# Maharashtra Board Practice Set 13 Class 6 Maths Solutions Chapter 4 Operations on Fractions

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 4 Operations on Fractions Class 6 Practice Set 13 Answers Solutions.

## 6th Standard Maths Practice Set 13 Answers Chapter 4 Operations on Fractions

Question 1.
Write the reciprocals of the following numbers:

1. 7
2. $$\frac { 11 }{ 3 }$$
3. $$\frac { 5 }{ 13 }$$
4. 2
5. $$\frac { 6 }{ 7 }$$

Solution:

1. $$\frac { 1 }{ 7 }$$
2. $$\frac { 3 }{ 11 }$$
3. $$\frac { 13 }{ 5 }$$
4. $$\frac { 1 }{ 2 }$$
5. $$\frac { 7 }{ 6 }$$

Question 2.
Carry out the following Divisions:
i. $$\frac{2}{3} \div \frac{1}{4}$$
ii. $$\frac{5}{9} \div \frac{3}{2}$$
iii. $$\frac{3}{7} \div \frac{5}{11}$$
iv. $$\frac{11}{12} \div \frac{4}{7}$$
Solution:
i. $$\frac{2}{3} \div \frac{1}{4}$$ ii. $$\frac{5}{9} \div \frac{3}{2}$$ iii. $$\frac{3}{7} \div \frac{5}{11}$$ iv. $$\frac{11}{12} \div \frac{4}{7}$$ Question 3.
There were 420 students participating in the Swachh Bharat Campaign. They cleaned $$\frac { 42 }{ 75 }$$ part of the town, Sevagram. What part of Sevagram did each student clean if the work was equally shared by all?
Solution:
Total number of students = 420
Part of town cleaned by all the students = $$\frac { 42 }{ 75 }$$
∴ Part of town cleaned by one student ∴ Part of town cleaned bv one student is $$\frac { 1 }{ 750 }$$

#### Maharashtra Board Class 6 Maths Chapter 4 Operations on Fractions Practice Set 13 Intext Questions and Activities

Question 1.
Ramanujan’s Magic square. (Textbook pg. no. 28) • Add the four numbers in the rows, the columns and along the diagonals of this square.
• What is the sum?
• Is it the same every time?
• What is the peculiarity?
• Look at the numbers in the first row, 22 – 12 – 1887. Find out why this date is special.

Obtain and read a biography of the great Indian mathematician Srinivasa Ramanujan.
Solution:
Sum of the numbers in each row:
i. 22 + 12 + 18 + 87 = 139
ii. 88 + 17 + 9 + 25 = 139
iii. 10 + 24 + 89 + 16 = 139
iv. 19 + 86 + 23 + 11 = 139

Sum of the numbers along the diagonals:
i. 22 + 17 + 89 + 11 = 139
ii. 87 + 9 + 24 + 19 = 139

Sum of the numbers in each column:
i. 22 + 88 + 10 + 19 = 139
ii. 12 + 17 + 24 + 86 = 139
iii. 18 + 9 + 89 + 23 = 139
iv. 87 + 25 + 16 + 11 = 139

∴ We observe that the sum of the numbers in each of the rows, the columns and along each diagonal remains the same every time. The numbers in the first row 22 – 12 – 1887 is the birth date of Srinivasa Ramanujan.