer:

  1. During ETS, NADH2 and FADH2 undergoes oxidation where they are converted to NAD+ and FAD+ respectively.
  2. During this conversion, hydrogen is removed, which latter forms proton and electron. This electron so formed is passed on to different electron carriers. During this transfer of electron, energy is released which is used in ATP synthesis.
  3. In case of NADH2, energy is released at three places hence results into formation of 3 ATPs whereas, in case of FADH2 energy is released at only two places, hence results into formation of only 2 ATPs.
  4. Here, the ATP formation occurs by Chemiosmotic hypothesis.

Question 45.
Quick Review

Various steps involved in glycolysis:

Step(s)SubstrateEnzymeEnd product(s)
PhosphorylationGlucose + ATPHexokinaseGlucose – 6 – Phosphate + ADP
IsomerisationGlucose – 6-PhosphatePhosphohexose isomeraseFructose – 6 – Phosphate
PhosphorylationFructose – 6-Phosphate + ATP (Phosphate donor)PhosphofructokinaseFructose 1,6-Diphosphate + ADP
CleavageFructose -1, 6-DiphosphateAldolase3 – Phosphoglyceraldehyde + Dihydroxyacetone phosphate
Phosphorylation and Dehydrogenation3-PGAL + H3PO4 + NAD+Triosephosphate

dehydrogenase

1, 3 Diphosphoglyceric acid + NADH + H+
Dephosphorylation1, 3-DPGA + ADPDiphosphoglycerate kinase (Mg2)ATP + 3-Phosphoglyceric acid
Rearrangement3-PGAPhosphoglycerate mutase2-Phosphoglyceric acid
Dehydration2-PGAEnolasePhosphoenol Pyruvic acid + H20
DephosphorylationPhosphoenol Pyruvic acid +ADPPyruvate kinasePyruvic acid + ATP

Various steps involved in Krebs cycle:

Step(s)SubstrateEnzymeEnd product(s)
CondensationAcetyl-CoA+Oxalo- acetic acid + H20Citrate synthaseCitric acid (6C) + Coenzyme- A
Dehydration
Hydration
It is again completed in two steps:
Citric acid
Cis-Aconitic acid + H20
Aconitase
Aconitase
Cis-Aconitic acid + H20 Iso-citric acid(6C)
Oxidative decarboxylationa. Isocitric acid + NAD+Isocitrate dehydrogenaseOxalo succinic acid(6C) + NADH + H+
b. Oxalosuccinic acidIsocitrate dehydrogenasea – ketoglutaric acid(5C) + CO
Oxidative Decarboxylation. (-2H) (-C02)a-Ketoglutaric acid + H20 + NAD + Coenzyme Aa-Ketoglutarate dehydrogenase complexSuccinyl-CoA(4C) + NADH + H++co2
Substrate level phosphorylationSuccinyl – Co A + GDP + iPSuccinyl CoA synthetaseSuccinic acid (4C) + Coenzyme-A + GTP
Dehydrogenation (-2H)Succinic acid + FAD (H-acceptor)Succinate dehydrogenaseFumaric acid (4C) + FADH2
Hydration(+H20)Fumaric acid + H20Hydration(+H20)Fumaric acid + H20
Dehydrogenation (-2H)Malic acid + NAD+ (H-acceptor)Dehydrogenation (-2H)Malic acid + NAD+ (H-acceptor)

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer 7

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 46.
Exercise

Question 1.
Define phosphorylation.
Answer:
It is the formation of ATP, by addition inorganic phosphate to ADP.
ADP + Pi → ATP

Question 2.
Mention the different ways of phosphorylation.
Answer:
Phosphorylation occurs in three different ways as – photophosphorylation, substrate-level phosphorylation and oxidative phosphorylation.

Question 3.
Define substrate-level phosphorylation.
Answer:
Substrate-level phosphorylation is a direct phosphorylation of ADP by transfer of a phosphate group from any suitable substrate. It occurs in cytoplasm of the cells and matrix of mitochondria.

Question 4.
What is fermentation?
Answer:
1. Anaerobic respiration is the cellular respiration that does not involve the atmospheric oxygen. It is also called as fermentation.
2. It involves glycolysis where the product of glycolysis i.e. pyruvate is converted to either lactic acid or ethanol.

Question 5.
Where does glycolysis occurs?
Answer:
Glycolysis is a process where glucose is broken down into two molecules of pyruvic acid, hence called glycolysis (glucose-breaking). It is common to both aerobic and anaerobic respiration. It occurs in the cytoplasm of the cell. It involves ten steps.
Glycolysis consists of two major phases:
1. Preparatory phase (1-5 steps).
2. Payoff phase (6-10 steps).
1. Preparatory phase:
a. In this phase, glucose is phosphorylated twice by using two ATP molecules and a molecule of fructose 1,6-bisphosphate is formed.
b. It is then cleaved into two molecules of glyceraldehyde-3-phosphate and dihydroxy acetone phosphate. These two molecules are 3-carbon carbohydrates (trioses) and are isomers of each other.
c. Dihydroxy acetone phosphate is isomerised to second molecule of glyceraldehyde-3-phosphate.
d. Therefore, two molecules of glyceraldehyde-3- phosphate are formed.
e. Preparatory phase of glycolysis ends.

2. Payoff phase:
a. In this phase, both molecules of glyceraldehyde-3-phosphate are converted to two molecules of 1,3- bisphoglycerate by oxidation and phosphorylation. Here, the phosphorylation is brought about by inorganic phosphate instead of ATP.
b. Both molecules of 1, 3-bisphosphoglycerate are converted into two molecules of pyruvic acid through series of reactions accompanied with release of energy. This released energy is used to produce ATP (4 molecules) by substrate-level phosphorylation.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 6.
What is glycolysis? Explain with the help of schematic representation.
Answer:
Glycolysis is a process where glucose is broken down into two molecules of pyruvic acid, hence called glycolysis (glucose-breaking). It is common to both aerobic and anaerobic respiration. It occurs in the cytoplasm of the cell. It involves ten steps.
Glycolysis consists of two major phases:
1. Preparatory phase (1-5 steps).
2. Payoff phase (6-10 steps).
1. Preparatory phase:
a. In this phase, glucose is phosphorylated twice by using two ATP molecules and a molecule of fructose 1,6-bisphosphate is formed.
b. It is then cleaved into two molecules of glyceraldehyde-3-phosphate and dihydroxy acetone phosphate. These two molecules are 3-carbon carbohydrates (trioses) and are isomers of each other.
c. Dihydroxy acetone phosphate is isomerised to second molecule of glyceraldehyde-3-phosphate.
d. Therefore, two molecules of glyceraldehyde-3- phosphate are formed.
e. Preparatory phase of glycolysis ends.

2. Payoff phase:
a. In this phase, both molecules of glyceraldehyde-3-phosphate are converted to two molecules of 1,3- bisphoglycerate by oxidation and phosphorylation. Here, the phosphorylation is brought about by inorganic phosphate instead of ATP.
b. Both molecules of 1, 3-bisphosphoglycerate are converted into two molecules of pyruvic acid through series of reactions accompanied with release of energy. This released energy is used to produce ATP (4 molecules) by substrate-level phosphorylation.

Question 7.
Define fermentation. What are the different types of fermentation?
Answer:
1. Anaerobic respiration is the cellular respiration that does not involve the atmospheric oxygen. It is also called as fermentation.
2. It involves glycolysis where the product of glycolysis i.e. pyruvate is converted to either lactic acid or ethanol.
It is a process of anaerobic respiration where the pyruvic acid undergoes reduction by addition of one proton and two electrons donated by NADH+H+ to form lactic acid as the product and NAD+ as the byproduct of oxidation. Skeletal muscles usually derive energy by this process.
Alcoholic fermentation is a type of anaerobic respiration where the pyruvate is decarboxylated to acetaldehyde. The acetaldehyde is then reduced by NADH+H+ to ethanol and Carbon dioxide. Since ethanol is produced during the process, it is termed alcoholic fermentation.

Question 8.
Name the products of lactic acid fermentation.
Answer:
It is a process of anaerobic respiration where the pyruvic acid undergoes reduction by addition of one proton and two electrons donated by NADH+H+ to form lactic acid as the product and NAD+ as the byproduct of oxidation. Skeletal muscles usually derive energy by this process.

Question 9.
Write the chemical reaction of lactic acid fermentation.
Answer:
It is a process of anaerobic respiration where the pyruvic acid undergoes reduction by addition of one proton and two electrons donated by NADH+H+ to form lactic acid as the product and NAD+ as the byproduct of oxidation. Skeletal muscles usually derive energy by this process.

Question 10.
Explain alcoholic fermentation.
Answer:
Alcoholic fermentation is a type of anaerobic respiration where the pyruvate is decarboxylated to acetaldehyde. The acetaldehyde is then reduced by NADH+H+ to ethanol and Carbon dioxide. Since ethanol is produced during the process, it is termed alcoholic fermentation.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 11.
Less energy is produced during anaerobic respiration that in aerobic respiration. Justify.
Answer:
Anaerobic respiration produces less energy because:

  1. Incomplete breakdown of respiratory substrate takes place.
  2. Some of the products of anaerobic respiration can be oxidised further to release energy which shows that anaerobic respiration does not liberate the whole energy contained in the respiratory substrate.
  3. NADH2 does not produce ATP, as electron transport is absent.
  4. Only 2 ATP molecules are generated from one molecule of glucose during anaerobic respiration.

Question 12.
Enlist steps involved in aerobic respiration.
Answer:
It involves glycolysis, acetyl CoA formation (connecting link reaction), Krebs cycle, electron transfer chain reaction and terminal oxidation.

Question 13.
Write the reaction of connecting link between glycolysis and Krebs cycle.
Answer:
This reaction is called as ‘connecting link’ reaction between glycolysis and Krebs cycle.

Question 14.
How glycolysis is regulated?
Answer:
Glycolysis is strongly regulated by the complex interplay between ATP consumption, NADH2 regeneration and regulation of various glycolytic enzymes like hexokinase, PFK-1, pyruvate kinase, etc. Besides, it is also controlled by hormones like glucagon, epinephrine and insulin.

Question 15.
Write the significance of ETS.
Answer:
Significance of ETS:

  1. Major amount of energy is generated through ETS or terminal oxidation in the form of ATP molecules.
  2. Per glucose molecule 38 ATP molecules are formed, out of which 34 ATP molecules are produced through ETS.
  3. Oxidized coenzymes such as NAD and FAD are regenerated from their reduced forms (NADH+H+ and FADH2) for recycling.
  4. In this process, energy is released in a controlled and stepwise manner to prevent any damage to the cell.
  5. ETS produces water molecules.

Question 16.
Give the schematic representation of glycolysis.
Answer:
Glycolysis is a process where glucose is broken down into two molecules of pyruvic acid, hence called glycolysis (glucose-breaking). It is common to both aerobic and anaerobic respiration. It occurs in the cytoplasm of the cell. It involves ten steps.
Glycolysis consists of two major phases:
1. Preparatory phase (1-5 steps).
2. Payoff phase (6-10 steps).
1. Preparatory phase:
a. In this phase, glucose is phosphorylated twice by using two ATP molecules and a molecule of fructose 1,6-bisphosphate is formed.
b. It is then cleaved into two molecules of glyceraldehyde-3-phosphate and dihydroxy acetone phosphate. These two molecules are 3-carbon carbohydrates (trioses) and are isomers of each other.
c. Dihydroxy acetone phosphate is isomerised to second molecule of glyceraldehyde-3-phosphate.
d. Therefore, two molecules of glyceraldehyde-3- phosphate are formed.
e. Preparatory phase of glycolysis ends.

2. Payoff phase:
a. In this phase, both molecules of glyceraldehyde-3-phosphate are converted to two molecules of 1,3- bisphoglycerate by oxidation and phosphorylation. Here, the phosphorylation is brought about by inorganic phosphate instead of ATP.
b. Both molecules of 1, 3-bisphosphoglycerate are converted into two molecules of pyruvic acid through series of reactions accompanied with release of energy. This released energy is used to produce ATP (4 molecules) by substrate-level phosphorylation.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 17.
Describe the formation of Acetyl Co-A in respiration.
Answer:

  1. The conversion of pyruvic acid to acetyl CoA is an oxidative decarboxylation reaction.
  2. It is catalyzed by a multienzyme complex-pyruvate dehydrogenase complex (PDH). This enzyme is present in mitochondria of eukaryotes and cytosol of prokaryotes.
  3. This reaction is called as ‘connecting link’ reaction between glycolysis and Krebs cycle.

Question 18.
Give the schematic representation of the overall view of Krebs cycle.
Answer:

  1. Krebs cycle or citric acid cycle is the second phase of aerobic respiration which takes place in the matrix of the mitochondria.
  2. The acetyl CoA formed during the link reaction undergoes aerobic oxidation.
  3. This cycle serves a common oxidative pathway for carbohydrates, fats and proteins.
  4. In mitochondria pyruvic acid is decarboxylated and the remaining 2-carbon fragment is combined with a molecule of coenzyme A to form acetyl-CoA.
  5. This reaction is an oxidative decarboxylation process and produces H+ ions and electrons along with carbon dioxide. During the process NAD+ is reduced to NADH+H+.
  6. P-oxidation of fatty acids also produces acetyl-CoA as the end product.
  7. Acetyl-CoA from both sources is condensed with oxaloacetic acid to form citric acid. Citric acid is oxidized step-wise by mitochondrial enzymes, releasing carbon dioxide.
  8. Regeneration of oxaloacetic acid occurs to complete the cycle.
  9. There are four steps of oxidation in this cycle, catalyzed by dehydrogenases (oxidoreductases) using NAD+ or FAD+ as the coenzyme.
  10. The coenzymes are consequently reduced to NADH+H+ and FADH2 respectively. These transfer their electrons to the mitochondrial respiratory chain to get reoxidised.
  11. One molecule of GTP (ATP) is also generated for every molecule of citric acid oxidized.

Question 19.
Explain why the respiratory pathway is an amphibolic pathway?
Answer:

  1. Respiration is considered as a catabolic process; however, it is not entirely correct in case of Krebs cycle.
  2. Many reactions of Krebs cycle involve oxidation of acetyl CoA to release energy and C02.
  3. However, the breakdown of respiratory substrates provides intermediates like a-ketoglutarate, oxaloacetate are used as precursors for synthesis of fatty acids, glutamic acid and aspartic acid respectively.
  4. Thus, as the same respiratory process acts as catabolic as well as anabolic pathway for synthesis of various intermediate metabolic products, it is called amphibolic pathway.

Question 20.
Write a detailed note on the connecting link between glycolysis and Krebs cycle.
Answer:

  1. The conversion of pyruvic acid to acetyl CoA is an oxidative decarboxylation reaction.
  2. It is catalyzed by a multienzyme complex-pyruvate dehydrogenase complex (PDH). This enzyme is present in mitochondria of eukaryotes and cytosol of prokaryotes.
  3. This reaction is called as ‘connecting link’ reaction between glycolysis and Krebs cycle.

Question 21.
Give the diagrammatic representation of ETS.
Answer:

  1. NADH2 and FADH2 produced during glycolysis, connecting link reaction and Krebs cycle are oxidized with the help of various electron carriers and enzymes.
  2. These carriers and enzymes are arranged on inner mitochondrial membrane in the form of various complexes as complex I, II, III, VI and V.
  3. NADH+H+ is oxidised by NADH dehydrogenase (complex I) and it’s electrons are transferred to ubiquinone (coenzyme Q-CoQ) present on inner membrane of mitochondria. Reduced ubiquinone is called as ubiqunol.
  4. FADH2 is oxidised by complex II (Succinate dehydrogenase) and these electrons are also transferred to CoQ.
  5. During oxidation of NADH+H+ and FADH2, electrons and protons are released but only electrons are canned forward whereas protons are released into outer chamber of mitochondria (intermembrane space).
  6. Ubiquinol is oxidised by complex-III (Cytochrome bcl complex) and it’s electrons are transferred to cytochrome C.
  7. Cytochrome C is a small, iron-containing protein, loosely associated with inner membrane. It acts as a mobile electron carrier, transferring the electrons between complex III and IV.
  8. Cytochrome C is oxidised by complex IV or cytochrome C oxidase consisting of cytochrome a and a3. Electrons are transferred by this complex to the molecular oxygen. This is terminal oxidation.
  9. Reduced molecular oxygen reacts with protons to form water molecule called as metabolic water.
  10. Protons necessary for this are channelled from outer chamber of mitochondria into inner chamber by F0 part of oxysome (complex V) present in inner mitochondrial membrane.
  11. This proton channelling by F0 is coupled to catalytic site of F1 which catalyses the synthesis of ATP from ADP and inorganic phosphate. This is oxidative phosphorylation.
  12. As transfer of protons is accompanied with synthesis of ATP, this process is named as ‘Chemiosmosis’ by Peter Mitchell.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 22.
Explain the process of terminal oxidation. Give its significance (any two points).
Answer:

  1. NADH2 and FADH2 produced during glycolysis, connecting link reaction and Krebs cycle are oxidized with the help of various electron carriers and enzymes.
  2. These carriers and enzymes are arranged on inner mitochondrial membrane in the form of various complexes as complex I, II, III, VI and V.
  3. NADH+H+ is oxidised by NADH dehydrogenase (complex I) and it’s electrons are transferred to ubiquinone (coenzyme Q-CoQ) present on inner membrane of mitochondria. Reduced ubiquinone is called as ubiqunol.
  4. FADH2 is oxidised by complex II (Succinate dehydrogenase) and these electrons are also transferred to CoQ.
  5. During oxidation of NADH+H+ and FADH2, electrons and protons are released but only electrons are canned forward whereas protons are released into outer chamber of mitochondria (intermembrane space).
  6. Ubiquinol is oxidised by complex-III (Cytochrome bcl complex) and it’s electrons are transferred to cytochrome C.
  7. Cytochrome C is a small, iron-containing protein, loosely associated with inner membrane. It acts as a mobile electron carrier, transferring the electrons between complex III and IV.
  8. Cytochrome C is oxidised by complex IV or cytochrome C oxidase consisting of cytochrome a and a3. Electrons are transferred by this complex to the molecular oxygen. This is terminal oxidation.
  9. Reduced molecular oxygen reacts with protons to form water molecule called as metabolic water.
  10. Protons necessary for this are channelled from outer chamber of mitochondria into inner chamber by F0 part of oxysome (complex V) present in inner mitochondrial membrane.
  11. This proton channelling by F0 is coupled to catalytic site of F1 which catalyses the synthesis of ATP from ADP and inorganic phosphate. This is oxidative phosphorylation.
  12. As transfer of protons is accompanied with synthesis of ATP, this process is named as ‘Chemiosmosis’ by Peter Mitchell.

Question 23.
1. Enlist the main steps involved in aerobic respiration and their place of occurrence.
2. Differentiate between photosynthesis and aerobic respiration.
Answer:
1. Glycolysis takes place in the cytoplasm of a cell.
2. It is catalyzed by a multienzyme complex-pyruvate dehydrogenase complex (PDH). This enzyme is present in mitochondria of eukaryotes and cytosol of prokaryotes.,
3. Krebs cycle or citric acid cycle is the second phase of aerobic respiration which takes place in the matrix of the mitochondria. and These carriers and enzymes are arranged on inner mitochondrial membrane in the form of various complexes as complex I, II, III, VI and V.

Question 24.
1. Give the schematic representation of ETS.
2. Differentiate between respiration and combustion.
Answer:

  1. NADH2 and FADH2 produced during glycolysis, connecting link reaction and Krebs cycle are oxidized with the help of various electron carriers and enzymes.
  2. These carriers and enzymes are arranged on inner mitochondrial membrane in the form of various complexes as complex I, II, III, VI and V.
  3. NADH+H+ is oxidised by NADH dehydrogenase (complex I) and it’s electrons are transferred to ubiquinone (coenzyme Q-CoQ) present on inner membrane of mitochondria. Reduced ubiquinone is called as ubiqunol.
  4. FADH2 is oxidised by complex II (Succinate dehydrogenase) and these electrons are also transferred to CoQ.
  5. During oxidation of NADH+H+ and FADH2, electrons and protons are released but only electrons are canned forward whereas protons are released into outer chamber of mitochondria (intermembrane space).
  6. Ubiquinol is oxidised by complex-III (Cytochrome bcl complex) and it’s electrons are transferred to cytochrome C.
  7. Cytochrome C is a small, iron-containing protein, loosely associated with inner membrane. It acts as a mobile electron carrier, transferring the electrons between complex III and IV.
  8. Cytochrome C is oxidised by complex IV or cytochrome C oxidase consisting of cytochrome a and a3. Electrons are transferred by this complex to the molecular oxygen. This is terminal oxidation.
  9. Reduced molecular oxygen reacts with protons to form water molecule called as metabolic water.
  10. Protons necessary for this are channelled from outer chamber of mitochondria into inner chamber by F0 part of oxysome (complex V) present in inner mitochondrial membrane.
  11. This proton channelling by F0 is coupled to catalytic site of F1 which catalyses the synthesis of ATP from ADP and inorganic phosphate. This is oxidative phosphorylation.
  12. As transfer of protons is accompanied with synthesis of ATP, this process is named as ‘Chemiosmosis’ by Peter Mitchell.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 25.
Enlist the different respiratory substrate.
Answer:
Respiratory substrates are the molecules that are oxidized during respiration to release energy which can be used for ATP synthesis. Carbohydrates, fats and proteins are the common respiratory substrate. Glucose is the most common respiratory substrate.

Question 26.
Define R.Q. What is its value for fats?
Answer:
1. Respiratory quotient (R.Q.) or respiratory ratio is the ratio of volume of CO2 released to the volume of O2 consumed in respiration.
2. R.Q. = Volume of CO2 released/Volume of O2 consumed

Question 27.
Write the significance of respiration.
Answer:

  1. Respiration provides energy for biosynthesis of biomolecules.
  2. It is also a source of energy for cell division, growth, repairs and replacement of worn out parts, movements,
    locomotion etc.
  3. Various intermediates of Krebs cycle are used as building blocks for synthesis of other complex compounds.
  4. Coupled with photosynthesis, it helps to maintain the balance between C02 and O2 in the atmosphere.
  5. Anaerobic respiration (fermentation) is used in various industries such as dairies, bakeries, distilleries, leather industries, paper industries etc. It is used in the commercial production of alcohol, organic acids, vitamins, antibiotics etc.

Question 47.
Multiple Choice Questions:

Question 1.
Respiration is regarded as a ________ process.
(A) catabolic
(B) anabolic
(C) reduction
(D) synthetic
Answer:
(A) catabolic

Question 2.
Anaerobic respiration is also called as ________ .
(A) Glycolysis
(B) fermentation
(C) phosphoryaltion
(D) decarboxylation
Answer:
(B) fermentation

Question 3.
The first compound formed in glycolysis is
(A) Glucose-6-phosphate
(B) Glucose-1,6-biphosphate
(C) Fructose-6-phosphate
(D) Pyruvic acid
Answer:
(A) Glucose-6-phosphate

Question 4.
Which of the following compounds in last step of glycolysis gives pyruvic acid?
(A) 3 – phosphoglyceraldehyde
(B) dihydroxy acetone phosphate
(C) phosphoenolpyruvate
(D) 2-phosphoglycerate
Answer:
(C) phosphoenolpyruvate

Question 5.
In glycolysis, dehydration occurs during formation of
(A) 3 – phosphoglyceraldehyde
(B) 2 – phosphoglycerate
(C) phosphoenolpyruvate
(D) dihydroxyacetone phosphate
Answer:
(B) 2 – phosphoglycerate

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 6.
In which of the following steps dehydrogenation occurs?
(A) Glucose → Glucose 6-phosphate
(B) 3-phophoglcerate → 2-phophoglccratc
(C) phosphoenolpyruvate → pyruvate
(D) 3 – phosphoglyceraldehyde → 1, 3-bisphosphoglycerate
Answer:
(D) 3 – phosphoglyceraldehyde → 1, 3-bisphosphoglycerate

Question 7.
The compound common to both aerobic and anaerobic respiration is
(A) C02
(B) pyruvic acid
(C) acetyl CoA
(D) free oxygen
Answer:
(B) pyruvic acid

Question 8.
Which compound is found both in respiration and photosynthesis?
(A) Phosphoglycerate
(B) Phosphoglyceraldehyde
(C) Both (A) and (B)
(D) Succinic acid
Answer:
(C) Both (A) and (B)

Question 9.
Which type of respiration does not release C02?
(A) Aerobic respiration
(B) Alcoholic fermentation
(C) Lactic acid fermentation
(D) Krebs cycle
Answer:
(C) Lactic acid fermentation

Question 10.
What is the overall goal of glycolysis, Krebs cycle and electron transport system?
(A) Synthesis of ATP in fermentation reaction
(B) Carbohydrates
(C) Nucleic acids
(D) ATP in small stepwise units
Answer:
(D) ATP in small stepwise units

Question 11.
The intermediate between glycolysis and TCA cycle is:
(A) Lactic acid
(B) Acetaldehyde
(C) Fructose-6-phosphate
(D) Acetyl Co-A
Answer:
(D) Acetyl Co-A

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 12.
During alcoholic fermentation, decarboxylation of pyruvate gives
(A) acetaldehyde
(B) lactic acid
(C) ethyl alcohol
(D) methyl alcohol
Answer:
(A) acetaldehyde

Question 13.
Where the link reaction occurs in prokaryotes?
(A) cytoplasm
(B) mitochondrial matrix
(C) cell membrane
(D) mitochondrial membrane
Answer:
(A) cytoplasm

Question 14.
In Krebs cycle, dehydration of substrate occurs
(A) once
(B) twice
(C) thrice
(D) four times
Answer:
(A) once

Question 15.
Which of the following steps generate ATP without ETS?
(A) Pyruvic acid → Acetyl Co-A
(B) ∝-ketoglutarate → Succinic acid
(C) Iso-citric acid → Oxalosuccinic acid
(D) Succinyl Co-A → Succinic acid
Answer:
(D) Succinyl Co-A → Succinic acid

Question 16.
In Krebs cycle, the acid which undergoes oxidative decarboxylation is
(A) citric acid
(B) succinic acid
(C) malic acid
(D) ∝-ketoglutaric acid
Answer:
(D) ∝-ketoglutaric acid

Question 17.
During Krebs cycle, fumaric acid gets converted into malic acid by
(A) decarboxylation
(B) dehydrogenation
(C) dehydration
(D) hydration
Answer:
(D) hydration

Question 18.
Krebs cycle is also called TCA cycle because
(A) the first compound formed is citric acid.
(B) it was discovered by Sir Hans Krebs.
(C) organic acids formed have 3 carboxylic acid groups.
(D) acetyl Co-A is formed
Answer:
(C) organic acids formed have 3 carboxylic acid groups.

Question 19.
Which of the following compound is the acceptor of Acetyl Co-A in Krebs cycle?
(A) Oxaloacetic acid
(B) Fumaric acid
(C) Malic acid
(D) Oxalo succinic acid
Answer:
(A) Oxaloacetic acid

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 20.
Which of the following compounds is formed in Krebs cycle from fumaric acid?
(A) Oxalo acetic acid
(B) Malic acid
(C) ∝-KGA
(D) Citric acid
Answer:
(B) Malic acid

Question 21.
Which of the following step of aerobic respiration would be omitted when fatty acids are used as respiratory substrate?
(A) Glycolysis
(B) Krebs cycle
(C) Electron transfer chain reaction
(D) Terminal oxidation.
Answer:
(A) Glycolysis

Question 22.
During Krebs cycle, decarboxylation occurs _______ time/s.
(A) 1
(B) 2
(C) 3
(D) 4
Answer:
(B) 2

Question 23.
The conversion of malic acid to oxalo acetic acid is catalyzed by
(A) malate reductase
(B) malate thiokinase
(C) fumarase
(D) malate dehydrogenase
Answer:
(D) malate dehydrogenase

Question 24.
Electron carriers of oxidative phosphorylation are present on
(A) outer membrane of mitochondria.
(B) inner membrane of mitochondria.
(C) thylakoid membrane of chloroplast.
(D) matrix of mitochondria.
Answer:
(B) inner membrane of mitochondria.

Question 25.
Which of the following derives maximum energy per molecule of glucose?
(A) Alcoholic fermentation.
(B) Lactic acid fermentation.
(C) Aerobic respiration in unicellular organisms.
(D) Glycolysis in liver cells.
Answer:
(C) Aerobic respiration in unicellular organisms.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 26.
The cytochrome which donates de-energised electron to oxygen is
(A) cytochrome-a
(B) cytochrome-b
(C) cytochrome-a3
(D) cytochrome-c
Answer:
(C) cytochrome-a3

Question 27.
In terminal oxidation FADH2 is oxidized by
(A) complex I
(B) complex II
(C) complex III
(D) complex IV
Answer:
(B) complex II

Question 28.
The net gain of energy from a molecule of glucose in the aerobic respiration is
(A) 38
(B) 35
(C) 70
(D) 76
Answer:
(A) 38

Question 29.
Each molecule of NADH2 through ETS yields
(A) 1 ATP
(B) 2 ATPs
(C) 3 ATPs
(D) 4 ATPs
Answer:
(C) 3 ATPs

Question 30.
One glucose molecule, through ETS yields
(A) 2 ATP molecules
(B) 3 ATP molecules
(C) 34 ATP molecules
(D) 38 ATP molecules
Answer:
(C) 34 ATP molecules

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 31.
The adenosine triphosphate (ATP) gain during glycolysis, connecting link and Krebs cycle respectively are _______ .
(A) 8, 6,24
(B) 8,24, 6
(C) 24, 8, 6
(D) 6, 8, 24
Answer:
(A) 8, 6,24

Question 32.
The respiratory quotient (R.Q.) of carbohydrate is ________ .
(A) 0.7
(B) 1
(C) 0.9
(D) 0.1
Answer:
(B) 1

Question 33.
R. Q. for proteins is about _______ .
(A) 0.7
(B) 0.8
(C) 0.9
(D) 1.0
Answer:
(C) 0.9

Question 48.
Competitive Corner:

Question 1.
Which of the following statements regarding mitochondria is INCORRECT?
(A) Inner membrane is convoluted with infoldings.
(B) Mitochondrial matrix contains single circular DNA molecule and ribosomes.
(C) Outer membrane is permeable to monomers of carbohydrates, fats and proteins.
(D) Enzymes of electron transport are embedded in outer membrane.
Hint: Enzymes of electron transport are embedded in inner membrane.
Answer:
(D) Enzymes of electron transport are embedded in outer membrane.

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 2.
Where is the respiratory electron transport system (ETS) located in plants?
(A) Intermembrane space
(B) Mitochondrial matrix
(C) Outer mitochondrial membrane
(D) Inner mitochondrial membrane
Answer:
(D) Inner mitochondrial membrane

Question 3.
In case of anaerobic respiration, the R.Q is _____ .
(A) always less than one
(B) always more than one
(C) always infinity
(D) Variable on the basis of substrate.
Answer:
(C) always infinity

Question 4.
The net gain of ATP molecules during aerobic breakdown of one glucose molecule is _______ .
(A) 40
(B) 38
(C) 36
(D) 30
Answer:
(B) 38

Question 5.
During glycolysis the compounds PGAL and DHAP are formed from fructose 1,6- diphosphate by _______.
(A) cleavage
(B) isomerisation
(C) phosphorylation
(D) condensation
Answer:
(A) cleavage

Maharashtra Board Class 11 Biology Important Questions Chapter 13 Respiration and Energy Transfer

Question 6.
Number of oxygen molecules utilized in glycolysis is ________ .
(A) 0
(B) 2
(C) 4
(D) 6
Answer:
(A) 0

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Balbharati Maharashtra State Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law Important Questions and Answers.

Maharashtra State Board 11th Information Technology Important Questions Chapter 4 Cyber Law

1. Fill in the Blanks.

Question 1.
__________ is the area of law that deals with the Internet’s relationship to technological and electronic elements.
Answer:
Cyberlaw

Question 2.
__________ is the part of the overall legal system that deals with the Internet, cyberspace, and their respective legal issues.
Answer:
Cyberlaw

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 3.
__________ covers a fairly broad area, encompassing several subtopics including freedom of expression, access to and usage of the Internet, and online privacy.
Answer:
Cyberlaw

Question 4.
The attempts to change outdated laws and provides ways to deal with cybercrimes.
Answer:
Information Technology Act 2000

Question 5.
The Act offers the much-needed legal framework so that information is not denied.
Answer:
Information Technology

Question 6.
The Act has also proposed a legal framework for the authentication and origin of an electronic records.
Answer:
Information Technology

Question 7.
__________ is also called moral philosophy is the discipline concerned with what is morally good and bad, right or wrong.
Answer:
Ethics

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 8.
__________ is the standards of behaviour; principles of right and wrong behaviour.
Answer:
Morals

Question 9.
Thus __________ are dictated by society, culture or religion.
Answer:
Morals

Question 10.
Computer Crime is alternatively referred to as __________
Answer:
Cybercrime

Question 11.
Computer crime is an act performed by a knowledgeable computer user, sometimes referred to as a __________
Answer:
Hacker

Question 12.
A __________ who illegally browses or steals a company’s or individual’s private information.
Answer:
Hacker

Question 13.
__________ can involve criminal activities that are traditional in nature, such as theft, fraud, forgery, defamation and mischief.
Answer:
Cybercrimes

Question 14.
__________ is nothing but copyright violation of software created originally by an individual or an institution.
Answer:
Software piracy

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 15.
__________ includes stealing of codes/programs and other information illegally and creating the imitated copy by unauthorized means.
Answer:
Software piracy

Question 16.
Gaining access without the users’ permission is known as __________
Answer:
Unauthorized Access

Question 17.
__________ means granting access rights to resources.
Answer:
Authorization

Question 18.
A __________ is a legal right that gives the creator of a literary, artistic, musical, or other creative work.
Answer:
Copyright

Question 19.
__________ owners have the right to control the reproduction of their work, including the right to receive the royalty payment for that reproduction.
Answer:
Copyright

Question 20.
Activity such as decipher codes or passwords and breaking security systems for illegal reasons is called __________
Answer:
Cracking

Question 21.
The cracker will use a program or script known as a __________
Answer:
Crack

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 22.
__________ is a criminal practice where an individual uses the Internet to systematically harass or threaten someone.
Answer:
Cyberstalking

Question 23.
__________ is a technique of extracting confidential information such as credit card numbers and username password combos by pretending as a legal enterprise.
Answer:
Phishing

Question 24.
__________ is typically carried out by email spoofing.
Answer:
Phishing

Question 25.
__________ is presenting someone else’s work or idea as your own without their consent.
Answer:
Plagarism

Question 26.
__________ refers to unauthorised intrusion into a computer or a network.
Answer:
Hacking

Question 27.
__________ is a person intensely interested in the deep and hidden or concealed working of any computer operating system and programming language.
Answer:
Hacker

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 28.
__________ is a method of converting the original message into random text.
Answer:
Encryption

Question 29.
Full form of SSL is __________
Answer:
Secure Socket Layer

Question 30.
Through the __________, transmission of data is encrypted.
Answer:
Secure Socket Layer

Question 31.
__________ refers to a network security (Hardware and Software) system which blocks certain types of information.
Answer:
Firewall

Question 32.
__________ is an Act to provide legal recognition for transactions carried out by means of electronic data interchange and other means of electronic communication.
Answer:
Information Technology Act, 2000

Question 33.
__________ aims to provide the legal infrastructure for E-Commerce in India.
Answer:
Information Technology Act, 2000

Question 34.
The __________ have a major impact on E-Businesses and the new economy in India.
Answer:
Cyber laws

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 35.
The __________ also aims to provide for the legal framework.
Answer:
Information Technology Act, 2000

Question 36.
__________ has been replaced with the electronic signature to make it a more technology-neutral act.
Answer:
Digital Signature

2. True or False.

Question 1.
Criminal Law is the area of law that deals with the Internet’s relationship to technological and electronic elements.
Answer:
False

Question 2.
Cyberlaw is the part of the overall legal system that deals with the Internet, cyberspace, and their respective legal issues.
Answer:
True

Question 3.
Cyberlaw covers a fairly broad area, encompassing several subtopics including freedom of expression, access to and usage of the Internet, and online privacy.
Answer:
True

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 4.
The Information Technology Act 2000 attempts to change outdated laws and provides ways to deal with cybercrimes.
Answer:
True

Question 5.
The Information Technology Act offers the much-needed legal framework so that information is not denied.
Answer:
True

Question 6.
The Computer Act has also proposed a legal framework for the authentication and origin of an electronic records.
Answer:
False

Question 7.
Morals are also called moral philosophy is the discipline concerned with what is morally good and bad, right or wrong.
Answer:
False

Question 8.
Ethics is the standards of behaviour; principles of right and wrong behaviour.
Answer:
False

Question 9.
Thus Morals are dictated by society, culture, or religion.
Answer:
True

Question 10.
Computer Crime is alternatively referred to as Hacker.
Answer:
False

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 11.
Computer crime is an act performed by a knowledgeable computer user, sometimes referred to as a Hacker.
Answer:
True

Question 12.
A Cybercrime who illegally browses or steals a company’s or individual’s private information.
Answer:
False

Question 13.
Cybercrimes can involve criminal activities that are traditional in nature, such as theft, fraud, forgery, defamation, and mischief.
Answer:
True

Question 14.
Software piracy is nothing but copyright violation of software created originally by an individual or an institution.
Answer:
True

Question 15.
Unauthorized access includes stealing of codes/programs and other information illegally and creating the imitated copy by unauthorized means.
Answer:
False

Question 16.
Gaining access without the user’s permission is known as Software piracy.
Answer:
False

Question 17.
Authorization means granting access rights to resources.
Answer:
True

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 18.
Cracking is a legal right that gives the creator of a literary, artistic, musical, or other creative work.
Answer:
False

Question 19.
Copyright owners have the right to control the reproduction of their work, including the right to receive the royalty payment for that reproduction.
Answer:
True

Question 20.
Activity such as decipher codes or passwords and breaking security systems for illegal reasons is called copyright.
Answer:
False

Question 21.
The cracker will use a program or script known as a Crack.
Answer:
True

Question 22.
Cyberstalking is a criminal practice where an individual uses the Internet to systematically harass or threaten someone.
Answer:
True

Question 23.
Phishing is a technique of extracting confidential information such as credit card numbers and username password combos by pretending as a legal enterprise.
Answer:
True

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 24.
Phishing is typically carried out by email spoofing.
Answer:
True

Question 25.
Plagiarism is presenting someone else’s work or idea as your own without their consent.
Answer:
True

Question 26.
Hacking refers to unauthorized intrusion into a computer or a network.
Answer:
True

Question 27.
Hacker is a person intensely interested in the deep and hidden or concealed working of any computer operating system and programming language.
Answer:
True

Question 28.
Encryption is a method of converting the original message into random text.
Answer:
True

Question 29.
The full form of SSL is Secure Socket Layer.
Answer:
True

Question 30.
Through the Encryption transmission of data is encrypted.
Answer:
False

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 31.
Encryption refers to a network security (Hardware and Software) system which blocks certain types of information.
Answer:
False

Question 32.
A digital signature is an Act to provide legal recognition for transactions carried out by means of electronic data interchange and other means of electronic communication.
Answer:
False

Question 33.
Information Technology Act, 2000 aims to provide the legal infrastructure for E-Commerce in India.
Answer:
True

Question 34.
Cyber laws have a major impact on E-Businesses and the new economy in India.
Answer:
True

Question 35.
The Information Technology Act, 2000 also aims to provide for the legal framework.
Answer:
True

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 36.
Cyber laws have been replaced with electronic signatures to make it a more technology-neutral act.
Answer:
False

3. Multiple Choice Question (Single Choice)

Question 1.
__________ is the area of law that deals with the Internet’s relationship to technological and electronic elements.
(A) Cyberlaw
(B) Criminal Law
(C) Business Law
(D) Internet Law
Answer:
(A) Cyberlaw

Question 2.
__________ is the part of the overall legal system that deals with the Internet, cyberspace, and their respective legal issues.
(A) Cyberlaw
(B) Criminal Law
(C) Business Law
(D) Internet Law
Answer:
(A) Cyberlaw

Question 3.
__________ covers a fairly broad area, encompassing several subtopics including freedom of expression, access to and usage of the Internet, and online privacy.
(A) Cyberlaw
(B) Criminal Law
(C) Business Law
(D) Internet Law
Answer:
(A) Cyberlaw

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 4.
The __________ attempts to change outdated laws and provides ways to deal with cybercrimes.
(A) Information Technology Act 2000
(B) Cyber Rule
(C) Computer Act
(D) Legal Act
Answer:
(A) Information Technology Act 2000

Question 5.
The __________ Act offers the much-needed legal framework so that information is not denied.
(A) Cyber Rule
(B) Information Technology
(C) Computer Act
(D) Legal Act
Answer:
(B) Information Technology

Question 6.
The __________ Act has also proposed a legal framework for the authentication and origin of an electronic records.
(A) Cyber Rule
(B) Information Technology
(C) Computer Act
(D) Legal Act
Answer:
(B) Information Technology

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 7.
__________ is also called moral philosophy is the discipline concerned with what is morally good and bad, right or wrong.
(A) Ethics
(B) Morals
(C) Society
(D) Culture
Answer:
(A) Ethics

Question 8.
__________ is the standards of behaviour; principles of right and wrong behaviour.
(A) Ethics
(B) Morals
(C) Society
(D) Culture
Answer:
(B) Morals

Question 9.
Thus __________ are dictated by society, culture or religion.
(A) Ethics
(B) Morals
(C) Society
(D) Culture
Answer:
(B) Morals

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 10.
Computer Crime is alternatively referred to as __________
(A) Cybercrime
(B) Hacker
(C) Computer crime
(D) Illegal Act
Answer:
(A) Cybercrime

Question 11.
Computer crime is an act performed by a knowledgeable computer user, sometimes referred to as a __________
(A) Cybercrime
(B) Hacker
(C) Computer crime
(D) Illegal Act
Answer:
(B) Hacker

Question 12.
A __________ who illegally browses or steals a company’s or individual’s private information.
(A) Cybercrime
(B) Hacker
(C) Computer crime
(D) Illegal Act
Answer:
(B) Hacker

Question 13.
__________ can involve criminal activities that are traditional in nature, such as theft, fraud, forgery, defamation, and mischief.
(A) Cybercrimes
(B) Hacker
(C) Computer crime
(D) Illegal Act
Answer:
(A) Cybercrimes

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 14.
__________ is nothing but copyright violation of software created originally by an individual or an institution.
(A) Software piracy
(B) Unauthorized access
(C) Authorization
(D) Copyright
Answer:
(A) Software piracy

Question 15.
__________ includes stealing of codes/programs and other information illegally and creating the imitated copy by unauthorized means.
(A) Software piracy
(B) Unauthorized access
(C) Authorization
(D) Copyright
Answer:
(A) Software piracy

Question 16.
Gaining access without the users’ permission is known as __________
(A) Software piracy
(B) Unauthorized access
(C) Authorization
(D) Copyright
Answer:
(B) Unauthorized access

Question 17.
__________ means granting access rights to resources.
(A) Software piracy
(B) Unauthorized access
(C) Authorization
(D) Copyright
Answer:
(C) Authorization

Question 18.
A __________ is a legal right that gives the creator of a literary, artistic, musical, or other creative work.
(A) Software piracy
(B) Unauthorized access
(C) Authorization
(D) Copyright
Answer:
(D) Copyright

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 19.
__________ owners have the right to control the reproduction of their work, including the right to receive the royalty payment for that reproduction.
(A) Software piracy
(B) Unauthorized access
(C) Authorization
(D) Copyright
Answer:
(D) Copyright

Question 20.
Activity such as decipher codes or passwords and breaking security systems for illegal reasons is called __________
(A) Cracking
(B) Crack
(C) Cyberstalking
(D) Phishing
Answer:
(A) Cracking

Question 21.
The cracker will use a program or script known as a __________
(A) Cracking
(B) Crack
(C) Cyberstalking
(D) Phishing
Answer:
(B) Crack

Question 22.
__________ is a criminal practice where an individual uses the Internet to systematically harass or threaten someone.
(A) Cracking
(B) Crack
(C) Cyberstalking
(D) Phishing
Answer:
(C) Cyberstalking

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 23.
__________ is a technique of extracting confidential information such as credit card numbers and username password combos by pretending as a legal enterprise.
(A) Cracking
(B) Crack
(C) Cyberstalking
(D) Phishing
Answer:
(D) Phishing

Question 24.
__________ is typically carried out by email spoofing.
(A) Cracking
(B) Crack
(C) Cyberstalking
(D) Phishing
Answer:
(D) Phishing

Question 25.
__________ is presenting someone else’s work or idea as your own without their consent.
(A) Plagiarism
(B) Hacking
(C) Hacker
(D) A. Cracking
Answer:
(A) Plagarism

Question 26.
__________ refers to unauthorised intrusion into a computer or a network.
(A) Plagiarism
(B) Hacking
(C) Hacker
(D) Cracking
Answer:
(B) Hacking

Question 27.
__________ is a person intensely interested in the deep and hidden or concealed working of any computer operating system and programming language.
(A) Plagiarism
(B) Hacking
(C) Hacker
(D) Cracking
Answer:
(C) Hacker

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 28.
__________ is a method of converting the original message into random text.
(A) Encryption
(B) Secure Socket Layer
(C) Firewall
(D) Hardware
Answer:
(A) Encryption

Question 29.
Full form of SSL is __________
(A) Secure Socket Layer
(B) Secure Switch Layer
(C) Secure Session Lesson
(D) System Secure Layer
Answer:
(A) Secure Socket Layer

Question 30.
Through the __________, transmission of data is encrypted.
(A) Secure Socket Layer
(B) Secure Switch Layer
(C) Secure Session Lesson
(D) System Secure Layer
Answer:
(A) Secure Socket Layer

Question 31.
__________ refers to a network security (Hardware and Software) system which blocks certain types of information.
(A) Encryption
(B) Secure Socket Layer
(C) Firewall
(D) Hardware
Answer:
(C) Firewall

Question 32.
__________ is an Act to provide legal recognition for transactions carried out by means of electronic data interchange and other means of electronic communication.
(A) Information Technology Act, 2000
(B) Cyber laws
(C) Digital Signature
(D) Digital Certificate
Answer:
(A) Information Technology Act, 2000

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 33.
__________ aims to provide the legal infrastructure for e-commerce in India.
(A) Information Technology Act, 2000
(B) Cyber laws
(C) Digital signature
(D) Digital Certificate
Answer:
(A) Information Technology Act, 2000

Question 34.
The __________ have a major impact on E-Businesses and the new economy in India.
(A) Information Technology Act, 2000
(B) Cyber Laws
(C) Digital signature
(D) Digital Certificate
Answer:
(B) Cyber Laws

Question 35.
The also aims to provide for the legal framework.
(A) Information Technology Act, 2000
(B) Cyber Laws
(C) Digital signature
(D) Digital Certificate
Answer:
(A) Information Technology Act, 2000

Question 36.
__________ has been replaced with the electronic signature to make it a more technology-neutral act.
(A) Information Technology Act, 2000
(B) Cyber laws
(C) Digital Signature
(D) Digital Certificate
Answer:
(C) Digital Signature

4. Multiple Choice Two Correct Answers.

Question 1.
The Information Technology Act 2000 attempts to change outdated __________ and provides ways to deal with __________
(A) Authentication
(B) Laws
(C) Electronic record
(D) Cybercrimes
(E) Morals
Answer:
(B) Laws, (D) Cybercrimes

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 2.
The Information Technology Act has also proposed a legal framework for the __________ and origin of __________
(A) Authentication
(B) Laws
(C) Electronic record
(D) Cybercrimes
(E) Morals
Answer:
(A) Authentication, (C) Electronic record

Question 3.
Thus __________ are dictated by society, culture or religion while __________ are chosen by the person himself which governs his life.
(A) Authentication
(B) Laws
(C) Electronic record
(D) Morals
(E) Ethics
Answer:
(D) Morals, (E) Ethics

Question 4.
Hacker is a person intensely interested in the deep and hidden or concealed working of any computer __________ and __________
(A) Operating System
(B) Programming Language
(C) Individual
(D) Institution
(E) Passwords
Answer:
(A) Operating System, (B) Programming Language

Question 5.
Software piracy is nothing but copyright violation of software created originally by an __________ or an __________
(A) Operating system
(B) Programming language
(C) Individual
(D) Institution
(E) Passwords
Answer:
(C) Individual, (D) Institution

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 6.
Activity such as __________ or __________ and breaking security systems for illegal reasons is called cracking.
(A) Operating system
(B) Programming language
(C) Individual
(D) Decipher Codes
(E) Passwords
Answer:
(D) Decipher Codes, (E) Passwords

Question 7.
Phishing is a technique of extracting confidential information such as __________ and __________ combos by pretending as a legal enterprise.
(A) Computer
(B) Credit Card Numbers
(C) Network
(D) Username Password
(E) Programming Language
Answer:
(B) Credit Card Numbers, (D) Username Password

Question 8.
Hacking refers to unauthorised intrusion into a __________ or a __________
(A) Computer
(B) Credit Card Numbers
(C) Network
(D) Username Password
(E) Programming Language
Answer:
(A) Computer, (C) Network

Question 9.
Hacker is a person intensely interested in the deep and hidden or concealed working of any computer __________ and __________
(A) Operating system
(B) Programming language
(C) Individual
(D) Decipher Codes
(E) Passwords
Answer:
(A) Operating system, (B) Programming language

Question 10.
Encryption is a method of converting the __________ message into __________ text.
(A) Original
(B) Random
(C) Hardware
(D) Software
(E) Electronic communication
Answer:
(A) Original, (B) Random

Question 11.
Firewall refers to network security __________ and __________ system which blocks certain type of information.
(A) Original
(B) Random
(C) Hardware
(D) Software
(E) Electronic communication
Answer:
(C) Hardware, (D) Software

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 12.
Information Technology Act, 2000 is an Act to provide legal recognition for transaction carried out by means of __________ and other means of __________
(A) Original
(B) Random
(C) Hardware
(D) Electronic Data Interchange
(E) Electronic Communication
Answer:
(D) Electronic Data Interchange, (E) Electronic Communication

Question 13.
Information Technology Act, 2000 aims to provide the __________ infrastructure for __________ in India.
(A) Legal
(B) E-Commerce
(C) Original
(D) Random
(E) Hardware
Answer:
(A) Legal, (B) E-Commerce

5. Multiple Choice Three Correct Answers.

Question 1.
Cyberlaw is the area of law that deals with the Internet’s relationship to technological and electronic elements, including computers, __________, __________ and __________
(A) Software
(B) Internet
(C) Hardware
(D) Legal Issues
(E) Information Systems
Answer:
(A) Software, (C) Hardware, (E) Information Systems

Question 2.
Cyberlaw is the part of the overall legal system that deals with the __________, __________, and their respective __________
(A) Software
(B) Internet
(C) Cyberspace
(D) Legal Issues
(E) Information Systems
Answer:
(B) Internet, (C) Cyberspace, (D) Legal Issues

Question 3.
Cyber lawcoversafairlybroadarea,encompassingseveralsubtopicsincluding __________, access to and __________, and __________
(A) Freedom of expression
(B) Usage of the Internet
(C) Online privacy
(D) Electronic Crime
(E) Hi-Tech Crime
Answer:
(A) Freedom of expression, (B) Usage of the Internet, (C) Online privacy

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 4.
Computer Crime is alternatively referred to as __________, __________ or __________
(A) Freedom of expression
(B) Usage of the Internet
(C) Cybercrime
(D) Electronic Crime
(E) Hi-Tech Crime
Answer:
(C) Cybercrime, (D) Electronic Crime, (E) Hi-Tech Crime

Question 5.
Activity such as __________ codes or __________ and breaking __________ systems for illegal reasons is called cracking.
(A) Cyber Cafe
(B) Decipher
(C) Cyber Security
(D) Passwords
(E) Security
Answer:
(B) Decipher, (D) Passwords, (E) Security

Question 6.
The IT Act 2000 was amended in 2008 and 2011 and it includes rules for __________, __________, __________ by service provider, Audit of electronic document etc.
(A) Cyber Cafe
(B) Decipher
(C) Cyber Security
(D) Delivery of Services
(E) Security
Answer:
(A) Cyber Cafe, (C) Cyber Security, (D) Delivery of Services

6. Match the following.

Question 1.

Column ‘A’Column ‘B’
(1) Ethics(A) Computer Crime
(2) Morals(B) Principles of right and wrong
(3) Cyber Crime(C) Moral philosophy
(4) Hacker(D) Illegally browses or steals a company’s or individual’s private information

Answer:

Column ‘A’Column ‘B’
(1) Ethics(C) Moral philosophy
(2) Morals(B) Principles of right and wrong
(3) Cyber Crime(A) Computer Crime
(4) Hacker(D) Illegally browses or steals a company’s or individual’s private information

Question 2.

Column ‘A’Column ‘B’
(1) Software Piracy(A) Legal right
(2) Unauthorized access(B) Gaining access without the users’ permission
(3) Authorization(C) Granting access rights to resources
(4) Copyright(D) Copyright violation of software

Answer:

Column ‘A’Column ‘B’
(1) Software Piracy(D) Copyright violation of software
(2) Unauthorized access(B) Gaining access without the users’ permission
(3) Authorization(C) Granting access rights to resources
(4) Copyright(A) Legal right

Question 3.

Column ‘A’Column ‘B’
(1) Copyright owners(A) Have the right to control the reproduction of their work
(2) Cracking(B) Will use a program or script known as a crack
(3) Cracker(C) Breaking security systems for illegal reasons
(4) Cyberstalking(D) Uses the Internet to systematically harass or threaten someone

Answer:

Column ‘A’Column ‘B’
(1) Copyright owners(A) Have the right to control the reproduction of their work
(2) Cracking(C) Breaking security systems for illegal reasons
(3) Cracker(B) Will use a program or script known as a crack
(4) Cyberstalking(D) Uses the Internet to systematically harass or threaten someone

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 4.

Column ‘A’Column ‘B’
(1) Phishing(A) Technique of extracting confidential information
(2) Plagiarism(B) Presenting someone else’s work or idea as your own without their consent
(3) Hacking(C) Safe and responsible use of information and communication technology
(4) Cyber Safety(D) Refers to unauthorized intrusion into a computer or a network

Answer:

Column ‘A’Column ‘B’
(1) Phishing(A) Technique of extracting confidential information
(2) Plagiarism(B) Presenting someone else’s work or idea as your own without their consent
(3) Hacking(D) Refers to unauthorized intrusion into a computer or a network
(4) Cyber Safety(C) Safe and responsible use of information and communication technology

Question 5.

Column ‘A’Column ‘B’
(1) Netiquette(A) Network Security
(2) Encryption(B) Method of converting the original message into random text
(3) Secure Socket Layer(C) Transmission of data is encrypted
(4) Firewall(D) Internet etiquette

Answer:

Column ‘A’Column ‘B’
(1) Netiquette(D) Internet etiquette
(2) Encryption(B) Method of converting the original message into random text
(3) Secure Socket Layer(C) Transmission of data is encrypted
(4) Firewall(A) Network Security

Question 6.

Column ‘A’Column ‘B’
(1) IT Act 2000(A) Provide legal recognition for transactions carried out by means of electronic data interchange
(2) Digital Signature(B) Electronic Signature

Answer:

Column ‘A’Column ‘B’
(1) IT Act 2000(A) Provide legal recognition for transactions carried out by means of electronic data interchange
(2) Digital Signature(B) Electronic Signature

7. Answer Briefly.

Question 1.
What is Cyber Law?
Answer:

  1. Cyberlaw is the area of law that deals with the Internet’s relationship to technological and electronic elements.
  2. Cyberlaw is the part of the overall legal system that deals with the Internet, cyberspace, and their respective legal issues.
  3. Cyberlaw covers a fairly broad area, encompassing several subtopics including freedom of expression, access to and usage of the Internet, and online privacy

Question 2.
State the advantages of Cyber Law.
Answer:

  1. The Information Technology Act 2000 attempts to change outdated laws and provides ways to deal with cybercrimes.
  2. The Information Technology Act offers the much-needed legal framework so that information is not denied.
  3. The Information Technology Act has also proposed a legal framework for the authentication and origin of electronic records.

Question 3.
Define Ethics and Morals.
Answer:

  1. Ethics is also called moral philosophy is the discipline concerned with what is morally good and bad, right or wrong.
  2. Morals are the standards of behaviour; principles of right and wrong behaviour.
  3. Thus Morals are dictated by society, culture, or religion.

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 4.
What is Cyber Crime?
Answer:

  1. Computer Crime is alternatively referred to as Cybercrime.
  2. Computer crime is an act performed by a knowledgeable computer user, sometimes referred to as a Hacker.
  3. A Hacker who illegally browses or steals a company’s or individual’s private information.
  4. Cybercrimes can involve criminal activities that are traditional in nature, such as theft, fraud, forgery, defamation, and mischief.

Question 5.
State the examples of Cyber Crime.
Answer:

  1. Software piracy is nothing but copyright violation of software created originally by an individual or an institution.
  2. Software piracy includes stealing codes/programs and other information illegally and creating the imitated copy by unauthorized means.
  3. Gaining access without the users’ permission is known as unauthorized access.
  4. Authorization means granting access rights to resources.
  5. A copyright is a legal right that gives the creator of a literary, artistic, musical, or other creative work.
  6. Copyright owners have the right to control the reproduction of their work, including the right to receive the royalty payment for that reproduction.
  7. Activity such as decipher codes or passwords and breaking security systems for illegal reasons is called cracking.
  8. The cracker will use a program or script known as a Crack.
  9. Cyberstalking is a criminal practice where an individual uses the Internet to systematically harass or threaten someone.
  10. Phishing is a technique of extracting confidential information such as credit card numbers and username password combos by pretending as a legal enterprise.
  11. Phishing is typically carried out by email spoofing.
  12. Plagiarism is presenting someone else’s work or idea as your own without their consent.
  13. Hacking refers to unauthorized intrusion into a computer or a network.
  14. Hacker is a person intensely interested in the deep and hidden or concealed working of any computer operating system and programming language.

Question 6.
Explain Security Procedures.
Answer:

  1. Encryption is a method of converting the original message into random text.
  2. The full form of SSL is Secure Socket Layer.
  3. Through the Secure Socket Layer, the transmission of data is encrypted.
  4. A firewall refers to a network security (Hardware and Software) system which blocks certain types of information.

Maharashtra Board Class 11 Information Technology Important Questions Chapter 4 Cyber Law

Question 7.
Discuss the IT Act of India 2000 and its features.
Answer:

  1. Information Technology Act, 2000 is an Act to provide legal recognition for transactions carried out by means of electronic data interchange and other means of electronic communication.
  2. Information Technology Act, 2000 aims to provide the legal infrastructure for E-Commerce in India.
  3. Cyber Laws have a major impact on e-businesses and the new economy in India.
  4. The Information Technology Act, 2000 also aims to provide for the legal framework.
  5. Digital signature has been replaced with the electronic signature to make it a more technology-neutral act.