Class 6

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 11 Ratio-Proportion Class 6 Practice Set 28 Answers Solutions.

6th Standard Maths Practice Set 28 Answers Chapter 11 Ratio-Proportion

6th Standard Maths Practice Set 28 Question 1.
In each example below, find the ratio of the first number to the second:
i. 24, 56
ii. 63,49
iii. 52, 65
iv. 84, 60
v. 35, 65
vi. 121, 99
Solution:
i. 24, 56
\(\frac{24}{56}=\frac{24 \div 8}{56 \div 8}=\frac{3}{7}\)
= 3:7

ii. 63,49
\(\frac{63}{49}=\frac{63 \div 7}{49 \div 7}=\frac{9}{7}\)
= 9:7

iii. 52, 65
\(\frac{52}{65}=\frac{52 \div 13}{65 \div 13}=\frac{4}{5}\)
= 4:5

iv. 84, 60
\(\frac{84}{60}=\frac{84 \div 12}{60 \div 12}=\frac{7}{5}\)
= 7:5

v. 35, 65
\(\frac{35}{65}=\frac{35 \div 5}{65 \div 5}=\frac{7}{13}\)
= 7:13

vi. 121, 99
\(\frac{121}{99}=\frac{121 \div 11}{99 \div 11}=\frac{11}{9}\)
= 11:9

6th Maths Practice Set 28 Question 2.
Find the ratio of the first quantity to the second.
i. 25 beads, 40 beads
ii. Rs 40, Rs 120
iii. 15 minutes, 1 hour
iv. 30 litres, 24 litres
v. 99 kg, 44000 grams
vi. 1 litre, 250 ml
vii. 60 paise, 1 rupee
viii. 750 grams, \(\frac { 1 }{ 2 }\) kg
ix. 125 cm, 1 metre
Solution:
i. Required Ratio = \(\frac{25}{40}=\frac{25 \div 5}{40 \div 5}=\frac{5}{8}\)

ii. Required Ratio = \(\frac{40}{120}=\frac{40 \div 40}{120 \div 40}=\frac{1}{3}\)

iii. 1 hour = 60 minutes
Required Ratio = \(\frac{15}{60}=\frac{15 \div 15}{60 \div 15}=\frac{1}{4}\)

iv. Required Ratio = \(\frac{30}{24}=\frac{30 \div 6}{24 \div 6}=\frac{5}{4}\)

v. 99 kg = 99 x 1000 grams = 99000 grams
Required Ratio = \(\frac{99000}{44000}=\frac{99000 \div 1000}{44000 \div 1000}=\frac{99}{44}\)
= \(\frac{99}{44}=\frac{99 \div 11}{44 \div 11}=\frac{9}{4}\)

vi. 1 litre, 250 ml
1 litre = 1000 ml
Required Ratio = \(\frac{1000}{250}=\frac{1000 \div 10}{250 \div 10}=\frac{100}{25}\)
= \(\frac{100}{25}=\frac{100 \div 25}{25 \div 25}=\frac{4}{1}\)

viii. 750 grams, \(\frac { 1 }{ 2 }\) kg
\(\frac { 1 }{ 2 }\) kg = \(\frac { 1000 }{ 2 }\) grams = 500 grams
Required Ratio = \(\frac{750}{500}=\frac{750 \div 10}{500 \div 10}=\frac{75}{50}\)
= \(\frac{75}{50}=\frac{75 \div 25}{50 \div 25}=\frac{3}{2}\)

ix. 125 cm, 1 metre
1 metre = 100 cm
Required Ratio = \(\frac{125}{100}=\frac{125 \div 25}{100 \div 25}=\frac{5}{4}\)

6th Std Maths Practice Set 28 Question 3.
Reema has 24 notebooks and 18 books. Find the ratio of notebooks to books.
Solution:
Ratio of notebooks to books

∴ The ratio of notebooks to books with Reema is \(\frac { 4 }{ 3 }\)

Practice Set 28 Question 4.
30 cricket players and 20 kho-kho players are training on a field. What is the ratio of cricket players to the total number of players?
Solution:
Total number of players = Cricket players + Kho-kho players
= 30 + 20 = 50
Ratio of cricket players to the total number of players

∴ The ratio of cricket players to the total number of players is \(\frac { 3 }{ 5 }\).

Question 5.
Snehal has a red ribbon that is 80 cm long and a blue ribbon 2.20 m long. What is the ratio of the length of the red ribbon to that of the blue ribbon?
Solution:
1 metre =100 cm
Length of the red ribbon = 80 cm
Length of the blue ribbon = 2.20 m = 2.20 x 100 cm
\(=\frac{220}{100} \times \frac{100}{1}=\frac{220 \times 100}{100 \times 1}\)
= 220 cm
∴ Ratio of length of the red ribbon to that of the blue ribbon

∴ The ratio of the length of the red ribbon to that of the blue ribbon is \(\frac { 4 }{ 11 }\).

11 Ratio Question 6.
Shubham’s age today is 12 years and his father’s is 42 years. Shubham’s mother is younger than his father by 6 years. Find the following ratios.
i. Ratio of Shubham’s age today to his mother’s age today.
ii. Ratio of Shubham’s mother’s age today to his father’s age today.
iii. The ratio of Shubham’s age to his mother’s age when Shubham was 10 years old.
Solution:
Shubham’s age today = 12 years
Shubham’s father’s age = 42 years
Shubham’s mother age = Shubham’s father’s age – 6 years
= 42 years – 6 years = 36 years

i. Ratio of Shubham’s age today to his mother’s age today

∴ The ratio of Shubham’s age today to his mother’s age today is \(\frac { 1 }{ 3 }\).

ii. Ratio of Shubham’s mother age today to his father’s age today

∴ The ratio of Shubham’s mother’s age today to his father’s age today is \(\frac { 6 }{ 7 }\).

iii. Shubham’s age today is 12 years and his mothers age is 36 years.
Hence when Shubham’s age was 10 years, his mother’s age was 34 years (i.e. 36 – 2 years).
Ratio of Shubham’s age to his mother’s age when Shubham was 10 years old

∴ The ratio of Shubham’s age to his mother’s age when Shubham was 10 years old is \(\frac { 5 }{ 17 }\)

Maharashtra Board Class 6 Maths Chapter 11 Ratio-Proportion Practice Set 28 Intext Questions and Activities

Question 1.
In the figure, colour some squares with any colour you like and leave some blank. (Textbook pg. no. 57)

i. Count all the boxes and write the number.
ii. Count the colored ones and write the number.
iii. Count the blank ones and write the number.
iv. Find the ratio of the colored boxes to the blank ones.
v. Find the ratio of the colored boxes to the total boxes.
vi. Find the ratio of the blank boxes to the total boxes.
Solution:
i. The number of all boxes is 16.
ii. The number of colored boxes is 7.
iii. The number of blank boxes is 9.
iv. Ratio of the colored boxes to the blank ones

v. Ratio of the colored boxes to the total boxes

vi. Ratio of the blank boxes to the total boxes

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 3 Integers Class 6 Practice Set 5 Answers Solutions.

6th Standard Maths Practice Set 5 Answers Chapter 3 Integers

Question 1.
Add:

1. 8 + 6
2. 9 + (-3)
3. 5 + (-6)
4. – 7 + 2
5. – 8 + 0
6. – 5 + (-2)

Solution:

1. 8 + 6 = (+8) + (+6) = +14	2. 9 + (-3) = (+9) + (- 3) = +6	3. 5 + (-6) = (+5) + (-6) = -1
4. -7 + 2 = (-7) + (+2) = -5	5. -8 + 0 = (-8) + 0 = -8	6. -5 + (-2) = (-5) + (-2) = -7

Question 2.
Complete the table given below:

+	8	4	-3	-5
-2	-2 + 8 = +6
6
0
-4

Solution:

+	8	4	-3	-5
-2	(-2) + (+8) = +6	(-2) +(+4) = 2	(-2) +(-3) =-5	(-2) +(-5) =-7
6	(+6) + (+8) = 14	(+6) + (+4) = 10	(+6) + (-3) = 3	(+6) + (-5) = 1
0	0 + (+8) = 8	0 + (+4) = 4	0 + (-3) = -3	0 + (-5) = -5
-4	(-4) + (+8) = 4	(-4) +(+4) = 0	(-4) + (-3) = -7	(-4) + (-5) = -9

Maharashtra Board Class 6 Maths Chapter 3 Integers Practice Set 5 Intext Questions and Activities

Question 1.
On the playground, mark a timeline showing the years from 2000 to 2024. With one child standing at the position of the 2017, ask the following questions: (Textbook pg. no. 15)

1. While playing this game, what is his/her age?
2. Five years ago, which year was it? And what was his / her age then?
3. In which year will he / she go to Std X? How old will he / she be then?

The child should find answers to such questions by walking the right number of units and in the right direction on the timeline.
[Assume child born year is 2009]
Solutions:

1. Age of child is 8 years.
2. Five years ago, year was 2012. His/her age is 3 years.
3. In 2024, he/she will go the Std X. His/her age is 15 years.

Question 2.
On a playground mark a timeline of 100 years. This will make it possible to count the years from 0 to 2100 on it. Important historical events can then be shown in proper centuries. (Textbook pg. no. 16)
Solution:
(Students should attempt this activity on their own)

Question 3.
Observe the figures and write appropriate number in the boxes given below. (Textbook pg. no. 16 and 17)
i.

a. At first the rabbit was at the number ____
b. It hopped ___ units to the right.
c. It is now at the number ___
Solution:
i.
a. +1
b. 5
c. +6

ii.

a. At first the rabbit was at the number ___
b. It hopped ____ units to the right.
c. It is now at the number ____
Solution:
ii.
a. -2
b. 5
c. +3

iii.

a. At first the rabbit was at the number ___
b. It hopped ____ units to the left.
c. It is now at the number ___
Solution:
iii.
a. -3
b. 4
c. -7

iv.

a. At first the rabbit was at the number ___
b. It hopped___units to the left.
c. It is now at the number ____
Solution:
iv.
a. +3
b. 4
c. -1

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 17 Geometrical Constructions Class 6 Practice Set 39 Answers Solutions.

6th Standard Maths Practice Set 39 Answers Chapter 17 Geometrical Constructions

Question 1.
Draw line l. Take any point P on the line. Using a set square, draw a line perpendicular to line l at the point P.
Solution:
Step 1:

Step 2:

line PQ ⊥ line l

Question 2.
Draw a line AB. Using a compass, draw a line perpendicular to AB at point B.
Solution:
Step 1:

Step 2:

Step 3:

line BC ⊥ line AB.

Question 3.
Draw line CD. Take any point M on the line. Using a protractor, draw a line perpendicular to line CD at the point M.
Solution:
Step 1:

Step 2:

line MN ⊥ line CD

Maharashtra Board Class 6 Maths Chapter 17 Geometrical Constructions Practice Set 39 Questions and Activities

Question 1.
When constructing a building, what is the method used to make sure that a wall is exactly upright? What does the mason in the picture have in his hand? What do you think is his purpose for using it? (Textbook pg. no. 87)

Solution:
When constructing a building, a weight (usually with a pointed tip at the bottom) suspended from a string called as plummet or plump bob is aligned from the top of the wall to make sure that the wall is built exactly upright.
The mason in the picture is holding a plumb bob.
The string of the plumb bob is suspended from the top of the wall, such that plumb bob hangs freely. By observing whether the vertical wall is parallel to the string we can check if the constructed wall is vertical.

Question 2.
Have you looked at lamp posts on the roadside? How do they stand? (Textbook pg. no. 87)
Solution:
The lamp posts on the road side are standing erect or vertical.

Question 3.
For the above explained construction, why must we take a distance greater than half of the length of AB? What will happen if we take a smaller distance? (Textbook pg. no. 88)
Solution:
For the above construction, in step-3 we take distance greater than half of the length of AB, so that the arcs drawn by keeping the compass on points A and B intersect each other at point Q.
If the distance in compass is less than half of the length of AB, then the arcs drawn by keeping the compass at A and B will not intersect each other.

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 6 Bar Graphs Class 6 Practice Set 18 Answers Solutions.

6th Standard Maths Practice Set 18 Answers Chapter 6 Bar Graphs

Question 1.
This bar graph shows the maximum temperatures in degrees Celsius in different cities on a certain day in February. Observe the graph and answer the questions:

1. What data is shown on the vertical and the horizontal lines?
2. Which city had the highest temperature?
3. Which cities had equal maximum temperatures?
4. Which cities had a maximum temperature of 30 °C?
5. What is the difference between the maximum temperatures of Panchgani and Chandrapur?

Solution:

1. Temperature is shown on the vertical line and cities are shown on the horizontal line.
2. The city Chandrapur had the highest temperature.
3. Pune and Nashik had the equal maximum temperature of 30°C and Panchgani and Matheran had the equal maximum temperature of 25°C.
4. Pune and Nashik had a maximum temperature of 30 °C.
5. The difference between the maximum temperatures of Panchgani and Chandrapur can be calculated as Difference in temperature = Temperature of Chandrapur – Temperature of Panchgani
   = 35°C – 25°C
   = 10°C

Maharashtra Board Class 6 Maths Chapter 6 Bar Graphs Practice Set 18 Intext Questions and Activities

Question 1.
Observe the picture alongside: (Textbook pg. no. 35)

1. To which sport is this data related?
2. How many things does the picture tell us about?
3. What shape has been used in the picture to represent runs?

Ans:

1. The given data is related to cricket.
2. The picture tells about runs scored in different overs by India and Srilanka. The represents the wickets fallen in that over.
3. To represent runs, rectangular or bar shape is used.

Question 2.
A pictogram of the types and numbers of vehicles in a city is given below.
Taking 1 picture = 5 vehicles, write the numbers in the pictogram. (Textbook pg. no.35)

Solution:

Drawing pictograms is time consuming.
Sometimes, it is practically not possible to draw pictures for the given values (for example population of villages etc). In such cases, representing the data by making use of graphs can serve the purpose. Such data can be represented by using graphs.

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 3 Integers Class 6 Practice Set 4 Answers Solutions.

6th Standard Maths Practice Set 4 Answers Chapter 3 Integers

Question 1.
Classify the following numbers as positive numbers and negative numbers.
-5, +4, -2, 7, +26, -49, -37, 19, -25, +8, 5, -4, -12, 27
Solution:

Positive Numbers	+4, 7, +26, 19, +8, 5, 27
Negative Numbers	-5, -2, -49, -37, -25, -4, -12

Question 2.
Given below are the temperatures in some cities. Write them using the proper signs.

Place	Shimla	Leh	Delhi	Nagpur
Temperature	7 °C below 0°	12 °C below 0°	22 °C above 0°	31 °C above 0°

Solution:

Place	Shimla	Leh	Delhi	Nagpur
Temperature with proper sign	-7 °C	-12 °C	+22 °C	+31 °C

Question 3.
Write the numbers in the following examples using the proper signs.

1. A submarine is at a depth of 512 meters below sea level.
2. The height of Mt Everest, the highest peak in the Himalayas, is 8848 meters.
3. A kite is flying at a distance of 120 meters from the ground.
4. The tunnel is at a depth of 2 meters under the ground.

Solution:

1. A submarine is at a depth of -512 meters from sea level.
2. The height of Mt Everest, the highest peak in the Himalayas is +8848 meters.
3. A kite is flying at a distance of +120 meters from the ground.
4. The tunnel is at a depth of -2 meters from the ground.

Maharashtra Board Class 6 Maths Chapter 3 Integers Practice Set 4 Intext Questions and Activities

Question 1.
Take warm water in one beaker, some crushed ice in another and a mixture of salt and crushed ice in a third beaker. Ask your teacher for help in measuring the temperature of the substance in each of the beakers using a thermometer. Note the temperatures. (Textbook pg. no. 13)

Solution:
( Students should attempt this activity on their own)

Question 2.
Look at the picture of the kulfi man. Why do you think he keeps the kulfi moulds in a mixture of salt and ice? (Textbook pg. no. 14)

Solution:
Kulfi man keeps the kulfi moulds in a mixture of salt and ice because such a mixture helps in keeping the kulfi cool for a longer period of time. The kulfi kept in the said mixture relatively takes more time to melt. This mixture is Considered ideal as it has the temperature of -4°C as against the temperature of ice i.e. 0°C.

Question 3.
My class, i.e. Std. VI, is a part of my school. My school is in my town. My town is a part of a taluka. In the same way, the taluka is a part of a district, and the district is a part of Maharashtra State. In the same way, what can you say about these groups of numbers? Textbook pg. no. 15)

Solution:
By observing the above given groups of numbers, we can infer that natural numbers are a part of whole numbers. In turn, whole numbers are a part of integers.

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 5 Decimal Fractions Class 6 Practice Set 17 Answers Solutions.

6th Standard Maths Practice Set 17 Answers Chapter 5 Decimal Fractions

Question 1.
Carry out the following divisions.
i. 4.8÷2
ii. 17.5÷5
iii. 20.6÷2
iv. 32.5÷25
Solution:
i. 4.8÷2

ii. 17.5÷5

iii. 20.6÷2

iv. 32.5÷25

Question 2.
A road is 4 km 800 m long. If trees are planted on both its sides at intervals of 9.6 m, how many trees were planted?
Solution:
Length of road = 4 km 800 m
= 4 × 1000 m + 800 m
= 4000 m + 800 m
= 4800 m
Number of trees on one side = 4800 ÷ 9.6

= 500
∴ Number of trees on both sides = 2 x number of trees on one side
= 2 x 500 = 1000
If the trees are planted at the beginning of the road, then
Total number of trees = 1000 + 2 = 1002
∴ Total number of trees planted is 1000 or 1002.

Question 3.
Pradnya exercises regularly by walking along a circular path on a field. If she walks a distance of 3.825 km in 9 rounds of the path, how much does she walk in one round?
Solution:
Total distance walked in 9 rounds = 3.825 km
∴Distance walked in 1 round = 3.825 4 ÷ 9

= 0.425 km
∴ Total distance walked in 1 round is 0.425 km.

Question 4.
A pharmaceutical manufacturer bought 0.25 quintal of hirada, a medicinal plant, for Rs 9500. What is the cost per quintal of hirada? (1 quintal = 100 kg)
Solution:
Cost of 0.25 quintal of hirada = Rs 9500
∴ Cost of 1 quintal of hirada = 9500 ÷ 0.25

= Rs 38,000
∴ Cost per quintal of hirada is Rs 38,000.

Maharashtra Board Class 6 Maths Chapter 4 Operations on Fractions Practice Set 17 Intext Questions and Activities

Question 1.
Maths is fun! (Textbook pg. no. 34)

1. Consider any three-digit number (say 527).
2. Multiply the number by 7. Then multiply the product obtained by 13, and this product by 11.
3. The found product is 5,27,527.

Take two or three other numbers. Do the same multiplication and find out how it is done.
Solution:
7 × 13 × 11 = 1001
∴ 527 × 1001 = 527 × (1000+ 1)
= (527 × 1000) + (527 × 1)
= 527000 + 527 = 527527
Thus, when any three-digit number is multiplied with 1001, the product obtained is a six-digit number in which the original three-digit number is written back to back twice.
(Students may consider any other three-digit numbers and verify the property.)

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 16 Quadrilaterals Class 6 Practice Set 38 Answers Solutions.

6th Standard Maths Practice Set 38 Answers Chapter 16 Quadrilaterals

Question 1.
Draw ₹XYZW and answer the following:
i. The pairs of opposite angles.
ii. The pairs of opposite sides.
iii. The pairs of adjacent sides.
iv. The pairs of adjacent angles.
v. The diagonals of the quadrilateral.
vi. The name of the quadrilateral in different ways.
Solution:

i. a. ∠XYZ and ∠XWZ
b. ∠YXW and ∠YZW

ii. a. side XY and side WZ
b. side XW and side YZ

iii. a. side XY and side XW
b. side WX and side WZ
c. side ZW and side ZY
d. side YZ and side YX

iv. a. ∠XYZ and ∠YZW
b. ∠YZW and ∠ZWX
c. ∠ZWX and ∠WXY
d. ∠WXY and ∠XYZ

v. Seg XZ and seg YW

vi. ₹XYZW
₹YZWX
₹ZWXY
₹WXYZ
₹XWZY
₹WZYX
₹ZYXW
₹YXWZ

Question 2.
In the table below, write the number of sides the polygon has.

Names	Quadrilateral	Octagon	Pentagon	Heptagon	Hexagon
Number of sides

Solution:

Names	Quadrilateral	Octagon	Pentagon	Heptagon	Hexagon
Number of sides	4	8	5	7	6

Question 3.
Look for examples of polygons in your surroundings. Draw them.
Solution:

Question 4.
We see polygons when we join the tips of the petals of various flowers. Draw these polygons and write down the number of sides of each polygon.
Solution:

Question 5.
Draw any polygon and divide it into triangular parts as shown here. Thus work out the sum of the measures of the angles of the polygon.

Solution:

Hexagon ABCDEF can be divided in 4 triangles namely ∆BAF, ∆BFE, ∆BED and ∆BCD
Sum of the measures of the angles of a triangle = 180°
∴ Sum of measures of the angles of the polygon ABCDEF = Sum of the measures of all the four triangles
= 180° + 180° + 180°+ 180°
= 720°
∴ The sum of the measures of the angles of the given polygon (hexagon) is 720°.

Maharashtra Board Class 6 Maths Chapter 16 Quadrilaterals Practice Set 38 Intext Questions and Activities

Question 1.
From your compass boxes, collect set squares of the same shapes and place them side by side in all possible different ways. What figures do you get? Write their names. (Textbook pg. no. 85)
a. Two set squares
b. Three set squares
c. four set squares
Solution:
a. Two set squares

b. Three set squares

c. four set squares

Question 2.
Kaprekar Number. (Textbook pg. no. 86)
i. Take any 4-digit number in which all the digits are not the same.
ii. Obtain a new 4-digit number by arranging the digits in descending order.
iii. Obtain another 4-digit number by arranging the digits of the new number in ascending order.
iv. Subtract the smaller of these two new numbers from the bigger number. The difference obtained will be a 4-digit number. If it is a 3-digit number, put a 0 in the thousands place. Repeat the above steps with the difference obtained as a result of the subtraction.
v. After some repetitions, you will get the number 6174. If you continue to repeat the same steps you will get the number 6174 every time. Let us begin with the number 8531.
8531 → 7173 → 6354 → 3087 → 8352 → 6174 → 6174
This discovery was made by the mathematician, Dattatreya Ramchandra Kaprekar. That is why the number 6174 was named the Kaprekar number.
Solution:

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 5 Decimal Fractions Class 6 Practice Set 16 Answers Solutions.

6th Standard Maths Practice Set 16 Answers Chapter 5 Decimal Fractions

Question 1.
If, 317 × 45 = 14265, then 3.17 × 4.5 = ?
Solution:
3.17 × 4.5
= 14.265

Question 2.
If, 503 × 217 = 109151, then 5.03 × 2.17 = ?
Solution:
5.03 x 2.17
= 10.9151

Question 3.
i. 2.7 × 1.4
ii. 6.17 × 3.9
iii. 0.57 × 2
iv. 5.04 × 0.7
Solution:
i. 2.7 × 1.4

= 3.75

ii. 6.17 × 3.9

= 24.063

iii. 0.57 × 2

= 1.14

iv. 5.04 × 0.7

= 3.528

Question 4.
Virendra bought 18 bags of rice, each bag weighing 5.250 kg. How much rice did he buy altogether? If the rice costs Rs 42 per kg, how much did he pay for it?
Solution:
Weight of one bag of rice = 5.250 kg
Number of bags of rice = 18
∴ Total Weight = 18 × 5.250

Cost of 1 kg of rice = Rs 42
∴ Cost of 94.5 kg of rice = 42 × 94.5

∴ Total rice bought by Virendra is 94.5 kg, and the amount paid for it is Rs 3969.

Question 5.
Vedika has 23.5 metres of cloth. She used it to make 5 curtains of equal size. If each curtain required 4 metres 25 cm to make, how much cloth is left over?
Solution:
We know, that 1 m = 100 cm
Cloth required to make 1 curtain = 4 m 25 cm
= 4 m + \(\frac { 25 }{ 100 }\) m
= 4 m + 0.25 m

= 4.25 m
∴ Cloth required to make 5 curtains = 5 × 4.25

= 21.25 m
Cloth remaining with Vedika = Total cloth with Vedika – Cloth used
= 23.5 m – 21.25 m

= 2.25 m
∴ The length of cloth remaining with Vedika is 2.25 m.

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 18 Three Dimensional Shapes Class 6 Practice Set 41 Answers Solutions.

6th Standard Maths Practice Set 41 Answers Chapter 18 Three Dimensional Shapes

Question 1.
Write the number of faces, edges and vertices of each shape in the table.

Solution:

Name	Cylinder	Cone	Pentagonal pyramid	Hexagonal pyramid	Hexagonal prism	Pentagonal prism
Faces	3 (2 flat + 1 curved)	2 (1 flat + 1 curved)	6 (5 triangles + 1 pentagon)	7 (6 triangles + 1 hexagon)	8 (6 rectangles + 2 hexagons)	7 (5 rectangles + 2 pentagons)
Vertices	0	1	6	7	12	10
Edges	2 (circular)	1 (circular)	10	12	18	15

Maharashtra Board Class 6 Maths Chapter 18 Three Dimensional Shapes Practice Set 41 Questions and Activities

Question 1.

1. Take a rectangular sheet.
2. Bring together its opposite sides. What shape does it form? (Textbook pg. no. 94)

Solution:
It forms a hollow cylinder.

Question 2.

1. Take a cylindrical tin.
2. Take a rectangular sheet with one side equal to the height of the tin.
3. Wrap it around the tin to cover it completely and cut away the extra paper.
4. Then unfold it and spread it out on a table.
5. Take another sheet. Place the tin on it and draw its circular outline.
6. Cut away the paper around it. Cut out another circle like this one.
7. Place these discs next to the rectangular paper as shown in the given figure. Which figure is obtained? (Textbook pg. no. 94)

Solution:
The figure obtained is the net of the closed cylinder.

Question 3.
Can you tell? (Textbook pg. no. 95)
When playing carom, you make a pile of the pieces as shown in the picture. What is the shape of this pile?
If you place a number of CD’s or round biscuits one on top of the other, what shape do you get?

Solution:
In all the cases, it will form a cylindrical shape (2 circular faces and 1 curved surface).

Question 4.

1. Draw a net as shown in figure (a) on a card sheet and cut it out.
2. Fold along the dotted lines of the square and bring the sides together so that the vertices A, B, C and D meet at a point.

What shape does it form? (Textbook pg. no. 95)

Solution:
The given net forms a quadrangular pyramid.

Question 5.

1. Draw a net as shown in figure (a) on a card sheet and cut it out.
2. Fold along the dotted lines of the triangle and bring the sides together so that the vertices A, B and C meet at a point.

What shape does it form? (Textbook pg. no. 95)

Solution:
The given net forms a triangular pyramid.

Question 6.

1. Using a compass draw a circle with centre C on a paper.
2. Draw two radii CR and CS.
3. Cut out the circle.
4. Cut along the radii and obtain two pieces of the circle.
5. Bring together the sides CR and CS of each piece.

On completing the activity, what shapes did you get? (Textbook pg. no. 95)

Solution:
On completing the activity, we get an open cone.

Read Also:

• Shapes Worksheets

Balbharti Maharashtra State Board Class 6 English Solutions Chapter 1.3 Autobiography of a Great Indian Bustard Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 6 English Solutions Chapter 1.3 Autobiography of a Great Indian Bustard

Class 6 English Chapter 1.3 Autobiography of a Great Indian Bustard Textbook Questions and Answers

1. Read the passage aloud.

World Heritage English Workshop Question 1.
Read the passage aloud.

2. You are going to meet a Great Indian Bustard very soon. Prepare at least 10 questions to interview him.

World Heritage Question And Answer 10th Class Question 1.
You are going to meet a Great Indian Bustard very soon. Prepare at least 10 questions to interview him.
Answer:
Hello! It is nice to meet you! Please answer a few questions:

1. What can you tell us about yourself?
2. Where are you and your friends found in India?
3. When are you the most happiest?
4. Why are your numbers on a decline across the globe?
5. Which are the organisations which are supporting you in your struggle for survival?
6. How can the government play a role to help birds and animals on the verge of extinction?
7. Whose initiatives have led to increased awareness about the plight of the Great Indian Bustard?
8. How can media help you in creating awareness about the problems faced by you?
9. What would you like the children to do to support you in order to survive?
10. Do you have any message for human beings?

3. Play the roles of an interviewer and a Great Indian Bustard and write the interview.

World Heritage Class 10 Question 1.
Play the roles of an interviewer and a Great Indian Bustard and write the interview.
Answer:
(Students to attempt)

4. Write u letter to your friend about the Great Indian Bustard. You may use the following points:
Why we need to protect the bird.
What you plan to do to help the bird.

World Heritage 10th Class Lesson Question 1.
Write u letter to your friend about the Great Indian Bustard. You may use the following points:
Why we need to protect the bird.
What you plan to do to help the bird.
Answer:

A/18 Deep Mahal,
Sahar Road,
Vile Parle (E),
Mumbai – 400 057,
15th August, 2016.

Dear Rajani,
Hi! Hope this letter finds you in good health and happiness. I am writing this . letter to express my concern about the fact that only the last 200 of the Great Indian Bustards are left in this world.

The animals, birds, insects, trees, rivers, seas and other elements of nature including man are all the part of a link which binds us together, and which keeps us going. It is high time we protect the Great Indian Bustard and other species which are on the verge of extinction.

How right are the words, “Let’s preserve nature, if not for anything else, For the beauty and strength it inspires!”
We can protect the birds by creating awareness through our school magazine. We can write letters to the government officials too. We can discuss this issue with the elders. We can ask our teacher to take us to sanctuaries to have a better understanding of the life of the Great Indian Bustard.

Let us remember: ‘The future lies in our hands. Let us conserve, preserve and protect all the elements of nature.’
Please think about the issue I shared with you.

Yours lovingly,
XYZ

5. Form pairs and decide whether the following statements are those of a Great Indian Bustard or not.

World Heritage Question And Answer Question 1.
Form pairs and decide whether the following statements are those of a Great Indian Bustard or not.

Answer:

Statements	Great Indian Bustard	Some Other Bird
a. I am the heaviest flying bird in India.	✓
b. I am known as Maldhok or Hoom in Marathi.	✓
c. I live in mountainous regions.		✓
d. I don’t like grasshoppers or beetles.		✓
e. We don’t believe in building nests.	✓
f. Our chick stays with the mother for a period of nearly one year.	✓
g. I am the State Bird of Maharashtra.		✓
h. We have been pushed away from more than 90 per cent of our home regions.	✓

6. With the help of the internet and other sources, obtain more information about the critically endangered birds and animals in India. Find the names of their sanctuaries.

Some critically endangered birds and animals in India:
‘CR’ or critically endangered birds or animals are those that are likely to become extinct in the wild. We may never see them again.

• Forest Owlet
• Indian Vulture
• Siberian Crane
• Deoluli Minnow (fish)
• Asiatic Cheetah
• Himalayan Wolf
• Amboli Toad

7. Prepare a poster on the need for the conservation of the Great Indian Bustard.

World Heritage English Workshop 10th Standard Question 1.
Maharashtra Board Class 6 English Solutions Chapter 1.3 Autobiography of a Great Indian Bustard
Answer:

8. Write a short autobiography of any bird or animal of your choice.

English Workshop Of World Heritage Question 1.
Write a short autobiography of any bird or animal of your choice.
Answer:
Hello friends! I reside in a dense jungle. I love rains and I express my joy by dancing in the rain. People say watching me dance is indeed a beautiful sight. Yes, I am a peacock. I long to fly in the high blue sky like the pigeon. I wish I could fly above the clouds and beyond. Alas! It is not possible.

But I count my blessings. My beauty and the fact that I am the National Bird of India gives me reasons to rejoice and celebrate. Next time you see a graceful bird with a bright shining tail, dancing to its heart’s content in the rainy seasons, you can be rest assured, it’s me.

I have a humble request. Please preserve and protect us. Many of us – my fellow beings are on the verge of extinction. Please save us else we will soon become a part of history.
Remember: Harmony between man and wild life is the only way to solve all the problems faced by the world.
Come, together let us co-exist.

9. Make a list of the channels available on your TV under the following categories:
News, entertainment, sports, movies, music, etc.
Which are the channels on which you can watch programmes on animals, wildlife, conservation of environment, etc.?

10. Ask your parents to show you TV programmes on animals, wildlife and conservation of environment on channels like the following:
DD National, National Geographic, Discovery and Animal Planet.

11. You have won a prize to visit a wildlife sanctuary or National Park in Africa or Australia. Choose a location, read about it. Imagine that you are visiting it and write a letter to your friend about it.

12. Language Study: Identify the following from the list given in the box below :
4 nouns, 4 verbs, 4 adjectives, 4 adverbs, 4 pronouns.

Question 1.
Identify the following from the list given in the box below :

Answer:

Nouns	Verbs	Adjectives	Adverbs	Pronouns
1. bird	1. gather	1. wonderful	1. directly	1. we
2. friends	2. helps	2. healthy	2. together	2. I
3. humans	3. protect	3. happy	3. away	3. you
4. grasslands	4. arrive	4. afraid	4. slowly	4. us

Class 6 English Chapter 1.3 Autobiography of a Great Indian Bustard Additional Important Questions and Answers

Answer in one sentence.

4.3 World Heritage Question 1.
Which is the heaviest flying bird in India?
Answer:
The Great Indian Bustard is the heaviest flying bird in India.

World Heritage 10th Class Lesson Workshop Question 2.
How is the female Indian Bustard different from the male one?
Answer:
The female Indian Bustards are smaller and slimmer than their male counterparts, and their neck is not white.

10th Class World Heritage English Workshop Question 3.
Where do the Great Indian Bustards live?
Answer:
The Great Indian Bustards live on grasslands and deserts.

Question 4.
Name any two things which are favourite food items of a Great Indian Bustards.
Answer:
Grasshoppers and beetles.

Question 5.
Rains usher happiness into the lives of the Great Indian Bustards. Pick out proof from the lesson for this statement.
Answer:
“I dance in joy with puffed feathers and cocked up tail and dropped down wings.”

Question 6.
Who are the enemies of the Great Indian Bustard’s eggs and chicks?
Answer:
Monitor lizards, foxes, dogs, pigs, snakes and eagles are the enemies of the Great Indian Bustard’s eggs and chicks.

Question 7.
What is the difference between the young ones of other birds and the Great Indian Bustards?
Answer:
The difference between the young ones of other birds and the young ones of Great Indian Bustards is that unlike the young ones of other birds which soon fly away from the nest, the Great Indian Bustard’s mother and chick stay together for nearly a year.

Reading Skills, Vocabulary and Grammar

Read the following extract and complete the activities that follow.

Question 1.
Complete the list of things we can do to extend our love and support to help the Great Indian Bustard survive.
Answer:

1. Write letters to our leaders and make appeals.
2. Make drawings and submit it to your teacher.
3. Discuss with your parents.
4. Visit a sanctuary.

Question 2.
Which environmental problem is highlighted in the extract?
Answer:
The decline of the population of the Great Indian Bustard, driving them to the verge of extinction is highlighted in the passage.

Question 3.
Who suggested that the Great Indian Bustard should be given the status of the ‘National Bird?
Answer:
Dr. Salim Ali, a friend of Great Indian Bustards suggested that the Great Indian Bustard should be given the status of the ‘National Bird’.

Question 4.
What is the consequence of the growing population of man on the Great Indian Bustard?
Answer:
The growing population of man has pushed the Great Indian Bustard from more than 90 per cent of their home regions.

Question 5.
Two causes which has led to the decline in the number of the Great Indian Bustard.
Answer:
Hunting, Electric power-line

Question 6.
We used to live in all parts of India. (State the word class of the underlined part.)
Answer:
all – adjective

Question 7.
We are losing our homes. (Add a question tag.)
Answer:
We are losing our homes, aren’t we?

Question 8.
We need your support and love in order to survive. (Use not only … but also.)
Answer:
We need not only your support but also love in order to survive.

Question 9.
Give the verb forms of:
Answer:
population: populate electric: electrify/electrocute

Question 10.
Why should we save animals from extinction?
Answer:
Animals are also an important element of the food chain. Many species of animals have become extinct. The animals are invaluable. Our existence depends on them, so to stop the links of food chains from breaking, we should save the animals from extinction.

Language Study

Do as directed.

Question 1.
I have got a long white neck, brown wings, tall yellow legs and a black cap on my head.
Fill in the chart with Nouns and Adjectives.
Answer:

Nouns	Adjectives
necks	long
wings	white
legs	brown
cap	tall
head	yellow
	black

Question 2.
Mrs. Bustard is smaller and slimmer than I am. (Pick out the adjectives and state the degree of comparison used.)
Answer:
Adjective: Smaller
Slimmer: Degree of comparison: Comparative

Question 3.
That’s a very healthy habit! (Pick out the adverb.)
Answer:
Adverb: very

Question 4.
It helps me to impress my soulmate. (Rewrite the sentence using the underlined word as noun.)
Answer:
It helps me create an impression on my soulmate.

Question 5.
I dance in joy. (Make it exclamatory.)
Answer:
How I dance in joy!

Question 6.
The egg looks like a stone. (Pick out the articles.)
Answer:
Articles: The, a

Question 7.
We need your support and love in order to survive. (Pick out the noun and state their kind.)
Answer:
support and love: Abstract Noun

Question 8.
You can discuss this with your parents. (Pick out the modal and state its function.)
Answer:
can: possibility

Question 9.
Come to see us at a sanctuary. (Pick out the preposition.)
Answer:
at: preposition

Question 10.
You will only see us in pictures. (Pick out the adverb.)
Answer:
only – Adverb

Word building.

Complete the table:

Noun	Adjective	Verb
impression	impressive	impress
health	healthy	heal
speciality	special	specialise
beauty	beautiful	beautify
electricity	electric	electrify/electrocute
picture	pictorial	picture

Do you know?

Penguins arrive in Mumbai Zoo. Three male and four female humboldt penguins have been brought in from Seoul, Korea. They have been kept in the quarantine section of the Veermata Jijabhai Bhosale Zoo. While the penguins need to be kept in a temperature between 4° and 25° Celsius, the temperature in the quarantine is between 16° and 18° Celsius. The humboldt penguins are between one and three years of age and have a life expectancy of around 20-25 years.

Autobiography of a Great Indian Bustard Summary in English

In this lesson, the author acquaints us with the different physical characteristics of the Great Indian Bustard. He also talks about their habitat, their eating habits and other details, apart from providing information about their young ones.

He further elaborates that though it is the State Bird of Rajasthan and despite having ten sanctuaries for their protection, their number is on a decline.

Due to uncontrolled population explosion created by man, the Indian Bustards were being pushed away from more than 90 percent of their home regions.

There are other reasons for their decline in number like hunting, electric shock, loss of habitat etc. With the last 200 of the birds left in the world, the lesson reminds us that the birds need our love and support for their survival. The lesson also enlists various ways in which we can do our part to stop the birds from becoming extinct.

Introduction:

Autobiography is a history of a person’s life as narrated by that person, which could be written or oral. Dr. Pramod Patil has used this method of writing to drive home the plight of the Great Indian Bustards who are on the verge of extinction.

Glossary:

1. impressive (adj) – one which evokes admiration
2. grasslands (n) – open area in a region covered with grass
3. deserts (n) – a large, dry, barren region
4. gulp (v) – swallow quickly
5. pouch (n) – a sac-like structure in animals, a pocket-like space (here)
6. resonating (y) – producing a loud, deep sound
7. swarming (v) – moving in large numbers
8. sanctuaries (n) – a reserved area for birds and animals to provide them protection
9. power-lines (n) – used for electric power transmission
10. predators (n) – animals that hunt, kill and eat other animals