Class 8

Balbharti Maharashtra State Board Class 8 Maths Solutions covers the Miscellaneous Exercise 1 8th Std Maths Answers Solutions.

Miscellaneous Exercise 1 8th Std Maths Answers

Question 1.
Choose the correct alternative answer for each of the following questions.
i. In ₹PQRS, m∠P = m∠R = 108°, m∠Q = m∠S = 72°. State which pair of sides of those given below is parallel. [Chapter 8]
(A) side PQ and side QR
(B) side PQ and side SR
(C) side SR and side SP
(D) side PS and side PQ
Solution:
(B) side PQ and side SR

Hint:

In ₹PQRS,
m∠P + m∠S = 108°+ 72
= 180°
Since, interior angles are supplementary.
∴ side PQ || side SR

ii. Read the following statements and choose the correct alternative from those given below them. [Chapter 8]
a. Diagonals of a rectangle are perpendicular bisectors of each other.
b. Diagonals of a rhombus are perpendicular bisectors of each other.
c. Diagonals of a parallelogram are perpendicular bisectors of each other.
d. Diagonals of a kite bisect each other.
(A) Statements (b) and (c) are true
(B) Only statement (b) is true
(C) Statements (b) and (d) are true
(D) Statements (a), (c) and (d) are true.
Solution:
(B) Only statement (b) is true

iii. If 19³ = 6859, find \(\sqrt[3]{0.006859}\). [Chapter 3]
(A) 1.9
(B) 19
(C) 0.019
(D) 0.19
Solution:
(D) 0.19

Hint:
\(\sqrt[3]{0.006859}\)

Question 2.
Find the cube roots of the following numbers. [Chapter 3]
i. 5832
ii. 4096
Solution:
i. 5832 = 2 × 2 × 2 × 3 × 3 × 3 × 3 × 3 × 3
= (2 × 3 × 3) × (2 × 3 × 3) × (2 × 3 × 3)
= (2 × 3 × 3)³
= (18)³
\(\sqrt[3]{5832}=18\)

ii. 4096 = (4 × 4) × (4 × 4) × (4 × 4)
= (4 × 4)
= 16³
\( \sqrt[3]{4096}=16\)

Question 3.
m∝n,n = 15 when m = 25. Hence
i. Find m when n = 87,
ii. Find n when m = 155. [Chapter 7]
Solution:
Given that, m ∝ n
∴ m = kn …(i)
where, k is the constant of variation.
When m = 25, n = 15
∴ Substituting, m = 25 and n = 15 in (i), we get
m = kn
∴ 25 = k × 15
∴ k = \(\frac { 25 }{ 15 }\)
∴ k = \(\frac { 5 }{ 3 }\)
Substituting k = \(\frac { 5 }{ 3 }\) in (i), we get
m = kn
∴ m = \(\frac { 5 }{ 3 }n\) …(ii)

i. When n = 87, m = ?
Substituting n = 87 in (ii), we get
m = \(\frac { 5 }{ 3 }n\)
m = \(\frac { 5 }{ 3 }\) × 87
m = 5 × 29
m = 145

ii. When m = 155, n = ?
∴ Substituting m = 155 in (ii), we get
m = \(\frac { 5 }{ 3 }n\)
∴ 155 = \(\frac { 5 }{ 3 }n\)
∴ \(\frac{155 \times 3}{5}=n\)
∴ n = 31 × 3
∴ n = 93

Question 4.
y varies inversely with x. If y = 30 when x = 12, find [Chapter 7]
i. y when x = 15,
ii. x when y = 18.
Solution:
Given that,
\(y \propto \frac{1}{x}\)
∴ \(y=k \times \frac{1}{x}\)
where, k is the constant of variation.
∴ y × x = k …(i)
When x = 12, y = 30
∴ Substituting, x = 12 and y = 30 in (i), we get
y × x = k
∴ 30 × 12 = k
∴ k = 360
Substituting, k = 360 in (i), we get
y × x = k
∴ y × x = 360 ….(ii)

i. When x = 15,y = ?
∴ Substituting x = 15 in (ii), we get
y × x = 360
∴ y × 15 = 360
∴ y = \(\frac { 360 }{ 15 }\)
∴ y = 24

ii. When y = 18, x = ?
∴ Substituting y = 18 in (ii), we get
y × x = 360
∴18 × x = 360
∴ x = \(\frac { 360 }{ 18 }\)
∴ x = 20

Question 5.
Draw a line l. Draw a line parallel to line l at a distance of 3.5 cm. [Chapter 2]
Solution:
Steps of construction:

1. Draw a line l and take any two points M and N on the line.
2. Draw perpendiculars to line l at points M and N.
3. On the perpendicular lines take points S and T at a distance 3.5 cm from points M and N respectively.
4. Draw a line through points S and T. Name the line as n.

Line n is parallel to line l at a distance of 3.5 cm from it.

Question 6.
Fill in the blanks in the following statement.
The number \((256)^{\frac{5}{7}}\) is __ of __ power of __. [Chapter 3]
Solution:
The number \((256)^{\frac{5}{7}}\) is 7th root of 5th power of 256.

Question 7.
Expand.
i. (5x – 7) (5x – 9)
ii. (2x – 3y)³
iii. \(\left(a+\frac{1}{2}\right)^{3}\) [Chapter 5]
Solution:
i. (5x – 7) (5x – 9)
= (5x)² + (-7 -9) 5x + (-7) × (-9).
…[∵ (x + a) (x + b) = x² + (a + b)x + ab]
= 25x² + (-16) × 5x + 63
= 25x² – 80x + 63

ii. Here, a = 2x and b = 3y
(2x – 3y)³
= (2x)³ – 3 (2x)² (3y) + 3 (2x) (3y)² – (3y)³
…[∵ (a – b)³ = a³ – 3a²b + 3ab² – b³]
= 8x³ – 3 (4x²) (3y) + 3 (2x) (9y²) – 27y³
= 8x³ – 36x²y + 54xy² – 27p³

iii. Here, A= a and B = \(\frac { 1 }{ 2 }\)
\(\left(a+\frac{1}{2}\right)^{3}=(a)^{3}+3(a)^{2}\left(\frac{1}{2}\right)+3(a)\left(\frac{1}{2}\right)^{2}+\left(\frac{1}{2}\right)^{3}\)
…[(A + B)³ = A³ + 3A²B + 3AB² + B³]
\(=\mathbf{a}^{3}+\frac{3 \mathbf{a}^{2}}{2}+\frac{3 \mathbf{a}}{4}+\frac{1}{8}\)

Question 8.
Draw an obtuse angled triangle. Draw all of its medians and show their point of concurrence. [Chapter 4]
Solution:

The point of concurrence of the medians PS, RU and QV is G.

Question 9.
Draw ∆ABC such that l(BC) = 5.5 cm, m∠ABC = 90°, l(AB) = 4 cm. Show the orthocentre of the triangle. [Chapter 4]
Solution:

Here, point B is the orthocentre of ∆ABC.

Question 10.
Identify the variation and solve.
It takes 5 hours to travel from one town to the other if speed of the bus is 48 km/hr. If the speed of the bus is reduced by 8 km/hr, how much time will it take for the same travel? [Chapter 7]
Solution:
Let, v represent the speed of the bus and t represent the time required to travel from one town to the other.
The speed of the bus varies inversely with the time required to travel from one town to the other.
∴ \(\mathbf{v} \propto \frac{1}{\mathbf{t}}\)
∴ \(\mathbf{v}=\mathbf{k} \times \frac{1}{\mathbf{t}}\)
where, k is the constant of variation.
∴ v × t = k …(i)
It takes 5 hours to travel from one town to the other if speed of the bus is 48 km/hr.
i.e., when v = 48, t = 5
∴ Substituting v = 48 and t = 5 in (i), we get
v × t = k
∴ 48 × 5 = k
∴ k = 240
Substituting k = 240 in (i), we get
v × t = k
∴ v × t = 240 …(ii)
Since, the speed of the bus is reduced by 8 km/hr,
∴ Speed of the bus in second case (v)
= 48 – 8 = 40 km/hr
∴ When v = 40, t = ?
∴ Substituting v = 40 in (ii), we get
v × t = 240
∴ 40 × t = 240
∴ \(t=\frac { 240 }{ 40 }\)
∴ t = 6
∴ The problem is of inverse variation and the bus would take 6 hours to travel the distance if its speed is reduced by 8 km/hr.

Question 11.
Seg AD and seg BE are medians of ∆ABC and point G is the centroid. If l(AG) = 5 cm, find l(GD). If l(GE) = 2 cm, find l(BE). [Chapter 4]
Solution:
The centroid of a triangle divides each median in the ratio 2:1.
i. Point G is the centroid and seg AD is the median.

ii. Point G is the centroid and seg BE is the median.

∴ l(BG) × 1 = 2 × 2
∴ l(BG) = 4 cm
Now, l(BE) = l(BG) + l(GE)
∴ l(BE) = 4 + 2
∴ l(BE) = 6 cm

Question 12.
Convert the following rational numbers into decimal form. [Chapter 1]
i. \(\frac { 8 }{ 13 }\)
ii. \(\frac { 11 }{ 7 }\)
iii. \(\frac { 5 }{ 16 }\)
iv. \(\frac { 7 }{ 9 }\)
Solution:
i. \(\frac { 8 }{ 13 }\)

ii. \(\frac { 11 }{ 7 }\)

iii. \(\frac { 5 }{ 16 }\)

iv. \(\frac { 7 }{ 9 }\)

Question 13.
Factorize.
i. 2y² – 11y + 5
ii. x² – 2x – 80
iii. 3x² – 4x + 1
Solution:
i. 2y² – 11y + 5
= 2y² – 10y – y + 5
= 2y(y – 5) – 1(y – 5)
= (y – 5)(2y – 1)

ii. x² – 2x – 80
= x² – 10x + 8x – 80
= x (x – 10) + 8 (x – 10)
= (x – 10)(x + 8)

iii. 3x² – 4x + 1
= 3x² – 3x – x + 1
= 3x(x – 1) – 1(x – 1)
= (x – 1) (3x – 1)

Question 14.
The marked price of a T.V. set is Rs 50,000. The shopkeeper sold it at 15% discount. Find the price of it for the customer. [Chapter 9]
Solution:
Here, marked price = Rs 50,000,
discount = 15%
Let the discount percent be x
∴x = 15%
i. Discount

= 500 × 15
= Rs 7,500

ii. Selling price = Marked price – Discount
= 50,000 – 7,500
= Rs 42,500
∴The price of the T.V. set for the customer is Rs 42,500.

Question 15.
Rajabhau sold his flat to Vasantrao for Rs 88,00,000 through an agent. The agent charged 2 % commission for both of them. Find how much commission the agent got. [Chapter 9]
Solution:
Here, selling price of the flat = Rs 88,00,000
Rate of commission = 2%
Commission = 2% of selling price
= \(\frac { 2 }{ 100 }\) × 88,00,000
= 2 × 88,000
= Rs 1,76,000
∴ Total commission = Commission from Rajabhau + Commission from Vasantrao
= Rs 1,76,000 + Rs 1,76,000
= Rs 3,52,000
∴ The agent got a commission of Rs 3,52,000.

Question 16.
Draw a parallelogram ABCD such that l(DC) = 5.5 cm, m∠D = 45°, l(AD) = 4 cm. [Chapter 8]
Solution:
Opposite sides of a parallelogram are congruent.
∴ l(AD) = l(BC) = 4 cm and
l(DC) = l(AB) = 5.5 cm

Question 17.
In the figure, line l || line m and line p || line q. Find the measures of ∠a, ∠b, ∠c and ∠d. [Chapter 2]

Solution:
i. line l|| line m and line p is a transversal.
∴m∠a = 78° …(i) [Corresponding angles]

ii. line p || line q and line m is a transversal.
∴m∠d = m∠a …[Corresponding angles]
∴m∠d = 78° …(ii)[From (i)]

iii. m∠b = m∠d …[Vertically opposite angles]
∴m∠b = 78° …[From (ii)]

iv. line l|| line m and line q is a transversal.
∴m∠c + m∠d = 180° …[Interior angles]
∴m∠c + 78° = 180° … [From (ii)]
∴m∠c =180° – 78°
∴m∠c = 102°
∴m∠a = 78°, m∠b = 78°, m∠c = 102°, m∠d = 78°

Maharashtra Board Class 8 Maths Solutions

Balbharti Maharashtra State Board Class 8 Maths Solutions covers the Practice Set 17.1 8th Std Maths Answers Solutions Chapter 17 Circle: Chord and Arc.

Practice Set 17.1 8th Std Maths Answers Chapter 17 Circle: Chord and Arc

Question 1.
In a circle with centre P, chord AB is drawn of length 13 cm, seg PQ ⊥ chord AB, then find l(QB)

Solution:
seg PQ ⊥ chord AB … [Given]
∴l(QB) = \(\frac { 1 }{ 2 }\) l(AB)… [Perpendicular drawn from the centre of a circle to its chord bisects the chord]
∴l(QB) = \(\frac { 1 }{ 2 }\) x 13 …[∵ l(AB) = 13 cm]
∴l(QB) = 6.5 cm

Question 2.
Radius of a circle with centre O is 25 cm. Find the distance of a chord from the centre if length of the chord is 48 cm.

Solution:
seg OP ⊥ chord CD … [Given]
∴l(PD) = \(\frac { 1 }{ 2 }\) l(CD) … [Perpendicular drawn from the centre of a circle to its chord bisects the chord]
∴l(PD) = \(\frac { 1 }{ 2 }\) x 48 …[∵ l(CD) = 48 cm]
∴l(PD) = 24 cm …(i)
In ∆OPD, m∠OPD = 90°
∴[l(OD)]² = [l(OP)]² + [l(PD)]² … [Pythagoras theorem]
∴(25)² = [l(OP)]² + (24)² … [From (i) and l(OD) = 25 cm]
∴(25)² – (24)² = [l(OP)]²
∴(25 + 24) (25 – 24) = [l(OP)]² …[∵ a² – b² = (a + b) (a – b)]
∴49 x 1 = [l(OP)]²
∴[l(OP)]² = 49
∴l(OP) = √49 …[Taking square root of both sides]
∴l(OP) = 7 cm
∴The distance of the chord from the centre of the circle is 7 cm.

Question 3.
O is centre of the circle. Find the length of radius, if the chord of length 24 cm is at a distance of 9 cm from the centre of the

Solution:
Let seg OP ⊥ chord AB
∴ l(AP) = \(\frac { 1 }{ 2 }\) l(AB) … [Perpendicular drawn from the centre of a circle to its chord bisects the chord]

∴l(AP) = \(\frac { 1 }{ 2 }\) x 24 …[∵ l(AB) = 24 cm]
∴l(AP) = 12 cm …(i)
In ∆OPA, m∠OPA = 90°
∴[l(AO)]² = [l(OP)]² + [l(AP)]² … [Pythagoras theorem]
∴[l(AO)]² = (9)² + (12)² … [From (i) and l(OP) = 9 cm]
= 81 + 144
∴[l(AO)]² = 225
∴l(AO) = √225 …[Taking square root of both sides]
∴l(AO) = 15 cm
∴The length of radius of the circle is 15 cm.

Question 4.
C is the centre of the circle whose radius is 10 cm. Find the distance of the chord from the centre if the length of the chord is 12 cm.
Solution:
Let seg AB be the chord of the circle with centre C.
Draw seg CD ⊥ chord AB.

∴l(AD) = \(\frac { 1 }{ 2 }\) l(AB) …[Perpendicular drawn from the centre of a circle to its chord bisects the chord]
= \(\frac { 1 }{ 2 }\) x 12 …[∵ l(AB) = 12 cm]
∴l(AD) = 6 cm …(i)
∴In ∆ACD, m∠ADC = 90°
∴[l(AC)]² = [l(AD)]² + [l(CD)]² … [Pythagoras theorem]
∴(10)² = (6)² + [l(CD)]² … [From (i) and l(AC) = 10 cm]
∴(10)² – (6)² = [l(CD)]²
∴100 – 36 = [l(CD)]²
∴64 = [l(CD)]²
i. e. [l(CD)]² = 64
∴l(CD) = √64 …[Taking square root of both sides]
∴l(CD) = 8 cm
∴The distance of the chord from the centre of the circle is 8 cm.

Maharashtra Board Class 8 Maths Chapter 17 Circle: Chord and Arc Practice Set 17.1 Intext Questions and Activities

Question 1.
In the given figure, O is the centre of the circle. With reference to the figure fill in the blanks. (Textbook pg. No. 114)

Solution:

1. Seg OD is radius of the circle.
2. Seg AB is diameter of the circle.
3. Seg PQ is chord of the circle.
4. ∠DOB is the central angle.
5. Minor arc : arc AXD, arc BD, arc AP, arc PQ, arc BQ, etc.
6. Major arc : arc PAB, arc PDQ, arc PDB, arc ADQ, etc.
7. Semicircular arc : arc ADB, arc AQB.
8. m (arc DB) = m∠DOB
9. m (arc DAB) = 360° – m∠DOB

Question 2.
Draw chord AB of a circle with centre O. Draw perpendicular OP to chord AB. Measure seg AP and seg PB. What do you observe. (Textbook pg. no. 114)
Solution:
l(AP) = l(PB) = 0.9 cm
∴the perpendicular drawn from the centre of the circle to its chord bisects the chord.

Question 3.
Draw five circles with different radii. Draw a chord and perpendicular from the centre to each chord in each circle. Verify with a divider that the two parts of the chords are equal. (Textbook pg. no. 114)
Solution:
[Students should attempt the above activities on their own.]

Question 4.
Draw five circles of different radii on a paper. Draw a chord in each circle. Find the midpoint of each chord. Join the centre of the circle and midpoint of the chord as shown in the figure. Name the chord as AB and midpoint of the chord as P. Check with set-square or protractor that ∠APO or ∠BPO are right angles.
Check whether the same result is observed for the chord of each circle. (Textbook pg, no. 115)
Solution:
[Students should attempt the above activities on their own.]

Balbharti Maharashtra State Board Class 8 Maths Solutions covers the Practice Set 14.2 8th Std Maths Answers Solutions Chapter 14 Compound Interest.

Practice Set 14.2 8th Std Maths Answers Chapter 14 Compound Interest

Compound Interest class 8 practice set 14.2 Question 1. On the construction work of a flyover bridge there were 320 workers initially. The number of workers were increased by 25% every year. Find the number of workers after 2 years.
Solution:
Here, P = Initial number of workers = 320
R = Increase in the number of workers per year = 25%
N = 2 years
A = Number of workers after 2 years

∴ The number of workers after 2 years would be 500.

Question 2.
A shepherd has 200 sheep with him. Find the number of sheeps with him after 3 years if the increase in number of sheeps is 8% every year.
Solution:
Here, P = Present number of sheeps = 200
R = Increase in number of sheeps per year = 8%
N = 3 years
A = Number of sheeps after 3 years

= \(\frac{0.32}{25} \times 27 \times 27 \times 27\)
= 0.0128 × 27 × 27 × 27
= 251.9424
= 252
∴ The number of sheeps with the shepherd after 2 years would be 252 (approx).

8th Class Math Practice Set 14.2 Question 3.
In a forest there are 40,000 trees. Find the expected number of trees after 3 years if the objective is to increase the number at the rate 5% per year.
Solution:
Here, P = Present number of trees in the forest = 40,000
R = Increase in the number of trees per year = 5%
N = 3 years
A = Number of trees after 3 years

= 5 × 21 × 21 × 21
= 5 × 9261
= 46,305
∴ The expected number of trees in the forest after 3 years is 46,305.

Std 8 Maths Practice Set 14.2 Question 4.
The cost price of a machine is Rs 2,50,000. If the rate of depreciation is 10% per year, find the depreciation in price of the machine after two years.
Solution:
Here, P = Cost price of machine = Rs 2,50,000
R = Rate of depreciation per year = 10%
N = 2 years
A = Depreciated price of the machine after 2 years

= 2,500 × 81
= Rs 2,02,500
Depreciation in price = Cost price (P) – Depreciated price (A)
= 2,50,000 – 2,02,500
= Rs 47,500
∴ The depreciation in price of the machine after 2 years would be Rs 47,500.

Question 5.
Find the compound interest if the amount of a certain principal after two years is Rs 4036.80 at the rate of 16 p.c.p.a.
Solution:
Here, A = Rs 4036.80, R = 16 p.c.p.a. and N = 2 years
i. \(\mathbf{A}=\mathbf{P}\left[1+\frac{\mathbf{R}}{100}\right]^{N}\)

ii. Interest = Amount (A) – Principal (P)
= 4036.80 – 3000
= Rs 1036.80
∴ The compound interest after 2 years would be Rs 1036.80.

Question 6.
A loan of Rs 15,000 was taken on compound interest. If the rate of compound interest is 12 p.c.p.a. find the amount to settle the loan after 3 years.
Solution:
Here, P = Rs 15,000, R = 12 p.c.p.a, and
N = 3 years

∴ The amount required to settle the loan after 3 years is Rs 21,073.92.

Practice Set 14.2 Class 8 Question 7.
A principal amounts to Rs 13,924 in 2 years by compound interest at 18 p.c.p.a. Find the principal.
Solution:
Here, A = Rs 13,924, R = 18 p.c.p.a., and N = 2 years

∴ P = 4 x 50 x 50
∴ P = Rs 10,000
∴ The principal is Rs 10,000.

Question 8.
The population of a suburb is 16,000. Find the rate of increase in the population if the population after two years is 17,640.
Solution:
Here, P = Population of a suburb = 16,000
N = 2 years
A = Increase in the population after 2 years = 17,640
R = Rate of increase in population


∴5 = R
i.e., R = 5%
∴The rate of increase in the population is 5 p.c.p.a.

Compound Interest Practice Set 14.2 Question 9.
In how many years Rs 700 will amount to Rs 847 at a compound interest rate of 10 p.c.p.a.
Solution:
Here, P = Rs 700, R = 10 p.c.p.a., A = Rs 847

∴Rs 700 will amount to Rs 847 in 2 years.

Practice Set 14.2 Question 10.
Find the difference between simple interest and compound interest on Rs 20,000 in 2 years at 8 p.c.p.a.
Solution:
Here, P = Rs 20,000, R = 8 p.c.p.a.,
N = 2 years
i. Simple interest (I)

Simple interest (I) = Rs 3200

ii. Compound Interest (I):


= 32 × 27 × 27
= Rs 23,328
Compound interest (I)
= Amount (A) – Principal (P)
= 23,328 – 20,000
= Rs 3328 ,..(ii)

iii. Difference
= Compound interest – Simple interest
= 3328 – 3200 … [Form (i) and (ii)]
= Rs 128
∴ The difference between compound interest and simple interest is Rs 128.
[Note: The question is modified as per the answer given in the textbook.]

Maharashtra Board Class 8 Maths Chapter 14 Compound Interest Practice Set 14.2 Intext Questions and Activities

8th Standard Maths Practice Set 14.2 Question 1.
Visit the bank nearer to your house and get the information regarding the different schemes and rates of interests. Make a chart and display in your class. (Textbook pg. no. 90)
Solution:
(Students should attempt this activity at their own.)

Balbharti Maharashtra State Board Class 8 Maths Solutions covers the Practice Set 13.1 8th Std Maths Answers Solutions Chapter 13 Congruence of Triangles.

Practice Set 13.1 8th Std Maths Answers Chapter 13 Congruence of Triangles

Congruence of Triangles Practice Set 13.1 Question 1.
In each pair of triangles in the following figures, parts bearing identical marks are congruent. State the test and correspondence of vertices by which triangles in each pair are congruent.
i.

ii.

iii.

iv.

v.

Solution:
i.

The two triangles are congruent by SAS test in the correspondence XWZ ↔ YWZ.

ii.

The two triangles are congruent by hypotenuse-side test in the correspondence KJI ↔ LJI.

iii.

The two triangles are congruent by SSS test in the correspondence HEG ↔ FGE.

iv.
The two triangles are congruent by ASA test is the correspondence SMA ↔ OPT.

v.

The two triangles are congruent by ASA test or SAS test or SAA test in the correspondence MTN ↔ STN.

Maharashtra Board Class 8 Maths Chapter 13 Congruence of Triangles Practice Set 13.1 Intext Questions and Activities

Practice Set 13.1 Question 1.
Write answers to the following questions referring to the given figure.

1. Which is the angle opposite to the side DE?
2. Which is the side opposite to ∠E?
3. Which angle is included by side DE and side DF?
4. Which side is included by ∠E and ∠F?
5. State the angles adjacent to side DE. (Textbook pg, no. 81)

Solution:

1. ∠DFE i.e. ∠F is the angle opposite to side DE.
2. Side DF is the side opposite to ∠E.
3. ∠EDF i.e. ∠D is included by side DE and side DF.
4. Side EF is included by ∠E and ∠F.
5. ∠DEF and ∠EDF i.e. ∠E and ∠D are adjacent to side DE.

Congruence of Triangles Class 8th Practice Set 13.1 Question 2.
In the given figure, parts of triangles indicated by identical marks are congruent.
a. Identify the one-to-one correspondence of vertices in which the two triangles are congruent and write the congruence.
b. State with reason, whether the statement, ∆XYZ ≅ ∆STU is right or wrong. (Textbook pg. no. 82)

Solution:
a. From the figure,
S ↔ X, T ↔ Z, U ↔ Y i.e.,
STU ↔ XZY, or SUT ↔ XYZ, or
TUS ↔ ZYX, or TSU ↔ ZXY, or
UTS ↔ YZX, or UST ↔ YXZ

∴ ∆STU ≅ ∆XZY, or ∆SUT ≅ ∆XYZ, or
∆TUS ≅ ∆ZYX, or ∆TSU ≅ ∆ZXY, or
∆UTS ≅ ∆YZX, or ∆UST ≅ ∆YXZ

b. If ∆XYZ ≅ ∆STU, then
∠Y ≅ ∠T, ∠Z ≅ ∠U,
seg XY ≅ seg ST, seg XZ ≅ seg SU
∴ But, all the above statements are wrong. The statement AXYZ ≅ ASTU is wrong.

Balbharti Maharashtra State Board Class 8 Maths Solutions covers the Practice Set 1.4 8th Std Maths Answers Solutions Chapter 1 Rational and Irrational Numbers.

Practice Set 1.4 8th Std Maths Answers Chapter 1 Rational and Irrational Numbers

Question 1.
The number √2 is shown on a number line. Steps are given to show √3 on the number line using √2. Fill in the boxes properly and complete the activity.

The point Q on the number line shows the number ……….
A line perpendicular to the number line is drawn through the point Q. Point R is at unit distance from Q on the line.
Right angled ∆OQR is obtained by drawing seg OR.
l(OQ) = √2, l(QR) = 1
∴By Pythagoras theorem,
[l(OR)]² = [l(OQ)]² + [l(QR)]²

Draw an arc with centre O and radius OR. Mark the point of intersection of the line and the arc as C. The point C shows the number √3
Solution:
The point Q on the number line shows the number √2
A line perpendicular to the number line is drawn through the point Q. Point R is at unit distance from Q on the line.
Right angled ∆OQR is obtained by drawing seg OR.
l(OQ) = √2, l(QR) = 1
∴By Pythagoras theorem,
[l(OR)]² = [l(OQ)]² + [l(QR)]²

.. .[Taking square root of both sides]
Draw an arc with centre O and radius OR. Mark the point of intersection of the line and the arc as C. The point C shows the number √3.

Question 2.
Show the number √5 on the number line.
Solution:
Draw a number line and take a point Q at 2
such that l(OQ) = 2 units.
Draw a line QR perpendicular to the number line through the point Q such that l(QR) = 1 unit.
Draw seg OR.
∆OQR formed is a right angled triangle.
By Pythagoras theorem,
[l(OR)]² = [l(OQ)]² + [l(QR)]²
= 2² + 1²
= 4 + 1
= 5
∴l(OR) = √5 units
…[Taking square root of both sides]
Draw an arc with centre O and radius OR. Mark the point of intersection of the number line and arc as C. The point C shows the number √5.

Question 3.
Show the number √7 on the number line.
Solution:
Draw a number line and take a point Q at 2 such that l(OQ) = 2 units.
Draw a line QR perpendicular to the number line through the point Q such that l(QR) = 1 unit.
Draw seg OR.
∆OQR formed is a right angled triangle.
By Pythagoras theorem,
[l(OR)]² = [l(OQ)]² + [l(QR)]²
= 2² + 1²
= 4 + 1
= 5
∴ l(OR) = √5 units
… [Taking square root of both sides]
Draw an arc with centre O and radius OR.
Mark the point of intersection of the number line and arc as C. The point C shows the number √5.
Similarly, draw a line CD perpendicular to the number line through the point C such that l(CD) = 1 unit.
By Pythagoras theorem,
l(OD) = √6 units
The point E shows the number √6 .
Similarly, draw a line EP perpendicular to the number line through the point E such that l(EP) = 1 unit.
By Pythagoras theorem,
l(OP) = √7 units
The point F shows the number √7.

Balbharti Maharashtra State Board Class 8 Maths Solutions covers the Practice Set 13.2 8th Std Maths Answers Solutions Chapter 13 Congruence of Triangles.

Practice Set 13.2 8th Std Maths Answers Chapter 13 Congruence of Triangles

Congruence of Triangles Class 8th Practice Set 13.2 Question 1.
In each pair of triangles given below, parts shown by identical marks are congruent. State the test and the one-to-one correspondence of vertices by which triangles in each pair are congruent. Also state the remaining congruent parts.


Solution:
i. In ∆MST and ∆TBM,
∴ side MS ≅ side TB … [Given]
m∠MST = m∠TBM = 90° … [Given]
hypotenuse MT ≅ hypotenuse MT
…[Common side]
∴ ∆MST ≅ ∆TBM …[by hypotenuse-side test]
∴ side ST ≅ side BM …[Corresponding sides of congruent triangles]
∠SMT ≅ ∠BTM …[Corresponding sides of congruent triangles]
∠STM ≅ ∠BMT …[Corresponding sides of congruent triangles]

ii. In ∆PRQ and ∆TRS,
side PR ≅ side TR … [Given]
∠PRQ ≅ ∠TRS …[Vertically opposite angles]
side RQ ≅ side RS … [Given]
∴ ∆PRQ ≅ ∆TRS …[by SAS test]
∴ side PQ ≅ side TS …[Corresponding sides of congruent triangles]
∠RPQ ≅ ∠RTS …[Corresponding sides of congruent triangles]
∠PQR ≅ ∠TSR …[Corresponding sides of congruent triangles]

iii. In ∆DCH and ∆DCF,
∠DCH ≅ ∠DCF …[Given]
∠DHC ≅ ∠DFC …[Given]
side DC ≅ side DC …[Common side]
∴ ∆DCH ≅ ∆DCF …[by AAS test]
∴ side HC ≅ side FC …[Corresponding sides of congruent triangles]
side DH ≅ side DF…[Corresponding sides of congruent triangles]
∠HDC ≅ ∠FDC ….[Corresponding sides of congruent triangles]

Congruence of Triangles Practice Set 13.2 Question 2.
In the given figure, seg AD ≅ seg EC. Which additional information is needed to show that ∆ABD and ∆EBC will be congruent by AAS test?

Solution:
In ∆ABD and ∆CBE,
∴ seg AD ≅ seg CE …[Given]
∠ABD ≅ ∠CBE …[Vertically opposite angles]
∴ The necessary condition for the two triangles to be congruent by AAS test is
∠ADB ≅ ∠CEB, or
∠DAB ≅ ∠ECB

Maharashtra Board Class 8 Maths Chapter 13 Congruence of Triangles Practice Set 13.2 Intext Questions and Activities

Practice Set 13.2 Class 8 Question 1.
Draw ∆ABC and ∆LMN such that two pairs of their sides and the angles included by them are congruent.
Draw ∆ABC and ∆LMN, l(AB) = l(LM), l(BC) = l(MN), m∠ABC = m∠LMN.
Copy ∆ABC on a tracing paper. Place the paper on ∆LMN in such a way that point A coincides with point L, side AB overlaps side LM. What do you notice?(Textbook pg. no. 83)

Solution:
We notice that ∆ABC ≅ ∆LMN.

Congruence of Triangles Class 8 Solutions Question 2.
Draw ∆PQR and ∆XYZ such that l(PQ) = l(X Y), l(Q R) = l(YZ), l(RP) = l(ZX). Copy ∆PQR on a tracing paper. Place it on ∆XYZ observing the correspondence P ↔ X, Q ↔ Y, R ↔ Z. What do you notice? (Textbook pg. no. 84)

Solution:
We notice that ∆PQR ≅ ∆XYZ.

Congruence of Triangles Class 8 Question 3.
Draw ∆XYZ and ∆DEF such that, l(XZ) = l(DF), ∠X ≅ ∠D and ∠Z ≅ ∠F.
Copy ∆XYZ on a tracing paper and place it over ∆DEF. What do you notice?(Textbook pg. no. 84)

Solution:
We notice that ∆XYZ ≅ ∆DEF in the correspondence X ↔ D, Y ↔ E, Z ↔ F.

Question 4.
Draw two right angled triangles such that a side and the hypotenuse of one is congruent with the corresponding parts of the other. Copy one triangle on tracing paper and place it over the other. What do you notice? (Textbook pg. no. 84)

Solution:
We notice that the two triangles are congruent.
(Students should draw figures and verify the answers.)

Balbharti Maharashtra State Board Class 8 Geography Solutions Chapter 9 Map Scale Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 8 Geography Solutions Chapter 9 Map Scale

Class 8 Geography Chapter 9 Map Scale Textbook Questions and Answers

1. 

Map Scale Std 8 Question a.
Classify maps showing the following areas into small scale or large scale:
(1) Building (2) School (3) Country of India (4) Church (5) Mall (6) World map (7) Garden (8) Dispensary (9) Maharashtra state (10) The north sky at night.
Answer:
The classification of maps showing the given areas is as follows:
(A) Small scale maps:

1. Country of India
2. World map
3. Maharashtra state
4. The north sky at night.

(B) Large scale maps :

1. Building
2. School
3. Church
4. Mall
5. Garden!
6. Dispensary.

Map Scale Class 8 Geography Question b.
There are two maps with respective scales of 1cm = 100 m and 1cm = 100 km. Give well reasoned answer as to which of them would be a large scale map and which a small scale map. Recognize the types of maps.
Answer:
A. Out of the two maps with respective scales of 1 cm = 100 m and 1 cm = 100 km, a map with respective scale of 1 cm = 100 m would be a large scale map.
B. Reasons :

1. 1 metre is equal to 100 centimetres and 100 metre is equal to 10000 centimetres.
2. Thus, the value of the given verbal scale (1cm = 100 m) is 1 : 10000 in numerical terms (scale).
3. A map having a numerical scale of 1 : 10,000 or less than it is called large scale map. Therefore, 1cm = 100 m would be a large scale map.

C. Types of maps :

1. Maps of villages, church, agricultural fields, etc. are the large scale maps.
2. Maps of state, country, continent, world, etc. are the small scale maps.

2. Using a map of India from the atlas measure straight Line distance between the following cities and complete the table below.

Question a.

Answer:

Cities	Distance on a map	Actual distance
1. Mumbai to Bangaluru	0.98 cm	980 km
2. Vijaypura to Jaipur	2 cm	2000 km
3. Hyderabad to Surat	0.9 cm	900 km
4. Ujjain to Shimla	1.14 cm	1140 km
5. Patna to Raipur	0.75 cm	750 km
6. Delhi to Kolkata	1 cm	1000 km

3. 

Map Scale Std 8 Questions And Answers Question a.
The distance between two points A and B on the ground is 500 m. Show this distance on paper by a line of 2 cm. Express the map scale by any one method and mention it.
Answer:

Question b.
Convert verbal scale of 1cm = 53 km to a numerical scale.
Answer:

1. 1 kilometre is equal to 100000 centimetres. Therefore, 53 kilometres is equal to 5300000 centimetres.
2. Therefore, the verbal scale of 1 cm = 53 km can be converted to a numerical scale as – 1 : 5300000.

Class 8 Geography Chapter 9 Map Scale Question c.
Convert numerical scale of 1 : 10000000 to a verbal scale in the metric system.
Answer:

1. 100000 centimetres is equal to 1 kilometre. Thus, 10000000 centimetres is equal to 100 kilometres.
2. Therefore, numerical scale of 1 : 10000000 to a verbal scale in the metric system can be converted as 1 cm = 100 km.

4. Help them, using road and railway maps of the state of Maharashtra. Use the scale given in the maps.

Std 8 Geography Chapter 9 Map Scale Question a.
Ajay wants to arrange a family trip. Beed-Aurangabad-Dhule-Nasik Mumbal-Pune-Solapur-Beed. He wants to visit tourist places along this route. The cost of the vehicle is Rs 12/- per km. What would be the approximate cost of travel?

Map Scale Questions And Answers Question b.
Saloni has been asked to organize a trip by her teacher. She has selected Nagpur Chandrapur-Nanded-Washim-Akola Malkapur. What would be the total coverage in kilometers?

Geography Class 8 Chapter 9 Question c.
Vishawasrao is transporting goods in a vehicle from Alibag (district Raigad) to Naldurg (district – Osmanabad). How many km. will he be covering aproximately for a to and fro travel?

Projects:

Map Scale Questions Question a.
Measure the length and breadth of your school. Prepare a sketch according to scale. Show different parts of your school on the sketch.

Maharashtra State Board Class 8 Geography Solutions Question b.
With the help of google maps find the distance between your village and your neighbouring village. Represent all the three methods of map scale on paper.

Class 8 Geography Chapter 9 Map Scale Additional Important Questions and Answers

Mark ✓ the box next to the right alternative:
(Note: The answers are given directly.)

Question a.
Which of the following factor’s map will be a large scale map?
(a) Temple [ ]
(b) State [ ]
(c) Nation [ ]
(d) Continent [ ]
Answer:
(a) Temple [✓]

Question b.
Which of the following scale indicates small scale map?
(a) 1 : 100 [ ]
(b) 1 : 1000 [ ]
(c) 1 : 10000 [ ]
(d) 1 : 100000 [ ]
Answer:
(d) 1 : 100000 [✓]

Answer the following questions in one sentence each:

Question a.
What is verbal scale?
Answer:
A scale in which distances are expressed with the use of words indicating measurement is called verbal scale.

Question b.
What is numerical scale?
Answer:
A scale in which distances are expressed as ratio is called numerical scale.

Question c.
What is linear scale?
Answer:
A scale in which distances are expressed by drawing graphical scale is called linear scale.

Question d.
What is large scale map?
Answer:
A map in which a particular part of ground covers comparatively more area is called large scale map.

Question e.
What is small scale map?
Answer:
A map in which a particular part of ground covers comparatively less area is called small scale map.

Write short notes on:

Question a.
Verbal scale.
Answer:
1. A scale in which distances are expressed with the use of words indicating measurement is called verbal scale.
2. For example, 1cm = 100 km.

3. In verbal scale, the word indicating measurement on the left hand side indicates the distance between any two points on a s map. On the other hand, the word indicating 1 measurement on the right hand side! indicates the ground distance between those two points.

4. When the map is reduced or enlarged by taking its photo copy, the verbal scale on the original map does not change.

Question b.
Numerical scale.
Answer:

1. Numerical scale: A scale in which distances are expressed as ratio is called numerical scale.
2. For example, 1:10000. It is also known as representative fraction.
3. In numerical scale, the same measuring unit is used for the figures on the left hand side and right hand side. However, no words are used to indicate this measuring unit.
4. In numerical scale, number 1 on the left hand side indicates the distance between any two points on a map. On the other hand, the number 10000 on the right hand side indicates the ground distance between those two points.
5. When the map is reduced or enlarged by taking its photo copy, the numerical scale on the original map does not change.

Question c.
Linear scale.
Answer:

1. A scale in which distances are expressed by drawing graphical scale is called linear scale.
2. For example,
   
3. Compass or blade of grass is used if the ruler is not available for the measurement.
4. A thread is used for measuring the curved distances between two points shown in a map.
5. When the map is reduced or enlarged by taking its photo copy, the linear scale drawn on the original map changes as per the changing size of the map.

Highlight differences /Distinguish between the following:

Question a.
Large scale map and Small scale map.
Answer:

Question b.
Numerical scale and Linear scale.
Answer:

Study the following map /figure/graph and answer the following questions:

Study the Figure and answer the following questions:

Question a.
How much is the ground distance between Mumbai and Gondia?
Answer:
The ground distance between Mumbai and Gondia is approximately 810 kilometres.

Question b.
How much is the distance between Satara and Sangli on a map?
Answer:
The distance between Satara and Sangli on a map is approximately 1.5 centimetres.

Thought-Provoking Question:

Think about it. 

Question a.
What is the need to use map scale? Think about it and write a paragraph.
Answer:

1. If the map scale is not mentioned in a map, it will become difficult to know the ground (actual) distance between any two points shown in a map.
2. Map scale is important element of a map. It facilitates map reading.
3. If the map scale is mentioned in a map, it will become very easy to understand the ground (actual) distance between any two points shown in a map.

Open-Ended Question:

Question a.
Which of the following scale will you prefer to use: (a) Verbal scale (b) Numerical scale (c) Linear scale?
Answer:

1. Different measuring units are used in different countries of the world. Due to linguistic differences, particular verbal scale or linear scale may not be used with ease in all the countries.
2. Numerical scale is a global scale. It can be used universally. Therefore, we will prefer numerical scale.

Balbharti Maharashtra State Board Class 8 English Solutions Chapter 3.4 Leisure Notes, Textbook Exercise Important Questions, and Answers.

Maharashtra State Board Class 8 English Solutions Chapter 3.4 Leisure

Class 8 English Chapter 3.4 Leisure Textbook Questions and Answers

Leisure Poem 8th Std Warming Up:

1. Discuss in groups and share with one another:

Leisure Poem Questions And Answers Class 8 Question 1.
The daily routine of your mother and father on working days
Answer:
(Points: what time they get up – what time they leave for work – what time they return home – have lunch – dinner – bedtime, etc.)

3.4 Leisure Questions And Answe Question 2.
How your family relaxes on weekends
Answer:
(Points: rest at home – visit relatives – shopping – malls – movies – gardens – catch up on housework, etc.)

Std 8 English Poem Leisure Question 3.
When you go for a picnic, what and how do you enjoy it?
Answer:
(Points: go to the beach/mall /garden/movies etc. – relax and enjoy by yourself – sing songs – go in big groups – go as a family – go to restaurants for food, etc.)

Leisure Question Answers Class 8 Question 4.
Do you spend time admiring and thinking over the beauties of nature? Elaborate on your response.
Answer:
(Points: no beautiful nature around/ gardens nearby – like enjoying natural beauties – prefer city life – like animals and birds – visit zoos and parks. etc.)

2. When a poet I writer attempts (o describe something in words, so that it appeals to our five senses (sight, smell, hearing, touch, taste) he/she has used a des ice called Imager.
For example a host of golden daffodils’.
to a chasm, deep and vast and wide’.
Go through other poems in your textbook or other books and find outlines that contain Imagery. Write them does n along with the name of the poem and line/stanza number.
Answer:
Students can attempt this activity on their own.

3. Prepare un Acrostic from the word ‘Leisure’. The words should be related to what one likes to do in free time:

1. L ………..
2. E ………….
3. I …………
4. S ………..
5. U ………..
6. Reading stories
7. E …………

Answer:

1. Laze around
2. Enjoy movies
3. Initiate games
4. Sleep
5. Undertake to clean house
6. Read stories
7. Exercise

1. Say Where:

Question a.
………… do the cows and sheep stand? …………..
Answer:
Beneath the branches of trees.

Question b.
………… do squirrels store their food? ………….
Answer:
In the grass.

Question c.
………….. do stars shine in the daytime …………..
Answer:
In the streams.

Question d.
………….. does Beauty’s smile begin? ……………….
Answer:
In her eyes.

2. Think and answer in your own words:

Question a.
What could have inspired the poet to compose this poem? Do you think it relates to our present-day life? Defend your choice.
Answer:
The poet must have seen the busy lives of people around him, who are always in a hurry and have no leisure to look at the beauty around. Yes, it certainly relates to our present life, which keeps getting busier and busier. Today, with the Internet, the mobile phone, the computer, and social networking sites, our lives are getting more I and more artificial and further from nature than ever before.

Question b.
Which line proves that in our busy lives we do not even have a fraction of a second to enjoy nature’s beauty?
Answer:
The lines are :
No time to see, when woods we pass
Where squirrels hide their nuts in the grass?
No time to see, in broad daylight,
Are streams full of stars, like skies at night?
No time to turn at Beauty’s glance,
And watch her feet, how they can dance?
No time to wait till her mouth can
Enrich that smile her eyes began.

Question c.
‘Beauty’ in stanza 5 to 6 can refer to a beautiful maiden as well as nature itself. Explain when and how nature ‘dances’ and also ‘smiles’.
Answer:
Nature dances during spring and: summer, when the leaves of trees and the flowers sway in the breeze. Nature smiles at the beginning of spring when the plants begin to once again bloom slowly.

Question d.
Why does the poet call our life ‘poor’?
Answer:
The poet calls our life ‘poor’ because we are always anxious and under stress. We are completely cut off from nature and cannot relax and enjoy its beauty. He feels that this type of life is a ‘poor’ life.

3. You have learned that when u human attribute is given to anything that is not a human being or it is spoken of as a person, the Figure of Speech used is culled as ‘Personification’:

Question a.
Pick out two examples of Personification from the poem
Answer:
(i) ‘No time to turn at Beauty’s glance, I And watch her feet, how they can; dance?’ Nature has been given the human qualities of ‘glancing’ and ‘dancing’.
(ii) ‘No time to wait till her mouth can Enrich the smile her eyes began.’ Nature has been given the human quality of ‘smiling’.

Question b.
Pick out from the poem, two examples of each of the following Figures of Speech:

3.4 Leisure Question 1.
Alliteration
Answer:
(i) We have no time to stand and stare.’ Repetition of the sound of the letter ‘s’.
(ii) ‘Streams full of stars, like skies at; night.’ Repetition of the sound of the letter ‘s’.

8th Standard English Poem Leisure Notes Question 2.
Simile
Answer:
(i) ‘And stare as long as sheep or cows.’ Here, a direct comparison has been made between sheep and cows.
(ii) ‘Streams full of stars, like skies at night.’ Here, a direct comparison has been made to the night skies.

Leisure Poem 8th Std Question 3.
Metaphor
Answer:
(i) ‘No time to turn at Beauty’s; glance.’ Here nature has been implicitly compared to a beautiful woman.
(ii) ‘Enrich the smile her eyes began.’ Here the blooming of flowers has been implicitly compared to a woman smiling.

Question c.
The poet opens his poem with a question. Is the question asked to receive some answer? No. It is a question used to emphasize and stress the fact that modern man has no time to enrich his life from nature. Such a device used by poets falls under the Figure of Speech called ‘Interrogation
or ‘Rhetorical Question’. Refer to the poem ‘The Pilgrim’ and find examples of Interrogation.
Answer:
‘What is this life, if full of care,
We have no time to stand and stare?’
Here the poet asks a question to emphasize and stress the fact that modern man has no time to appreciate nature.
(Note: The lines in stanzas 2,3,4,5 and 6 are also examples of Interrogation.)

4. Say where the images from mature given in the poem exist:

Air/Land/Water

Question a.
beneath the thoughts …………..
Answer:
Land

Question b.
squirrel hide nuts in grass …………
Answer:
Land

Question c.
streams in day time ………..
Answer:
Water

Question d.
stars/ skies at night …………
Answer:
Air

5. Make a paraphrase of the poem ‘Leisure’ in your own simple words. Write down in your notebook.
Answer:
In this poem, the poet, W.H. Davies, questions the type of life we are leading if we have no time to appreciate the beauties of nature. He says that we have no time to stand beneath the trees and stare as sheep and cows do. When we are walking through the woods we have no time to watch where the squirrels hide their food in the grass. We have no time to look at streams that sparkle and a twinkle in broad daylight and appear to be full of stars like the skies at night.

We have no time to watch when a beautiful young girl dances, or wait for her lips to complete the smile which started in her eyes. (We can also say that ‘Beauty’ is nature, and we have no time to see trees swaying In the breeze or flowers blooming slowly.)
In the concluding lines, the poet repeats that our life is a poor life if it is full of cares and worries with no time to appreciate and enjoy the beauty of nature.

Class 8 English Chapter 3.4 Leisure Additional Important Questions and Answers

Complex Factual Activities:

Class 8 English Leisure Question 1.
What does the poet want us to stare at and gain from it?
Answer:
The poet wants us to spare some time from our busy schedules to look at the beauty of nature and enjoy it.

Leisure Class 8 Question 2.
Enlist the beautiful things in nature that we overlook.
Answer:
We overlook:

1. squirrels hiding their food in the grass
2. twinkling and sparkling streams
3. a beautiful girl smile and dance/trees swaying in the breeze and flowers blooming slowly.

8th Standard English Poem Leisure Question 3.
Analysis/ Appreciation Of The Poem
Answer:

1. Poem and poet: ‘Leisure’ by William Henry Davies.
2. Theme: The poet regrets that ours is a poor life if it is full of cares and worries and we have no time to appreciate and enjoy the beauty of nature.
3. Tone: Serious and analytical; reflective poem.
4. Structure and stanzas: The stanzas are of two lines each; seven couplets with lines of equal length.
5. Rhyme and Rhythm: The rhyme scheme is aa, bb, cc, and so on, with the ending words of each couplet rhyming.
6. Language and Imagery: The language is simple; the poem has many figures of speech and is full of imagery when the poet describes the beauty of nature.
7. Figures of Speech: Alliteration, Personification, Simile, Metaphor, Repetition, Interrogation.

Balbharti Maharashtra State Board Class 8 English Solutions Chapter 3.2 The Kite Festival Notes, Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 8 English Solutions Chapter 3.2 The Kite Festival

Class 8 English Chapter 3.2 The Kite Festival Textbook Questions and Answers

The Kite Festival Std 8 Warming Up:

1. Cut out the wrong kites:

Answer:

2. Name the festival that you enjoy the most of all. Fill in the facts about that festival.
(a) Name of the festival:_______.
(b) When it is celebrated: _______.
(c) Why it is celebrated: ______.
(d) How it is celebrated: _______.
(e) Special cuisine: _______.
(f) Other special features: _______.
Answer:
Students can discuss and write down details about their favourite festival. They can consult their parents/friends / the internet, etc.

1. Give the Antonyms und Synonyms of the words below, choosing from those given:

Answer:

Words	Synonyms	Antonyms
Happily	Joyfully	Sorrowfully
Traditional	Old-fashioned	Modern
Halt	pause	start
Triumph	victory	defeat
Exotic	foreign	native
Rival	competitor	partner
Soar	rise	drop
Brilliance	lustre	dullness

2. Say whether the following statements are true or false:

Question a.
Fibreglass kites led to creating power – driven aeroplanes.
Answer:
False

Question b.
In Gujarat, the kite – festival is celebrated to welcome the Spring.
Answer:
False

Question c.
Uttarayana’ starts from Makar Sankranti onwards.
Answer:
True

Question d.
Kite – flying in Gujarat, is a competitive sport – cum – festival.
Answer:
True

Question e.
The kite – Bazar in Ahmedabad, is open day and night for a week.
Answer:
True

Question f.
The special thread for kite – flying is sharpened by adding sugar and glass pieces.
Answer:
False

3. Using points from the lesson, give the details of the following in a short paragraph for each topic:

Question a.
Different types of kites.
Answer:
Traditional kites are made of kite paper and have thin wooden frames. The modern kites may be motorized or made of fibreglass. Exotic kites have marvellous shapes such as that of eagles and snakes. There are also illuminated box-kites called tukals.

Question b.
International Kite Festival at Ahmedabad.
Answer:
The International Kite Festival at Ahmedabad is held either at the Sardar Patel Stadium or the Police Stadium. It attracts international kite-flyers as well as local champions. Little Indian paper kites compete with those from Japan, USA, UK and other countries. Exotic kites with marvellous shapes such as eagles and snakes soar in the sky. The Patang or Kite Bazar, in the heart of Ahmedabad, is open 24 hours a day for a whole week, and people crowd the streets through the night. Skilled craftsmen demonstrate age- old kite-making skills and how to prepare special thread. At night, illuminated box- kites are sent into the sky.

Question c.
The kite Bazar of Ahmedabad.
Answer:
During the Kite Festival at Ahmedabad, the Patang or Kite Bazar, in the heart of Ahmedabad, is open 24 hours a day for a whole week. People crowd the streets and buy their stocks, haggling through the night. Skilled craftsmen demonstrate age-old kite-making skills and how to prepare special thread covered with a mixture of glue and ground glass.

4. You hue just returned after your first experience of the kite – festival in Gujarat/Ahmedabad. You were thrilled with the festivities.

Write a short report about the kite – festival for your local newspaper. Give an attractive headline, a dateline and an account of the kite – festive. Write the report in third person with more use of Passive voice.
You have a friend who lives abroad. Write a letter to your friend describing how you enjoyed the kite-festival.

5.A. Verb forms show both, Tense (Present, Past, Future) and Aspect (Progressive, Perfect,Perfect Progressive):

Progressive (Continuous): be + verb-ing
Present Progressive: He is playing.
Past Progressive: He was playing.
Future Progressive: He will be playing.

Perfect: have / has / hod verb – en / cd
Present Perfect: They have played.
Past Perfect: They had played.
Future Perfect: They will have played.

Perfect Progressive: have/has/had + been + verb – ing
Present Perfect Progressive: We have been playing.
Past Perfect Progressive: We had been playing.
Future Perfect Progressive: We shall have been playing.

5. B. Underline the verb forms in the following sentences and state their Tense and Aspect:

(i) They are waiting for the right winds.
(ii) People were haggling over the price of kites.
(iii) Vendors had been selling kites all through the week.
(iv) Skilled craftsmen had demonstrated age-old skills.
(v) State Tourism Corporation will be organising the International Kite Festival.
(vi) Kite – flyers have demonstrated their skills with exotic kites.
Answer:

Sentences	Tense	Aspect
i. They are waiting for the right winds.	present	progressive
ii. People were haggling over the price of kites.	past	progressive
iii. Vendors had been selling kites all through the week.	past	perfect  progressive
iv. Skilled craftsmen had demonstrated age-old skills.	past	perfect
v. State Tourism Corporation will be organizing the International Kite Festival.	future	progressive
vi. Kite-flyers have demonstrated their skills with exotic kites.	present	perfect

Class 8 English Chapter 3.2 The Kite Festival Additional Important Questions and Answers

Complete the table showing how modern ones:

The Kite Festival Std 8 Question 1.

Kites of the past	Modem kites

Answer:

Kites of the past	Modem kites
(1) made of kite paper (2) had thin wooden frames (3) box kites	(1) motorized kites (2) kites made of fibreglass

The Kite Festival Std 8 Questions And Answers Question 2.
When is kite-flying at its peak in India?
Answer:
Kite-flying is at its peak in India during the coming of Spring and during the festival of Makar Sankranti, which coincides with the festival of Uttarayan.

3.2 The Kite Festival Questions And Answers Question 3.
Write how they celebrate the kite-flying festival in Gujarat.
Answer:
During the kite-flying festival, people of all ages go out into the open to fly kites and to cut’ each others’ kites. In towns and cities, where open spaces are difficult to find, terraces and rooftops are often used to fly the kites.

Activities based on Contextual Grammar:

The Kite Festival Questions And Answers Question 1.
People of all ages go out into the open to try their luck with their kites.
(Pick out the finite verbs and the infinitives.)
Answer:
finite verb – go; infinitive – to try

The Kite Festival Std 8 Question Answer Question 2.
It is also a celebration to mark the end of winter. (Rewrite using ‘which’.)
Answer:
It is also a celebration which marks the end of winter.

Personal Response:

The Kite Festival Std 8 Question Answer Question 1.
Do you like flying kites? Why?
Answer:
I am not a very big fan of kites. I do not like to fly them, but I like to watch other people do so. I used to fly kites earlier; but once I came to know that birds died because of the glass-covered thread, and there were injuries to people too, I stopped this sport.

List the reasons:

The Kite Festival Answers Question 1.
The kite-festival at Ahmedabad is very special.
Answer:
The kite-festival at Ahmedabad is very special because:

• An International Kite Festival is held either at the Sardar Patel Stadium or the Police Stadium.
• It attracts international kite-flyers as well as local champions.
• Little Indian paper kites compete with those from Japan, the USA, UK and other countries.
• Exotic kites with marvellous shapes such as eagles and snakes soar in the sky.
• The Patang or Kite Bazar in the heart of Ahmedabad is open 24 hours a day for a whole week, and people
• crowd the streets through the night.
• Skilled craftsmen demonstrate kite-making age-old skills and how to prepare a special thread.
• At night, illuminated box-kites are sent into the sky.

3.2 The Kite Festival Question 2.
How do they celebrate the kite-flying festival in Gujarat?
Answer:
The kite-flying begins at dawn and continues throughout the day. People of all ages gather in the open, on rooftops and terraces. They compete with each other and are triumphant when someone cuts the thread of a rival. Some people prepare special lines for their kites. There is music in the air and traditional delicacies are specially prepared. An International Kite Festival is organized by the Gujarat State Tourism Corporation.

Complete the following:

Class 8 English Chapter 3.2 Question Answer Question 1.
A visit to the Patang Bazar proves that _______.
Answer:
the entire city of Ahmedabad is obsessed with kites

Question 2.
The special thread for kite-flying is prepared by ________.
Answer:
covering the thread with a mixture of glue and ground glass and allowing it to dry

Answer the following:

Question 1.
Different types of kites:
Answer:
Traditional kites are made of kite paper and have thin wooden frames. The modern kites may be motorized or made of fibreglass. Exotic kites have marvellous shapes such as that eagles and snakes. There are also illuminated box-kites called tukuls.

Question 2.
International Kite Festival at Ahmedabad:
Answer:
The International Kite Festival at Ahmedabad is held either at the Sardar Patel Stadium or the Police Stadium. It attracts international kite-flyers as well as local champions. Little Indian paper kites compete with those from Japan, USA, UK and other countries. Exotic kites with marvellous shapes such as eagles and snakes soar in the sky. The Patang or Kite Bazar, in the heart of Ahmedabad, is open 24 hours a day for a whole week, and people crowd the streets through the night. Skilled craftsmen demonstrate age-old kite-making skills and how to prepare a special thread. At night, illuminated box- kites are sent into the sky.

Question 3.
The Kite-Bazar of Ahmedabad:
Answer:
During the Kite Festival at Ahmedabad, the Patang or Kite Bazar, in the heart of Ahmedabad, is open 24 hours a day for a whole week. People crowd the streets and buy their stocks, haggling through the night. Skilled craftsmen demonstrate age-old kite-making skills and how to prepare special thread covered with a mixture of glue and ground glass.

Question 4.
One of the highlights of this festival is the Patang Bazar, which is open twenty-four hours a day, for a whole week.
(Underline the clauses in the sentence.)
Answer:
One of the highlights of this festival is the Patang Bazar, which is open twenty-four hours a day, for a whole week.

Question 5.
They add a grand beauty to the dark sky and compete with the brilliance of the stars.
(Rewrite as two separate sentences.)
Answer:
They add a grand beauty to the dark sky. They compete with the brilliance of the stars.

Personal Response:

Question 1.
What is the care to be taken by children while flying kites?
Answer:
Children should not run after kites on the road or try to rescue them from trees. This could lead to accidents. They should be careful if they are flying kites from terraces and rooftops. The thread should be handled with care, and there should be no injuries to animals or human beings because of it.

Do as directed:

Question 1.
Pick out two compounds, words from the lesson.
Answer:
Two compound words: kiteflying, power-driven

Question 2.
Use the following phrase in your own sentence: in the middle of the night.
Answer:
The baby woke up in the middle of the night and began to play.

Question 3.
Build a word chain of five adjectives :
Answer:
long → green → naughty → young → grateful → lovely.

Question 4.
Find out four hidden words from the given word:
traditional (Each word should have at least 3 letters.)
Answer:
traditional: tradition, train, drain, trait

Question 5.
Use the following word in two separate sentences, the word having different meanings (homographs):
watch
Answer:
(i) The policemen watched the house the whole day.
(ii) I was very upset as I had lost my watch.

Question 6.
Underline the clauses in the following sentence:
There is music in the air and traditional delicacies are specially prepared for the day
Answer:
There is music in the air and traditional delicacies are specially prepared for the day.

Question 7.
Identify the type of sentence:
The little boy would happily pick up his kite and run out into the field.
Answer:
Assertive sentence.

Question 8.
Rewrite as an affirmative sentence:
In India, however, the tradition of kite-flying has not changed.
Answer:
In India, however, the tradition of kite-flying has remained the same.

Question 9.
Rewrite in indirect speech:
The harassed mother would often say
to her restless son, “Why don’t you go fly a kite ?”
Answer:
The harassed mother would often ask her restless son why he did not go fly a kite.

Question 10.
Use the following word as a noun and a verb in two separate sentences:
cut
Answer:

• The cut on my hand healed soon, (noun)
• I cut my finger when I was slicing a mango, (verb)

Writing Skills:

Question 1.
You have just returned after your first experience of the kite-festival in Gujarat/Ahmedabad. You were thrilled with the festivities.
Write a short report about the kite festival for your local newspaper. Give an attractive headline, a dateline, and an account of the kite-festival. Write the report in the third person with more use of Passive Voice.
Answer:

High-Flying Kites Adorn The Sky

Ahmedabad, 17 January: A variety of colourful kites adorned the sky this year during the International Kite Festival here. A record number of countries participated in this annual festival. The famous International Kite Festival, organized by the Gujarat State Tourism Corporation, was held at the Sardar Patel Stadium. 14 countries, including India, participated. The kites were very colourful and in a variety of shapes. There were dragons, eagles, snakes, crocodiles, etc. Some had tiny lights in them, while j some were studded with stones. Excited spectators watched in awe as the kites; soared in the sky, free as birds.

This year, the first prize, a gold-plated cup in the shape of a kite, went to Korea. The Korean team succeeded in keeping their kite in the sky for the longest time. Last year’s winner and the host country, India, J did not stand a chance this year and were ; out of the competition at an early stage. “We will double our efforts for the next year and come out with flying colours,” said Rakesh ) Pandya, captain of the home team. We wish them all the best for the next year, Harsh Mehta.

Question 2.
You have a friend who lives abroad.
Write a letter to him/her describing how you enjoyed the kite-festival,
Answer:
‘Gulmohar’
Ahmedabad
17 January 2019

Hi Dominic,
How are you? You have hardly written j to me since you went to London. Why the silence?
Yes, I know you are busy, but you can spare some time for an old friend, can’t you?

Here in Ahmedabad, the kite festival is just over. We had a wonderful time flying kites and cheering others. The school was closed for two days, and my friends and I spent one j day watching the competition at the Police Stadium and the other day at the ground near our house, flying an assortment of kites. Our kites were ordinary ones, but you should have seen the exotic kites being flown at the Police Stadium! They were from Japan, the U.S., U.K., Thailand, Korea and other places. They were in the shape of eagles, snakes, crocodiles, dragons, etc. Some had shining tails while some had bejewelled bodies. The competition was very stiff-but guess what! The first prize was won by the Indian team!
Our own competition too was very thrilling. We cut so many kites! We were also awake the whole night shopping for kites and eating. It was really a wonderful time.

Well, I hope that next year you will be back in India and maybe you can come to Ahmedabad during this time. You will certainly enjoy the festival-and the eats! Hope you find time to reply.
Your friend,
Harsh.

Balbharti Maharashtra State Board Class 8 English Solutions Chapter 3.3 The Last Leaf Notes, Textbook Exercise Important Questions, and Answers.

Maharashtra State Board Class 8 English Solutions Chapter 3.3 The Last Leaf

Class 8 English Chapter 3.3 The Last Leaf Textbook Questions and Answers

3.3 The Last Leaf Warming Up:

1. Suppose you suffer from a long – term illness (one or two weeks), what should you do and what should you avoid? Fill up the table of Do’s and Don’ts:

Do’s	Don’ts
(1) Go to a doctor for a diagnosis.	(1) Do not …………..
(2) …………	(2) Do not avoid medication on time.
(3) Take a suitable diet.	(3) Avoid …………..
(4) Take rest.	(4) Avoid physical stress and exertion.
(5) Rest in a properly ventilated room.	(5) Do not …………….
(6) Have cheerful thoughts, courage, a positive attitude.	(6) Do not lose …….. and ………….

Answer:

Do’s	Don’ts
(1) Go to a doctor for diagnosis.	(1) Do not try any medication on your own.
(2) Take medicines on time.	(2) Do not avoid medication on time.
(3) Take a suitable diet.	(3) Avoid junk food.
(4) Take rest.	(4) Avoid physical stress and exertion.
(5) Rest in a properly ventilated room.	(5) Do not close doors and windows.
(6) Have cheerful thoughts, courage, a positive attitude.	(6) Do not lose hope and courage.

2. You already know that Homophones are pairs of words that sound the same but differ in spellings and meanings:
For example sum and some
There are some words that even have the same spelling and pronunciations, but have different meanings in different situations or contexts.
For example: bat (a bird) and ki (sports / games equipment)
Such words are called Homographs.
Make pairs of sentences of your own to point out the different meanings of the following Homographs

The Last Leaf Class 8 Questions And Answers Maharashtra Board Question 1.
fine:
Answer:
(i) The new driver had to pay a fine for breaking the signal.
(ii) We decided to go for a picnic only if the day was fine.

The Last Leaf Class 8 Questions And Answers Question 2.
wave:
Answer:
(i) Ronny waved to his father before going for the picnic.
(ii) The waves in the sea before the tsunami were huge.

The Last Leaf Question Answer Class 8 Question 3.
bear:
Answer:
(i) The grizzly bear hibernates during winter.
(ii) Simi could not bear to see the two cats fighting.

3.3 The Last Leaf Question 4.
rose:
Answer:
(i) The rose is a beautiful flower.
(ii) The teacher rose from her chair to explain the sum.

3.3 The Last Leaf Questions And Answers Question 5.
lead:
Answer:
(i) Lead is used in pencils.
(ii) A good king leads his country to prosperity.

Class 8 English Chapter 3.3 The Last Leaf Question Answer Question 6.
match:
Answer:
(i) Though we lost the match, we were not upset,
(ii) “Buy the shoes only if they match the dress,” said mother to Madhu.

The Last Leaf Class 8 Questions And Answers Pdf Question 7.
second:
Answer:
(i) Every second counts when we are writing an examination paper.
(ii) “Take the second turn on the right,” directed the policeman.

The Last Leaf 8th Standard Question 8.
object:
Answer:
(i) The lawyer objected to what the witness said.
(ii) The objects on the table were taken away before the girl could see them properly.

1. Read the story and choose the appropriate meanings:

Question a.
Struggling artists:
(i) artists fighting with one another
(ii) artists trying hard to earn a living
(iii) artists painting war scenes
Answer:
(ii) artists trying hard to earn a living

Question b.
Skeleton branches:
(i) bones branching out from joints
(ii) leafy branches
(iii) bare branches
Answer:
(iii) bare branches

Question c.
Wielded the brush:
(i) painted skillfully
(ii) broke the brush
(iii) joined the broken brush
Answer:
(i) painted skillfully

Question d.
Palette:
(i) the tip of the brush
(ii) a board used by artists to mix colours
(iii) a fancy dinner plate
Answer:
(ii) a board used by artists to mix colours

Question e.
Masterpiece:
(i) a master who promotes peace
(ii) the very first creation of on artist
(iii) an exceptionally beautiful work of art
Answer:
(iii) an exceptionally beautiful work of art

2. Make pairs of sentences to show the difference between the meanings of the following Homographs from the story:

Question a.
interest
Answer:
(i) The bank promised a high rate of interest to its customers.
(ii) The audience soon lost interest in the boring match.

Question b.
well
Answer:
(i) The well was so deep that one could not see the water.
(ii) The Principal sent Sumeet home as he was not feeling well.

Question c.
left
Answer:
(i) When Roma turned to her left, she saw a long line of taxis.
(ii) The Mayor had left before it begem to rain.

Question d.
just
Answer:
(i) The children had just left when the magician arrived.
(ii) It is the duty of a judge to be just.

Question e.
mind
Answer:
(i) “Mind your language!” said the man to the rude young boy angrily.
(ii) We should try not to have any negative thoughts in our mind.

3. State the facts about the story:

Main characters:
Problem:
Attempts made to solve it:
Climax / Turning point:
Problem solved:
End:
Answer:
Main characters: Sue, Johnsy, the doctor and Behrman
Problem: Johnsy’s negative attitude, her lack of will to live and the fancy that she would die when the last leaf fell from the ivy vine.
Attempts made to solve it: The doctor informed Sue that Johnsy would recover only if she had the wish to live. Sue looked after her well and tried to make her think positively. Finally, Behrman painted a leaf on the wall so that the last leaf would never fall, and Johnsy would live.
Climax/Tuming point:
(i) When Johnsy sees the last leaf still clinging to the vine, and realizes that she has been given a message that she was wicked to want to die.
(ii) The sweeper finding Behrman in very wet clothes and shoes, with scattered brushes and a palette with yellow and green colors mixed on it.
Problem solved: Johnsy realizes her mistake and begins to look forward to life again.
End: Though Johnsy lives, Behrman, who painted the last leaf, contracts pneumonia due to exposure to rain and snow. He dies due to his efforts. He dies so that Johnsy lives.

4. Say whether the following statements are right or wrong:

Question a.
Sue and Johnsy were very close friends.
Answer:
Right

Question b.
Sue was a rich girl.
Answer:
Wrong

Question c.
Johnsy was hopeful that she will live.
Answer:
Wrong

Question d.
Behrman was a hard-hearted person.
Answer:
Wrong

Question e.
The last leaf fell off during the rain.
Answer:
Right

Question f.
Johnsy realized that her thinking was wrong.
Answer:
Right

Question g.
Behrman did not know anything about the last leaf on the ivy.
Answer:
Wrong

5. Correct the following statements:

Question a.
Sue and Johnsy were good neighbours.
Answer:
Sue and Johnsy were very good friends.

Question b.
Johnsy was eager to recover from her illness.
Answer:
Johnsy had made up her mind that she was not going to recover.

Question c.
Sue ignored Johnsy completely.
Answer:
Sue looked after Johnsy well.

Question d.
Behrman was a very heartless person.
Answer:
Behrman was a very kind-hearted person.

Question e.
The real ivy leaf did not fall off at all.
Answer:
The real ivy leaf fell off the night it rained and snowed.

Question f.
The last leaf was a real leaf that survived.
Answer:
The last leaf was a leaf painted on the wall by Behrman.

6. Read the descriptions of the following from the story and describe any one of them using your own words:

Question 1.
The ivy vine
Answer:
Outside the window there was an old ivy vine, gnarled and decayed at the roots. It had climbed half way up the brick wall. It had lost most of its leaves due to the cold autumn. Only a few bare branches were left, clinging to the bricks.

Question 2.
Behrman
Answer:
Behrman was a struggling painter who lived on the ground floor of the building where Sue and Johnsy lived. He was a failure in art, for though he had been painting for forty years, he had not made any money. He always dreamt about painting a masterpiece, and often spoke about it, but had never got round to doing it. He served as a model for the young artists in the colony, who could not afford other models.

He was shocked when he heard about Johnsy’s fancy and thought that the place was not good for her. He was a generous, compassionate and kind- hearted man. Even though he was old, he braved the wind, rain and snow to go out and paint the last leaf on the wall. He died in order that Johnsy could live.

Question 3.
The last leaf that Johnsy saw
Answer:
The last leaf that Johnsy saw was not a real leaf but a leaf painted on the wall by Behrman. It was dark green near its stem, but its edges were tinted with yellow. It hung from a branch some twenty feet above the ground. Naturally it never fluttered or moved when the wind blew. It was Behrman’s masterpiece and had been painted the night when the real last leaf had fallen.

7. You have learnt that a Clause is a group of words that has a Subject and a Verb, and is a part of a larger sentence:
In the sentence, ‘We returned home, when school was over’ there are two clauses.
(i) We returned home and
(ii) When school was over’.
The first one makes complete sense, so it is called Main I Principal Clause. The second one is not complete by itself. It depends on the Main Clause to convey proper sense. So it is called Dependant or Subordinate Clause. ‘When’ is the joining word, and it is called o Subordinator.

In the following sentences, point out the Main Clause and Subordinate Clause. Encircle the Subordinator.

Question a.
There was a colony, where many struggling artists lived.
Answer:
Main Clause: There was a colony
Subordinate Clause: where many struggling artists lived
Subordlnator: where

Question b.
Though Sue looked after her well, Johnsy showed no signs of improvement.
Answer:
Main Clause: Johnsy showed no signs of improvement
Subordinate Clause: Though Sue looked after her very well
Subordlnator: Though

Question c.
Sue thought that she had fallen asleep.
Answer:
Main Clause: Sue thought
Subordinate Clause: that she had fallen asleep
Subordinator: that

Question d.
Old Behrman was a painter, who lived on the ground floor.
Answer:
Main Clause: Old Behrman was a painter
Subordinate Clause: who lived on the ground floor
Subordlnator: who

Question e.
Johnsy was sleeping when the two went upstairs.
Answer:
Main Clause: Johnsy was sleeping
Subordinate Clause: when the two went upstairs
Subordlnator: when

Question f.
I want to see the last one before it falls.
Answer:
Main Clause: I want to see the last one
Subordinate Clause: before It falls
Subordlnator: before

8. Compose an imaginary dialogue between Sue and Johns, when I realise what Behrman had done for Johnsy:
Answer:
Johnsy: Sue, did you know that Mr. Behrman had painted that last leaf?
Sue: No, I knew it just now, too.
Johnsy: Sue, that means that he got wet that night painting the last leaf!
Sue: And got pneumonia after that!
Johnsy: Yes, because of my stupid fancy that I would die when the last leaf fell.
Sue: It certainly was a stupid idea.
Johnsy: I feel so guilty now! Sue, it is as if …. as if …. he died for me!
Sue: Yes, so that you may live.
Johnsy: Oh, what a wonderful, compassionate man! To go out in that cold, wintry, snowy night just to paint that leaf!
Sue: And develop pneumonia ….
Johnsy: What can I do now? How can I ever thank him?
Sue: I know what you can do!
Johnsy: What? What?
Sue: Paint your masterpiece of the Bay of Naples and dedicate it to him.
Johnsy: Yes, I think that’s a good idea.Yes, I’ll do that. Thanks, Sue.

Class 8 English Chapter 3.3 The Last Leaf Additional Important Questions and Answers

Complex Factual Activities:

Question 1.
What did the doctor tell Sue about Johnsy?
Answer:
The doctor told Sue that Johnsy had one chance in ten. That chance was for Johnsy to want to live, and Johnsy had made up her mind that she was not going to get well. He also told Sue that medicines alone would not help if the patient did not want to live.

Question 2.
Describe the ivy vine outside the window.
Answer:
Outside the window, there was an old ivy vine, gnarled and decayed at the roots. It had climbed half way up the brick wall. It had lost most of its leaves due to the cold autumn. Only a few bare branches were left, clinging to the bricks.

Question 3.
Explain the false belief that Johnsy had about the ivy vine.
Answer:
Johnsy felt that when the last leaf fell off from the ivy vine, she too would die.

Question 4.
Who was Behrman? Explain why Sue called Him to their flat.
Answer:
Behrman was a struggling painter who lived on the ground floor of the building where Sue and Johnsy lived. He served as a model for the young artists in the colony. Sue called him to their flat to act as a model for the old man that she was drawing.

Question 5.
What happened that night and what did the two friends see when the window was open?
Answer:
That night it rained and snowed. A fierce wind blew. When the window was open, the two friends saw one ivy leaf still clinging to the vine. It was dark green near the stem, but its edges were tinted with yellow. It hung from a branch some twenty feet above the ground.

Question 6.
What did Johnsy declare when she saw the last ivy leaf?
Answer:
When Johnsy saw the last ivy leaf, she declared that it would fall that day and she would die at the same time.

Question 7.
What change came over Johnsy the next day? Why?
Answer:
Johnsy now felt that she had been wicked earlier and it was a sin to want to die. She wanted to sit up in bed and was ready to have broth and milk. She looked forward to the future and hoped to paint the Bay of Naples some day. It was the sight of the last leaf staying on the vine that was the reason for her change.

Question 8.
Explain what happened to Mr. Behrman.
Answer:
Mr. Behrman had gone out in the rain and snow to paint the last leaf on the wall. He had got thoroughly wet and became ill with pneumonia. He died in a hospital two days later.

Question 9.
Who had saved Johnsy’s life and how?
Answer:
Mr. Behrman had saved Johnsy’s life. He had realized that Johnsy had a fancy that she would die after the last leaf; fell. He wanted to make certain that the last J leaf never fell, and hence he painted a false leaf on the wall. The sight of the persistent leaf, which Johnsy thought was real, made her come to her senses and want to live.

Personal Response:

Question 1.
What type of attitude should a person have when he/she is ill?
Answer:
When a person is ill, he/she should have a positive attitude. He/She should have cheerful thoughts and courage and try to keep the mind occupied. Only then will medication help.

Question 2.
Do you think that Johnsy was talking nonsense? Or did she have some forewarning that she would die?
Answer:
I think that Johnsy was talking nonsense. How can the number of leaves on an ivy vine indicate when she was going to die? This is just having negative thoughts when the mind is idle and frightened.

Write who said the given words and to whom:

Question 1.

The words	Who said	To whom
(1) Open the window
(2) She is very ill and weak
(3) I have not heard of such a thing.
(4) It is the last one.

Answer:

The words	Who said	To whom
(1) Open the window	Johnsy	Sue
(2) She is very ill and weak	Sue	Behrman
(3) I have not heard of such a thing.	Behrman	Sue
(4) It is the last one.	Johnsy	Sue

Write the words given below in the proper columns:

Question 1.
idiotic, fancy, foolish, weak, place, away, upstairs, work, rain, continuously,closed, window, fierce, bravely, branch,surely
Answer:

Nouns	Adjectives	Adverbs
fancy, place,	idiotic,	away,
work, rain,	foolish,	upstairs,
window,	weak,	continuously,
branch	closed,	bravely,
	fierce	surely

Do as directed:

Pick out two words from the lesson whose first letter is silent.
Answer:
pneumonia, gnarled.

Question 2.
Use the following phrase in your own sentence : above the ground
Answer:
During monsoon, the clouds are just a few feet above the ground in Ooty.

Question 3.
Add two letters before the given word to form three separate words:
own
Answer:
brown, crown, drown

Question 4.
Find out four hidden words from the given word:
twilight (Each word should have at least 3 letters.)
Answer:
twilight: light, tight, wilt, tilt

Question 5.
Use the following word and its homophone in two separate sentences: earn
Answer:
(i) It is difficult to earn a living if you are illiterate.
(ii) I placed the flowers in an urn and poured water into it.

Question 6.
Pick out the main clause and subordinate clause from the following sentence:
Medicines alone did not help if the patient did not wish to live.
Answer:
Medicines alone did not help- the main clause if the patient did not wish to live-subordinate clause.

Question 7.
Rewrite in indirect speech :
“Open the window; I want to see,” she
ordered. Sue obeyed.
Answer:
She ordered Sue to open the window as she wanted to see. Sue obeyed.

Question 8.
Pick out the non-finite verb and state what it is:
He always talked of his coming masterpiece.
Answer:
coming – present participle

Question 9.
Rewrite as an affirmative sentence:
In those days, it was not easy to cure pneumonia patients.
Answer:
In those days, it was difficult to cure pneumonia patients.

Question 10.
Rewrite using the positive form of the adjective:
They are falling faster now.
Answer:
They were not falling as fast as before.